How can I put `vdots` at centre of each column in this alignat?
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I am trying to put vdots at centre of each column in alignat, but I can't. This is my code.
documentclass[12pt,a4paper]article
usepackageamsmath
usepackagefourier
usepackage[left=2cm,right=2cm,top=2cm,bottom=2cm]geometry
usepackagemathtools
DeclarePairedDelimiterabslvertrvert
begindocument
beginalignat*3
& absa_2 - a_3 && leqslant dfrac1 2|a_1 - a_2|\
& absa_3 - a_4 && leqslant dfrac1 2absa_2 - a_3 && leqslant dfrac1 2^2|a_1 - a_2|\
& absa_4 - a_5 && leqslant dfrac1 2absa_3 - a_4 && leqslant dfrac1 2^3|a_1 - a_2|\
& vdots && <vdots && < vdots \
&abs*a_n -a_n+1 && leqslant dfrac1 2absa_n-1 - a_n && leqslant dfrac1 2^n-1|a_1 - a_2|
endalignat*
enddocument
How can I put vdots at centre of each column in this alignat?
alignat
edited Sep 4 at 8:51
current_user
2,5741428
asked Sep 4 at 8:41
minhthien_2016
1,066812
add a comment |Â
up vote
3
down vote
favorite
I am trying to put vdots at centre of each column in alignat, but I can't. This is my code.
documentclass[12pt,a4paper]article
usepackageamsmath
usepackagefourier
usepackage[left=2cm,right=2cm,top=2cm,bottom=2cm]geometry
usepackagemathtools
DeclarePairedDelimiterabslvertrvert
begindocument
beginalignat*3
& absa_2 - a_3 && leqslant dfrac1 2|a_1 - a_2|\
& absa_3 - a_4 && leqslant dfrac1 2absa_2 - a_3 && leqslant dfrac1 2^2|a_1 - a_2|\
& absa_4 - a_5 && leqslant dfrac1 2absa_3 - a_4 && leqslant dfrac1 2^3|a_1 - a_2|\
& vdots && <vdots && < vdots \
&abs*a_n -a_n+1 && leqslant dfrac1 2absa_n-1 - a_n && leqslant dfrac1 2^n-1|a_1 - a_2|
endalignat*
enddocument
How can I put vdots at centre of each column in this alignat?
alignat
edited Sep 4 at 8:51
current_user
2,5741428
asked Sep 4 at 8:41
minhthien_2016
1,066812
add a comment |Â
up vote
3
down vote
favorite
up vote
3
down vote
favorite
I am trying to put vdots at centre of each column in alignat, but I can't. This is my code.
documentclass[12pt,a4paper]article
usepackageamsmath
usepackagefourier
usepackage[left=2cm,right=2cm,top=2cm,bottom=2cm]geometry
usepackagemathtools
DeclarePairedDelimiterabslvertrvert
begindocument
beginalignat*3
& absa_2 - a_3 && leqslant dfrac1 2|a_1 - a_2|\
& absa_3 - a_4 && leqslant dfrac1 2absa_2 - a_3 && leqslant dfrac1 2^2|a_1 - a_2|\
& absa_4 - a_5 && leqslant dfrac1 2absa_3 - a_4 && leqslant dfrac1 2^3|a_1 - a_2|\
& vdots && <vdots && < vdots \
&abs*a_n -a_n+1 && leqslant dfrac1 2absa_n-1 - a_n && leqslant dfrac1 2^n-1|a_1 - a_2|
endalignat*
enddocument
How can I put vdots at centre of each column in this alignat?
alignat
edited Sep 4 at 8:51
current_user
2,5741428
asked Sep 4 at 8:41
minhthien_2016
1,066812
I am trying to put vdots at centre of each column in alignat, but I can't. This is my code.
documentclass[12pt,a4paper]article
usepackageamsmath
usepackagefourier
usepackage[left=2cm,right=2cm,top=2cm,bottom=2cm]geometry
usepackagemathtools
DeclarePairedDelimiterabslvertrvert
begindocument
beginalignat*3
& absa_2 - a_3 && leqslant dfrac1 2|a_1 - a_2|\
& absa_3 - a_4 && leqslant dfrac1 2absa_2 - a_3 && leqslant dfrac1 2^2|a_1 - a_2|\
& absa_4 - a_5 && leqslant dfrac1 2absa_3 - a_4 && leqslant dfrac1 2^3|a_1 - a_2|\
& vdots && <vdots && < vdots \
&abs*a_n -a_n+1 && leqslant dfrac1 2absa_n-1 - a_n && leqslant dfrac1 2^n-1|a_1 - a_2|
endalignat*
enddocument
How can I put vdots at centre of each column in this alignat?
alignat
alignat
edited Sep 4 at 8:51
current_user
2,5741428
asked Sep 4 at 8:41
minhthien_2016
1,066812
edited Sep 4 at 8:51
current_user
2,5741428
asked Sep 4 at 8:41
minhthien_2016
1,066812
edited Sep 4 at 8:51
current_user
2,5741428
edited Sep 4 at 8:51
current_user
2,5741428
edited Sep 4 at 8:51
current_user
2,5741428
2,5741428
asked Sep 4 at 8:41
minhthien_2016
1,066812
asked Sep 4 at 8:41
minhthien_2016
1,066812
asked Sep 4 at 8:41
minhthien_2016
1,066812
1,066812
add a comment |Â
add a comment |Â
2 Answers
2
active
oldest
votes
up vote
3
down vote
accepted
I'd place the vertical dots below the inequality signs, so here's the code for both methods.
documentclass[12pt,a4paper]article
usepackageamsmath
usepackagemathtools
usepackagefourier
usepackage[left=2cm,right=2cm,top=2cm,bottom=2cm]geometry
usepackagecalc
DeclarePairedDelimiterabslvertrvert
newcommandcto[2]%
mathmakebox[widthof$displaystyle#1$]#2%
begindocument
beginalignat*3
& absa_2 - a_3
&& leqslant frac12|a_1 - a_2|
\
& absa_3 - a_4
&& leqslant frac12absa_2 - a_3
&& leqslant frac12^2|a_1 - a_2|
\
& absa_4 - a_5
&& leqslant frac12absa_3 - a_4
&& leqslant frac12^3|a_1 - a_2|
\
& ctoabsa_2 - a_3vdots
&& leqslant ctofrac12absa_3 - a_4vdots
&& leqslant ctovdots
\
& abs*a_n -a_n+1
&& leqslant frac12absa_n-1 - a_n
&& leqslant frac12^n-1|a_1 - a_2|
endalignat*
beginalignat*3
& absa_2 - a_3
&& leqslant frac12|a_1 - a_2|
\
& absa_3 - a_4
&& leqslant frac12absa_2 - a_3
&& leqslant frac12^2|a_1 - a_2|
\
& absa_4 - a_5
&& leqslant frac12absa_3 - a_4
&& leqslant frac12^3|a_1 - a_2|
\
&&& ctoleqslantvdots
&& ctoleqslantvdots
\
& abs*a_n -a_n+1
&& leqslant frac12absa_n-1 - a_n
&& leqslant frac12^n-1|a_1 - a_2|
endalignat*
enddocument
answered Sep 4 at 9:01
egreg
682k8418183064
Isn’t there a commandvdotswithinleqslantfrommathtoolsalready that does the exact same thing?
– Ruixi Zhang
Sep 4 at 12:07
@RuixiZhang Yes, but it allows just one vdots per row
– egreg
Sep 4 at 12:29
I don’t think I could follow: Page 23 of themathtoolsdocumentation demonstrates an equation with&vdotswithin+ &&&& vdotswithin+. So I think one can use more than one vdots per row. But if you are referring to the use ofcto<arg>vdotsvdots, then I’d agree. But this usage is not present in this example.
– Ruixi Zhang
Sep 4 at 13:18
add a comment |Â
up vote
3
down vote
Here is solution with eqparbox. I took the liberty so simplify a bit your preamble (needless to load amsmath when you load mathtools). Also, I thought the medium-sized fractions from nccmath look nicer for numerical coefficients:
documentclass[12pt, a4paper]article
usepackagefourier
usepackage[margin=2cm]geometry
usepackagemathtools, nccmath
DeclarePairedDelimiterabslvertrvert
usepackageeqparbox
newcommandeqmathbox[2][M]eqmakebox[#1]$displaystyle#2$
newcommandlongvdotsraisebox0.6ex[0pt][0pt]rotatebox[origin=c]90makebox[1cm]dotfill
begindocument
beginalignat*3
& absa_2 - a_3 && leqslant mfrac1 2absa_1 - a_2 \
& absa_3 - a_4 && leqslant mfrac1 2absa_2 - a_3 && leqslant mfrac1 2^2absa_1 - a_2\
&eqmathboxabsa_4 - a_5 && leqslant mfrac1 2eqmathbox[M1]absa_3 - a_4 && leqslant mfrac1 2^3 eqmathbox[M2]absa_1 - a_2 \
& eqmathboxlongvdots && leqslantphantommfrac1 2eqmathbox[M1]longvdots && leqslantphantommfrac1 2^3 eqmathbox[M2]longvdots\
&abs*a_n -a_n+1 && leqslant mfrac1 2absa_n-1 - a_n && leqslant mfrac1 2^n-1absa_1 - a_2
endalignat*
enddocument
answered Sep 4 at 9:43
Bernard
156k763189
add a comment |Â
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
3
down vote
accepted
I'd place the vertical dots below the inequality signs, so here's the code for both methods.
documentclass[12pt,a4paper]article
usepackageamsmath
usepackagemathtools
usepackagefourier
usepackage[left=2cm,right=2cm,top=2cm,bottom=2cm]geometry
usepackagecalc
DeclarePairedDelimiterabslvertrvert
newcommandcto[2]%
mathmakebox[widthof$displaystyle#1$]#2%
begindocument
beginalignat*3
& absa_2 - a_3
&& leqslant frac12|a_1 - a_2|
\
& absa_3 - a_4
&& leqslant frac12absa_2 - a_3
&& leqslant frac12^2|a_1 - a_2|
\
& absa_4 - a_5
&& leqslant frac12absa_3 - a_4
&& leqslant frac12^3|a_1 - a_2|
\
& ctoabsa_2 - a_3vdots
&& leqslant ctofrac12absa_3 - a_4vdots
&& leqslant ctovdots
\
& abs*a_n -a_n+1
&& leqslant frac12absa_n-1 - a_n
&& leqslant frac12^n-1|a_1 - a_2|
endalignat*
beginalignat*3
& absa_2 - a_3
&& leqslant frac12|a_1 - a_2|
\
& absa_3 - a_4
&& leqslant frac12absa_2 - a_3
&& leqslant frac12^2|a_1 - a_2|
\
& absa_4 - a_5
&& leqslant frac12absa_3 - a_4
&& leqslant frac12^3|a_1 - a_2|
\
&&& ctoleqslantvdots
&& ctoleqslantvdots
\
& abs*a_n -a_n+1
&& leqslant frac12absa_n-1 - a_n
&& leqslant frac12^n-1|a_1 - a_2|
endalignat*
enddocument
answered Sep 4 at 9:01
egreg
682k8418183064
Isn’t there a commandvdotswithinleqslantfrommathtoolsalready that does the exact same thing?
– Ruixi Zhang
Sep 4 at 12:07
@RuixiZhang Yes, but it allows just one vdots per row
– egreg
Sep 4 at 12:29
I don’t think I could follow: Page 23 of themathtoolsdocumentation demonstrates an equation with&vdotswithin+ &&&& vdotswithin+. So I think one can use more than one vdots per row. But if you are referring to the use ofcto<arg>vdotsvdots, then I’d agree. But this usage is not present in this example.
– Ruixi Zhang
Sep 4 at 13:18
add a comment |Â
up vote
3
down vote
accepted
I'd place the vertical dots below the inequality signs, so here's the code for both methods.
documentclass[12pt,a4paper]article
usepackageamsmath
usepackagemathtools
usepackagefourier
usepackage[left=2cm,right=2cm,top=2cm,bottom=2cm]geometry
usepackagecalc
DeclarePairedDelimiterabslvertrvert
newcommandcto[2]%
mathmakebox[widthof$displaystyle#1$]#2%
begindocument
beginalignat*3
& absa_2 - a_3
&& leqslant frac12|a_1 - a_2|
\
& absa_3 - a_4
&& leqslant frac12absa_2 - a_3
&& leqslant frac12^2|a_1 - a_2|
\
& absa_4 - a_5
&& leqslant frac12absa_3 - a_4
&& leqslant frac12^3|a_1 - a_2|
\
& ctoabsa_2 - a_3vdots
&& leqslant ctofrac12absa_3 - a_4vdots
&& leqslant ctovdots
\
& abs*a_n -a_n+1
&& leqslant frac12absa_n-1 - a_n
&& leqslant frac12^n-1|a_1 - a_2|
endalignat*
beginalignat*3
& absa_2 - a_3
&& leqslant frac12|a_1 - a_2|
\
& absa_3 - a_4
&& leqslant frac12absa_2 - a_3
&& leqslant frac12^2|a_1 - a_2|
\
& absa_4 - a_5
&& leqslant frac12absa_3 - a_4
&& leqslant frac12^3|a_1 - a_2|
\
&&& ctoleqslantvdots
&& ctoleqslantvdots
\
& abs*a_n -a_n+1
&& leqslant frac12absa_n-1 - a_n
&& leqslant frac12^n-1|a_1 - a_2|
endalignat*
enddocument
answered Sep 4 at 9:01
egreg
682k8418183064
Isn’t there a commandvdotswithinleqslantfrommathtoolsalready that does the exact same thing?
– Ruixi Zhang
Sep 4 at 12:07
@RuixiZhang Yes, but it allows just one vdots per row
– egreg
Sep 4 at 12:29
I don’t think I could follow: Page 23 of themathtoolsdocumentation demonstrates an equation with&vdotswithin+ &&&& vdotswithin+. So I think one can use more than one vdots per row. But if you are referring to the use ofcto<arg>vdotsvdots, then I’d agree. But this usage is not present in this example.
– Ruixi Zhang
Sep 4 at 13:18
add a comment |Â
up vote
3
down vote
accepted
up vote
3
down vote
accepted
I'd place the vertical dots below the inequality signs, so here's the code for both methods.
documentclass[12pt,a4paper]article
usepackageamsmath
usepackagemathtools
usepackagefourier
usepackage[left=2cm,right=2cm,top=2cm,bottom=2cm]geometry
usepackagecalc
DeclarePairedDelimiterabslvertrvert
newcommandcto[2]%
mathmakebox[widthof$displaystyle#1$]#2%
begindocument
beginalignat*3
& absa_2 - a_3
&& leqslant frac12|a_1 - a_2|
\
& absa_3 - a_4
&& leqslant frac12absa_2 - a_3
&& leqslant frac12^2|a_1 - a_2|
\
& absa_4 - a_5
&& leqslant frac12absa_3 - a_4
&& leqslant frac12^3|a_1 - a_2|
\
& ctoabsa_2 - a_3vdots
&& leqslant ctofrac12absa_3 - a_4vdots
&& leqslant ctovdots
\
& abs*a_n -a_n+1
&& leqslant frac12absa_n-1 - a_n
&& leqslant frac12^n-1|a_1 - a_2|
endalignat*
beginalignat*3
& absa_2 - a_3
&& leqslant frac12|a_1 - a_2|
\
& absa_3 - a_4
&& leqslant frac12absa_2 - a_3
&& leqslant frac12^2|a_1 - a_2|
\
& absa_4 - a_5
&& leqslant frac12absa_3 - a_4
&& leqslant frac12^3|a_1 - a_2|
\
&&& ctoleqslantvdots
&& ctoleqslantvdots
\
& abs*a_n -a_n+1
&& leqslant frac12absa_n-1 - a_n
&& leqslant frac12^n-1|a_1 - a_2|
endalignat*
enddocument
answered Sep 4 at 9:01
egreg
682k8418183064
I'd place the vertical dots below the inequality signs, so here's the code for both methods.
documentclass[12pt,a4paper]article
usepackageamsmath
usepackagemathtools
usepackagefourier
usepackage[left=2cm,right=2cm,top=2cm,bottom=2cm]geometry
usepackagecalc
DeclarePairedDelimiterabslvertrvert
newcommandcto[2]%
mathmakebox[widthof$displaystyle#1$]#2%
begindocument
beginalignat*3
& absa_2 - a_3
&& leqslant frac12|a_1 - a_2|
\
& absa_3 - a_4
&& leqslant frac12absa_2 - a_3
&& leqslant frac12^2|a_1 - a_2|
\
& absa_4 - a_5
&& leqslant frac12absa_3 - a_4
&& leqslant frac12^3|a_1 - a_2|
\
& ctoabsa_2 - a_3vdots
&& leqslant ctofrac12absa_3 - a_4vdots
&& leqslant ctovdots
\
& abs*a_n -a_n+1
&& leqslant frac12absa_n-1 - a_n
&& leqslant frac12^n-1|a_1 - a_2|
endalignat*
beginalignat*3
& absa_2 - a_3
&& leqslant frac12|a_1 - a_2|
\
& absa_3 - a_4
&& leqslant frac12absa_2 - a_3
&& leqslant frac12^2|a_1 - a_2|
\
& absa_4 - a_5
&& leqslant frac12absa_3 - a_4
&& leqslant frac12^3|a_1 - a_2|
\
&&& ctoleqslantvdots
&& ctoleqslantvdots
\
& abs*a_n -a_n+1
&& leqslant frac12absa_n-1 - a_n
&& leqslant frac12^n-1|a_1 - a_2|
endalignat*
enddocument
answered Sep 4 at 9:01
egreg
682k8418183064
answered Sep 4 at 9:01
egreg
682k8418183064
answered Sep 4 at 9:01
egreg
682k8418183064
answered Sep 4 at 9:01
egreg
682k8418183064
682k8418183064
Isn’t there a commandvdotswithinleqslantfrommathtoolsalready that does the exact same thing?
– Ruixi Zhang
Sep 4 at 12:07
@RuixiZhang Yes, but it allows just one vdots per row
– egreg
Sep 4 at 12:29
I don’t think I could follow: Page 23 of themathtoolsdocumentation demonstrates an equation with&vdotswithin+ &&&& vdotswithin+. So I think one can use more than one vdots per row. But if you are referring to the use ofcto<arg>vdotsvdots, then I’d agree. But this usage is not present in this example.
– Ruixi Zhang
Sep 4 at 13:18
add a comment |Â
Isn’t there a commandvdotswithinleqslantfrommathtoolsalready that does the exact same thing?
– Ruixi Zhang
Sep 4 at 12:07
@RuixiZhang Yes, but it allows just one vdots per row
– egreg
Sep 4 at 12:29
I don’t think I could follow: Page 23 of themathtoolsdocumentation demonstrates an equation with&vdotswithin+ &&&& vdotswithin+. So I think one can use more than one vdots per row. But if you are referring to the use ofcto<arg>vdotsvdots, then I’d agree. But this usage is not present in this example.
– Ruixi Zhang
Sep 4 at 13:18
Isn’t there a command
vdotswithinleqslant from mathtools already that does the exact same thing?– Ruixi Zhang
Sep 4 at 12:07
Isn’t there a command
vdotswithinleqslant from mathtools already that does the exact same thing?– Ruixi Zhang
Sep 4 at 12:07
@RuixiZhang Yes, but it allows just one vdots per row
– egreg
Sep 4 at 12:29
@RuixiZhang Yes, but it allows just one vdots per row
– egreg
Sep 4 at 12:29
I don’t think I could follow: Page 23 of the
mathtools documentation demonstrates an equation with &vdotswithin+ &&&& vdotswithin+. So I think one can use more than one vdots per row. But if you are referring to the use of cto<arg>vdotsvdots, then I’d agree. But this usage is not present in this example.– Ruixi Zhang
Sep 4 at 13:18
I don’t think I could follow: Page 23 of the
mathtools documentation demonstrates an equation with &vdotswithin+ &&&& vdotswithin+. So I think one can use more than one vdots per row. But if you are referring to the use of cto<arg>vdotsvdots, then I’d agree. But this usage is not present in this example.– Ruixi Zhang
Sep 4 at 13:18
add a comment |Â
up vote
3
down vote
Here is solution with eqparbox. I took the liberty so simplify a bit your preamble (needless to load amsmath when you load mathtools). Also, I thought the medium-sized fractions from nccmath look nicer for numerical coefficients:
documentclass[12pt, a4paper]article
usepackagefourier
usepackage[margin=2cm]geometry
usepackagemathtools, nccmath
DeclarePairedDelimiterabslvertrvert
usepackageeqparbox
newcommandeqmathbox[2][M]eqmakebox[#1]$displaystyle#2$
newcommandlongvdotsraisebox0.6ex[0pt][0pt]rotatebox[origin=c]90makebox[1cm]dotfill
begindocument
beginalignat*3
& absa_2 - a_3 && leqslant mfrac1 2absa_1 - a_2 \
& absa_3 - a_4 && leqslant mfrac1 2absa_2 - a_3 && leqslant mfrac1 2^2absa_1 - a_2\
&eqmathboxabsa_4 - a_5 && leqslant mfrac1 2eqmathbox[M1]absa_3 - a_4 && leqslant mfrac1 2^3 eqmathbox[M2]absa_1 - a_2 \
& eqmathboxlongvdots && leqslantphantommfrac1 2eqmathbox[M1]longvdots && leqslantphantommfrac1 2^3 eqmathbox[M2]longvdots\
&abs*a_n -a_n+1 && leqslant mfrac1 2absa_n-1 - a_n && leqslant mfrac1 2^n-1absa_1 - a_2
endalignat*
enddocument
answered Sep 4 at 9:43
Bernard
156k763189
add a comment |Â
up vote
3
down vote
Here is solution with eqparbox. I took the liberty so simplify a bit your preamble (needless to load amsmath when you load mathtools). Also, I thought the medium-sized fractions from nccmath look nicer for numerical coefficients:
documentclass[12pt, a4paper]article
usepackagefourier
usepackage[margin=2cm]geometry
usepackagemathtools, nccmath
DeclarePairedDelimiterabslvertrvert
usepackageeqparbox
newcommandeqmathbox[2][M]eqmakebox[#1]$displaystyle#2$
newcommandlongvdotsraisebox0.6ex[0pt][0pt]rotatebox[origin=c]90makebox[1cm]dotfill
begindocument
beginalignat*3
& absa_2 - a_3 && leqslant mfrac1 2absa_1 - a_2 \
& absa_3 - a_4 && leqslant mfrac1 2absa_2 - a_3 && leqslant mfrac1 2^2absa_1 - a_2\
&eqmathboxabsa_4 - a_5 && leqslant mfrac1 2eqmathbox[M1]absa_3 - a_4 && leqslant mfrac1 2^3 eqmathbox[M2]absa_1 - a_2 \
& eqmathboxlongvdots && leqslantphantommfrac1 2eqmathbox[M1]longvdots && leqslantphantommfrac1 2^3 eqmathbox[M2]longvdots\
&abs*a_n -a_n+1 && leqslant mfrac1 2absa_n-1 - a_n && leqslant mfrac1 2^n-1absa_1 - a_2
endalignat*
enddocument
answered Sep 4 at 9:43
Bernard
156k763189
add a comment |Â
up vote
3
down vote
up vote
3
down vote
Here is solution with eqparbox. I took the liberty so simplify a bit your preamble (needless to load amsmath when you load mathtools). Also, I thought the medium-sized fractions from nccmath look nicer for numerical coefficients:
documentclass[12pt, a4paper]article
usepackagefourier
usepackage[margin=2cm]geometry
usepackagemathtools, nccmath
DeclarePairedDelimiterabslvertrvert
usepackageeqparbox
newcommandeqmathbox[2][M]eqmakebox[#1]$displaystyle#2$
newcommandlongvdotsraisebox0.6ex[0pt][0pt]rotatebox[origin=c]90makebox[1cm]dotfill
begindocument
beginalignat*3
& absa_2 - a_3 && leqslant mfrac1 2absa_1 - a_2 \
& absa_3 - a_4 && leqslant mfrac1 2absa_2 - a_3 && leqslant mfrac1 2^2absa_1 - a_2\
&eqmathboxabsa_4 - a_5 && leqslant mfrac1 2eqmathbox[M1]absa_3 - a_4 && leqslant mfrac1 2^3 eqmathbox[M2]absa_1 - a_2 \
& eqmathboxlongvdots && leqslantphantommfrac1 2eqmathbox[M1]longvdots && leqslantphantommfrac1 2^3 eqmathbox[M2]longvdots\
&abs*a_n -a_n+1 && leqslant mfrac1 2absa_n-1 - a_n && leqslant mfrac1 2^n-1absa_1 - a_2
endalignat*
enddocument
answered Sep 4 at 9:43
Bernard
156k763189
Here is solution with eqparbox. I took the liberty so simplify a bit your preamble (needless to load amsmath when you load mathtools). Also, I thought the medium-sized fractions from nccmath look nicer for numerical coefficients:
documentclass[12pt, a4paper]article
usepackagefourier
usepackage[margin=2cm]geometry
usepackagemathtools, nccmath
DeclarePairedDelimiterabslvertrvert
usepackageeqparbox
newcommandeqmathbox[2][M]eqmakebox[#1]$displaystyle#2$
newcommandlongvdotsraisebox0.6ex[0pt][0pt]rotatebox[origin=c]90makebox[1cm]dotfill
begindocument
beginalignat*3
& absa_2 - a_3 && leqslant mfrac1 2absa_1 - a_2 \
& absa_3 - a_4 && leqslant mfrac1 2absa_2 - a_3 && leqslant mfrac1 2^2absa_1 - a_2\
&eqmathboxabsa_4 - a_5 && leqslant mfrac1 2eqmathbox[M1]absa_3 - a_4 && leqslant mfrac1 2^3 eqmathbox[M2]absa_1 - a_2 \
& eqmathboxlongvdots && leqslantphantommfrac1 2eqmathbox[M1]longvdots && leqslantphantommfrac1 2^3 eqmathbox[M2]longvdots\
&abs*a_n -a_n+1 && leqslant mfrac1 2absa_n-1 - a_n && leqslant mfrac1 2^n-1absa_1 - a_2
endalignat*
enddocument
answered Sep 4 at 9:43
Bernard
156k763189
edited Sep 4 at 9:54
answered Sep 4 at 9:43
Bernard
156k763189
answered Sep 4 at 9:43
Bernard
156k763189
answered Sep 4 at 9:43
Bernard
156k763189
156k763189
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