Doubt about 0-norm in Majda Bertozzi
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I'm studyind Majda Bertozzi book about vorticity and incompressible flow, and I don't know what's the 0 norm which appears in it. Thanks a lot!
fluid-dynamics
asked Sep 8 at 9:09
Alex
11
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up vote
-3
down vote
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I'm studyind Majda Bertozzi book about vorticity and incompressible flow, and I don't know what's the 0 norm which appears in it. Thanks a lot!
fluid-dynamics
asked Sep 8 at 9:09
Alex
11
Sometimes $lVert xrVert_0=lvertlbrace k,:, x_kne 0rbracervert$, so for instance $lVert (1,0,-5,3)rVert_0=3$.
– Saucy O'Path
Sep 8 at 9:31
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up vote
-3
down vote
favorite
up vote
-3
down vote
favorite
I'm studyind Majda Bertozzi book about vorticity and incompressible flow, and I don't know what's the 0 norm which appears in it. Thanks a lot!
fluid-dynamics
asked Sep 8 at 9:09
Alex
11
I'm studyind Majda Bertozzi book about vorticity and incompressible flow, and I don't know what's the 0 norm which appears in it. Thanks a lot!
fluid-dynamics
fluid-dynamics
asked Sep 8 at 9:09
Alex
11
asked Sep 8 at 9:09
Alex
11
asked Sep 8 at 9:09
Alex
11
asked Sep 8 at 9:09
Alex
11
asked Sep 8 at 9:09
Alex
11
11
Sometimes $lVert xrVert_0=lvertlbrace k,:, x_kne 0rbracervert$, so for instance $lVert (1,0,-5,3)rVert_0=3$.
– Saucy O'Path
Sep 8 at 9:31
add a comment |Â
Sometimes $lVert xrVert_0=lvertlbrace k,:, x_kne 0rbracervert$, so for instance $lVert (1,0,-5,3)rVert_0=3$.
– Saucy O'Path
Sep 8 at 9:31
Sometimes $lVert xrVert_0=lvertlbrace k,:, x_kne 0rbracervert$, so for instance $lVert (1,0,-5,3)rVert_0=3$.
– Saucy O'Path
Sep 8 at 9:31
Sometimes $lVert xrVert_0=lvertlbrace k,:, x_kne 0rbracervert$, so for instance $lVert (1,0,-5,3)rVert_0=3$.
– Saucy O'Path
Sep 8 at 9:31
add a comment |Â
1 Answer
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As the first line of p. 89 says, $|cdot|_0$ is the $L^2$ norm on $mathbbR^N$. The $0$ makes sense when you check out p. 97, where this is generalised to Sobolev spaces of functions having derivatives up to order $m$ that are in $L^2$. $L^2$ is then the case $m=0$.
answered Sep 8 at 10:02
Kusma
3,415219
add a comment |Â
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
2
down vote
accepted
As the first line of p. 89 says, $|cdot|_0$ is the $L^2$ norm on $mathbbR^N$. The $0$ makes sense when you check out p. 97, where this is generalised to Sobolev spaces of functions having derivatives up to order $m$ that are in $L^2$. $L^2$ is then the case $m=0$.
answered Sep 8 at 10:02
Kusma
3,415219
add a comment |Â
up vote
2
down vote
accepted
As the first line of p. 89 says, $|cdot|_0$ is the $L^2$ norm on $mathbbR^N$. The $0$ makes sense when you check out p. 97, where this is generalised to Sobolev spaces of functions having derivatives up to order $m$ that are in $L^2$. $L^2$ is then the case $m=0$.
answered Sep 8 at 10:02
Kusma
3,415219
add a comment |Â
up vote
2
down vote
accepted
up vote
2
down vote
accepted
As the first line of p. 89 says, $|cdot|_0$ is the $L^2$ norm on $mathbbR^N$. The $0$ makes sense when you check out p. 97, where this is generalised to Sobolev spaces of functions having derivatives up to order $m$ that are in $L^2$. $L^2$ is then the case $m=0$.
answered Sep 8 at 10:02
Kusma
3,415219
As the first line of p. 89 says, $|cdot|_0$ is the $L^2$ norm on $mathbbR^N$. The $0$ makes sense when you check out p. 97, where this is generalised to Sobolev spaces of functions having derivatives up to order $m$ that are in $L^2$. $L^2$ is then the case $m=0$.
answered Sep 8 at 10:02
Kusma
3,415219
answered Sep 8 at 10:02
Kusma
3,415219
answered Sep 8 at 10:02
Kusma
3,415219
answered Sep 8 at 10:02
Kusma
3,415219
3,415219
add a comment |Â
add a comment |Â
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Sometimes $lVert xrVert_0=lvertlbrace k,:, x_kne 0rbracervert$, so for instance $lVert (1,0,-5,3)rVert_0=3$.
– Saucy O'Path
Sep 8 at 9:31