Coordinates of sector of circle

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I know the coordinates of one point on a circle, this point is part of a sector. I know the angle of the sector at the centre of radius, I know the radius and I know the arc length. How do I calculate the coordinates of the other coordinate of the sector ?



Picture



I have quickly mocked up the problem in the image above, please note it is B I am aiming to find.



Angle in rads = 0.262



Radius = 21



Arc length = 5.5



A = (0.5,21)










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  • You can use complex numbers to calculate the co-ordinates of the new points . Take the init point as $0.5+21i$ and multiply it with $e^itheta$ where $theta = $ the radians by which it is rotated
    – AbKDs
    Mar 5 '14 at 12:20











  • In contrast to your other question, this time you have too much information. The radis and angle tell you the arclength.
    – bubba
    Mar 5 '14 at 12:23














up vote
2
down vote

favorite












I know the coordinates of one point on a circle, this point is part of a sector. I know the angle of the sector at the centre of radius, I know the radius and I know the arc length. How do I calculate the coordinates of the other coordinate of the sector ?



Picture



I have quickly mocked up the problem in the image above, please note it is B I am aiming to find.



Angle in rads = 0.262



Radius = 21



Arc length = 5.5



A = (0.5,21)










share|cite|improve this question























  • You can use complex numbers to calculate the co-ordinates of the new points . Take the init point as $0.5+21i$ and multiply it with $e^itheta$ where $theta = $ the radians by which it is rotated
    – AbKDs
    Mar 5 '14 at 12:20











  • In contrast to your other question, this time you have too much information. The radis and angle tell you the arclength.
    – bubba
    Mar 5 '14 at 12:23












up vote
2
down vote

favorite









up vote
2
down vote

favorite











I know the coordinates of one point on a circle, this point is part of a sector. I know the angle of the sector at the centre of radius, I know the radius and I know the arc length. How do I calculate the coordinates of the other coordinate of the sector ?



Picture



I have quickly mocked up the problem in the image above, please note it is B I am aiming to find.



Angle in rads = 0.262



Radius = 21



Arc length = 5.5



A = (0.5,21)










share|cite|improve this question















I know the coordinates of one point on a circle, this point is part of a sector. I know the angle of the sector at the centre of radius, I know the radius and I know the arc length. How do I calculate the coordinates of the other coordinate of the sector ?



Picture



I have quickly mocked up the problem in the image above, please note it is B I am aiming to find.



Angle in rads = 0.262



Radius = 21



Arc length = 5.5



A = (0.5,21)







circle coordinate-systems






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edited Apr 10 '17 at 6:09









Frenzy Li

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asked Mar 5 '14 at 11:43









Amie-lea Sambrook

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  • You can use complex numbers to calculate the co-ordinates of the new points . Take the init point as $0.5+21i$ and multiply it with $e^itheta$ where $theta = $ the radians by which it is rotated
    – AbKDs
    Mar 5 '14 at 12:20











  • In contrast to your other question, this time you have too much information. The radis and angle tell you the arclength.
    – bubba
    Mar 5 '14 at 12:23
















  • You can use complex numbers to calculate the co-ordinates of the new points . Take the init point as $0.5+21i$ and multiply it with $e^itheta$ where $theta = $ the radians by which it is rotated
    – AbKDs
    Mar 5 '14 at 12:20











  • In contrast to your other question, this time you have too much information. The radis and angle tell you the arclength.
    – bubba
    Mar 5 '14 at 12:23















You can use complex numbers to calculate the co-ordinates of the new points . Take the init point as $0.5+21i$ and multiply it with $e^itheta$ where $theta = $ the radians by which it is rotated
– AbKDs
Mar 5 '14 at 12:20





You can use complex numbers to calculate the co-ordinates of the new points . Take the init point as $0.5+21i$ and multiply it with $e^itheta$ where $theta = $ the radians by which it is rotated
– AbKDs
Mar 5 '14 at 12:20













In contrast to your other question, this time you have too much information. The radis and angle tell you the arclength.
– bubba
Mar 5 '14 at 12:23




In contrast to your other question, this time you have too much information. The radis and angle tell you the arclength.
– bubba
Mar 5 '14 at 12:23










1 Answer
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Same technique as in your other question here.



Let $A = (x,y)$ and let $B= (x_1, y_1)$. Then
$$
x_1 = ; xcos(0.262) + ysin(0.262) \
y_1 = -xsin(0.262) + ycos(0.262) \
$$



This assumes the center is again at $(0,0)$.






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    up vote
    0
    down vote













    Same technique as in your other question here.



    Let $A = (x,y)$ and let $B= (x_1, y_1)$. Then
    $$
    x_1 = ; xcos(0.262) + ysin(0.262) \
    y_1 = -xsin(0.262) + ycos(0.262) \
    $$



    This assumes the center is again at $(0,0)$.






    share|cite|improve this answer


























      up vote
      0
      down vote













      Same technique as in your other question here.



      Let $A = (x,y)$ and let $B= (x_1, y_1)$. Then
      $$
      x_1 = ; xcos(0.262) + ysin(0.262) \
      y_1 = -xsin(0.262) + ycos(0.262) \
      $$



      This assumes the center is again at $(0,0)$.






      share|cite|improve this answer
























        up vote
        0
        down vote










        up vote
        0
        down vote









        Same technique as in your other question here.



        Let $A = (x,y)$ and let $B= (x_1, y_1)$. Then
        $$
        x_1 = ; xcos(0.262) + ysin(0.262) \
        y_1 = -xsin(0.262) + ycos(0.262) \
        $$



        This assumes the center is again at $(0,0)$.






        share|cite|improve this answer














        Same technique as in your other question here.



        Let $A = (x,y)$ and let $B= (x_1, y_1)$. Then
        $$
        x_1 = ; xcos(0.262) + ysin(0.262) \
        y_1 = -xsin(0.262) + ycos(0.262) \
        $$



        This assumes the center is again at $(0,0)$.







        share|cite|improve this answer














        share|cite|improve this answer



        share|cite|improve this answer








        edited Apr 13 '17 at 12:21









        Community♦

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        answered Mar 5 '14 at 12:27









        bubba

        29.1k32884




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