Proving $frac1sqrtxge frac2x+1$ for $x> 0$ [closed]
Clash Royale CLAN TAG#URR8PPP
up vote
0
down vote
favorite
Prove:
$$frac1sqrtxge frac2x+1, quadforall x>0$$
Yeah, pretty much it. I've tried all manner of rearranging and just can't seem to get it. Thanks.
algebra-precalculus inequality
closed as off-topic by Nosrati, amWhy, Adrian Keister, Lord Shark the Unknown, José Carlos Santos Aug 15 at 19:49
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." â Nosrati, amWhy, Adrian Keister, Lord Shark the Unknown, José Carlos Santos
add a comment |Â
up vote
0
down vote
favorite
Prove:
$$frac1sqrtxge frac2x+1, quadforall x>0$$
Yeah, pretty much it. I've tried all manner of rearranging and just can't seem to get it. Thanks.
algebra-precalculus inequality
closed as off-topic by Nosrati, amWhy, Adrian Keister, Lord Shark the Unknown, José Carlos Santos Aug 15 at 19:49
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." â Nosrati, amWhy, Adrian Keister, Lord Shark the Unknown, José Carlos Santos
1
Let $y=sqrt x$ and then cross multiply.
â Mohammad Zuhair Khan
Aug 15 at 8:24
add a comment |Â
up vote
0
down vote
favorite
up vote
0
down vote
favorite
Prove:
$$frac1sqrtxge frac2x+1, quadforall x>0$$
Yeah, pretty much it. I've tried all manner of rearranging and just can't seem to get it. Thanks.
algebra-precalculus inequality
Prove:
$$frac1sqrtxge frac2x+1, quadforall x>0$$
Yeah, pretty much it. I've tried all manner of rearranging and just can't seem to get it. Thanks.
algebra-precalculus inequality
edited Aug 15 at 8:30


Blue
43.8k868141
43.8k868141
asked Aug 15 at 8:22
FurryFerretMan
364
364
closed as off-topic by Nosrati, amWhy, Adrian Keister, Lord Shark the Unknown, José Carlos Santos Aug 15 at 19:49
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." â Nosrati, amWhy, Adrian Keister, Lord Shark the Unknown, José Carlos Santos
closed as off-topic by Nosrati, amWhy, Adrian Keister, Lord Shark the Unknown, José Carlos Santos Aug 15 at 19:49
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." â Nosrati, amWhy, Adrian Keister, Lord Shark the Unknown, José Carlos Santos
1
Let $y=sqrt x$ and then cross multiply.
â Mohammad Zuhair Khan
Aug 15 at 8:24
add a comment |Â
1
Let $y=sqrt x$ and then cross multiply.
â Mohammad Zuhair Khan
Aug 15 at 8:24
1
1
Let $y=sqrt x$ and then cross multiply.
â Mohammad Zuhair Khan
Aug 15 at 8:24
Let $y=sqrt x$ and then cross multiply.
â Mohammad Zuhair Khan
Aug 15 at 8:24
add a comment |Â
4 Answers
4
active
oldest
votes
up vote
4
down vote
accepted
Hint: if $a,bgeq 0$ then you can use $$a+bgeq 2sqrtab$$
and notice that if $ane b$, then we have $>$ instead of $geq$
add a comment |Â
up vote
4
down vote
by cross multiplying, we get the following question:
$$ x+1 geq 2sqrtx $$
or
$$x - 2sqrtx + 1 geq 0 $$
Now we can say:
$$x-2sqrtx+1 = left(sqrtx - 1right)^2 geq 0 $$
which proves the inequality :)
add a comment |Â
up vote
0
down vote
Substitute $y:=sqrt x>0$, multiply away the (positive!) denominators, bring all terms to the left side and recognize the left as a square.
add a comment |Â
up vote
0
down vote
It is often a good idea to just multiply with all the denominators, and see if you can do something with the more complicated expressions. Try such trivial approaches first, and if you get stuck, you can still ask for help.
add a comment |Â
4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
4
down vote
accepted
Hint: if $a,bgeq 0$ then you can use $$a+bgeq 2sqrtab$$
and notice that if $ane b$, then we have $>$ instead of $geq$
add a comment |Â
up vote
4
down vote
accepted
Hint: if $a,bgeq 0$ then you can use $$a+bgeq 2sqrtab$$
and notice that if $ane b$, then we have $>$ instead of $geq$
add a comment |Â
up vote
4
down vote
accepted
up vote
4
down vote
accepted
Hint: if $a,bgeq 0$ then you can use $$a+bgeq 2sqrtab$$
and notice that if $ane b$, then we have $>$ instead of $geq$
Hint: if $a,bgeq 0$ then you can use $$a+bgeq 2sqrtab$$
and notice that if $ane b$, then we have $>$ instead of $geq$
answered Aug 15 at 8:26


greedoid
26.9k93575
26.9k93575
add a comment |Â
add a comment |Â
up vote
4
down vote
by cross multiplying, we get the following question:
$$ x+1 geq 2sqrtx $$
or
$$x - 2sqrtx + 1 geq 0 $$
Now we can say:
$$x-2sqrtx+1 = left(sqrtx - 1right)^2 geq 0 $$
which proves the inequality :)
add a comment |Â
up vote
4
down vote
by cross multiplying, we get the following question:
$$ x+1 geq 2sqrtx $$
or
$$x - 2sqrtx + 1 geq 0 $$
Now we can say:
$$x-2sqrtx+1 = left(sqrtx - 1right)^2 geq 0 $$
which proves the inequality :)
add a comment |Â
up vote
4
down vote
up vote
4
down vote
by cross multiplying, we get the following question:
$$ x+1 geq 2sqrtx $$
or
$$x - 2sqrtx + 1 geq 0 $$
Now we can say:
$$x-2sqrtx+1 = left(sqrtx - 1right)^2 geq 0 $$
which proves the inequality :)
by cross multiplying, we get the following question:
$$ x+1 geq 2sqrtx $$
or
$$x - 2sqrtx + 1 geq 0 $$
Now we can say:
$$x-2sqrtx+1 = left(sqrtx - 1right)^2 geq 0 $$
which proves the inequality :)
answered Aug 15 at 8:34
Alla Tarighati
2023
2023
add a comment |Â
add a comment |Â
up vote
0
down vote
Substitute $y:=sqrt x>0$, multiply away the (positive!) denominators, bring all terms to the left side and recognize the left as a square.
add a comment |Â
up vote
0
down vote
Substitute $y:=sqrt x>0$, multiply away the (positive!) denominators, bring all terms to the left side and recognize the left as a square.
add a comment |Â
up vote
0
down vote
up vote
0
down vote
Substitute $y:=sqrt x>0$, multiply away the (positive!) denominators, bring all terms to the left side and recognize the left as a square.
Substitute $y:=sqrt x>0$, multiply away the (positive!) denominators, bring all terms to the left side and recognize the left as a square.
answered Aug 15 at 8:27


Hagen von Eitzen
265k21258477
265k21258477
add a comment |Â
add a comment |Â
up vote
0
down vote
It is often a good idea to just multiply with all the denominators, and see if you can do something with the more complicated expressions. Try such trivial approaches first, and if you get stuck, you can still ask for help.
add a comment |Â
up vote
0
down vote
It is often a good idea to just multiply with all the denominators, and see if you can do something with the more complicated expressions. Try such trivial approaches first, and if you get stuck, you can still ask for help.
add a comment |Â
up vote
0
down vote
up vote
0
down vote
It is often a good idea to just multiply with all the denominators, and see if you can do something with the more complicated expressions. Try such trivial approaches first, and if you get stuck, you can still ask for help.
It is often a good idea to just multiply with all the denominators, and see if you can do something with the more complicated expressions. Try such trivial approaches first, and if you get stuck, you can still ask for help.
answered Aug 15 at 8:30


A. Pongrácz
3,797625
3,797625
add a comment |Â
add a comment |Â
1
Let $y=sqrt x$ and then cross multiply.
â Mohammad Zuhair Khan
Aug 15 at 8:24