Understanding the definition of prime element.
Clash Royale CLAN TAG#URR8PPP
up vote
0
down vote
favorite
I have trouble understanding the definition of a prime element. The definition says that
$p$ is a prime element if $p$ divides $ab$
then either $p$ divides $a$ or $p$ divides
$b$.
but if we consider the integer 10, then it divides
$2 cdot 20$ and also divides 20,
so is 10 a prime elenent?
can you explain this?
abstract-algebra
add a comment |Â
up vote
0
down vote
favorite
I have trouble understanding the definition of a prime element. The definition says that
$p$ is a prime element if $p$ divides $ab$
then either $p$ divides $a$ or $p$ divides
$b$.
but if we consider the integer 10, then it divides
$2 cdot 20$ and also divides 20,
so is 10 a prime elenent?
can you explain this?
abstract-algebra
The prime elements of the ring $mathbb Z$ are the integers with an absolute value beging a prime number. $1$ is usually ruled out.
â Peter
Aug 15 at 10:47
But it satisfies the definition of a prime element, the definition says nothing about $p$ being a prime number.
â paradox
Aug 15 at 10:49
1
But it must satisfy the property for every elements $a,b$ in the ring.
â Peter
Aug 15 at 10:51
If $R$ is a unital ring then $pin R$ is a prime element in $R$ if $p$ is not a unit and satisfies: $forall a,bin R[pmid abimplies pmid avee pmid b]$.
â drhab
Aug 15 at 10:57
add a comment |Â
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I have trouble understanding the definition of a prime element. The definition says that
$p$ is a prime element if $p$ divides $ab$
then either $p$ divides $a$ or $p$ divides
$b$.
but if we consider the integer 10, then it divides
$2 cdot 20$ and also divides 20,
so is 10 a prime elenent?
can you explain this?
abstract-algebra
I have trouble understanding the definition of a prime element. The definition says that
$p$ is a prime element if $p$ divides $ab$
then either $p$ divides $a$ or $p$ divides
$b$.
but if we consider the integer 10, then it divides
$2 cdot 20$ and also divides 20,
so is 10 a prime elenent?
can you explain this?
abstract-algebra
edited Aug 15 at 10:46
asked Aug 15 at 10:43
paradox
92
92
The prime elements of the ring $mathbb Z$ are the integers with an absolute value beging a prime number. $1$ is usually ruled out.
â Peter
Aug 15 at 10:47
But it satisfies the definition of a prime element, the definition says nothing about $p$ being a prime number.
â paradox
Aug 15 at 10:49
1
But it must satisfy the property for every elements $a,b$ in the ring.
â Peter
Aug 15 at 10:51
If $R$ is a unital ring then $pin R$ is a prime element in $R$ if $p$ is not a unit and satisfies: $forall a,bin R[pmid abimplies pmid avee pmid b]$.
â drhab
Aug 15 at 10:57
add a comment |Â
The prime elements of the ring $mathbb Z$ are the integers with an absolute value beging a prime number. $1$ is usually ruled out.
â Peter
Aug 15 at 10:47
But it satisfies the definition of a prime element, the definition says nothing about $p$ being a prime number.
â paradox
Aug 15 at 10:49
1
But it must satisfy the property for every elements $a,b$ in the ring.
â Peter
Aug 15 at 10:51
If $R$ is a unital ring then $pin R$ is a prime element in $R$ if $p$ is not a unit and satisfies: $forall a,bin R[pmid abimplies pmid avee pmid b]$.
â drhab
Aug 15 at 10:57
The prime elements of the ring $mathbb Z$ are the integers with an absolute value beging a prime number. $1$ is usually ruled out.
â Peter
Aug 15 at 10:47
The prime elements of the ring $mathbb Z$ are the integers with an absolute value beging a prime number. $1$ is usually ruled out.
â Peter
Aug 15 at 10:47
But it satisfies the definition of a prime element, the definition says nothing about $p$ being a prime number.
â paradox
Aug 15 at 10:49
But it satisfies the definition of a prime element, the definition says nothing about $p$ being a prime number.
â paradox
Aug 15 at 10:49
1
1
But it must satisfy the property for every elements $a,b$ in the ring.
â Peter
Aug 15 at 10:51
But it must satisfy the property for every elements $a,b$ in the ring.
â Peter
Aug 15 at 10:51
If $R$ is a unital ring then $pin R$ is a prime element in $R$ if $p$ is not a unit and satisfies: $forall a,bin R[pmid abimplies pmid avee pmid b]$.
â drhab
Aug 15 at 10:57
If $R$ is a unital ring then $pin R$ is a prime element in $R$ if $p$ is not a unit and satisfies: $forall a,bin R[pmid abimplies pmid avee pmid b]$.
â drhab
Aug 15 at 10:57
add a comment |Â
2 Answers
2
active
oldest
votes
up vote
2
down vote
It must be true for every pair $a,b$ that satisfies $pmid ab$.
Observe that also $10mid4times5$ while $10$ does not divide $4$ and does not divide $5$. This shows that $10$ is not prime.
add a comment |Â
up vote
2
down vote
You're overlooking the quantifiers; the implication needs to hold for all $a$ and $b$, not merely for a single choice of $a$ and $b$.
add a comment |Â
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
2
down vote
It must be true for every pair $a,b$ that satisfies $pmid ab$.
Observe that also $10mid4times5$ while $10$ does not divide $4$ and does not divide $5$. This shows that $10$ is not prime.
add a comment |Â
up vote
2
down vote
It must be true for every pair $a,b$ that satisfies $pmid ab$.
Observe that also $10mid4times5$ while $10$ does not divide $4$ and does not divide $5$. This shows that $10$ is not prime.
add a comment |Â
up vote
2
down vote
up vote
2
down vote
It must be true for every pair $a,b$ that satisfies $pmid ab$.
Observe that also $10mid4times5$ while $10$ does not divide $4$ and does not divide $5$. This shows that $10$ is not prime.
It must be true for every pair $a,b$ that satisfies $pmid ab$.
Observe that also $10mid4times5$ while $10$ does not divide $4$ and does not divide $5$. This shows that $10$ is not prime.
answered Aug 15 at 10:47


drhab
87.5k541118
87.5k541118
add a comment |Â
add a comment |Â
up vote
2
down vote
You're overlooking the quantifiers; the implication needs to hold for all $a$ and $b$, not merely for a single choice of $a$ and $b$.
add a comment |Â
up vote
2
down vote
You're overlooking the quantifiers; the implication needs to hold for all $a$ and $b$, not merely for a single choice of $a$ and $b$.
add a comment |Â
up vote
2
down vote
up vote
2
down vote
You're overlooking the quantifiers; the implication needs to hold for all $a$ and $b$, not merely for a single choice of $a$ and $b$.
You're overlooking the quantifiers; the implication needs to hold for all $a$ and $b$, not merely for a single choice of $a$ and $b$.
answered Aug 15 at 10:48
Hurkyl
108k9113254
108k9113254
add a comment |Â
add a comment |Â
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f2883466%2funderstanding-the-definition-of-prime-element%23new-answer', 'question_page');
);
Post as a guest
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
The prime elements of the ring $mathbb Z$ are the integers with an absolute value beging a prime number. $1$ is usually ruled out.
â Peter
Aug 15 at 10:47
But it satisfies the definition of a prime element, the definition says nothing about $p$ being a prime number.
â paradox
Aug 15 at 10:49
1
But it must satisfy the property for every elements $a,b$ in the ring.
â Peter
Aug 15 at 10:51
If $R$ is a unital ring then $pin R$ is a prime element in $R$ if $p$ is not a unit and satisfies: $forall a,bin R[pmid abimplies pmid avee pmid b]$.
â drhab
Aug 15 at 10:57