Obtaining the polar form of the planar system?

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Consider the two variables $x_1,x_2$ which are functions of time $t$, we refer $dotx_1$ as the time derivative of $x_1$.



Let $alpha$ be a constant parameter, and consider the following system of equations:



beginalign*
dotx_1 &= alpha x_1 - x_2 - x_1(x_1^2 + x_2^2)\
dotx_2 &= x_1 + alpha x_2 - x_2(x_1^2 + x_2^2).
endalign*



Now we transform the above system to polar $(rho,theta)$ coordinates. I think after the transformation the above equations lead to the following:



beginalign*
dotrho &= rho(alpha - rho^2)\
dottheta &= 1.
endalign*



Where $x_1 = rho cos(theta)$ and $x_2 = rho sin(theta)$. If I substitute then I am thinking about the partial derivatives involved and I think which variable I should differentiate with respect to the time?
I can observe that the $x_1^2 +x_2^2 = 1$ which could simplify a lot but how should I deal with $dotx_1, dotx_2$ which can help me in getting the polar form of the above system?










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    up vote
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    down vote

    favorite












    Consider the two variables $x_1,x_2$ which are functions of time $t$, we refer $dotx_1$ as the time derivative of $x_1$.



    Let $alpha$ be a constant parameter, and consider the following system of equations:



    beginalign*
    dotx_1 &= alpha x_1 - x_2 - x_1(x_1^2 + x_2^2)\
    dotx_2 &= x_1 + alpha x_2 - x_2(x_1^2 + x_2^2).
    endalign*



    Now we transform the above system to polar $(rho,theta)$ coordinates. I think after the transformation the above equations lead to the following:



    beginalign*
    dotrho &= rho(alpha - rho^2)\
    dottheta &= 1.
    endalign*



    Where $x_1 = rho cos(theta)$ and $x_2 = rho sin(theta)$. If I substitute then I am thinking about the partial derivatives involved and I think which variable I should differentiate with respect to the time?
    I can observe that the $x_1^2 +x_2^2 = 1$ which could simplify a lot but how should I deal with $dotx_1, dotx_2$ which can help me in getting the polar form of the above system?










    share|cite|improve this question

























      up vote
      2
      down vote

      favorite









      up vote
      2
      down vote

      favorite











      Consider the two variables $x_1,x_2$ which are functions of time $t$, we refer $dotx_1$ as the time derivative of $x_1$.



      Let $alpha$ be a constant parameter, and consider the following system of equations:



      beginalign*
      dotx_1 &= alpha x_1 - x_2 - x_1(x_1^2 + x_2^2)\
      dotx_2 &= x_1 + alpha x_2 - x_2(x_1^2 + x_2^2).
      endalign*



      Now we transform the above system to polar $(rho,theta)$ coordinates. I think after the transformation the above equations lead to the following:



      beginalign*
      dotrho &= rho(alpha - rho^2)\
      dottheta &= 1.
      endalign*



      Where $x_1 = rho cos(theta)$ and $x_2 = rho sin(theta)$. If I substitute then I am thinking about the partial derivatives involved and I think which variable I should differentiate with respect to the time?
      I can observe that the $x_1^2 +x_2^2 = 1$ which could simplify a lot but how should I deal with $dotx_1, dotx_2$ which can help me in getting the polar form of the above system?










      share|cite|improve this question















      Consider the two variables $x_1,x_2$ which are functions of time $t$, we refer $dotx_1$ as the time derivative of $x_1$.



      Let $alpha$ be a constant parameter, and consider the following system of equations:



      beginalign*
      dotx_1 &= alpha x_1 - x_2 - x_1(x_1^2 + x_2^2)\
      dotx_2 &= x_1 + alpha x_2 - x_2(x_1^2 + x_2^2).
      endalign*



      Now we transform the above system to polar $(rho,theta)$ coordinates. I think after the transformation the above equations lead to the following:



      beginalign*
      dotrho &= rho(alpha - rho^2)\
      dottheta &= 1.
      endalign*



      Where $x_1 = rho cos(theta)$ and $x_2 = rho sin(theta)$. If I substitute then I am thinking about the partial derivatives involved and I think which variable I should differentiate with respect to the time?
      I can observe that the $x_1^2 +x_2^2 = 1$ which could simplify a lot but how should I deal with $dotx_1, dotx_2$ which can help me in getting the polar form of the above system?







      differential-equations dynamical-systems transformation polar-coordinates






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      edited Sep 7 at 5:40









      user7530

      33.8k658110




      33.8k658110










      asked Sep 7 at 5:29









      BAYMAX

      2,56721121




      2,56721121




















          1 Answer
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          I don't understand your last paragraph (notice for instance $x_1^2+x_2^2 = rho^2$, not $1$) or how you got your second set of equations. To transform your differential equations, just apply the product and chain rules: for instance the first equation becomes
          $$dotrho cos(theta) - rho sin(theta)dottheta = alpha rho cos(theta) - rho sin(theta) - rho^3 cos(theta),$$
          and you will get something similar for the second equation. You can then apply standard variable elimination techniques to isolate equations for $dotrho$ and $dottheta$ and try to simplify them. Give it a try and let me know if you need more help.






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          • Exactly!!! thank you Now i got them both :)
            – BAYMAX
            Sep 7 at 9:00










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          1 Answer
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          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes








          up vote
          2
          down vote



          accepted










          I don't understand your last paragraph (notice for instance $x_1^2+x_2^2 = rho^2$, not $1$) or how you got your second set of equations. To transform your differential equations, just apply the product and chain rules: for instance the first equation becomes
          $$dotrho cos(theta) - rho sin(theta)dottheta = alpha rho cos(theta) - rho sin(theta) - rho^3 cos(theta),$$
          and you will get something similar for the second equation. You can then apply standard variable elimination techniques to isolate equations for $dotrho$ and $dottheta$ and try to simplify them. Give it a try and let me know if you need more help.






          share|cite|improve this answer






















          • Exactly!!! thank you Now i got them both :)
            – BAYMAX
            Sep 7 at 9:00














          up vote
          2
          down vote



          accepted










          I don't understand your last paragraph (notice for instance $x_1^2+x_2^2 = rho^2$, not $1$) or how you got your second set of equations. To transform your differential equations, just apply the product and chain rules: for instance the first equation becomes
          $$dotrho cos(theta) - rho sin(theta)dottheta = alpha rho cos(theta) - rho sin(theta) - rho^3 cos(theta),$$
          and you will get something similar for the second equation. You can then apply standard variable elimination techniques to isolate equations for $dotrho$ and $dottheta$ and try to simplify them. Give it a try and let me know if you need more help.






          share|cite|improve this answer






















          • Exactly!!! thank you Now i got them both :)
            – BAYMAX
            Sep 7 at 9:00












          up vote
          2
          down vote



          accepted







          up vote
          2
          down vote



          accepted






          I don't understand your last paragraph (notice for instance $x_1^2+x_2^2 = rho^2$, not $1$) or how you got your second set of equations. To transform your differential equations, just apply the product and chain rules: for instance the first equation becomes
          $$dotrho cos(theta) - rho sin(theta)dottheta = alpha rho cos(theta) - rho sin(theta) - rho^3 cos(theta),$$
          and you will get something similar for the second equation. You can then apply standard variable elimination techniques to isolate equations for $dotrho$ and $dottheta$ and try to simplify them. Give it a try and let me know if you need more help.






          share|cite|improve this answer














          I don't understand your last paragraph (notice for instance $x_1^2+x_2^2 = rho^2$, not $1$) or how you got your second set of equations. To transform your differential equations, just apply the product and chain rules: for instance the first equation becomes
          $$dotrho cos(theta) - rho sin(theta)dottheta = alpha rho cos(theta) - rho sin(theta) - rho^3 cos(theta),$$
          and you will get something similar for the second equation. You can then apply standard variable elimination techniques to isolate equations for $dotrho$ and $dottheta$ and try to simplify them. Give it a try and let me know if you need more help.







          share|cite|improve this answer














          share|cite|improve this answer



          share|cite|improve this answer








          edited Sep 7 at 5:54

























          answered Sep 7 at 5:48









          user7530

          33.8k658110




          33.8k658110











          • Exactly!!! thank you Now i got them both :)
            – BAYMAX
            Sep 7 at 9:00
















          • Exactly!!! thank you Now i got them both :)
            – BAYMAX
            Sep 7 at 9:00















          Exactly!!! thank you Now i got them both :)
          – BAYMAX
          Sep 7 at 9:00




          Exactly!!! thank you Now i got them both :)
          – BAYMAX
          Sep 7 at 9:00

















           

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