Understanding the definition of prime element.

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I have trouble understanding the definition of a prime element. The definition says that
$p$ is a prime element if $p$ divides $ab$
then either $p$ divides $a$ or $p$ divides
$b$.
but if we consider the integer 10, then it divides
$2 cdot 20$ and also divides 20,
so is 10 a prime elenent?
can you explain this?







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  • The prime elements of the ring $mathbb Z$ are the integers with an absolute value beging a prime number. $1$ is usually ruled out.
    – Peter
    Aug 15 at 10:47











  • But it satisfies the definition of a prime element, the definition says nothing about $p$ being a prime number.
    – paradox
    Aug 15 at 10:49







  • 1




    But it must satisfy the property for every elements $a,b$ in the ring.
    – Peter
    Aug 15 at 10:51










  • If $R$ is a unital ring then $pin R$ is a prime element in $R$ if $p$ is not a unit and satisfies: $forall a,bin R[pmid abimplies pmid avee pmid b]$.
    – drhab
    Aug 15 at 10:57















up vote
0
down vote

favorite












I have trouble understanding the definition of a prime element. The definition says that
$p$ is a prime element if $p$ divides $ab$
then either $p$ divides $a$ or $p$ divides
$b$.
but if we consider the integer 10, then it divides
$2 cdot 20$ and also divides 20,
so is 10 a prime elenent?
can you explain this?







share|cite|improve this question






















  • The prime elements of the ring $mathbb Z$ are the integers with an absolute value beging a prime number. $1$ is usually ruled out.
    – Peter
    Aug 15 at 10:47











  • But it satisfies the definition of a prime element, the definition says nothing about $p$ being a prime number.
    – paradox
    Aug 15 at 10:49







  • 1




    But it must satisfy the property for every elements $a,b$ in the ring.
    – Peter
    Aug 15 at 10:51










  • If $R$ is a unital ring then $pin R$ is a prime element in $R$ if $p$ is not a unit and satisfies: $forall a,bin R[pmid abimplies pmid avee pmid b]$.
    – drhab
    Aug 15 at 10:57













up vote
0
down vote

favorite









up vote
0
down vote

favorite











I have trouble understanding the definition of a prime element. The definition says that
$p$ is a prime element if $p$ divides $ab$
then either $p$ divides $a$ or $p$ divides
$b$.
but if we consider the integer 10, then it divides
$2 cdot 20$ and also divides 20,
so is 10 a prime elenent?
can you explain this?







share|cite|improve this question














I have trouble understanding the definition of a prime element. The definition says that
$p$ is a prime element if $p$ divides $ab$
then either $p$ divides $a$ or $p$ divides
$b$.
but if we consider the integer 10, then it divides
$2 cdot 20$ and also divides 20,
so is 10 a prime elenent?
can you explain this?









share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Aug 15 at 10:46

























asked Aug 15 at 10:43









paradox

92




92











  • The prime elements of the ring $mathbb Z$ are the integers with an absolute value beging a prime number. $1$ is usually ruled out.
    – Peter
    Aug 15 at 10:47











  • But it satisfies the definition of a prime element, the definition says nothing about $p$ being a prime number.
    – paradox
    Aug 15 at 10:49







  • 1




    But it must satisfy the property for every elements $a,b$ in the ring.
    – Peter
    Aug 15 at 10:51










  • If $R$ is a unital ring then $pin R$ is a prime element in $R$ if $p$ is not a unit and satisfies: $forall a,bin R[pmid abimplies pmid avee pmid b]$.
    – drhab
    Aug 15 at 10:57

















  • The prime elements of the ring $mathbb Z$ are the integers with an absolute value beging a prime number. $1$ is usually ruled out.
    – Peter
    Aug 15 at 10:47











  • But it satisfies the definition of a prime element, the definition says nothing about $p$ being a prime number.
    – paradox
    Aug 15 at 10:49







  • 1




    But it must satisfy the property for every elements $a,b$ in the ring.
    – Peter
    Aug 15 at 10:51










  • If $R$ is a unital ring then $pin R$ is a prime element in $R$ if $p$ is not a unit and satisfies: $forall a,bin R[pmid abimplies pmid avee pmid b]$.
    – drhab
    Aug 15 at 10:57
















The prime elements of the ring $mathbb Z$ are the integers with an absolute value beging a prime number. $1$ is usually ruled out.
– Peter
Aug 15 at 10:47





The prime elements of the ring $mathbb Z$ are the integers with an absolute value beging a prime number. $1$ is usually ruled out.
– Peter
Aug 15 at 10:47













But it satisfies the definition of a prime element, the definition says nothing about $p$ being a prime number.
– paradox
Aug 15 at 10:49





But it satisfies the definition of a prime element, the definition says nothing about $p$ being a prime number.
– paradox
Aug 15 at 10:49





1




1




But it must satisfy the property for every elements $a,b$ in the ring.
– Peter
Aug 15 at 10:51




But it must satisfy the property for every elements $a,b$ in the ring.
– Peter
Aug 15 at 10:51












If $R$ is a unital ring then $pin R$ is a prime element in $R$ if $p$ is not a unit and satisfies: $forall a,bin R[pmid abimplies pmid avee pmid b]$.
– drhab
Aug 15 at 10:57





If $R$ is a unital ring then $pin R$ is a prime element in $R$ if $p$ is not a unit and satisfies: $forall a,bin R[pmid abimplies pmid avee pmid b]$.
– drhab
Aug 15 at 10:57











2 Answers
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It must be true for every pair $a,b$ that satisfies $pmid ab$.



Observe that also $10mid4times5$ while $10$ does not divide $4$ and does not divide $5$. This shows that $10$ is not prime.






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    You're overlooking the quantifiers; the implication needs to hold for all $a$ and $b$, not merely for a single choice of $a$ and $b$.






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      2 Answers
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      2 Answers
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      up vote
      2
      down vote













      It must be true for every pair $a,b$ that satisfies $pmid ab$.



      Observe that also $10mid4times5$ while $10$ does not divide $4$ and does not divide $5$. This shows that $10$ is not prime.






      share|cite|improve this answer
























        up vote
        2
        down vote













        It must be true for every pair $a,b$ that satisfies $pmid ab$.



        Observe that also $10mid4times5$ while $10$ does not divide $4$ and does not divide $5$. This shows that $10$ is not prime.






        share|cite|improve this answer






















          up vote
          2
          down vote










          up vote
          2
          down vote









          It must be true for every pair $a,b$ that satisfies $pmid ab$.



          Observe that also $10mid4times5$ while $10$ does not divide $4$ and does not divide $5$. This shows that $10$ is not prime.






          share|cite|improve this answer












          It must be true for every pair $a,b$ that satisfies $pmid ab$.



          Observe that also $10mid4times5$ while $10$ does not divide $4$ and does not divide $5$. This shows that $10$ is not prime.







          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered Aug 15 at 10:47









          drhab

          87.5k541118




          87.5k541118




















              up vote
              2
              down vote













              You're overlooking the quantifiers; the implication needs to hold for all $a$ and $b$, not merely for a single choice of $a$ and $b$.






              share|cite|improve this answer
























                up vote
                2
                down vote













                You're overlooking the quantifiers; the implication needs to hold for all $a$ and $b$, not merely for a single choice of $a$ and $b$.






                share|cite|improve this answer






















                  up vote
                  2
                  down vote










                  up vote
                  2
                  down vote









                  You're overlooking the quantifiers; the implication needs to hold for all $a$ and $b$, not merely for a single choice of $a$ and $b$.






                  share|cite|improve this answer












                  You're overlooking the quantifiers; the implication needs to hold for all $a$ and $b$, not merely for a single choice of $a$ and $b$.







                  share|cite|improve this answer












                  share|cite|improve this answer



                  share|cite|improve this answer










                  answered Aug 15 at 10:48









                  Hurkyl

                  108k9113254




                  108k9113254






















                       

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