Why do inverse function and chain rule not produce the same derivative?
Clash Royale CLAN TAG #URR8PPP up vote 0 down vote favorite I understand $'ln(x) = frac1'e^ln(x) =frac1x $ But if I use the chain rule in the denominator to calculate the derivative $'e^ln(x) => ('e^ln(x))('ln(x))=(x)(frac1x)=1$ But then $frac1xneqfrac11$ What am I doing wrong? calculus derivatives share | cite | improve this question asked Sep 4 at 12:36 jhuk 135 8 What is the inverse function of $ln x?$ â gammatester Sep 4 at 12:41 I think your notation might be causing you some confusion. If you write out the statements abstractly with a general function $f$, then carefully substitute your specific function, you should find what you're looking for. This is a good strategy in general. â Prototank Sep 4 at 12:54 add a comment  | up vote 0 down vote favorite I understand $'ln(x) = frac1'e^ln(x) =frac1x $ But if I use ...