For the negation of statement
Clash Royale CLAN TAG #URR8PPP up vote 0 down vote favorite âÂÂy â Z such that âÂÂx â Z, R(x + y) âÂÂx â Z, âÂÂy â Z such that R(x + y) Base on this two rule "For all x, A(x)" negation:"There exist x such that not A(x)" "There exists x such that A(x)" negation:"For every x, not A(x)" what I did is "âÂÂy â Z, not âÂÂx â Z, R(x + y)" "âÂÂx â Z, âÂÂy â Z such that R(x + y) " I wish anyone could help me to check whether this is right or not. Thank you! discrete-mathematics share | cite | improve this question asked Aug 19 at 11:55 TomSophicy 22 1 add a comment  | up vote 0 down vote favorite âÂÂy â Z such that âÂÂx â Z, R(x + y) âÂÂx â Z, âÂÂy â Z such that R(x + y) Base on this two rule "For all x, A(x)" negation:"There exist x such that not A(x)" "T