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Clash Royale CLAN TAG #URR8PPP up vote 0 down vote favorite I have a real world problem that I would like to solve. I think this problem is an optimisation one. But I am not sure, and I have never work with optimisation algorithms or formulas. I have 8 records of data: Start Date End Date Monday, Tuesday ... Sunday Values in milligrams Y So a single record is a range of dates that a patient took some medicine. The patient takes every day his medicine as indicated by the data above (3rd point). For example, 01/08/2018 15/08/2018 Monday: 4.5 milligram, Tuesday: 4.5 milligram, Wednesday: 5.0 milligram .... Sunday: 5.5 milligram. 2.46 Given the above data, start date, end date, milligram per day, this yields to the value of Y. I would like to calculate the milligram per day given a start, end dates and desired Y value. Although programmatically I was able to represent the problem and also to calculate the total medicine in milligram given the range of dates etc, I am strugglin

Clash Royale CLAN TAG #URR8PPP up vote 2 down vote favorite Hartogs's Theorem Let $f$ be a holomorphic function on a set $G setminus K$, where $G$ is an open subset of $mathbbC^n$ ($n ge 2$) and $K$ is a compact subset of $G$. If the complement $Gsetminus K$ is connected, then $f$ can be extended to a unique to a unique holomorphic function on $G$. This theorem can be used to show the following result about the zeros of analytic functions of several variables. Suppose that $f$ is an analytic function on some open set $U$ and that $f$ is not identically zero on $U subset mathbbC^n$ with $n ge 2$. Then, the set of zeros of $f$ (i.e. $Lambda(f)= z: f(z)=0$) is not compact. Since $Lambda(f)$ is not compact we can have the following three possibilities: $Lambda(f)$ is closed but is not bound $Lambda(f)$ is not closed but bounded $Lambda(f)$ is not closed and not bounded My question is the following: Can we come up with examples of $f$ for each of the three cases? H