Proving $frac1sqrtxge frac2x+1$ for $x> 0$ [closed]

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Prove:



$$frac1sqrtxge frac2x+1, quadforall x>0$$




Yeah, pretty much it. I've tried all manner of rearranging and just can't seem to get it. Thanks.







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closed as off-topic by Nosrati, amWhy, Adrian Keister, Lord Shark the Unknown, José Carlos Santos Aug 15 at 19:49


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Nosrati, amWhy, Adrian Keister, Lord Shark the Unknown, José Carlos Santos
If this question can be reworded to fit the rules in the help center, please edit the question.








  • 1




    Let $y=sqrt x$ and then cross multiply.
    – Mohammad Zuhair Khan
    Aug 15 at 8:24














up vote
0
down vote

favorite













Prove:



$$frac1sqrtxge frac2x+1, quadforall x>0$$




Yeah, pretty much it. I've tried all manner of rearranging and just can't seem to get it. Thanks.







share|cite|improve this question














closed as off-topic by Nosrati, amWhy, Adrian Keister, Lord Shark the Unknown, José Carlos Santos Aug 15 at 19:49


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Nosrati, amWhy, Adrian Keister, Lord Shark the Unknown, José Carlos Santos
If this question can be reworded to fit the rules in the help center, please edit the question.








  • 1




    Let $y=sqrt x$ and then cross multiply.
    – Mohammad Zuhair Khan
    Aug 15 at 8:24












up vote
0
down vote

favorite









up vote
0
down vote

favorite












Prove:



$$frac1sqrtxge frac2x+1, quadforall x>0$$




Yeah, pretty much it. I've tried all manner of rearranging and just can't seem to get it. Thanks.







share|cite|improve this question















Prove:



$$frac1sqrtxge frac2x+1, quadforall x>0$$




Yeah, pretty much it. I've tried all manner of rearranging and just can't seem to get it. Thanks.









share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Aug 15 at 8:30









Blue

43.8k868141




43.8k868141










asked Aug 15 at 8:22









FurryFerretMan

364




364




closed as off-topic by Nosrati, amWhy, Adrian Keister, Lord Shark the Unknown, José Carlos Santos Aug 15 at 19:49


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Nosrati, amWhy, Adrian Keister, Lord Shark the Unknown, José Carlos Santos
If this question can be reworded to fit the rules in the help center, please edit the question.




closed as off-topic by Nosrati, amWhy, Adrian Keister, Lord Shark the Unknown, José Carlos Santos Aug 15 at 19:49


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Nosrati, amWhy, Adrian Keister, Lord Shark the Unknown, José Carlos Santos
If this question can be reworded to fit the rules in the help center, please edit the question.







  • 1




    Let $y=sqrt x$ and then cross multiply.
    – Mohammad Zuhair Khan
    Aug 15 at 8:24












  • 1




    Let $y=sqrt x$ and then cross multiply.
    – Mohammad Zuhair Khan
    Aug 15 at 8:24







1




1




Let $y=sqrt x$ and then cross multiply.
– Mohammad Zuhair Khan
Aug 15 at 8:24




Let $y=sqrt x$ and then cross multiply.
– Mohammad Zuhair Khan
Aug 15 at 8:24










4 Answers
4






active

oldest

votes

















up vote
4
down vote



accepted










Hint: if $a,bgeq 0$ then you can use $$a+bgeq 2sqrtab$$



and notice that if $ane b$, then we have $>$ instead of $geq$






share|cite|improve this answer



























    up vote
    4
    down vote













    by cross multiplying, we get the following question:



    $$ x+1 geq 2sqrtx $$



    or



    $$x - 2sqrtx + 1 geq 0 $$



    Now we can say:



    $$x-2sqrtx+1 = left(sqrtx - 1right)^2 geq 0 $$



    which proves the inequality :)






    share|cite|improve this answer



























      up vote
      0
      down vote













      Substitute $y:=sqrt x>0$, multiply away the (positive!) denominators, bring all terms to the left side and recognize the left as a square.






      share|cite|improve this answer



























        up vote
        0
        down vote













        It is often a good idea to just multiply with all the denominators, and see if you can do something with the more complicated expressions. Try such trivial approaches first, and if you get stuck, you can still ask for help.






        share|cite|improve this answer



























          4 Answers
          4






          active

          oldest

          votes








          4 Answers
          4






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes








          up vote
          4
          down vote



          accepted










          Hint: if $a,bgeq 0$ then you can use $$a+bgeq 2sqrtab$$



          and notice that if $ane b$, then we have $>$ instead of $geq$






          share|cite|improve this answer
























            up vote
            4
            down vote



            accepted










            Hint: if $a,bgeq 0$ then you can use $$a+bgeq 2sqrtab$$



            and notice that if $ane b$, then we have $>$ instead of $geq$






            share|cite|improve this answer






















              up vote
              4
              down vote



              accepted







              up vote
              4
              down vote



              accepted






              Hint: if $a,bgeq 0$ then you can use $$a+bgeq 2sqrtab$$



              and notice that if $ane b$, then we have $>$ instead of $geq$






              share|cite|improve this answer












              Hint: if $a,bgeq 0$ then you can use $$a+bgeq 2sqrtab$$



              and notice that if $ane b$, then we have $>$ instead of $geq$







              share|cite|improve this answer












              share|cite|improve this answer



              share|cite|improve this answer










              answered Aug 15 at 8:26









              greedoid

              26.9k93575




              26.9k93575




















                  up vote
                  4
                  down vote













                  by cross multiplying, we get the following question:



                  $$ x+1 geq 2sqrtx $$



                  or



                  $$x - 2sqrtx + 1 geq 0 $$



                  Now we can say:



                  $$x-2sqrtx+1 = left(sqrtx - 1right)^2 geq 0 $$



                  which proves the inequality :)






                  share|cite|improve this answer
























                    up vote
                    4
                    down vote













                    by cross multiplying, we get the following question:



                    $$ x+1 geq 2sqrtx $$



                    or



                    $$x - 2sqrtx + 1 geq 0 $$



                    Now we can say:



                    $$x-2sqrtx+1 = left(sqrtx - 1right)^2 geq 0 $$



                    which proves the inequality :)






                    share|cite|improve this answer






















                      up vote
                      4
                      down vote










                      up vote
                      4
                      down vote









                      by cross multiplying, we get the following question:



                      $$ x+1 geq 2sqrtx $$



                      or



                      $$x - 2sqrtx + 1 geq 0 $$



                      Now we can say:



                      $$x-2sqrtx+1 = left(sqrtx - 1right)^2 geq 0 $$



                      which proves the inequality :)






                      share|cite|improve this answer












                      by cross multiplying, we get the following question:



                      $$ x+1 geq 2sqrtx $$



                      or



                      $$x - 2sqrtx + 1 geq 0 $$



                      Now we can say:



                      $$x-2sqrtx+1 = left(sqrtx - 1right)^2 geq 0 $$



                      which proves the inequality :)







                      share|cite|improve this answer












                      share|cite|improve this answer



                      share|cite|improve this answer










                      answered Aug 15 at 8:34









                      Alla Tarighati

                      2023




                      2023




















                          up vote
                          0
                          down vote













                          Substitute $y:=sqrt x>0$, multiply away the (positive!) denominators, bring all terms to the left side and recognize the left as a square.






                          share|cite|improve this answer
























                            up vote
                            0
                            down vote













                            Substitute $y:=sqrt x>0$, multiply away the (positive!) denominators, bring all terms to the left side and recognize the left as a square.






                            share|cite|improve this answer






















                              up vote
                              0
                              down vote










                              up vote
                              0
                              down vote









                              Substitute $y:=sqrt x>0$, multiply away the (positive!) denominators, bring all terms to the left side and recognize the left as a square.






                              share|cite|improve this answer












                              Substitute $y:=sqrt x>0$, multiply away the (positive!) denominators, bring all terms to the left side and recognize the left as a square.







                              share|cite|improve this answer












                              share|cite|improve this answer



                              share|cite|improve this answer










                              answered Aug 15 at 8:27









                              Hagen von Eitzen

                              265k21258477




                              265k21258477




















                                  up vote
                                  0
                                  down vote













                                  It is often a good idea to just multiply with all the denominators, and see if you can do something with the more complicated expressions. Try such trivial approaches first, and if you get stuck, you can still ask for help.






                                  share|cite|improve this answer
























                                    up vote
                                    0
                                    down vote













                                    It is often a good idea to just multiply with all the denominators, and see if you can do something with the more complicated expressions. Try such trivial approaches first, and if you get stuck, you can still ask for help.






                                    share|cite|improve this answer






















                                      up vote
                                      0
                                      down vote










                                      up vote
                                      0
                                      down vote









                                      It is often a good idea to just multiply with all the denominators, and see if you can do something with the more complicated expressions. Try such trivial approaches first, and if you get stuck, you can still ask for help.






                                      share|cite|improve this answer












                                      It is often a good idea to just multiply with all the denominators, and see if you can do something with the more complicated expressions. Try such trivial approaches first, and if you get stuck, you can still ask for help.







                                      share|cite|improve this answer












                                      share|cite|improve this answer



                                      share|cite|improve this answer










                                      answered Aug 15 at 8:30









                                      A. Pongrácz

                                      3,797625




                                      3,797625












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