How to compute $|z in mathbbZ mid z > -10, z^3 <0 |$

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Compute $|z in mathbbZ mid z > -10, z^3 <0 |$.




How do you compute these type of problems?



I know it says $z$ of all integers, $z$ has to be greater than $-10$ though by $z^3$ is less than 0.



I feel like that's a range, but not sure how you supposed to compute it?










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    up vote
    -2
    down vote

    favorite













    Compute $|z in mathbbZ mid z > -10, z^3 <0 |$.




    How do you compute these type of problems?



    I know it says $z$ of all integers, $z$ has to be greater than $-10$ though by $z^3$ is less than 0.



    I feel like that's a range, but not sure how you supposed to compute it?










    share|cite|improve this question

























      up vote
      -2
      down vote

      favorite









      up vote
      -2
      down vote

      favorite












      Compute $|z in mathbbZ mid z > -10, z^3 <0 |$.




      How do you compute these type of problems?



      I know it says $z$ of all integers, $z$ has to be greater than $-10$ though by $z^3$ is less than 0.



      I feel like that's a range, but not sure how you supposed to compute it?










      share|cite|improve this question
















      Compute $|z in mathbbZ mid z > -10, z^3 <0 |$.




      How do you compute these type of problems?



      I know it says $z$ of all integers, $z$ has to be greater than $-10$ though by $z^3$ is less than 0.



      I feel like that's a range, but not sure how you supposed to compute it?







      elementary-set-theory






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      edited Sep 7 at 11:28









      Jendrik Stelzner

      7,69121137




      7,69121137










      asked Sep 7 at 2:11









      tameer

      11




      11




















          1 Answer
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          Hint



          This notation means that an element of this set is an integer $z$ such that $z > -10$ and $z^3 <0.$ For instance, $-1$ is in the set. Because $-1$ is an integer, $-1 > -10$ and $(-1)^3=-1 < 0.$ Can you find the rest?






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          • ah ok, so it'd be -1 through -9 since they're all negative integers
            – tameer
            Sep 7 at 2:23










          • Yes, the condition $z^3<0$ is equivalent to $z<0.$ That is the answer. (Well, that's the set... the answer to the actual question is 9.)
            – spaceisdarkgreen
            Sep 7 at 2:26











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          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes








          up vote
          1
          down vote



          accepted










          Hint



          This notation means that an element of this set is an integer $z$ such that $z > -10$ and $z^3 <0.$ For instance, $-1$ is in the set. Because $-1$ is an integer, $-1 > -10$ and $(-1)^3=-1 < 0.$ Can you find the rest?






          share|cite|improve this answer




















          • ah ok, so it'd be -1 through -9 since they're all negative integers
            – tameer
            Sep 7 at 2:23










          • Yes, the condition $z^3<0$ is equivalent to $z<0.$ That is the answer. (Well, that's the set... the answer to the actual question is 9.)
            – spaceisdarkgreen
            Sep 7 at 2:26















          up vote
          1
          down vote



          accepted










          Hint



          This notation means that an element of this set is an integer $z$ such that $z > -10$ and $z^3 <0.$ For instance, $-1$ is in the set. Because $-1$ is an integer, $-1 > -10$ and $(-1)^3=-1 < 0.$ Can you find the rest?






          share|cite|improve this answer




















          • ah ok, so it'd be -1 through -9 since they're all negative integers
            – tameer
            Sep 7 at 2:23










          • Yes, the condition $z^3<0$ is equivalent to $z<0.$ That is the answer. (Well, that's the set... the answer to the actual question is 9.)
            – spaceisdarkgreen
            Sep 7 at 2:26













          up vote
          1
          down vote



          accepted







          up vote
          1
          down vote



          accepted






          Hint



          This notation means that an element of this set is an integer $z$ such that $z > -10$ and $z^3 <0.$ For instance, $-1$ is in the set. Because $-1$ is an integer, $-1 > -10$ and $(-1)^3=-1 < 0.$ Can you find the rest?






          share|cite|improve this answer












          Hint



          This notation means that an element of this set is an integer $z$ such that $z > -10$ and $z^3 <0.$ For instance, $-1$ is in the set. Because $-1$ is an integer, $-1 > -10$ and $(-1)^3=-1 < 0.$ Can you find the rest?







          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered Sep 7 at 2:18









          spaceisdarkgreen

          29.1k21549




          29.1k21549











          • ah ok, so it'd be -1 through -9 since they're all negative integers
            – tameer
            Sep 7 at 2:23










          • Yes, the condition $z^3<0$ is equivalent to $z<0.$ That is the answer. (Well, that's the set... the answer to the actual question is 9.)
            – spaceisdarkgreen
            Sep 7 at 2:26

















          • ah ok, so it'd be -1 through -9 since they're all negative integers
            – tameer
            Sep 7 at 2:23










          • Yes, the condition $z^3<0$ is equivalent to $z<0.$ That is the answer. (Well, that's the set... the answer to the actual question is 9.)
            – spaceisdarkgreen
            Sep 7 at 2:26
















          ah ok, so it'd be -1 through -9 since they're all negative integers
          – tameer
          Sep 7 at 2:23




          ah ok, so it'd be -1 through -9 since they're all negative integers
          – tameer
          Sep 7 at 2:23












          Yes, the condition $z^3<0$ is equivalent to $z<0.$ That is the answer. (Well, that's the set... the answer to the actual question is 9.)
          – spaceisdarkgreen
          Sep 7 at 2:26





          Yes, the condition $z^3<0$ is equivalent to $z<0.$ That is the answer. (Well, that's the set... the answer to the actual question is 9.)
          – spaceisdarkgreen
          Sep 7 at 2:26


















           

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