If $v = v(r)$ and $r^2 = sum_i=1^n x_i^2$, then prove $sum v_x_i x_i = v_r ((n-1)/r) + v_rr$

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If $v = v(r)$ and $r^2 = sum_i=1^n x_i^2$, then prove $$sum v_x_i x_i = v_r ((n-1)/r) + v_rr$$



I start by:



$$fracpartial rpartial x_i = fracx_ir$$



$$fracpartial vpartial x_i = fracpartial vpartial r fracpartial rpartial x_i = fracpartial vpartial r fracx_ir$$



Now,
$$fracpartial^2 vpartial x^2_i = fracpartialpartial x_i left(fracpartial vpartial r fracx_irright)$$



From here, I did bifurcation into two methods:



Method 1:



$$fracpartial^2 vpartial x^2_i = fracpartialpartial x_i left(fracpartial vpartial r fracx_irright)\
= fracpartial^2 vpartial x_ipartial rfracx_ir + fracpartial vpartial rfrac1r - x_ifracpartial vpartial rfrac1r^2fracpartial rpartial x_i\
= fracpartial^2 vpartial x_ipartial rfracx_ir + fracpartial vpartial rfrac1r - fracpartial vpartial rfracx_i^2r^3$$



Apply sigma



$$sumfracpartial^2 vpartial x^2_i =fracn-1r fracpartial vpartial r + colorredsum fracpartial^2 vpartial x_ipartial rfracx_ir$$



Method 1(A):



Wrote the red term as $$fracpartialpartial rleft(fracpartial vpartial rright) fracpartial rpartial x_i fracx_ir = fracpartial^2 vpartial r^2 fracx_i^2r^2$$
which on summing gives required result!



Method 1(B):



Wrote red part as:



$$fracpartial partial rleft(fracpartial vpartial x_iright)fracpartial r partial x_i = fracpartial ^2 vpartial x_i^2$$



which is obviously not correct, but doesnt appear where error occurs.



Method 2:



Using chain rule:



$$fracpartial^2 vpartial x^2_i= fracpartialpartial x_i left(fracpartial vpartial r fracx_irright) = fracpartialpartial r left(fracpartial vpartial r fracx_irright) fracpartial rpartial x_i\
= fracx_ir left( fracx_ir fracpartial^2 vpartial r^2 + colorred frac1r fracpartial vpartial rfracpartial x_ipartial r-fracpartial vpartial rfracx_i^2r^2right)$$



On applying sigma and noting $sum x_i fracpartial x_ipartial r = r$ we get wrong answer:



$$sumfracpartial^2 vpartial x_i^2 = fracpartial ^2 vpartial r^2 + 0$$



Here what went wrong?




I am really confused here, as to when we use chain rule without encountering error. Here I know $v$ is function of $r$ which is function of all $x_i$. So it is known that $fracpartial vpartial x_i = fracpartial vpartial r fracpartial rpartial x_i$. Where do I go wrong everytime?



Thank you a lot!










share|cite|improve this question



























    up vote
    0
    down vote

    favorite












    If $v = v(r)$ and $r^2 = sum_i=1^n x_i^2$, then prove $$sum v_x_i x_i = v_r ((n-1)/r) + v_rr$$



    I start by:



    $$fracpartial rpartial x_i = fracx_ir$$



    $$fracpartial vpartial x_i = fracpartial vpartial r fracpartial rpartial x_i = fracpartial vpartial r fracx_ir$$



    Now,
    $$fracpartial^2 vpartial x^2_i = fracpartialpartial x_i left(fracpartial vpartial r fracx_irright)$$



    From here, I did bifurcation into two methods:



    Method 1:



    $$fracpartial^2 vpartial x^2_i = fracpartialpartial x_i left(fracpartial vpartial r fracx_irright)\
    = fracpartial^2 vpartial x_ipartial rfracx_ir + fracpartial vpartial rfrac1r - x_ifracpartial vpartial rfrac1r^2fracpartial rpartial x_i\
    = fracpartial^2 vpartial x_ipartial rfracx_ir + fracpartial vpartial rfrac1r - fracpartial vpartial rfracx_i^2r^3$$



    Apply sigma



    $$sumfracpartial^2 vpartial x^2_i =fracn-1r fracpartial vpartial r + colorredsum fracpartial^2 vpartial x_ipartial rfracx_ir$$



    Method 1(A):



    Wrote the red term as $$fracpartialpartial rleft(fracpartial vpartial rright) fracpartial rpartial x_i fracx_ir = fracpartial^2 vpartial r^2 fracx_i^2r^2$$
    which on summing gives required result!



    Method 1(B):



    Wrote red part as:



    $$fracpartial partial rleft(fracpartial vpartial x_iright)fracpartial r partial x_i = fracpartial ^2 vpartial x_i^2$$



    which is obviously not correct, but doesnt appear where error occurs.



    Method 2:



    Using chain rule:



    $$fracpartial^2 vpartial x^2_i= fracpartialpartial x_i left(fracpartial vpartial r fracx_irright) = fracpartialpartial r left(fracpartial vpartial r fracx_irright) fracpartial rpartial x_i\
    = fracx_ir left( fracx_ir fracpartial^2 vpartial r^2 + colorred frac1r fracpartial vpartial rfracpartial x_ipartial r-fracpartial vpartial rfracx_i^2r^2right)$$



    On applying sigma and noting $sum x_i fracpartial x_ipartial r = r$ we get wrong answer:



    $$sumfracpartial^2 vpartial x_i^2 = fracpartial ^2 vpartial r^2 + 0$$



    Here what went wrong?




    I am really confused here, as to when we use chain rule without encountering error. Here I know $v$ is function of $r$ which is function of all $x_i$. So it is known that $fracpartial vpartial x_i = fracpartial vpartial r fracpartial rpartial x_i$. Where do I go wrong everytime?



    Thank you a lot!










    share|cite|improve this question

























      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      If $v = v(r)$ and $r^2 = sum_i=1^n x_i^2$, then prove $$sum v_x_i x_i = v_r ((n-1)/r) + v_rr$$



      I start by:



      $$fracpartial rpartial x_i = fracx_ir$$



      $$fracpartial vpartial x_i = fracpartial vpartial r fracpartial rpartial x_i = fracpartial vpartial r fracx_ir$$



      Now,
      $$fracpartial^2 vpartial x^2_i = fracpartialpartial x_i left(fracpartial vpartial r fracx_irright)$$



      From here, I did bifurcation into two methods:



      Method 1:



      $$fracpartial^2 vpartial x^2_i = fracpartialpartial x_i left(fracpartial vpartial r fracx_irright)\
      = fracpartial^2 vpartial x_ipartial rfracx_ir + fracpartial vpartial rfrac1r - x_ifracpartial vpartial rfrac1r^2fracpartial rpartial x_i\
      = fracpartial^2 vpartial x_ipartial rfracx_ir + fracpartial vpartial rfrac1r - fracpartial vpartial rfracx_i^2r^3$$



      Apply sigma



      $$sumfracpartial^2 vpartial x^2_i =fracn-1r fracpartial vpartial r + colorredsum fracpartial^2 vpartial x_ipartial rfracx_ir$$



      Method 1(A):



      Wrote the red term as $$fracpartialpartial rleft(fracpartial vpartial rright) fracpartial rpartial x_i fracx_ir = fracpartial^2 vpartial r^2 fracx_i^2r^2$$
      which on summing gives required result!



      Method 1(B):



      Wrote red part as:



      $$fracpartial partial rleft(fracpartial vpartial x_iright)fracpartial r partial x_i = fracpartial ^2 vpartial x_i^2$$



      which is obviously not correct, but doesnt appear where error occurs.



      Method 2:



      Using chain rule:



      $$fracpartial^2 vpartial x^2_i= fracpartialpartial x_i left(fracpartial vpartial r fracx_irright) = fracpartialpartial r left(fracpartial vpartial r fracx_irright) fracpartial rpartial x_i\
      = fracx_ir left( fracx_ir fracpartial^2 vpartial r^2 + colorred frac1r fracpartial vpartial rfracpartial x_ipartial r-fracpartial vpartial rfracx_i^2r^2right)$$



      On applying sigma and noting $sum x_i fracpartial x_ipartial r = r$ we get wrong answer:



      $$sumfracpartial^2 vpartial x_i^2 = fracpartial ^2 vpartial r^2 + 0$$



      Here what went wrong?




      I am really confused here, as to when we use chain rule without encountering error. Here I know $v$ is function of $r$ which is function of all $x_i$. So it is known that $fracpartial vpartial x_i = fracpartial vpartial r fracpartial rpartial x_i$. Where do I go wrong everytime?



      Thank you a lot!










      share|cite|improve this question















      If $v = v(r)$ and $r^2 = sum_i=1^n x_i^2$, then prove $$sum v_x_i x_i = v_r ((n-1)/r) + v_rr$$



      I start by:



      $$fracpartial rpartial x_i = fracx_ir$$



      $$fracpartial vpartial x_i = fracpartial vpartial r fracpartial rpartial x_i = fracpartial vpartial r fracx_ir$$



      Now,
      $$fracpartial^2 vpartial x^2_i = fracpartialpartial x_i left(fracpartial vpartial r fracx_irright)$$



      From here, I did bifurcation into two methods:



      Method 1:



      $$fracpartial^2 vpartial x^2_i = fracpartialpartial x_i left(fracpartial vpartial r fracx_irright)\
      = fracpartial^2 vpartial x_ipartial rfracx_ir + fracpartial vpartial rfrac1r - x_ifracpartial vpartial rfrac1r^2fracpartial rpartial x_i\
      = fracpartial^2 vpartial x_ipartial rfracx_ir + fracpartial vpartial rfrac1r - fracpartial vpartial rfracx_i^2r^3$$



      Apply sigma



      $$sumfracpartial^2 vpartial x^2_i =fracn-1r fracpartial vpartial r + colorredsum fracpartial^2 vpartial x_ipartial rfracx_ir$$



      Method 1(A):



      Wrote the red term as $$fracpartialpartial rleft(fracpartial vpartial rright) fracpartial rpartial x_i fracx_ir = fracpartial^2 vpartial r^2 fracx_i^2r^2$$
      which on summing gives required result!



      Method 1(B):



      Wrote red part as:



      $$fracpartial partial rleft(fracpartial vpartial x_iright)fracpartial r partial x_i = fracpartial ^2 vpartial x_i^2$$



      which is obviously not correct, but doesnt appear where error occurs.



      Method 2:



      Using chain rule:



      $$fracpartial^2 vpartial x^2_i= fracpartialpartial x_i left(fracpartial vpartial r fracx_irright) = fracpartialpartial r left(fracpartial vpartial r fracx_irright) fracpartial rpartial x_i\
      = fracx_ir left( fracx_ir fracpartial^2 vpartial r^2 + colorred frac1r fracpartial vpartial rfracpartial x_ipartial r-fracpartial vpartial rfracx_i^2r^2right)$$



      On applying sigma and noting $sum x_i fracpartial x_ipartial r = r$ we get wrong answer:



      $$sumfracpartial^2 vpartial x_i^2 = fracpartial ^2 vpartial r^2 + 0$$



      Here what went wrong?




      I am really confused here, as to when we use chain rule without encountering error. Here I know $v$ is function of $r$ which is function of all $x_i$. So it is known that $fracpartial vpartial x_i = fracpartial vpartial r fracpartial rpartial x_i$. Where do I go wrong everytime?



      Thank you a lot!







      multivariable-calculus partial-derivative chain-rule






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      edited Sep 8 at 8:17

























      asked Sep 8 at 6:18









      jeea

      47212




      47212




















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          Your troubles stem from dubious notation: The same letter $v$ is used for a certain function $rmapsto v(r)$ of one variable $r$, and then also for the nested function $$xmapsto f(x):=vbigl(r(x)bigr)$$ of the vector variable $x$. – We are told to compute the Laplacian $$Delta f(x):=sum_i=1^npartial^2 foverpartial x_i^2 .$$
          You started correctly with
          $$partial foverpartial x_i=v'(r)partial roverpartial x_i=v'(r)over r,x_i .$$
          Now the next step:
          $$partial^2 foverpartial x_i^2=dover drv'(r)over r cdot partial rover partial x_icdot x_i+v'(r)over r=r v''(r)-v'(r)over r^2>x_i^2over r+v'(r)over r .$$
          Summing over $i$ then gives the result you were asked to prove.






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            up vote
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            Your troubles stem from dubious notation: The same letter $v$ is used for a certain function $rmapsto v(r)$ of one variable $r$, and then also for the nested function $$xmapsto f(x):=vbigl(r(x)bigr)$$ of the vector variable $x$. – We are told to compute the Laplacian $$Delta f(x):=sum_i=1^npartial^2 foverpartial x_i^2 .$$
            You started correctly with
            $$partial foverpartial x_i=v'(r)partial roverpartial x_i=v'(r)over r,x_i .$$
            Now the next step:
            $$partial^2 foverpartial x_i^2=dover drv'(r)over r cdot partial rover partial x_icdot x_i+v'(r)over r=r v''(r)-v'(r)over r^2>x_i^2over r+v'(r)over r .$$
            Summing over $i$ then gives the result you were asked to prove.






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              2
              down vote













              Your troubles stem from dubious notation: The same letter $v$ is used for a certain function $rmapsto v(r)$ of one variable $r$, and then also for the nested function $$xmapsto f(x):=vbigl(r(x)bigr)$$ of the vector variable $x$. – We are told to compute the Laplacian $$Delta f(x):=sum_i=1^npartial^2 foverpartial x_i^2 .$$
              You started correctly with
              $$partial foverpartial x_i=v'(r)partial roverpartial x_i=v'(r)over r,x_i .$$
              Now the next step:
              $$partial^2 foverpartial x_i^2=dover drv'(r)over r cdot partial rover partial x_icdot x_i+v'(r)over r=r v''(r)-v'(r)over r^2>x_i^2over r+v'(r)over r .$$
              Summing over $i$ then gives the result you were asked to prove.






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                up vote
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                down vote










                up vote
                2
                down vote









                Your troubles stem from dubious notation: The same letter $v$ is used for a certain function $rmapsto v(r)$ of one variable $r$, and then also for the nested function $$xmapsto f(x):=vbigl(r(x)bigr)$$ of the vector variable $x$. – We are told to compute the Laplacian $$Delta f(x):=sum_i=1^npartial^2 foverpartial x_i^2 .$$
                You started correctly with
                $$partial foverpartial x_i=v'(r)partial roverpartial x_i=v'(r)over r,x_i .$$
                Now the next step:
                $$partial^2 foverpartial x_i^2=dover drv'(r)over r cdot partial rover partial x_icdot x_i+v'(r)over r=r v''(r)-v'(r)over r^2>x_i^2over r+v'(r)over r .$$
                Summing over $i$ then gives the result you were asked to prove.






                share|cite|improve this answer












                Your troubles stem from dubious notation: The same letter $v$ is used for a certain function $rmapsto v(r)$ of one variable $r$, and then also for the nested function $$xmapsto f(x):=vbigl(r(x)bigr)$$ of the vector variable $x$. – We are told to compute the Laplacian $$Delta f(x):=sum_i=1^npartial^2 foverpartial x_i^2 .$$
                You started correctly with
                $$partial foverpartial x_i=v'(r)partial roverpartial x_i=v'(r)over r,x_i .$$
                Now the next step:
                $$partial^2 foverpartial x_i^2=dover drv'(r)over r cdot partial rover partial x_icdot x_i+v'(r)over r=r v''(r)-v'(r)over r^2>x_i^2over r+v'(r)over r .$$
                Summing over $i$ then gives the result you were asked to prove.







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                answered Sep 8 at 15:07









                Christian Blatter

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