Probability of $A$ given $A$ intersection $B$ [closed]
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Two dice are rolled, and $A$ and $B$ stand for: $A=$ first of the numbers is an odd number, $B=$ the sum of the numbers is $4$.
How do I write down this probability?
probability conditional-probability
closed as unclear what you're asking by Did, Jose Arnaldo Bebita Dris, Shailesh, ccorn, rtybase Sep 2 at 16:33
Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, itâÂÂs hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.
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Two dice are rolled, and $A$ and $B$ stand for: $A=$ first of the numbers is an odd number, $B=$ the sum of the numbers is $4$.
How do I write down this probability?
probability conditional-probability
closed as unclear what you're asking by Did, Jose Arnaldo Bebita Dris, Shailesh, ccorn, rtybase Sep 2 at 16:33
Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, itâÂÂs hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.
1
Given $A$ and $B$ have both happened, what is the probability that $A$ has happened?
â GoodDeeds
Sep 2 at 11:14
What do you mean by probability of $A$ given $A cap B$ ? Really $mathbbP(A | A cap B)$ ?
â LucaMac
Sep 2 at 11:15
Welcome to MSE. It will be more likely that you will get an answer if you show us that you made an effort. This should be added to the question rather than in the comments.
â José Carlos Santos
Sep 2 at 11:17
P(A|A â©B) <--- that's how it looks like, it's a homework and I don't know how to write and calculate that correctly.
â user589214
Sep 2 at 11:20
add a comment |Â
up vote
0
down vote
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up vote
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down vote
favorite
Two dice are rolled, and $A$ and $B$ stand for: $A=$ first of the numbers is an odd number, $B=$ the sum of the numbers is $4$.
How do I write down this probability?
probability conditional-probability
Two dice are rolled, and $A$ and $B$ stand for: $A=$ first of the numbers is an odd number, $B=$ the sum of the numbers is $4$.
How do I write down this probability?
probability conditional-probability
probability conditional-probability
edited Sep 2 at 11:15
GoodDeeds
10.2k21335
10.2k21335
asked Sep 2 at 11:12
user589214
6
6
closed as unclear what you're asking by Did, Jose Arnaldo Bebita Dris, Shailesh, ccorn, rtybase Sep 2 at 16:33
Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, itâÂÂs hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.
closed as unclear what you're asking by Did, Jose Arnaldo Bebita Dris, Shailesh, ccorn, rtybase Sep 2 at 16:33
Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, itâÂÂs hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.
1
Given $A$ and $B$ have both happened, what is the probability that $A$ has happened?
â GoodDeeds
Sep 2 at 11:14
What do you mean by probability of $A$ given $A cap B$ ? Really $mathbbP(A | A cap B)$ ?
â LucaMac
Sep 2 at 11:15
Welcome to MSE. It will be more likely that you will get an answer if you show us that you made an effort. This should be added to the question rather than in the comments.
â José Carlos Santos
Sep 2 at 11:17
P(A|A â©B) <--- that's how it looks like, it's a homework and I don't know how to write and calculate that correctly.
â user589214
Sep 2 at 11:20
add a comment |Â
1
Given $A$ and $B$ have both happened, what is the probability that $A$ has happened?
â GoodDeeds
Sep 2 at 11:14
What do you mean by probability of $A$ given $A cap B$ ? Really $mathbbP(A | A cap B)$ ?
â LucaMac
Sep 2 at 11:15
Welcome to MSE. It will be more likely that you will get an answer if you show us that you made an effort. This should be added to the question rather than in the comments.
â José Carlos Santos
Sep 2 at 11:17
P(A|A â©B) <--- that's how it looks like, it's a homework and I don't know how to write and calculate that correctly.
â user589214
Sep 2 at 11:20
1
1
Given $A$ and $B$ have both happened, what is the probability that $A$ has happened?
â GoodDeeds
Sep 2 at 11:14
Given $A$ and $B$ have both happened, what is the probability that $A$ has happened?
â GoodDeeds
Sep 2 at 11:14
What do you mean by probability of $A$ given $A cap B$ ? Really $mathbbP(A | A cap B)$ ?
â LucaMac
Sep 2 at 11:15
What do you mean by probability of $A$ given $A cap B$ ? Really $mathbbP(A | A cap B)$ ?
â LucaMac
Sep 2 at 11:15
Welcome to MSE. It will be more likely that you will get an answer if you show us that you made an effort. This should be added to the question rather than in the comments.
â José Carlos Santos
Sep 2 at 11:17
Welcome to MSE. It will be more likely that you will get an answer if you show us that you made an effort. This should be added to the question rather than in the comments.
â José Carlos Santos
Sep 2 at 11:17
P(A|A â©B) <--- that's how it looks like, it's a homework and I don't know how to write and calculate that correctly.
â user589214
Sep 2 at 11:20
P(A|A â©B) <--- that's how it looks like, it's a homework and I don't know how to write and calculate that correctly.
â user589214
Sep 2 at 11:20
add a comment |Â
1 Answer
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$P(A|A cap B) = fracP(A cap A cap B)P(A cap B) = fracP(A cap B)P(A cap B) = 1$
Quite the same I got earlier myself, I just wasn't certain of it. Thank you :)
â user589214
Sep 2 at 11:46
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
$P(A|A cap B) = fracP(A cap A cap B)P(A cap B) = fracP(A cap B)P(A cap B) = 1$
Quite the same I got earlier myself, I just wasn't certain of it. Thank you :)
â user589214
Sep 2 at 11:46
add a comment |Â
up vote
1
down vote
$P(A|A cap B) = fracP(A cap A cap B)P(A cap B) = fracP(A cap B)P(A cap B) = 1$
Quite the same I got earlier myself, I just wasn't certain of it. Thank you :)
â user589214
Sep 2 at 11:46
add a comment |Â
up vote
1
down vote
up vote
1
down vote
$P(A|A cap B) = fracP(A cap A cap B)P(A cap B) = fracP(A cap B)P(A cap B) = 1$
$P(A|A cap B) = fracP(A cap A cap B)P(A cap B) = fracP(A cap B)P(A cap B) = 1$
answered Sep 2 at 11:22
Balaji sb
40325
40325
Quite the same I got earlier myself, I just wasn't certain of it. Thank you :)
â user589214
Sep 2 at 11:46
add a comment |Â
Quite the same I got earlier myself, I just wasn't certain of it. Thank you :)
â user589214
Sep 2 at 11:46
Quite the same I got earlier myself, I just wasn't certain of it. Thank you :)
â user589214
Sep 2 at 11:46
Quite the same I got earlier myself, I just wasn't certain of it. Thank you :)
â user589214
Sep 2 at 11:46
add a comment |Â
1
Given $A$ and $B$ have both happened, what is the probability that $A$ has happened?
â GoodDeeds
Sep 2 at 11:14
What do you mean by probability of $A$ given $A cap B$ ? Really $mathbbP(A | A cap B)$ ?
â LucaMac
Sep 2 at 11:15
Welcome to MSE. It will be more likely that you will get an answer if you show us that you made an effort. This should be added to the question rather than in the comments.
â José Carlos Santos
Sep 2 at 11:17
P(A|A â©B) <--- that's how it looks like, it's a homework and I don't know how to write and calculate that correctly.
â user589214
Sep 2 at 11:20