Polynomial as a multiple of a polynomial with shared zeros

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I came across this presentation on the Grassmannian, Plücker coordinates and Plücker relations (https://sites.math.washington.edu/~morrow/papers/matt-masters.pdf). It states that enter image description here



where $X$ denotes the image of the Grassmannian $Gr(k,n)$ under the Plücker embedding and for some vectorspace $S_k in Gr(k,n)$ and corresponding matrix $A$, $P_L$ denotes the determinant of the submatrix of $A$ obtained by only considering the columns indexed by a set $L$ (gives a $k times k$ matrix). Moreover, the following definition is given:
enter image description here



So, I wanted to prove this Theorem, but I'm having some trouble. I know that for some $p in X$, $F_I,J(p)=0$. Then I tried to argue along the lines of showing $V(G)=V(P_I,J)$ by showing both inclusions, but having this result does not necessarily mean that $G$ is a multiple of $F_I,J$.



So, I have no idea how to show this. I'm sure this has to hold even for a more general setting (i.e. not necessarily Plücker coordinates etc.). Thank you for any suggestions.










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    down vote

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    I came across this presentation on the Grassmannian, Plücker coordinates and Plücker relations (https://sites.math.washington.edu/~morrow/papers/matt-masters.pdf). It states that enter image description here



    where $X$ denotes the image of the Grassmannian $Gr(k,n)$ under the Plücker embedding and for some vectorspace $S_k in Gr(k,n)$ and corresponding matrix $A$, $P_L$ denotes the determinant of the submatrix of $A$ obtained by only considering the columns indexed by a set $L$ (gives a $k times k$ matrix). Moreover, the following definition is given:
    enter image description here



    So, I wanted to prove this Theorem, but I'm having some trouble. I know that for some $p in X$, $F_I,J(p)=0$. Then I tried to argue along the lines of showing $V(G)=V(P_I,J)$ by showing both inclusions, but having this result does not necessarily mean that $G$ is a multiple of $F_I,J$.



    So, I have no idea how to show this. I'm sure this has to hold even for a more general setting (i.e. not necessarily Plücker coordinates etc.). Thank you for any suggestions.










    share|cite|improve this question























      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      I came across this presentation on the Grassmannian, Plücker coordinates and Plücker relations (https://sites.math.washington.edu/~morrow/papers/matt-masters.pdf). It states that enter image description here



      where $X$ denotes the image of the Grassmannian $Gr(k,n)$ under the Plücker embedding and for some vectorspace $S_k in Gr(k,n)$ and corresponding matrix $A$, $P_L$ denotes the determinant of the submatrix of $A$ obtained by only considering the columns indexed by a set $L$ (gives a $k times k$ matrix). Moreover, the following definition is given:
      enter image description here



      So, I wanted to prove this Theorem, but I'm having some trouble. I know that for some $p in X$, $F_I,J(p)=0$. Then I tried to argue along the lines of showing $V(G)=V(P_I,J)$ by showing both inclusions, but having this result does not necessarily mean that $G$ is a multiple of $F_I,J$.



      So, I have no idea how to show this. I'm sure this has to hold even for a more general setting (i.e. not necessarily Plücker coordinates etc.). Thank you for any suggestions.










      share|cite|improve this question













      I came across this presentation on the Grassmannian, Plücker coordinates and Plücker relations (https://sites.math.washington.edu/~morrow/papers/matt-masters.pdf). It states that enter image description here



      where $X$ denotes the image of the Grassmannian $Gr(k,n)$ under the Plücker embedding and for some vectorspace $S_k in Gr(k,n)$ and corresponding matrix $A$, $P_L$ denotes the determinant of the submatrix of $A$ obtained by only considering the columns indexed by a set $L$ (gives a $k times k$ matrix). Moreover, the following definition is given:
      enter image description here



      So, I wanted to prove this Theorem, but I'm having some trouble. I know that for some $p in X$, $F_I,J(p)=0$. Then I tried to argue along the lines of showing $V(G)=V(P_I,J)$ by showing both inclusions, but having this result does not necessarily mean that $G$ is a multiple of $F_I,J$.



      So, I have no idea how to show this. I'm sure this has to hold even for a more general setting (i.e. not necessarily Plücker coordinates etc.). Thank you for any suggestions.







      algebraic-geometry polynomials grassmannian






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      asked Sep 4 at 9:40









      SallyOwens

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