Standard deviation is unknown, t-test or z-test with standard deviation estimation
Clash Royale CLAN TAG#URR8PPP
up vote
0
down vote
favorite
I have read some book, i still find it hard to understand, kinda need some clearance.
If I knew the standard deviation of the population (using previous study) and the sample is large, I can use z* score to find margin of error and confidence interval which is
z * standar deviation / sqrt(n)
What if i didn't know the population standard deviation, as there was no prior study. Can I use estimate of population standard deviation by using range / 4 and use z* score
Or should I use t* score instead by using standard error, the sample standard deviation?
Because t test unlike z test, which t test is really depends on the sample size, t test with sample size 10 will be different than t test with sample size 50
confidence-interval
add a comment |Â
up vote
0
down vote
favorite
I have read some book, i still find it hard to understand, kinda need some clearance.
If I knew the standard deviation of the population (using previous study) and the sample is large, I can use z* score to find margin of error and confidence interval which is
z * standar deviation / sqrt(n)
What if i didn't know the population standard deviation, as there was no prior study. Can I use estimate of population standard deviation by using range / 4 and use z* score
Or should I use t* score instead by using standard error, the sample standard deviation?
Because t test unlike z test, which t test is really depends on the sample size, t test with sample size 10 will be different than t test with sample size 50
confidence-interval
add a comment |Â
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I have read some book, i still find it hard to understand, kinda need some clearance.
If I knew the standard deviation of the population (using previous study) and the sample is large, I can use z* score to find margin of error and confidence interval which is
z * standar deviation / sqrt(n)
What if i didn't know the population standard deviation, as there was no prior study. Can I use estimate of population standard deviation by using range / 4 and use z* score
Or should I use t* score instead by using standard error, the sample standard deviation?
Because t test unlike z test, which t test is really depends on the sample size, t test with sample size 10 will be different than t test with sample size 50
confidence-interval
I have read some book, i still find it hard to understand, kinda need some clearance.
If I knew the standard deviation of the population (using previous study) and the sample is large, I can use z* score to find margin of error and confidence interval which is
z * standar deviation / sqrt(n)
What if i didn't know the population standard deviation, as there was no prior study. Can I use estimate of population standard deviation by using range / 4 and use z* score
Or should I use t* score instead by using standard error, the sample standard deviation?
Because t test unlike z test, which t test is really depends on the sample size, t test with sample size 10 will be different than t test with sample size 50
confidence-interval
confidence-interval
edited Sep 17 at 19:18
md2perpe
6,85311023
6,85311023
asked Sep 7 at 6:07
Alfin E. R.
1035
1035
add a comment |Â
add a comment |Â
active
oldest
votes
active
oldest
votes
active
oldest
votes
active
oldest
votes
active
oldest
votes
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f2908320%2fstandard-deviation-is-unknown-t-test-or-z-test-with-standard-deviation-estimati%23new-answer', 'question_page');
);
Post as a guest
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password