Insect Pest Population Growth Problem

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An insect pest population doubles every 18 days. If an insecticide kills 90% of the insects, how often should it be applied to keep in insect population in check?



I tried using this exponential growth/decay model: $$A = Pleft(fracA_1P_1right)^t/t_1$$
where $P_1$ (initial value), $A_1$ (new value), $t$ (time period).



However, would this be the proper way to do it? I'm not quite sure how to interpret (and thus solve) this problem.







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  • You need to fix the equation. I presume $A_1, P_1$ are initial values and $A$ the final value. $P$ and $t_1$ are not defined, while $t$ is the time period of what?
    – herb steinberg
    Aug 12 at 3:32










  • I think this is poorly worded question, to answer you need to decide exactly what "keep in insect population in check" means
    – WW1
    Aug 12 at 3:39














up vote
0
down vote

favorite












An insect pest population doubles every 18 days. If an insecticide kills 90% of the insects, how often should it be applied to keep in insect population in check?



I tried using this exponential growth/decay model: $$A = Pleft(fracA_1P_1right)^t/t_1$$
where $P_1$ (initial value), $A_1$ (new value), $t$ (time period).



However, would this be the proper way to do it? I'm not quite sure how to interpret (and thus solve) this problem.







share|cite|improve this question






















  • You need to fix the equation. I presume $A_1, P_1$ are initial values and $A$ the final value. $P$ and $t_1$ are not defined, while $t$ is the time period of what?
    – herb steinberg
    Aug 12 at 3:32










  • I think this is poorly worded question, to answer you need to decide exactly what "keep in insect population in check" means
    – WW1
    Aug 12 at 3:39












up vote
0
down vote

favorite









up vote
0
down vote

favorite











An insect pest population doubles every 18 days. If an insecticide kills 90% of the insects, how often should it be applied to keep in insect population in check?



I tried using this exponential growth/decay model: $$A = Pleft(fracA_1P_1right)^t/t_1$$
where $P_1$ (initial value), $A_1$ (new value), $t$ (time period).



However, would this be the proper way to do it? I'm not quite sure how to interpret (and thus solve) this problem.







share|cite|improve this question














An insect pest population doubles every 18 days. If an insecticide kills 90% of the insects, how often should it be applied to keep in insect population in check?



I tried using this exponential growth/decay model: $$A = Pleft(fracA_1P_1right)^t/t_1$$
where $P_1$ (initial value), $A_1$ (new value), $t$ (time period).



However, would this be the proper way to do it? I'm not quite sure how to interpret (and thus solve) this problem.









share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Aug 12 at 3:10









Szeto

4,2411521




4,2411521










asked Aug 12 at 3:05









Pedro Castorena

164




164











  • You need to fix the equation. I presume $A_1, P_1$ are initial values and $A$ the final value. $P$ and $t_1$ are not defined, while $t$ is the time period of what?
    – herb steinberg
    Aug 12 at 3:32










  • I think this is poorly worded question, to answer you need to decide exactly what "keep in insect population in check" means
    – WW1
    Aug 12 at 3:39
















  • You need to fix the equation. I presume $A_1, P_1$ are initial values and $A$ the final value. $P$ and $t_1$ are not defined, while $t$ is the time period of what?
    – herb steinberg
    Aug 12 at 3:32










  • I think this is poorly worded question, to answer you need to decide exactly what "keep in insect population in check" means
    – WW1
    Aug 12 at 3:39















You need to fix the equation. I presume $A_1, P_1$ are initial values and $A$ the final value. $P$ and $t_1$ are not defined, while $t$ is the time period of what?
– herb steinberg
Aug 12 at 3:32




You need to fix the equation. I presume $A_1, P_1$ are initial values and $A$ the final value. $P$ and $t_1$ are not defined, while $t$ is the time period of what?
– herb steinberg
Aug 12 at 3:32












I think this is poorly worded question, to answer you need to decide exactly what "keep in insect population in check" means
– WW1
Aug 12 at 3:39




I think this is poorly worded question, to answer you need to decide exactly what "keep in insect population in check" means
– WW1
Aug 12 at 3:39










1 Answer
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So you have an insect population that doubles every 18 days. Let's call it $m_0$. After 18 days, you will have $2m_0$, after another 18 days, you will have $4m_0$. The idea is that you model this growth with a function:



$f(t) = textsomething$,



but we know some values of this function:



$f(0 textdays) = m_0,$



$f(18 textdays) = 2m_0,$



$f(36 textdays) = 4m_0,$



$f(54 textdays) = 8m_0,$ and so on.



We know the form of the function:



$f(t textdays) = m_0 cdot n^t.$



To find $n$, we do:



$f(18 textdays) = 2m_0 = m_0 cdot n^18 textdays,$



$n=2^1/18 textdays.$



Our function is:



$f(t textdays) = m_0 cdot 2^t/18 textdays.$



Remember that the insect population is always growing, and it will hit the desired number of insects (or a critical number of insects) at $t_c$ (critical time). Let's call that critical number of insects $m_c$. Then you apply the insecticide and now the insect population is:



$$f(t_c)=m_0 cdot 2^t_c/18 = 0.1m_c$$



Then you have a new function of insect population:



$f(t textdays) = 0.1m_c cdot 2^t/18 textdays.$



Since the question is "how often should it be applied to keep the insect population in check?", the insect population will grow and it will hit the desired number of insects, $m_c$ after some time $t$, we want to know that time (in days):



$0.1m_c cdot 2^t/18 = m_c,$



and the result is (solve for $t$!):



$t=59.79 textdays.$






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    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

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    active

    oldest

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    active

    oldest

    votes








    up vote
    0
    down vote













    So you have an insect population that doubles every 18 days. Let's call it $m_0$. After 18 days, you will have $2m_0$, after another 18 days, you will have $4m_0$. The idea is that you model this growth with a function:



    $f(t) = textsomething$,



    but we know some values of this function:



    $f(0 textdays) = m_0,$



    $f(18 textdays) = 2m_0,$



    $f(36 textdays) = 4m_0,$



    $f(54 textdays) = 8m_0,$ and so on.



    We know the form of the function:



    $f(t textdays) = m_0 cdot n^t.$



    To find $n$, we do:



    $f(18 textdays) = 2m_0 = m_0 cdot n^18 textdays,$



    $n=2^1/18 textdays.$



    Our function is:



    $f(t textdays) = m_0 cdot 2^t/18 textdays.$



    Remember that the insect population is always growing, and it will hit the desired number of insects (or a critical number of insects) at $t_c$ (critical time). Let's call that critical number of insects $m_c$. Then you apply the insecticide and now the insect population is:



    $$f(t_c)=m_0 cdot 2^t_c/18 = 0.1m_c$$



    Then you have a new function of insect population:



    $f(t textdays) = 0.1m_c cdot 2^t/18 textdays.$



    Since the question is "how often should it be applied to keep the insect population in check?", the insect population will grow and it will hit the desired number of insects, $m_c$ after some time $t$, we want to know that time (in days):



    $0.1m_c cdot 2^t/18 = m_c,$



    and the result is (solve for $t$!):



    $t=59.79 textdays.$






    share|cite|improve this answer


























      up vote
      0
      down vote













      So you have an insect population that doubles every 18 days. Let's call it $m_0$. After 18 days, you will have $2m_0$, after another 18 days, you will have $4m_0$. The idea is that you model this growth with a function:



      $f(t) = textsomething$,



      but we know some values of this function:



      $f(0 textdays) = m_0,$



      $f(18 textdays) = 2m_0,$



      $f(36 textdays) = 4m_0,$



      $f(54 textdays) = 8m_0,$ and so on.



      We know the form of the function:



      $f(t textdays) = m_0 cdot n^t.$



      To find $n$, we do:



      $f(18 textdays) = 2m_0 = m_0 cdot n^18 textdays,$



      $n=2^1/18 textdays.$



      Our function is:



      $f(t textdays) = m_0 cdot 2^t/18 textdays.$



      Remember that the insect population is always growing, and it will hit the desired number of insects (or a critical number of insects) at $t_c$ (critical time). Let's call that critical number of insects $m_c$. Then you apply the insecticide and now the insect population is:



      $$f(t_c)=m_0 cdot 2^t_c/18 = 0.1m_c$$



      Then you have a new function of insect population:



      $f(t textdays) = 0.1m_c cdot 2^t/18 textdays.$



      Since the question is "how often should it be applied to keep the insect population in check?", the insect population will grow and it will hit the desired number of insects, $m_c$ after some time $t$, we want to know that time (in days):



      $0.1m_c cdot 2^t/18 = m_c,$



      and the result is (solve for $t$!):



      $t=59.79 textdays.$






      share|cite|improve this answer
























        up vote
        0
        down vote










        up vote
        0
        down vote









        So you have an insect population that doubles every 18 days. Let's call it $m_0$. After 18 days, you will have $2m_0$, after another 18 days, you will have $4m_0$. The idea is that you model this growth with a function:



        $f(t) = textsomething$,



        but we know some values of this function:



        $f(0 textdays) = m_0,$



        $f(18 textdays) = 2m_0,$



        $f(36 textdays) = 4m_0,$



        $f(54 textdays) = 8m_0,$ and so on.



        We know the form of the function:



        $f(t textdays) = m_0 cdot n^t.$



        To find $n$, we do:



        $f(18 textdays) = 2m_0 = m_0 cdot n^18 textdays,$



        $n=2^1/18 textdays.$



        Our function is:



        $f(t textdays) = m_0 cdot 2^t/18 textdays.$



        Remember that the insect population is always growing, and it will hit the desired number of insects (or a critical number of insects) at $t_c$ (critical time). Let's call that critical number of insects $m_c$. Then you apply the insecticide and now the insect population is:



        $$f(t_c)=m_0 cdot 2^t_c/18 = 0.1m_c$$



        Then you have a new function of insect population:



        $f(t textdays) = 0.1m_c cdot 2^t/18 textdays.$



        Since the question is "how often should it be applied to keep the insect population in check?", the insect population will grow and it will hit the desired number of insects, $m_c$ after some time $t$, we want to know that time (in days):



        $0.1m_c cdot 2^t/18 = m_c,$



        and the result is (solve for $t$!):



        $t=59.79 textdays.$






        share|cite|improve this answer














        So you have an insect population that doubles every 18 days. Let's call it $m_0$. After 18 days, you will have $2m_0$, after another 18 days, you will have $4m_0$. The idea is that you model this growth with a function:



        $f(t) = textsomething$,



        but we know some values of this function:



        $f(0 textdays) = m_0,$



        $f(18 textdays) = 2m_0,$



        $f(36 textdays) = 4m_0,$



        $f(54 textdays) = 8m_0,$ and so on.



        We know the form of the function:



        $f(t textdays) = m_0 cdot n^t.$



        To find $n$, we do:



        $f(18 textdays) = 2m_0 = m_0 cdot n^18 textdays,$



        $n=2^1/18 textdays.$



        Our function is:



        $f(t textdays) = m_0 cdot 2^t/18 textdays.$



        Remember that the insect population is always growing, and it will hit the desired number of insects (or a critical number of insects) at $t_c$ (critical time). Let's call that critical number of insects $m_c$. Then you apply the insecticide and now the insect population is:



        $$f(t_c)=m_0 cdot 2^t_c/18 = 0.1m_c$$



        Then you have a new function of insect population:



        $f(t textdays) = 0.1m_c cdot 2^t/18 textdays.$



        Since the question is "how often should it be applied to keep the insect population in check?", the insect population will grow and it will hit the desired number of insects, $m_c$ after some time $t$, we want to know that time (in days):



        $0.1m_c cdot 2^t/18 = m_c,$



        and the result is (solve for $t$!):



        $t=59.79 textdays.$







        share|cite|improve this answer














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        edited Aug 13 at 4:05

























        answered Aug 12 at 5:03









        David

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