Why the value of this kind of sequence always get bigger and then smaller

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I tried to use $1$, $2$ and $3$ into this formula, and for all the answer will get bigger first than smaller. I want to know the reason for it.



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  • The sequences are recursive sequences, as you might see. For example, in the first case, $$ x_n+1 = 1 + frac1x_n qquad textwith x_0 = 1 $$ So which one is bigger, $x_n$ or $x_n+1$? The limit of the sequence is $$ lim_x to infty x_n = frac1+sqrt52 = phi $$ and if $x_n < phi Rightarrow x_n+1 > phi$ etc ... You can see this by comparing the functions $$ f_1(x) = x $$ and $$ f_2(x) = 1+ frac1x $$ and figuring out when $f_1(x) > f_2(x)$.
    – Matti P.
    Sep 7 at 10:00











  • The sequence contains the convergents of the (simple) continued fraction of the golden ratio $ varphi $. Such a sequence always alternates between values above and values below the given number.
    – Peter
    Sep 7 at 11:08















up vote
0
down vote

favorite












I tried to use $1$, $2$ and $3$ into this formula, and for all the answer will get bigger first than smaller. I want to know the reason for it.



enter image description here










share|cite|improve this question























  • The sequences are recursive sequences, as you might see. For example, in the first case, $$ x_n+1 = 1 + frac1x_n qquad textwith x_0 = 1 $$ So which one is bigger, $x_n$ or $x_n+1$? The limit of the sequence is $$ lim_x to infty x_n = frac1+sqrt52 = phi $$ and if $x_n < phi Rightarrow x_n+1 > phi$ etc ... You can see this by comparing the functions $$ f_1(x) = x $$ and $$ f_2(x) = 1+ frac1x $$ and figuring out when $f_1(x) > f_2(x)$.
    – Matti P.
    Sep 7 at 10:00











  • The sequence contains the convergents of the (simple) continued fraction of the golden ratio $ varphi $. Such a sequence always alternates between values above and values below the given number.
    – Peter
    Sep 7 at 11:08













up vote
0
down vote

favorite









up vote
0
down vote

favorite











I tried to use $1$, $2$ and $3$ into this formula, and for all the answer will get bigger first than smaller. I want to know the reason for it.



enter image description here










share|cite|improve this question















I tried to use $1$, $2$ and $3$ into this formula, and for all the answer will get bigger first than smaller. I want to know the reason for it.



enter image description here







sequences-and-series






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edited Sep 7 at 10:30









user220178

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1768










asked Sep 7 at 9:40









teng

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42











  • The sequences are recursive sequences, as you might see. For example, in the first case, $$ x_n+1 = 1 + frac1x_n qquad textwith x_0 = 1 $$ So which one is bigger, $x_n$ or $x_n+1$? The limit of the sequence is $$ lim_x to infty x_n = frac1+sqrt52 = phi $$ and if $x_n < phi Rightarrow x_n+1 > phi$ etc ... You can see this by comparing the functions $$ f_1(x) = x $$ and $$ f_2(x) = 1+ frac1x $$ and figuring out when $f_1(x) > f_2(x)$.
    – Matti P.
    Sep 7 at 10:00











  • The sequence contains the convergents of the (simple) continued fraction of the golden ratio $ varphi $. Such a sequence always alternates between values above and values below the given number.
    – Peter
    Sep 7 at 11:08

















  • The sequences are recursive sequences, as you might see. For example, in the first case, $$ x_n+1 = 1 + frac1x_n qquad textwith x_0 = 1 $$ So which one is bigger, $x_n$ or $x_n+1$? The limit of the sequence is $$ lim_x to infty x_n = frac1+sqrt52 = phi $$ and if $x_n < phi Rightarrow x_n+1 > phi$ etc ... You can see this by comparing the functions $$ f_1(x) = x $$ and $$ f_2(x) = 1+ frac1x $$ and figuring out when $f_1(x) > f_2(x)$.
    – Matti P.
    Sep 7 at 10:00











  • The sequence contains the convergents of the (simple) continued fraction of the golden ratio $ varphi $. Such a sequence always alternates between values above and values below the given number.
    – Peter
    Sep 7 at 11:08
















The sequences are recursive sequences, as you might see. For example, in the first case, $$ x_n+1 = 1 + frac1x_n qquad textwith x_0 = 1 $$ So which one is bigger, $x_n$ or $x_n+1$? The limit of the sequence is $$ lim_x to infty x_n = frac1+sqrt52 = phi $$ and if $x_n < phi Rightarrow x_n+1 > phi$ etc ... You can see this by comparing the functions $$ f_1(x) = x $$ and $$ f_2(x) = 1+ frac1x $$ and figuring out when $f_1(x) > f_2(x)$.
– Matti P.
Sep 7 at 10:00





The sequences are recursive sequences, as you might see. For example, in the first case, $$ x_n+1 = 1 + frac1x_n qquad textwith x_0 = 1 $$ So which one is bigger, $x_n$ or $x_n+1$? The limit of the sequence is $$ lim_x to infty x_n = frac1+sqrt52 = phi $$ and if $x_n < phi Rightarrow x_n+1 > phi$ etc ... You can see this by comparing the functions $$ f_1(x) = x $$ and $$ f_2(x) = 1+ frac1x $$ and figuring out when $f_1(x) > f_2(x)$.
– Matti P.
Sep 7 at 10:00













The sequence contains the convergents of the (simple) continued fraction of the golden ratio $ varphi $. Such a sequence always alternates between values above and values below the given number.
– Peter
Sep 7 at 11:08





The sequence contains the convergents of the (simple) continued fraction of the golden ratio $ varphi $. Such a sequence always alternates between values above and values below the given number.
– Peter
Sep 7 at 11:08











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These are simple continued fractions. This from wikipedia tells you the approximation errors alternate in sign:




Corollary 1: The even convergents continually increase, but are
always less than $x$.



Corollary 2: The odd convergents continually decrease, but are always
greater than $x$ .




(Good for you for noticing this.)



https://en.wikipedia.org/wiki/Continued_fraction#Properties






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    1 Answer
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    active

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    1 Answer
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    up vote
    0
    down vote













    These are simple continued fractions. This from wikipedia tells you the approximation errors alternate in sign:




    Corollary 1: The even convergents continually increase, but are
    always less than $x$.



    Corollary 2: The odd convergents continually decrease, but are always
    greater than $x$ .




    (Good for you for noticing this.)



    https://en.wikipedia.org/wiki/Continued_fraction#Properties






    share|cite|improve this answer


























      up vote
      0
      down vote













      These are simple continued fractions. This from wikipedia tells you the approximation errors alternate in sign:




      Corollary 1: The even convergents continually increase, but are
      always less than $x$.



      Corollary 2: The odd convergents continually decrease, but are always
      greater than $x$ .




      (Good for you for noticing this.)



      https://en.wikipedia.org/wiki/Continued_fraction#Properties






      share|cite|improve this answer
























        up vote
        0
        down vote










        up vote
        0
        down vote









        These are simple continued fractions. This from wikipedia tells you the approximation errors alternate in sign:




        Corollary 1: The even convergents continually increase, but are
        always less than $x$.



        Corollary 2: The odd convergents continually decrease, but are always
        greater than $x$ .




        (Good for you for noticing this.)



        https://en.wikipedia.org/wiki/Continued_fraction#Properties






        share|cite|improve this answer














        These are simple continued fractions. This from wikipedia tells you the approximation errors alternate in sign:




        Corollary 1: The even convergents continually increase, but are
        always less than $x$.



        Corollary 2: The odd convergents continually decrease, but are always
        greater than $x$ .




        (Good for you for noticing this.)



        https://en.wikipedia.org/wiki/Continued_fraction#Properties







        share|cite|improve this answer














        share|cite|improve this answer



        share|cite|improve this answer








        edited Sep 7 at 12:17

























        answered Sep 7 at 12:05









        Ethan Bolker

        36.7k54299




        36.7k54299



























             

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