Homomorphism from $mathbb R^2to mathbb C$

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Is it possible to define a surjective ring homomorphism from $mathbb R^2$ onto $mathbb C$? The multiplication defined on $mathbb R^2$ is as follows:



$(a,b)(c,d)=(ac,bd)$







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    up vote
    3
    down vote

    favorite












    Is it possible to define a surjective ring homomorphism from $mathbb R^2$ onto $mathbb C$? The multiplication defined on $mathbb R^2$ is as follows:



    $(a,b)(c,d)=(ac,bd)$







    share|cite|improve this question
























      up vote
      3
      down vote

      favorite









      up vote
      3
      down vote

      favorite











      Is it possible to define a surjective ring homomorphism from $mathbb R^2$ onto $mathbb C$? The multiplication defined on $mathbb R^2$ is as follows:



      $(a,b)(c,d)=(ac,bd)$







      share|cite|improve this question














      Is it possible to define a surjective ring homomorphism from $mathbb R^2$ onto $mathbb C$? The multiplication defined on $mathbb R^2$ is as follows:



      $(a,b)(c,d)=(ac,bd)$









      share|cite|improve this question













      share|cite|improve this question




      share|cite|improve this question








      edited Aug 15 at 9:50









      barto

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      13.4k32581










      asked Aug 15 at 9:32









      Anupam

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      2,2021822




















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          Hint: If $A$ and $B$ are rings (with $1$), then the ideals of $Atimes B$ are exactly the subsets in the form $Itimes J$ for some pair of ideals $Isubseteq A$ and $Jsubseteq B$. Thus...






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            1 Answer
            1






            active

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            1 Answer
            1






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes








            up vote
            10
            down vote



            accepted










            Hint: If $A$ and $B$ are rings (with $1$), then the ideals of $Atimes B$ are exactly the subsets in the form $Itimes J$ for some pair of ideals $Isubseteq A$ and $Jsubseteq B$. Thus...






            share|cite|improve this answer


























              up vote
              10
              down vote



              accepted










              Hint: If $A$ and $B$ are rings (with $1$), then the ideals of $Atimes B$ are exactly the subsets in the form $Itimes J$ for some pair of ideals $Isubseteq A$ and $Jsubseteq B$. Thus...






              share|cite|improve this answer
























                up vote
                10
                down vote



                accepted







                up vote
                10
                down vote



                accepted






                Hint: If $A$ and $B$ are rings (with $1$), then the ideals of $Atimes B$ are exactly the subsets in the form $Itimes J$ for some pair of ideals $Isubseteq A$ and $Jsubseteq B$. Thus...






                share|cite|improve this answer














                Hint: If $A$ and $B$ are rings (with $1$), then the ideals of $Atimes B$ are exactly the subsets in the form $Itimes J$ for some pair of ideals $Isubseteq A$ and $Jsubseteq B$. Thus...







                share|cite|improve this answer














                share|cite|improve this answer



                share|cite|improve this answer








                edited Aug 15 at 9:45

























                answered Aug 15 at 9:35









                Saucy O'Path

                3,124323




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