How to Prove cantor Set is Perfect easily? [duplicate]

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  • A proof that the Cantor set is Perfect

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Can some one tell me how to prove Cantor set is perfect?







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marked as duplicate by José Carlos Santos, Shailesh, A. Pongrácz, Theo Bendit, Siong Thye Goh Aug 20 at 7:09


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    You can characterise elements of the Cantor sets by their Ternary expansions, particularly its the numbers in $[0, 1]$ with ternary expansions consisting only of $0$ and $2$. Simply modify one of the trits sufficiently far along the expansion, and you can find another element of the Cantor set that is within any $varepsilon > 0$ distance.
    – Theo Bendit
    Aug 20 at 6:25














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  • A proof that the Cantor set is Perfect

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Can some one tell me how to prove Cantor set is perfect?







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marked as duplicate by José Carlos Santos, Shailesh, A. Pongrácz, Theo Bendit, Siong Thye Goh Aug 20 at 7:09


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.










  • 1




    You can characterise elements of the Cantor sets by their Ternary expansions, particularly its the numbers in $[0, 1]$ with ternary expansions consisting only of $0$ and $2$. Simply modify one of the trits sufficiently far along the expansion, and you can find another element of the Cantor set that is within any $varepsilon > 0$ distance.
    – Theo Bendit
    Aug 20 at 6:25












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up vote
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This question already has an answer here:



  • A proof that the Cantor set is Perfect

    1 answer



Can some one tell me how to prove Cantor set is perfect?







share|cite|improve this question













This question already has an answer here:



  • A proof that the Cantor set is Perfect

    1 answer



Can some one tell me how to prove Cantor set is perfect?





This question already has an answer here:



  • A proof that the Cantor set is Perfect

    1 answer









share|cite|improve this question











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asked Aug 20 at 6:16









Lahiru Dhananjaya

92




92




marked as duplicate by José Carlos Santos, Shailesh, A. Pongrácz, Theo Bendit, Siong Thye Goh Aug 20 at 7:09


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.






marked as duplicate by José Carlos Santos, Shailesh, A. Pongrácz, Theo Bendit, Siong Thye Goh Aug 20 at 7:09


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.









  • 1




    You can characterise elements of the Cantor sets by their Ternary expansions, particularly its the numbers in $[0, 1]$ with ternary expansions consisting only of $0$ and $2$. Simply modify one of the trits sufficiently far along the expansion, and you can find another element of the Cantor set that is within any $varepsilon > 0$ distance.
    – Theo Bendit
    Aug 20 at 6:25












  • 1




    You can characterise elements of the Cantor sets by their Ternary expansions, particularly its the numbers in $[0, 1]$ with ternary expansions consisting only of $0$ and $2$. Simply modify one of the trits sufficiently far along the expansion, and you can find another element of the Cantor set that is within any $varepsilon > 0$ distance.
    – Theo Bendit
    Aug 20 at 6:25







1




1




You can characterise elements of the Cantor sets by their Ternary expansions, particularly its the numbers in $[0, 1]$ with ternary expansions consisting only of $0$ and $2$. Simply modify one of the trits sufficiently far along the expansion, and you can find another element of the Cantor set that is within any $varepsilon > 0$ distance.
– Theo Bendit
Aug 20 at 6:25




You can characterise elements of the Cantor sets by their Ternary expansions, particularly its the numbers in $[0, 1]$ with ternary expansions consisting only of $0$ and $2$. Simply modify one of the trits sufficiently far along the expansion, and you can find another element of the Cantor set that is within any $varepsilon > 0$ distance.
– Theo Bendit
Aug 20 at 6:25










1 Answer
1






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No. That is, not "easily".
For a proof, not necessarily an easy one, see here:



A proof that the Cantor set is Perfect






share|cite|improve this answer




















  • Thanks a lot. This gives better and easy view on proving above.
    – Lahiru Dhananjaya
    Aug 20 at 6:31

















1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes








up vote
0
down vote













No. That is, not "easily".
For a proof, not necessarily an easy one, see here:



A proof that the Cantor set is Perfect






share|cite|improve this answer




















  • Thanks a lot. This gives better and easy view on proving above.
    – Lahiru Dhananjaya
    Aug 20 at 6:31














up vote
0
down vote













No. That is, not "easily".
For a proof, not necessarily an easy one, see here:



A proof that the Cantor set is Perfect






share|cite|improve this answer




















  • Thanks a lot. This gives better and easy view on proving above.
    – Lahiru Dhananjaya
    Aug 20 at 6:31












up vote
0
down vote










up vote
0
down vote









No. That is, not "easily".
For a proof, not necessarily an easy one, see here:



A proof that the Cantor set is Perfect






share|cite|improve this answer












No. That is, not "easily".
For a proof, not necessarily an easy one, see here:



A proof that the Cantor set is Perfect







share|cite|improve this answer












share|cite|improve this answer



share|cite|improve this answer










answered Aug 20 at 6:23









uniquesolution

8,251823




8,251823











  • Thanks a lot. This gives better and easy view on proving above.
    – Lahiru Dhananjaya
    Aug 20 at 6:31
















  • Thanks a lot. This gives better and easy view on proving above.
    – Lahiru Dhananjaya
    Aug 20 at 6:31















Thanks a lot. This gives better and easy view on proving above.
– Lahiru Dhananjaya
Aug 20 at 6:31




Thanks a lot. This gives better and easy view on proving above.
– Lahiru Dhananjaya
Aug 20 at 6:31