Is there a difference between these two notations, $f(x)$ and $f((x))$?
Clash Royale CLAN TAG#URR8PPP
up vote
0
down vote
favorite
I'm curious, are these two notations same or different? If they are different, can anybody point out difference?
That is, is $f(x)$ and $f((x))$ the same thing? Similarly, what about $f(x,y)$ and $f((x,y))$?
functions notation
add a comment |Â
up vote
0
down vote
favorite
I'm curious, are these two notations same or different? If they are different, can anybody point out difference?
That is, is $f(x)$ and $f((x))$ the same thing? Similarly, what about $f(x,y)$ and $f((x,y))$?
functions notation
Where have you encountered this notation?
â Elements in Space
Aug 20 at 11:58
@ElementsinSpace "I'm curious"... Idk if this is even a thing. But it wouldn't hurt to confirm it
â William
Aug 20 at 11:59
add a comment |Â
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I'm curious, are these two notations same or different? If they are different, can anybody point out difference?
That is, is $f(x)$ and $f((x))$ the same thing? Similarly, what about $f(x,y)$ and $f((x,y))$?
functions notation
I'm curious, are these two notations same or different? If they are different, can anybody point out difference?
That is, is $f(x)$ and $f((x))$ the same thing? Similarly, what about $f(x,y)$ and $f((x,y))$?
functions notation
edited Aug 21 at 12:47
John Ma
37.7k93669
37.7k93669
asked Aug 20 at 11:56
William
885314
885314
Where have you encountered this notation?
â Elements in Space
Aug 20 at 11:58
@ElementsinSpace "I'm curious"... Idk if this is even a thing. But it wouldn't hurt to confirm it
â William
Aug 20 at 11:59
add a comment |Â
Where have you encountered this notation?
â Elements in Space
Aug 20 at 11:58
@ElementsinSpace "I'm curious"... Idk if this is even a thing. But it wouldn't hurt to confirm it
â William
Aug 20 at 11:59
Where have you encountered this notation?
â Elements in Space
Aug 20 at 11:58
Where have you encountered this notation?
â Elements in Space
Aug 20 at 11:58
@ElementsinSpace "I'm curious"... Idk if this is even a thing. But it wouldn't hurt to confirm it
â William
Aug 20 at 11:59
@ElementsinSpace "I'm curious"... Idk if this is even a thing. But it wouldn't hurt to confirm it
â William
Aug 20 at 11:59
add a comment |Â
3 Answers
3
active
oldest
votes
up vote
3
down vote
In some cases parentheses alone are notation for a nontrivial operation.
For example, in ring theory $(x)$ can mean the ideal generated by $x$, which is different from $x$ itself. So if a function takes subsets of the ring as arguments, applying it to a principal ideal would be written $f((x))$.
For another example, $(x,y)$ may -- other than an ordered pair -- be the notation for an open interval of the real line. If $f$ is a function that takes values that are subsets of $mathbb R$, the right way to apply it to the open unit interval would be $f((0,1))$.
In other cases it might simply be a typo.
Note that even though programming languages generally allow you to write as many redundant parentheses as you want, this is avoided in mathematics. Parentheses that serve a reasonable purpose of disambiguating expressions are fair game, but an additional set of parentheses just for the heck of it will leave the reader confused whether something like the above examples is in place.
add a comment |Â
up vote
1
down vote
I have not seen that notation and it seems it could be more interpretable in the world of programming.
Then, they are not the same. $f(x,y)$ is a function of $2$ variables and $f((x,y))$ is a function of $1$ variable that is a $2$-dimensional vector.
I suppose the same holds for the first example, so that $(x)$ is some kind of a natotion for $1$-dimensional vector.
add a comment |Â
up vote
1
down vote
$f(x)$ usually refers to a function of one single variable. For example $$f(x)=x^2$$ while in some scenarios $f((x))$ refers to a function of a vector or any other multi-dimension variable. In that case we have $(x)=(x_1,x_2,cdots ,x_n)$ where $x_i$s are all single variables. For example $$f((x))=x_1^2+cdots +x_n^2$$ generally such a notation relies on the question clarification since there are various cases to distinguish these notations.
add a comment |Â
3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
3
down vote
In some cases parentheses alone are notation for a nontrivial operation.
For example, in ring theory $(x)$ can mean the ideal generated by $x$, which is different from $x$ itself. So if a function takes subsets of the ring as arguments, applying it to a principal ideal would be written $f((x))$.
For another example, $(x,y)$ may -- other than an ordered pair -- be the notation for an open interval of the real line. If $f$ is a function that takes values that are subsets of $mathbb R$, the right way to apply it to the open unit interval would be $f((0,1))$.
In other cases it might simply be a typo.
Note that even though programming languages generally allow you to write as many redundant parentheses as you want, this is avoided in mathematics. Parentheses that serve a reasonable purpose of disambiguating expressions are fair game, but an additional set of parentheses just for the heck of it will leave the reader confused whether something like the above examples is in place.
add a comment |Â
up vote
3
down vote
In some cases parentheses alone are notation for a nontrivial operation.
For example, in ring theory $(x)$ can mean the ideal generated by $x$, which is different from $x$ itself. So if a function takes subsets of the ring as arguments, applying it to a principal ideal would be written $f((x))$.
For another example, $(x,y)$ may -- other than an ordered pair -- be the notation for an open interval of the real line. If $f$ is a function that takes values that are subsets of $mathbb R$, the right way to apply it to the open unit interval would be $f((0,1))$.
In other cases it might simply be a typo.
Note that even though programming languages generally allow you to write as many redundant parentheses as you want, this is avoided in mathematics. Parentheses that serve a reasonable purpose of disambiguating expressions are fair game, but an additional set of parentheses just for the heck of it will leave the reader confused whether something like the above examples is in place.
add a comment |Â
up vote
3
down vote
up vote
3
down vote
In some cases parentheses alone are notation for a nontrivial operation.
For example, in ring theory $(x)$ can mean the ideal generated by $x$, which is different from $x$ itself. So if a function takes subsets of the ring as arguments, applying it to a principal ideal would be written $f((x))$.
For another example, $(x,y)$ may -- other than an ordered pair -- be the notation for an open interval of the real line. If $f$ is a function that takes values that are subsets of $mathbb R$, the right way to apply it to the open unit interval would be $f((0,1))$.
In other cases it might simply be a typo.
Note that even though programming languages generally allow you to write as many redundant parentheses as you want, this is avoided in mathematics. Parentheses that serve a reasonable purpose of disambiguating expressions are fair game, but an additional set of parentheses just for the heck of it will leave the reader confused whether something like the above examples is in place.
In some cases parentheses alone are notation for a nontrivial operation.
For example, in ring theory $(x)$ can mean the ideal generated by $x$, which is different from $x$ itself. So if a function takes subsets of the ring as arguments, applying it to a principal ideal would be written $f((x))$.
For another example, $(x,y)$ may -- other than an ordered pair -- be the notation for an open interval of the real line. If $f$ is a function that takes values that are subsets of $mathbb R$, the right way to apply it to the open unit interval would be $f((0,1))$.
In other cases it might simply be a typo.
Note that even though programming languages generally allow you to write as many redundant parentheses as you want, this is avoided in mathematics. Parentheses that serve a reasonable purpose of disambiguating expressions are fair game, but an additional set of parentheses just for the heck of it will leave the reader confused whether something like the above examples is in place.
answered Aug 20 at 12:11
Henning Makholm
229k16295525
229k16295525
add a comment |Â
add a comment |Â
up vote
1
down vote
I have not seen that notation and it seems it could be more interpretable in the world of programming.
Then, they are not the same. $f(x,y)$ is a function of $2$ variables and $f((x,y))$ is a function of $1$ variable that is a $2$-dimensional vector.
I suppose the same holds for the first example, so that $(x)$ is some kind of a natotion for $1$-dimensional vector.
add a comment |Â
up vote
1
down vote
I have not seen that notation and it seems it could be more interpretable in the world of programming.
Then, they are not the same. $f(x,y)$ is a function of $2$ variables and $f((x,y))$ is a function of $1$ variable that is a $2$-dimensional vector.
I suppose the same holds for the first example, so that $(x)$ is some kind of a natotion for $1$-dimensional vector.
add a comment |Â
up vote
1
down vote
up vote
1
down vote
I have not seen that notation and it seems it could be more interpretable in the world of programming.
Then, they are not the same. $f(x,y)$ is a function of $2$ variables and $f((x,y))$ is a function of $1$ variable that is a $2$-dimensional vector.
I suppose the same holds for the first example, so that $(x)$ is some kind of a natotion for $1$-dimensional vector.
I have not seen that notation and it seems it could be more interpretable in the world of programming.
Then, they are not the same. $f(x,y)$ is a function of $2$ variables and $f((x,y))$ is a function of $1$ variable that is a $2$-dimensional vector.
I suppose the same holds for the first example, so that $(x)$ is some kind of a natotion for $1$-dimensional vector.
answered Aug 20 at 12:00
Sandro LovniÃÂki
1414
1414
add a comment |Â
add a comment |Â
up vote
1
down vote
$f(x)$ usually refers to a function of one single variable. For example $$f(x)=x^2$$ while in some scenarios $f((x))$ refers to a function of a vector or any other multi-dimension variable. In that case we have $(x)=(x_1,x_2,cdots ,x_n)$ where $x_i$s are all single variables. For example $$f((x))=x_1^2+cdots +x_n^2$$ generally such a notation relies on the question clarification since there are various cases to distinguish these notations.
add a comment |Â
up vote
1
down vote
$f(x)$ usually refers to a function of one single variable. For example $$f(x)=x^2$$ while in some scenarios $f((x))$ refers to a function of a vector or any other multi-dimension variable. In that case we have $(x)=(x_1,x_2,cdots ,x_n)$ where $x_i$s are all single variables. For example $$f((x))=x_1^2+cdots +x_n^2$$ generally such a notation relies on the question clarification since there are various cases to distinguish these notations.
add a comment |Â
up vote
1
down vote
up vote
1
down vote
$f(x)$ usually refers to a function of one single variable. For example $$f(x)=x^2$$ while in some scenarios $f((x))$ refers to a function of a vector or any other multi-dimension variable. In that case we have $(x)=(x_1,x_2,cdots ,x_n)$ where $x_i$s are all single variables. For example $$f((x))=x_1^2+cdots +x_n^2$$ generally such a notation relies on the question clarification since there are various cases to distinguish these notations.
$f(x)$ usually refers to a function of one single variable. For example $$f(x)=x^2$$ while in some scenarios $f((x))$ refers to a function of a vector or any other multi-dimension variable. In that case we have $(x)=(x_1,x_2,cdots ,x_n)$ where $x_i$s are all single variables. For example $$f((x))=x_1^2+cdots +x_n^2$$ generally such a notation relies on the question clarification since there are various cases to distinguish these notations.
answered Aug 20 at 12:02
Mostafa Ayaz
9,7483730
9,7483730
add a comment |Â
add a comment |Â
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f2888685%2fis-there-a-difference-between-these-two-notations-fx-and-fx%23new-answer', 'question_page');
);
Post as a guest
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Where have you encountered this notation?
â Elements in Space
Aug 20 at 11:58
@ElementsinSpace "I'm curious"... Idk if this is even a thing. But it wouldn't hurt to confirm it
â William
Aug 20 at 11:59