Probability of $A$ given $A$ intersection $B$ [closed]

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Two dice are rolled, and $A$ and $B$ stand for: $A=$ first of the numbers is an odd number, $B=$ the sum of the numbers is $4$.



How do I write down this probability?










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closed as unclear what you're asking by Did, Jose Arnaldo Bebita Dris, Shailesh, ccorn, rtybase Sep 2 at 16:33


Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.










  • 1




    Given $A$ and $B$ have both happened, what is the probability that $A$ has happened?
    – GoodDeeds
    Sep 2 at 11:14










  • What do you mean by probability of $A$ given $A cap B$ ? Really $mathbbP(A | A cap B)$ ?
    – LucaMac
    Sep 2 at 11:15











  • Welcome to MSE. It will be more likely that you will get an answer if you show us that you made an effort. This should be added to the question rather than in the comments.
    – José Carlos Santos
    Sep 2 at 11:17










  • P(A|A ∩B) <--- that's how it looks like, it's a homework and I don't know how to write and calculate that correctly.
    – user589214
    Sep 2 at 11:20














up vote
0
down vote

favorite












Two dice are rolled, and $A$ and $B$ stand for: $A=$ first of the numbers is an odd number, $B=$ the sum of the numbers is $4$.



How do I write down this probability?










share|cite|improve this question















closed as unclear what you're asking by Did, Jose Arnaldo Bebita Dris, Shailesh, ccorn, rtybase Sep 2 at 16:33


Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.










  • 1




    Given $A$ and $B$ have both happened, what is the probability that $A$ has happened?
    – GoodDeeds
    Sep 2 at 11:14










  • What do you mean by probability of $A$ given $A cap B$ ? Really $mathbbP(A | A cap B)$ ?
    – LucaMac
    Sep 2 at 11:15











  • Welcome to MSE. It will be more likely that you will get an answer if you show us that you made an effort. This should be added to the question rather than in the comments.
    – José Carlos Santos
    Sep 2 at 11:17










  • P(A|A ∩B) <--- that's how it looks like, it's a homework and I don't know how to write and calculate that correctly.
    – user589214
    Sep 2 at 11:20












up vote
0
down vote

favorite









up vote
0
down vote

favorite











Two dice are rolled, and $A$ and $B$ stand for: $A=$ first of the numbers is an odd number, $B=$ the sum of the numbers is $4$.



How do I write down this probability?










share|cite|improve this question















Two dice are rolled, and $A$ and $B$ stand for: $A=$ first of the numbers is an odd number, $B=$ the sum of the numbers is $4$.



How do I write down this probability?







probability conditional-probability






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edited Sep 2 at 11:15









GoodDeeds

10.2k21335




10.2k21335










asked Sep 2 at 11:12









user589214

6




6




closed as unclear what you're asking by Did, Jose Arnaldo Bebita Dris, Shailesh, ccorn, rtybase Sep 2 at 16:33


Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.






closed as unclear what you're asking by Did, Jose Arnaldo Bebita Dris, Shailesh, ccorn, rtybase Sep 2 at 16:33


Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.









  • 1




    Given $A$ and $B$ have both happened, what is the probability that $A$ has happened?
    – GoodDeeds
    Sep 2 at 11:14










  • What do you mean by probability of $A$ given $A cap B$ ? Really $mathbbP(A | A cap B)$ ?
    – LucaMac
    Sep 2 at 11:15











  • Welcome to MSE. It will be more likely that you will get an answer if you show us that you made an effort. This should be added to the question rather than in the comments.
    – José Carlos Santos
    Sep 2 at 11:17










  • P(A|A ∩B) <--- that's how it looks like, it's a homework and I don't know how to write and calculate that correctly.
    – user589214
    Sep 2 at 11:20












  • 1




    Given $A$ and $B$ have both happened, what is the probability that $A$ has happened?
    – GoodDeeds
    Sep 2 at 11:14










  • What do you mean by probability of $A$ given $A cap B$ ? Really $mathbbP(A | A cap B)$ ?
    – LucaMac
    Sep 2 at 11:15











  • Welcome to MSE. It will be more likely that you will get an answer if you show us that you made an effort. This should be added to the question rather than in the comments.
    – José Carlos Santos
    Sep 2 at 11:17










  • P(A|A ∩B) <--- that's how it looks like, it's a homework and I don't know how to write and calculate that correctly.
    – user589214
    Sep 2 at 11:20







1




1




Given $A$ and $B$ have both happened, what is the probability that $A$ has happened?
– GoodDeeds
Sep 2 at 11:14




Given $A$ and $B$ have both happened, what is the probability that $A$ has happened?
– GoodDeeds
Sep 2 at 11:14












What do you mean by probability of $A$ given $A cap B$ ? Really $mathbbP(A | A cap B)$ ?
– LucaMac
Sep 2 at 11:15





What do you mean by probability of $A$ given $A cap B$ ? Really $mathbbP(A | A cap B)$ ?
– LucaMac
Sep 2 at 11:15













Welcome to MSE. It will be more likely that you will get an answer if you show us that you made an effort. This should be added to the question rather than in the comments.
– José Carlos Santos
Sep 2 at 11:17




Welcome to MSE. It will be more likely that you will get an answer if you show us that you made an effort. This should be added to the question rather than in the comments.
– José Carlos Santos
Sep 2 at 11:17












P(A|A ∩B) <--- that's how it looks like, it's a homework and I don't know how to write and calculate that correctly.
– user589214
Sep 2 at 11:20




P(A|A ∩B) <--- that's how it looks like, it's a homework and I don't know how to write and calculate that correctly.
– user589214
Sep 2 at 11:20










1 Answer
1






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oldest

votes

















up vote
1
down vote













$P(A|A cap B) = fracP(A cap A cap B)P(A cap B) = fracP(A cap B)P(A cap B) = 1$






share|cite|improve this answer




















  • Quite the same I got earlier myself, I just wasn't certain of it. Thank you :)
    – user589214
    Sep 2 at 11:46

















1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes








up vote
1
down vote













$P(A|A cap B) = fracP(A cap A cap B)P(A cap B) = fracP(A cap B)P(A cap B) = 1$






share|cite|improve this answer




















  • Quite the same I got earlier myself, I just wasn't certain of it. Thank you :)
    – user589214
    Sep 2 at 11:46














up vote
1
down vote













$P(A|A cap B) = fracP(A cap A cap B)P(A cap B) = fracP(A cap B)P(A cap B) = 1$






share|cite|improve this answer




















  • Quite the same I got earlier myself, I just wasn't certain of it. Thank you :)
    – user589214
    Sep 2 at 11:46












up vote
1
down vote










up vote
1
down vote









$P(A|A cap B) = fracP(A cap A cap B)P(A cap B) = fracP(A cap B)P(A cap B) = 1$






share|cite|improve this answer












$P(A|A cap B) = fracP(A cap A cap B)P(A cap B) = fracP(A cap B)P(A cap B) = 1$







share|cite|improve this answer












share|cite|improve this answer



share|cite|improve this answer










answered Sep 2 at 11:22









Balaji sb

40325




40325











  • Quite the same I got earlier myself, I just wasn't certain of it. Thank you :)
    – user589214
    Sep 2 at 11:46
















  • Quite the same I got earlier myself, I just wasn't certain of it. Thank you :)
    – user589214
    Sep 2 at 11:46















Quite the same I got earlier myself, I just wasn't certain of it. Thank you :)
– user589214
Sep 2 at 11:46




Quite the same I got earlier myself, I just wasn't certain of it. Thank you :)
– user589214
Sep 2 at 11:46


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