Regarding geographic area bounded by 3 lines

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I have 3 points on a map that is specified in terms of a latitude and longitude coordinate. For each of this point, I am given an azimuth (i.e. 0 = North, measured clockwise).



By drawing 3 lines from the 3 points along the azimuth, I can find an intersecting region. My problem is thus: how can I find an equation used to compute the area of the region (e.g. in terms of km²) given the locations and azimuths?



I hope the picture below helps in understanding my question:



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  • Question: is the problem meant to be solved on the ball's surface (e.g. for larger areas), or on an approximate plane projection surface, like Mercator's?
    – Andreas
    Aug 20 at 7:34










  • Mercator projection should be fine, might be simpler?
    – Corse
    Aug 20 at 7:35










  • If you know the coords of the vertices of the triangle , you can use HΡΩΝ formula to find the area you are looking for
    – dmtri
    Aug 20 at 8:56










  • do you have a reference to the HΡΩΝ formula?
    – Corse
    Aug 20 at 9:29










  • anyone have any idea how this can be solved?
    – Corse
    Aug 24 at 3:04














up vote
1
down vote

favorite
1












I have 3 points on a map that is specified in terms of a latitude and longitude coordinate. For each of this point, I am given an azimuth (i.e. 0 = North, measured clockwise).



By drawing 3 lines from the 3 points along the azimuth, I can find an intersecting region. My problem is thus: how can I find an equation used to compute the area of the region (e.g. in terms of km²) given the locations and azimuths?



I hope the picture below helps in understanding my question:



Question







share|cite|improve this question




















  • Question: is the problem meant to be solved on the ball's surface (e.g. for larger areas), or on an approximate plane projection surface, like Mercator's?
    – Andreas
    Aug 20 at 7:34










  • Mercator projection should be fine, might be simpler?
    – Corse
    Aug 20 at 7:35










  • If you know the coords of the vertices of the triangle , you can use HΡΩΝ formula to find the area you are looking for
    – dmtri
    Aug 20 at 8:56










  • do you have a reference to the HΡΩΝ formula?
    – Corse
    Aug 20 at 9:29










  • anyone have any idea how this can be solved?
    – Corse
    Aug 24 at 3:04












up vote
1
down vote

favorite
1









up vote
1
down vote

favorite
1






1





I have 3 points on a map that is specified in terms of a latitude and longitude coordinate. For each of this point, I am given an azimuth (i.e. 0 = North, measured clockwise).



By drawing 3 lines from the 3 points along the azimuth, I can find an intersecting region. My problem is thus: how can I find an equation used to compute the area of the region (e.g. in terms of km²) given the locations and azimuths?



I hope the picture below helps in understanding my question:



Question







share|cite|improve this question












I have 3 points on a map that is specified in terms of a latitude and longitude coordinate. For each of this point, I am given an azimuth (i.e. 0 = North, measured clockwise).



By drawing 3 lines from the 3 points along the azimuth, I can find an intersecting region. My problem is thus: how can I find an equation used to compute the area of the region (e.g. in terms of km²) given the locations and azimuths?



I hope the picture below helps in understanding my question:



Question









share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Aug 20 at 6:49









Corse

1536




1536











  • Question: is the problem meant to be solved on the ball's surface (e.g. for larger areas), or on an approximate plane projection surface, like Mercator's?
    – Andreas
    Aug 20 at 7:34










  • Mercator projection should be fine, might be simpler?
    – Corse
    Aug 20 at 7:35










  • If you know the coords of the vertices of the triangle , you can use HΡΩΝ formula to find the area you are looking for
    – dmtri
    Aug 20 at 8:56










  • do you have a reference to the HΡΩΝ formula?
    – Corse
    Aug 20 at 9:29










  • anyone have any idea how this can be solved?
    – Corse
    Aug 24 at 3:04
















  • Question: is the problem meant to be solved on the ball's surface (e.g. for larger areas), or on an approximate plane projection surface, like Mercator's?
    – Andreas
    Aug 20 at 7:34










  • Mercator projection should be fine, might be simpler?
    – Corse
    Aug 20 at 7:35










  • If you know the coords of the vertices of the triangle , you can use HΡΩΝ formula to find the area you are looking for
    – dmtri
    Aug 20 at 8:56










  • do you have a reference to the HΡΩΝ formula?
    – Corse
    Aug 20 at 9:29










  • anyone have any idea how this can be solved?
    – Corse
    Aug 24 at 3:04















Question: is the problem meant to be solved on the ball's surface (e.g. for larger areas), or on an approximate plane projection surface, like Mercator's?
– Andreas
Aug 20 at 7:34




Question: is the problem meant to be solved on the ball's surface (e.g. for larger areas), or on an approximate plane projection surface, like Mercator's?
– Andreas
Aug 20 at 7:34












Mercator projection should be fine, might be simpler?
– Corse
Aug 20 at 7:35




Mercator projection should be fine, might be simpler?
– Corse
Aug 20 at 7:35












If you know the coords of the vertices of the triangle , you can use HΡΩΝ formula to find the area you are looking for
– dmtri
Aug 20 at 8:56




If you know the coords of the vertices of the triangle , you can use HΡΩΝ formula to find the area you are looking for
– dmtri
Aug 20 at 8:56












do you have a reference to the HΡΩΝ formula?
– Corse
Aug 20 at 9:29




do you have a reference to the HΡΩΝ formula?
– Corse
Aug 20 at 9:29












anyone have any idea how this can be solved?
– Corse
Aug 24 at 3:04




anyone have any idea how this can be solved?
– Corse
Aug 24 at 3:04















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