Insect Pest Population Growth Problem
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An insect pest population doubles every 18 days. If an insecticide kills 90% of the insects, how often should it be applied to keep in insect population in check?
I tried using this exponential growth/decay model: $$A = Pleft(fracA_1P_1right)^t/t_1$$
where $P_1$ (initial value), $A_1$ (new value), $t$ (time period).
However, would this be the proper way to do it? I'm not quite sure how to interpret (and thus solve) this problem.
algebra-precalculus exponential-function
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up vote
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down vote
favorite
An insect pest population doubles every 18 days. If an insecticide kills 90% of the insects, how often should it be applied to keep in insect population in check?
I tried using this exponential growth/decay model: $$A = Pleft(fracA_1P_1right)^t/t_1$$
where $P_1$ (initial value), $A_1$ (new value), $t$ (time period).
However, would this be the proper way to do it? I'm not quite sure how to interpret (and thus solve) this problem.
algebra-precalculus exponential-function
You need to fix the equation. I presume $A_1, P_1$ are initial values and $A$ the final value. $P$ and $t_1$ are not defined, while $t$ is the time period of what?
â herb steinberg
Aug 12 at 3:32
I think this is poorly worded question, to answer you need to decide exactly what "keep in insect population in check" means
â WW1
Aug 12 at 3:39
add a comment |Â
up vote
0
down vote
favorite
up vote
0
down vote
favorite
An insect pest population doubles every 18 days. If an insecticide kills 90% of the insects, how often should it be applied to keep in insect population in check?
I tried using this exponential growth/decay model: $$A = Pleft(fracA_1P_1right)^t/t_1$$
where $P_1$ (initial value), $A_1$ (new value), $t$ (time period).
However, would this be the proper way to do it? I'm not quite sure how to interpret (and thus solve) this problem.
algebra-precalculus exponential-function
An insect pest population doubles every 18 days. If an insecticide kills 90% of the insects, how often should it be applied to keep in insect population in check?
I tried using this exponential growth/decay model: $$A = Pleft(fracA_1P_1right)^t/t_1$$
where $P_1$ (initial value), $A_1$ (new value), $t$ (time period).
However, would this be the proper way to do it? I'm not quite sure how to interpret (and thus solve) this problem.
algebra-precalculus exponential-function
edited Aug 12 at 3:10
Szeto
4,2411521
4,2411521
asked Aug 12 at 3:05
Pedro Castorena
164
164
You need to fix the equation. I presume $A_1, P_1$ are initial values and $A$ the final value. $P$ and $t_1$ are not defined, while $t$ is the time period of what?
â herb steinberg
Aug 12 at 3:32
I think this is poorly worded question, to answer you need to decide exactly what "keep in insect population in check" means
â WW1
Aug 12 at 3:39
add a comment |Â
You need to fix the equation. I presume $A_1, P_1$ are initial values and $A$ the final value. $P$ and $t_1$ are not defined, while $t$ is the time period of what?
â herb steinberg
Aug 12 at 3:32
I think this is poorly worded question, to answer you need to decide exactly what "keep in insect population in check" means
â WW1
Aug 12 at 3:39
You need to fix the equation. I presume $A_1, P_1$ are initial values and $A$ the final value. $P$ and $t_1$ are not defined, while $t$ is the time period of what?
â herb steinberg
Aug 12 at 3:32
You need to fix the equation. I presume $A_1, P_1$ are initial values and $A$ the final value. $P$ and $t_1$ are not defined, while $t$ is the time period of what?
â herb steinberg
Aug 12 at 3:32
I think this is poorly worded question, to answer you need to decide exactly what "keep in insect population in check" means
â WW1
Aug 12 at 3:39
I think this is poorly worded question, to answer you need to decide exactly what "keep in insect population in check" means
â WW1
Aug 12 at 3:39
add a comment |Â
1 Answer
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So you have an insect population that doubles every 18 days. Let's call it $m_0$. After 18 days, you will have $2m_0$, after another 18 days, you will have $4m_0$. The idea is that you model this growth with a function:
$f(t) = textsomething$,
but we know some values of this function:
$f(0 textdays) = m_0,$
$f(18 textdays) = 2m_0,$
$f(36 textdays) = 4m_0,$
$f(54 textdays) = 8m_0,$ and so on.
We know the form of the function:
$f(t textdays) = m_0 cdot n^t.$
To find $n$, we do:
$f(18 textdays) = 2m_0 = m_0 cdot n^18 textdays,$
$n=2^1/18 textdays.$
Our function is:
$f(t textdays) = m_0 cdot 2^t/18 textdays.$
Remember that the insect population is always growing, and it will hit the desired number of insects (or a critical number of insects) at $t_c$ (critical time). Let's call that critical number of insects $m_c$. Then you apply the insecticide and now the insect population is:
$$f(t_c)=m_0 cdot 2^t_c/18 = 0.1m_c$$
Then you have a new function of insect population:
$f(t textdays) = 0.1m_c cdot 2^t/18 textdays.$
Since the question is "how often should it be applied to keep the insect population in check?", the insect population will grow and it will hit the desired number of insects, $m_c$ after some time $t$, we want to know that time (in days):
$0.1m_c cdot 2^t/18 = m_c,$
and the result is (solve for $t$!):
$t=59.79 textdays.$
add a comment |Â
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
So you have an insect population that doubles every 18 days. Let's call it $m_0$. After 18 days, you will have $2m_0$, after another 18 days, you will have $4m_0$. The idea is that you model this growth with a function:
$f(t) = textsomething$,
but we know some values of this function:
$f(0 textdays) = m_0,$
$f(18 textdays) = 2m_0,$
$f(36 textdays) = 4m_0,$
$f(54 textdays) = 8m_0,$ and so on.
We know the form of the function:
$f(t textdays) = m_0 cdot n^t.$
To find $n$, we do:
$f(18 textdays) = 2m_0 = m_0 cdot n^18 textdays,$
$n=2^1/18 textdays.$
Our function is:
$f(t textdays) = m_0 cdot 2^t/18 textdays.$
Remember that the insect population is always growing, and it will hit the desired number of insects (or a critical number of insects) at $t_c$ (critical time). Let's call that critical number of insects $m_c$. Then you apply the insecticide and now the insect population is:
$$f(t_c)=m_0 cdot 2^t_c/18 = 0.1m_c$$
Then you have a new function of insect population:
$f(t textdays) = 0.1m_c cdot 2^t/18 textdays.$
Since the question is "how often should it be applied to keep the insect population in check?", the insect population will grow and it will hit the desired number of insects, $m_c$ after some time $t$, we want to know that time (in days):
$0.1m_c cdot 2^t/18 = m_c,$
and the result is (solve for $t$!):
$t=59.79 textdays.$
add a comment |Â
up vote
0
down vote
So you have an insect population that doubles every 18 days. Let's call it $m_0$. After 18 days, you will have $2m_0$, after another 18 days, you will have $4m_0$. The idea is that you model this growth with a function:
$f(t) = textsomething$,
but we know some values of this function:
$f(0 textdays) = m_0,$
$f(18 textdays) = 2m_0,$
$f(36 textdays) = 4m_0,$
$f(54 textdays) = 8m_0,$ and so on.
We know the form of the function:
$f(t textdays) = m_0 cdot n^t.$
To find $n$, we do:
$f(18 textdays) = 2m_0 = m_0 cdot n^18 textdays,$
$n=2^1/18 textdays.$
Our function is:
$f(t textdays) = m_0 cdot 2^t/18 textdays.$
Remember that the insect population is always growing, and it will hit the desired number of insects (or a critical number of insects) at $t_c$ (critical time). Let's call that critical number of insects $m_c$. Then you apply the insecticide and now the insect population is:
$$f(t_c)=m_0 cdot 2^t_c/18 = 0.1m_c$$
Then you have a new function of insect population:
$f(t textdays) = 0.1m_c cdot 2^t/18 textdays.$
Since the question is "how often should it be applied to keep the insect population in check?", the insect population will grow and it will hit the desired number of insects, $m_c$ after some time $t$, we want to know that time (in days):
$0.1m_c cdot 2^t/18 = m_c,$
and the result is (solve for $t$!):
$t=59.79 textdays.$
add a comment |Â
up vote
0
down vote
up vote
0
down vote
So you have an insect population that doubles every 18 days. Let's call it $m_0$. After 18 days, you will have $2m_0$, after another 18 days, you will have $4m_0$. The idea is that you model this growth with a function:
$f(t) = textsomething$,
but we know some values of this function:
$f(0 textdays) = m_0,$
$f(18 textdays) = 2m_0,$
$f(36 textdays) = 4m_0,$
$f(54 textdays) = 8m_0,$ and so on.
We know the form of the function:
$f(t textdays) = m_0 cdot n^t.$
To find $n$, we do:
$f(18 textdays) = 2m_0 = m_0 cdot n^18 textdays,$
$n=2^1/18 textdays.$
Our function is:
$f(t textdays) = m_0 cdot 2^t/18 textdays.$
Remember that the insect population is always growing, and it will hit the desired number of insects (or a critical number of insects) at $t_c$ (critical time). Let's call that critical number of insects $m_c$. Then you apply the insecticide and now the insect population is:
$$f(t_c)=m_0 cdot 2^t_c/18 = 0.1m_c$$
Then you have a new function of insect population:
$f(t textdays) = 0.1m_c cdot 2^t/18 textdays.$
Since the question is "how often should it be applied to keep the insect population in check?", the insect population will grow and it will hit the desired number of insects, $m_c$ after some time $t$, we want to know that time (in days):
$0.1m_c cdot 2^t/18 = m_c,$
and the result is (solve for $t$!):
$t=59.79 textdays.$
So you have an insect population that doubles every 18 days. Let's call it $m_0$. After 18 days, you will have $2m_0$, after another 18 days, you will have $4m_0$. The idea is that you model this growth with a function:
$f(t) = textsomething$,
but we know some values of this function:
$f(0 textdays) = m_0,$
$f(18 textdays) = 2m_0,$
$f(36 textdays) = 4m_0,$
$f(54 textdays) = 8m_0,$ and so on.
We know the form of the function:
$f(t textdays) = m_0 cdot n^t.$
To find $n$, we do:
$f(18 textdays) = 2m_0 = m_0 cdot n^18 textdays,$
$n=2^1/18 textdays.$
Our function is:
$f(t textdays) = m_0 cdot 2^t/18 textdays.$
Remember that the insect population is always growing, and it will hit the desired number of insects (or a critical number of insects) at $t_c$ (critical time). Let's call that critical number of insects $m_c$. Then you apply the insecticide and now the insect population is:
$$f(t_c)=m_0 cdot 2^t_c/18 = 0.1m_c$$
Then you have a new function of insect population:
$f(t textdays) = 0.1m_c cdot 2^t/18 textdays.$
Since the question is "how often should it be applied to keep the insect population in check?", the insect population will grow and it will hit the desired number of insects, $m_c$ after some time $t$, we want to know that time (in days):
$0.1m_c cdot 2^t/18 = m_c,$
and the result is (solve for $t$!):
$t=59.79 textdays.$
edited Aug 13 at 4:05
answered Aug 12 at 5:03
David
592310
592310
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You need to fix the equation. I presume $A_1, P_1$ are initial values and $A$ the final value. $P$ and $t_1$ are not defined, while $t$ is the time period of what?
â herb steinberg
Aug 12 at 3:32
I think this is poorly worded question, to answer you need to decide exactly what "keep in insect population in check" means
â WW1
Aug 12 at 3:39