Proving one interval is a subset of others

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I am trying to prove that $left(a,bright)$ is an open set in $mathbbR$ under the usual metric $dleft(x,yright)=|x-y|$



given any $xin left(a,bright)$ I am supposed to produce an open ball which is contained in $left(a,bright)$.



I think $epsilon=minx-a,b-x$ will work for us as the radius of the ball. That is $left(x-epsilon,x+epsilonright) subset left(a,bright)$




I am unable to prove the following mathematically.
$left(x-epsilon,x+epsilonright) subset left(a,bright)$




Help me with this.










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  • The desired containment is equivalent to $a leq x - epsilon$ and $x + epsilon leq b$, and these in turn follow immediately from your definition of $epsilon$.
    – Bungo
    Sep 8 at 5:50














up vote
2
down vote

favorite












I am trying to prove that $left(a,bright)$ is an open set in $mathbbR$ under the usual metric $dleft(x,yright)=|x-y|$



given any $xin left(a,bright)$ I am supposed to produce an open ball which is contained in $left(a,bright)$.



I think $epsilon=minx-a,b-x$ will work for us as the radius of the ball. That is $left(x-epsilon,x+epsilonright) subset left(a,bright)$




I am unable to prove the following mathematically.
$left(x-epsilon,x+epsilonright) subset left(a,bright)$




Help me with this.










share|cite|improve this question





















  • The desired containment is equivalent to $a leq x - epsilon$ and $x + epsilon leq b$, and these in turn follow immediately from your definition of $epsilon$.
    – Bungo
    Sep 8 at 5:50












up vote
2
down vote

favorite









up vote
2
down vote

favorite











I am trying to prove that $left(a,bright)$ is an open set in $mathbbR$ under the usual metric $dleft(x,yright)=|x-y|$



given any $xin left(a,bright)$ I am supposed to produce an open ball which is contained in $left(a,bright)$.



I think $epsilon=minx-a,b-x$ will work for us as the radius of the ball. That is $left(x-epsilon,x+epsilonright) subset left(a,bright)$




I am unable to prove the following mathematically.
$left(x-epsilon,x+epsilonright) subset left(a,bright)$




Help me with this.










share|cite|improve this question













I am trying to prove that $left(a,bright)$ is an open set in $mathbbR$ under the usual metric $dleft(x,yright)=|x-y|$



given any $xin left(a,bright)$ I am supposed to produce an open ball which is contained in $left(a,bright)$.



I think $epsilon=minx-a,b-x$ will work for us as the radius of the ball. That is $left(x-epsilon,x+epsilonright) subset left(a,bright)$




I am unable to prove the following mathematically.
$left(x-epsilon,x+epsilonright) subset left(a,bright)$




Help me with this.







real-analysis






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asked Sep 8 at 5:16









user581912

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  • The desired containment is equivalent to $a leq x - epsilon$ and $x + epsilon leq b$, and these in turn follow immediately from your definition of $epsilon$.
    – Bungo
    Sep 8 at 5:50
















  • The desired containment is equivalent to $a leq x - epsilon$ and $x + epsilon leq b$, and these in turn follow immediately from your definition of $epsilon$.
    – Bungo
    Sep 8 at 5:50















The desired containment is equivalent to $a leq x - epsilon$ and $x + epsilon leq b$, and these in turn follow immediately from your definition of $epsilon$.
– Bungo
Sep 8 at 5:50




The desired containment is equivalent to $a leq x - epsilon$ and $x + epsilon leq b$, and these in turn follow immediately from your definition of $epsilon$.
– Bungo
Sep 8 at 5:50










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        answered Sep 8 at 6:08









        dmtri

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