How many different words can be formed from the letters of the word DAUGHTER when the letters T,A,D are never together.

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How many different words can be formed from the letters of the word DAUGHTER when the letters T,A,D are never together.







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    Please edit your question to show what you have attempted and explain where you are stuck so that you receive responses that address the specific difficulties you are encountering.
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How many different words can be formed from the letters of the word DAUGHTER when the letters T,A,D are never together.







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    Please edit your question to show what you have attempted and explain where you are stuck so that you receive responses that address the specific difficulties you are encountering.
    – N. F. Taussig
    Aug 20 at 10:10












up vote
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up vote
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favorite
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How many different words can be formed from the letters of the word DAUGHTER when the letters T,A,D are never together.







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How many different words can be formed from the letters of the word DAUGHTER when the letters T,A,D are never together.









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edited Aug 20 at 10:09









N. F. Taussig

38.7k93153




38.7k93153










asked Aug 20 at 9:46









jame samajoe

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569







  • 1




    Please edit your question to show what you have attempted and explain where you are stuck so that you receive responses that address the specific difficulties you are encountering.
    – N. F. Taussig
    Aug 20 at 10:10












  • 1




    Please edit your question to show what you have attempted and explain where you are stuck so that you receive responses that address the specific difficulties you are encountering.
    – N. F. Taussig
    Aug 20 at 10:10







1




1




Please edit your question to show what you have attempted and explain where you are stuck so that you receive responses that address the specific difficulties you are encountering.
– N. F. Taussig
Aug 20 at 10:10




Please edit your question to show what you have attempted and explain where you are stuck so that you receive responses that address the specific difficulties you are encountering.
– N. F. Taussig
Aug 20 at 10:10










2 Answers
2






active

oldest

votes

















up vote
1
down vote



accepted










I got another answer,it's pretty easy to know that the total of words you can form are $8!$, without any condition. Then, suppose the letters $TAD$ are together and they're one with the $5$ left. Then you have $6!$ ways to write words with $TAD$ together. This is because you can arrange $TAD$ on any of the six spaces, and then the other letters will have $5!$ ways to arrange, then $6*5!=6!$ $$(TAD)UGHER$$$$UG(TAD)HRE$$$$...$$



Remember that you can arrange $TAD$ as $TDA, ADT, ATD, DTA$ and $DAT$, so you have $6!*6$ words with the letters $T,A,D$ together. So you just need to take them away:
$$8!-6!*6=40320-4320=36000$$
Hence the answer is $36000$






share|cite|improve this answer



























    up vote
    2
    down vote













    It is obvious that



    -The words can be formed with that letters without any assumption are $8!$



    -The letters $T,A,D$ together, can be written with $6$ way $(TAD,TDA,ATD,...)$



    We can see that each one of the previous six possibilities can appear in $6$ position, such that the other $5$ letters can be arranged in $5!$ way , so all of them appear $6times 6 times 5!$ time, and the answer is ($8!-6times6!$)






    share|cite|improve this answer


















    • 2




      You forgot that every of those 36 times they appear, the other 5 letters can be arranged too
      – cptnSonoda
      Aug 21 at 18:23










    • @cptnSonoda thank you, I have fixed it.
      – The_lost
      Aug 22 at 0:06










    Your Answer




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    2 Answers
    2






    active

    oldest

    votes








    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes








    up vote
    1
    down vote



    accepted










    I got another answer,it's pretty easy to know that the total of words you can form are $8!$, without any condition. Then, suppose the letters $TAD$ are together and they're one with the $5$ left. Then you have $6!$ ways to write words with $TAD$ together. This is because you can arrange $TAD$ on any of the six spaces, and then the other letters will have $5!$ ways to arrange, then $6*5!=6!$ $$(TAD)UGHER$$$$UG(TAD)HRE$$$$...$$



    Remember that you can arrange $TAD$ as $TDA, ADT, ATD, DTA$ and $DAT$, so you have $6!*6$ words with the letters $T,A,D$ together. So you just need to take them away:
    $$8!-6!*6=40320-4320=36000$$
    Hence the answer is $36000$






    share|cite|improve this answer
























      up vote
      1
      down vote



      accepted










      I got another answer,it's pretty easy to know that the total of words you can form are $8!$, without any condition. Then, suppose the letters $TAD$ are together and they're one with the $5$ left. Then you have $6!$ ways to write words with $TAD$ together. This is because you can arrange $TAD$ on any of the six spaces, and then the other letters will have $5!$ ways to arrange, then $6*5!=6!$ $$(TAD)UGHER$$$$UG(TAD)HRE$$$$...$$



      Remember that you can arrange $TAD$ as $TDA, ADT, ATD, DTA$ and $DAT$, so you have $6!*6$ words with the letters $T,A,D$ together. So you just need to take them away:
      $$8!-6!*6=40320-4320=36000$$
      Hence the answer is $36000$






      share|cite|improve this answer






















        up vote
        1
        down vote



        accepted







        up vote
        1
        down vote



        accepted






        I got another answer,it's pretty easy to know that the total of words you can form are $8!$, without any condition. Then, suppose the letters $TAD$ are together and they're one with the $5$ left. Then you have $6!$ ways to write words with $TAD$ together. This is because you can arrange $TAD$ on any of the six spaces, and then the other letters will have $5!$ ways to arrange, then $6*5!=6!$ $$(TAD)UGHER$$$$UG(TAD)HRE$$$$...$$



        Remember that you can arrange $TAD$ as $TDA, ADT, ATD, DTA$ and $DAT$, so you have $6!*6$ words with the letters $T,A,D$ together. So you just need to take them away:
        $$8!-6!*6=40320-4320=36000$$
        Hence the answer is $36000$






        share|cite|improve this answer












        I got another answer,it's pretty easy to know that the total of words you can form are $8!$, without any condition. Then, suppose the letters $TAD$ are together and they're one with the $5$ left. Then you have $6!$ ways to write words with $TAD$ together. This is because you can arrange $TAD$ on any of the six spaces, and then the other letters will have $5!$ ways to arrange, then $6*5!=6!$ $$(TAD)UGHER$$$$UG(TAD)HRE$$$$...$$



        Remember that you can arrange $TAD$ as $TDA, ADT, ATD, DTA$ and $DAT$, so you have $6!*6$ words with the letters $T,A,D$ together. So you just need to take them away:
        $$8!-6!*6=40320-4320=36000$$
        Hence the answer is $36000$







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered Aug 21 at 18:21









        cptnSonoda

        204110




        204110




















            up vote
            2
            down vote













            It is obvious that



            -The words can be formed with that letters without any assumption are $8!$



            -The letters $T,A,D$ together, can be written with $6$ way $(TAD,TDA,ATD,...)$



            We can see that each one of the previous six possibilities can appear in $6$ position, such that the other $5$ letters can be arranged in $5!$ way , so all of them appear $6times 6 times 5!$ time, and the answer is ($8!-6times6!$)






            share|cite|improve this answer


















            • 2




              You forgot that every of those 36 times they appear, the other 5 letters can be arranged too
              – cptnSonoda
              Aug 21 at 18:23










            • @cptnSonoda thank you, I have fixed it.
              – The_lost
              Aug 22 at 0:06














            up vote
            2
            down vote













            It is obvious that



            -The words can be formed with that letters without any assumption are $8!$



            -The letters $T,A,D$ together, can be written with $6$ way $(TAD,TDA,ATD,...)$



            We can see that each one of the previous six possibilities can appear in $6$ position, such that the other $5$ letters can be arranged in $5!$ way , so all of them appear $6times 6 times 5!$ time, and the answer is ($8!-6times6!$)






            share|cite|improve this answer


















            • 2




              You forgot that every of those 36 times they appear, the other 5 letters can be arranged too
              – cptnSonoda
              Aug 21 at 18:23










            • @cptnSonoda thank you, I have fixed it.
              – The_lost
              Aug 22 at 0:06












            up vote
            2
            down vote










            up vote
            2
            down vote









            It is obvious that



            -The words can be formed with that letters without any assumption are $8!$



            -The letters $T,A,D$ together, can be written with $6$ way $(TAD,TDA,ATD,...)$



            We can see that each one of the previous six possibilities can appear in $6$ position, such that the other $5$ letters can be arranged in $5!$ way , so all of them appear $6times 6 times 5!$ time, and the answer is ($8!-6times6!$)






            share|cite|improve this answer














            It is obvious that



            -The words can be formed with that letters without any assumption are $8!$



            -The letters $T,A,D$ together, can be written with $6$ way $(TAD,TDA,ATD,...)$



            We can see that each one of the previous six possibilities can appear in $6$ position, such that the other $5$ letters can be arranged in $5!$ way , so all of them appear $6times 6 times 5!$ time, and the answer is ($8!-6times6!$)







            share|cite|improve this answer














            share|cite|improve this answer



            share|cite|improve this answer








            edited Aug 22 at 0:05

























            answered Aug 20 at 10:18









            The_lost

            1,067318




            1,067318







            • 2




              You forgot that every of those 36 times they appear, the other 5 letters can be arranged too
              – cptnSonoda
              Aug 21 at 18:23










            • @cptnSonoda thank you, I have fixed it.
              – The_lost
              Aug 22 at 0:06












            • 2




              You forgot that every of those 36 times they appear, the other 5 letters can be arranged too
              – cptnSonoda
              Aug 21 at 18:23










            • @cptnSonoda thank you, I have fixed it.
              – The_lost
              Aug 22 at 0:06







            2




            2




            You forgot that every of those 36 times they appear, the other 5 letters can be arranged too
            – cptnSonoda
            Aug 21 at 18:23




            You forgot that every of those 36 times they appear, the other 5 letters can be arranged too
            – cptnSonoda
            Aug 21 at 18:23












            @cptnSonoda thank you, I have fixed it.
            – The_lost
            Aug 22 at 0:06




            @cptnSonoda thank you, I have fixed it.
            – The_lost
            Aug 22 at 0:06












             

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