Regarding geographic area bounded by 3 lines

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I have 3 points on a map that is specified in terms of a latitude and longitude coordinate. For each of this point, I am given an azimuth (i.e. 0 = North, measured clockwise).
By drawing 3 lines from the 3 points along the azimuth, I can find an intersecting region. My problem is thus: how can I find an equation used to compute the area of the region (e.g. in terms of kmò) given the locations and azimuths?
I hope the picture below helps in understanding my question:

trigonometry area
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I have 3 points on a map that is specified in terms of a latitude and longitude coordinate. For each of this point, I am given an azimuth (i.e. 0 = North, measured clockwise).
By drawing 3 lines from the 3 points along the azimuth, I can find an intersecting region. My problem is thus: how can I find an equation used to compute the area of the region (e.g. in terms of kmò) given the locations and azimuths?
I hope the picture below helps in understanding my question:

trigonometry area
Question: is the problem meant to be solved on the ball's surface (e.g. for larger areas), or on an approximate plane projection surface, like Mercator's?
â Andreas
Aug 20 at 7:34
Mercator projection should be fine, might be simpler?
â Corse
Aug 20 at 7:35
If you know the coords of the vertices of the triangle , you can use Háéàformula to find the area you are looking for
â dmtri
Aug 20 at 8:56
do you have a reference to the Háéàformula?
â Corse
Aug 20 at 9:29
anyone have any idea how this can be solved?
â Corse
Aug 24 at 3:04
add a comment |Â
up vote
1
down vote
favorite
up vote
1
down vote
favorite
I have 3 points on a map that is specified in terms of a latitude and longitude coordinate. For each of this point, I am given an azimuth (i.e. 0 = North, measured clockwise).
By drawing 3 lines from the 3 points along the azimuth, I can find an intersecting region. My problem is thus: how can I find an equation used to compute the area of the region (e.g. in terms of kmò) given the locations and azimuths?
I hope the picture below helps in understanding my question:

trigonometry area
I have 3 points on a map that is specified in terms of a latitude and longitude coordinate. For each of this point, I am given an azimuth (i.e. 0 = North, measured clockwise).
By drawing 3 lines from the 3 points along the azimuth, I can find an intersecting region. My problem is thus: how can I find an equation used to compute the area of the region (e.g. in terms of kmò) given the locations and azimuths?
I hope the picture below helps in understanding my question:

trigonometry area
asked Aug 20 at 6:49
Corse
1536
1536
Question: is the problem meant to be solved on the ball's surface (e.g. for larger areas), or on an approximate plane projection surface, like Mercator's?
â Andreas
Aug 20 at 7:34
Mercator projection should be fine, might be simpler?
â Corse
Aug 20 at 7:35
If you know the coords of the vertices of the triangle , you can use Háéàformula to find the area you are looking for
â dmtri
Aug 20 at 8:56
do you have a reference to the Háéàformula?
â Corse
Aug 20 at 9:29
anyone have any idea how this can be solved?
â Corse
Aug 24 at 3:04
add a comment |Â
Question: is the problem meant to be solved on the ball's surface (e.g. for larger areas), or on an approximate plane projection surface, like Mercator's?
â Andreas
Aug 20 at 7:34
Mercator projection should be fine, might be simpler?
â Corse
Aug 20 at 7:35
If you know the coords of the vertices of the triangle , you can use Háéàformula to find the area you are looking for
â dmtri
Aug 20 at 8:56
do you have a reference to the Háéàformula?
â Corse
Aug 20 at 9:29
anyone have any idea how this can be solved?
â Corse
Aug 24 at 3:04
Question: is the problem meant to be solved on the ball's surface (e.g. for larger areas), or on an approximate plane projection surface, like Mercator's?
â Andreas
Aug 20 at 7:34
Question: is the problem meant to be solved on the ball's surface (e.g. for larger areas), or on an approximate plane projection surface, like Mercator's?
â Andreas
Aug 20 at 7:34
Mercator projection should be fine, might be simpler?
â Corse
Aug 20 at 7:35
Mercator projection should be fine, might be simpler?
â Corse
Aug 20 at 7:35
If you know the coords of the vertices of the triangle , you can use Háéàformula to find the area you are looking for
â dmtri
Aug 20 at 8:56
If you know the coords of the vertices of the triangle , you can use Háéàformula to find the area you are looking for
â dmtri
Aug 20 at 8:56
do you have a reference to the Háéàformula?
â Corse
Aug 20 at 9:29
do you have a reference to the Háéàformula?
â Corse
Aug 20 at 9:29
anyone have any idea how this can be solved?
â Corse
Aug 24 at 3:04
anyone have any idea how this can be solved?
â Corse
Aug 24 at 3:04
add a comment |Â
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Question: is the problem meant to be solved on the ball's surface (e.g. for larger areas), or on an approximate plane projection surface, like Mercator's?
â Andreas
Aug 20 at 7:34
Mercator projection should be fine, might be simpler?
â Corse
Aug 20 at 7:35
If you know the coords of the vertices of the triangle , you can use Háéàformula to find the area you are looking for
â dmtri
Aug 20 at 8:56
do you have a reference to the Háéàformula?
â Corse
Aug 20 at 9:29
anyone have any idea how this can be solved?
â Corse
Aug 24 at 3:04