Homomorphism from $mathbb R^2to mathbb C$
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Is it possible to define a surjective ring homomorphism from $mathbb R^2$ onto $mathbb C$? The multiplication defined on $mathbb R^2$ is as follows:
$(a,b)(c,d)=(ac,bd)$
abstract-algebra ring-theory complex-numbers real-numbers ring-homomorphism
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up vote
3
down vote
favorite
Is it possible to define a surjective ring homomorphism from $mathbb R^2$ onto $mathbb C$? The multiplication defined on $mathbb R^2$ is as follows:
$(a,b)(c,d)=(ac,bd)$
abstract-algebra ring-theory complex-numbers real-numbers ring-homomorphism
add a comment |Â
up vote
3
down vote
favorite
up vote
3
down vote
favorite
Is it possible to define a surjective ring homomorphism from $mathbb R^2$ onto $mathbb C$? The multiplication defined on $mathbb R^2$ is as follows:
$(a,b)(c,d)=(ac,bd)$
abstract-algebra ring-theory complex-numbers real-numbers ring-homomorphism
Is it possible to define a surjective ring homomorphism from $mathbb R^2$ onto $mathbb C$? The multiplication defined on $mathbb R^2$ is as follows:
$(a,b)(c,d)=(ac,bd)$
abstract-algebra ring-theory complex-numbers real-numbers ring-homomorphism
edited Aug 15 at 9:50
barto
13.4k32581
13.4k32581
asked Aug 15 at 9:32
Anupam
2,2021822
2,2021822
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1 Answer
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votes
up vote
10
down vote
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Hint: If $A$ and $B$ are rings (with $1$), then the ideals of $Atimes B$ are exactly the subsets in the form $Itimes J$ for some pair of ideals $Isubseteq A$ and $Jsubseteq B$. Thus...
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
10
down vote
accepted
Hint: If $A$ and $B$ are rings (with $1$), then the ideals of $Atimes B$ are exactly the subsets in the form $Itimes J$ for some pair of ideals $Isubseteq A$ and $Jsubseteq B$. Thus...
add a comment |Â
up vote
10
down vote
accepted
Hint: If $A$ and $B$ are rings (with $1$), then the ideals of $Atimes B$ are exactly the subsets in the form $Itimes J$ for some pair of ideals $Isubseteq A$ and $Jsubseteq B$. Thus...
add a comment |Â
up vote
10
down vote
accepted
up vote
10
down vote
accepted
Hint: If $A$ and $B$ are rings (with $1$), then the ideals of $Atimes B$ are exactly the subsets in the form $Itimes J$ for some pair of ideals $Isubseteq A$ and $Jsubseteq B$. Thus...
Hint: If $A$ and $B$ are rings (with $1$), then the ideals of $Atimes B$ are exactly the subsets in the form $Itimes J$ for some pair of ideals $Isubseteq A$ and $Jsubseteq B$. Thus...
edited Aug 15 at 9:45
answered Aug 15 at 9:35
Saucy O'Path
3,124323
3,124323
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