p is prime and a group of 2p - 2 number
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This is a question that I see in a book. I translate it and ask it here. my Mathematical ability is not good.
if $p$ is prime, we have $2p-2$ natural number that if we choose any $p$ of them (call S), the sum of numbers in S can not be divisible by $p$. Is below statement true?
for each $1 le i le p -1$ we have $p - 1$ numbers which sum of them is M and $Mequiv ipmod p$
Thanks.
calculus
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up vote
2
down vote
favorite
This is a question that I see in a book. I translate it and ask it here. my Mathematical ability is not good.
if $p$ is prime, we have $2p-2$ natural number that if we choose any $p$ of them (call S), the sum of numbers in S can not be divisible by $p$. Is below statement true?
for each $1 le i le p -1$ we have $p - 1$ numbers which sum of them is M and $Mequiv ipmod p$
Thanks.
calculus
add a comment |Â
up vote
2
down vote
favorite
up vote
2
down vote
favorite
This is a question that I see in a book. I translate it and ask it here. my Mathematical ability is not good.
if $p$ is prime, we have $2p-2$ natural number that if we choose any $p$ of them (call S), the sum of numbers in S can not be divisible by $p$. Is below statement true?
for each $1 le i le p -1$ we have $p - 1$ numbers which sum of them is M and $Mequiv ipmod p$
Thanks.
calculus
This is a question that I see in a book. I translate it and ask it here. my Mathematical ability is not good.
if $p$ is prime, we have $2p-2$ natural number that if we choose any $p$ of them (call S), the sum of numbers in S can not be divisible by $p$. Is below statement true?
for each $1 le i le p -1$ we have $p - 1$ numbers which sum of them is M and $Mequiv ipmod p$
Thanks.
calculus
asked Aug 12 at 5:44
Amin Borjian
906
906
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