How to compute $|z in mathbbZ mid z > -10, z^3 <0 |$
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Compute $|z in mathbbZ mid z > -10, z^3 <0 |$.
How do you compute these type of problems?
I know it says $z$ of all integers, $z$ has to be greater than $-10$ though by $z^3$ is less than 0.
I feel like that's a range, but not sure how you supposed to compute it?
elementary-set-theory
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up vote
-2
down vote
favorite
Compute $|z in mathbbZ mid z > -10, z^3 <0 |$.
How do you compute these type of problems?
I know it says $z$ of all integers, $z$ has to be greater than $-10$ though by $z^3$ is less than 0.
I feel like that's a range, but not sure how you supposed to compute it?
elementary-set-theory
add a comment |Â
up vote
-2
down vote
favorite
up vote
-2
down vote
favorite
Compute $|z in mathbbZ mid z > -10, z^3 <0 |$.
How do you compute these type of problems?
I know it says $z$ of all integers, $z$ has to be greater than $-10$ though by $z^3$ is less than 0.
I feel like that's a range, but not sure how you supposed to compute it?
elementary-set-theory
Compute $|z in mathbbZ mid z > -10, z^3 <0 |$.
How do you compute these type of problems?
I know it says $z$ of all integers, $z$ has to be greater than $-10$ though by $z^3$ is less than 0.
I feel like that's a range, but not sure how you supposed to compute it?
elementary-set-theory
elementary-set-theory
edited Sep 7 at 11:28
Jendrik Stelzner
7,69121137
7,69121137
asked Sep 7 at 2:11
tameer
11
11
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add a comment |Â
1 Answer
1
active
oldest
votes
up vote
1
down vote
accepted
Hint
This notation means that an element of this set is an integer $z$ such that $z > -10$ and $z^3 <0.$ For instance, $-1$ is in the set. Because $-1$ is an integer, $-1 > -10$ and $(-1)^3=-1 < 0.$ Can you find the rest?
ah ok, so it'd be -1 through -9 since they're all negative integers
â tameer
Sep 7 at 2:23
Yes, the condition $z^3<0$ is equivalent to $z<0.$ That is the answer. (Well, that's the set... the answer to the actual question is 9.)
â spaceisdarkgreen
Sep 7 at 2:26
add a comment |Â
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
accepted
Hint
This notation means that an element of this set is an integer $z$ such that $z > -10$ and $z^3 <0.$ For instance, $-1$ is in the set. Because $-1$ is an integer, $-1 > -10$ and $(-1)^3=-1 < 0.$ Can you find the rest?
ah ok, so it'd be -1 through -9 since they're all negative integers
â tameer
Sep 7 at 2:23
Yes, the condition $z^3<0$ is equivalent to $z<0.$ That is the answer. (Well, that's the set... the answer to the actual question is 9.)
â spaceisdarkgreen
Sep 7 at 2:26
add a comment |Â
up vote
1
down vote
accepted
Hint
This notation means that an element of this set is an integer $z$ such that $z > -10$ and $z^3 <0.$ For instance, $-1$ is in the set. Because $-1$ is an integer, $-1 > -10$ and $(-1)^3=-1 < 0.$ Can you find the rest?
ah ok, so it'd be -1 through -9 since they're all negative integers
â tameer
Sep 7 at 2:23
Yes, the condition $z^3<0$ is equivalent to $z<0.$ That is the answer. (Well, that's the set... the answer to the actual question is 9.)
â spaceisdarkgreen
Sep 7 at 2:26
add a comment |Â
up vote
1
down vote
accepted
up vote
1
down vote
accepted
Hint
This notation means that an element of this set is an integer $z$ such that $z > -10$ and $z^3 <0.$ For instance, $-1$ is in the set. Because $-1$ is an integer, $-1 > -10$ and $(-1)^3=-1 < 0.$ Can you find the rest?
Hint
This notation means that an element of this set is an integer $z$ such that $z > -10$ and $z^3 <0.$ For instance, $-1$ is in the set. Because $-1$ is an integer, $-1 > -10$ and $(-1)^3=-1 < 0.$ Can you find the rest?
answered Sep 7 at 2:18
spaceisdarkgreen
29.1k21549
29.1k21549
ah ok, so it'd be -1 through -9 since they're all negative integers
â tameer
Sep 7 at 2:23
Yes, the condition $z^3<0$ is equivalent to $z<0.$ That is the answer. (Well, that's the set... the answer to the actual question is 9.)
â spaceisdarkgreen
Sep 7 at 2:26
add a comment |Â
ah ok, so it'd be -1 through -9 since they're all negative integers
â tameer
Sep 7 at 2:23
Yes, the condition $z^3<0$ is equivalent to $z<0.$ That is the answer. (Well, that's the set... the answer to the actual question is 9.)
â spaceisdarkgreen
Sep 7 at 2:26
ah ok, so it'd be -1 through -9 since they're all negative integers
â tameer
Sep 7 at 2:23
ah ok, so it'd be -1 through -9 since they're all negative integers
â tameer
Sep 7 at 2:23
Yes, the condition $z^3<0$ is equivalent to $z<0.$ That is the answer. (Well, that's the set... the answer to the actual question is 9.)
â spaceisdarkgreen
Sep 7 at 2:26
Yes, the condition $z^3<0$ is equivalent to $z<0.$ That is the answer. (Well, that's the set... the answer to the actual question is 9.)
â spaceisdarkgreen
Sep 7 at 2:26
add a comment |Â
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