rotated straight line substending an angle at the x-y axis

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We have a straight line situated on the x-axis and it starts from the origin and its endpoints can be considered to be $(0,0)$ and $(d,0)$. We move this line through an angle $theta$ and now we have its length $d_1$. We know the value of $theta$ and also $d_1$. How can we proceed to find $d$? Making a triangle and doing $cos d_1$ doesn't seem to give a correct result.










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  • Umm it seems that $d=d_1$
    – Mohammad Zuhair Khan
    Sep 7 at 10:21










  • Can you explain the problem better? The hands of a clock do not change their length when rotated. Do you mean that the line $d$ is stretched straight up from point $(d,0)$?
    – Narlin
    Sep 7 at 12:13














up vote
0
down vote

favorite












We have a straight line situated on the x-axis and it starts from the origin and its endpoints can be considered to be $(0,0)$ and $(d,0)$. We move this line through an angle $theta$ and now we have its length $d_1$. We know the value of $theta$ and also $d_1$. How can we proceed to find $d$? Making a triangle and doing $cos d_1$ doesn't seem to give a correct result.










share|cite|improve this question























  • Umm it seems that $d=d_1$
    – Mohammad Zuhair Khan
    Sep 7 at 10:21










  • Can you explain the problem better? The hands of a clock do not change their length when rotated. Do you mean that the line $d$ is stretched straight up from point $(d,0)$?
    – Narlin
    Sep 7 at 12:13












up vote
0
down vote

favorite









up vote
0
down vote

favorite











We have a straight line situated on the x-axis and it starts from the origin and its endpoints can be considered to be $(0,0)$ and $(d,0)$. We move this line through an angle $theta$ and now we have its length $d_1$. We know the value of $theta$ and also $d_1$. How can we proceed to find $d$? Making a triangle and doing $cos d_1$ doesn't seem to give a correct result.










share|cite|improve this question















We have a straight line situated on the x-axis and it starts from the origin and its endpoints can be considered to be $(0,0)$ and $(d,0)$. We move this line through an angle $theta$ and now we have its length $d_1$. We know the value of $theta$ and also $d_1$. How can we proceed to find $d$? Making a triangle and doing $cos d_1$ doesn't seem to give a correct result.







trigonometry coordinate-systems






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edited Sep 7 at 11:09









bjcolby15

8751816




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asked Sep 7 at 10:14









satyajeet jha

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  • Umm it seems that $d=d_1$
    – Mohammad Zuhair Khan
    Sep 7 at 10:21










  • Can you explain the problem better? The hands of a clock do not change their length when rotated. Do you mean that the line $d$ is stretched straight up from point $(d,0)$?
    – Narlin
    Sep 7 at 12:13
















  • Umm it seems that $d=d_1$
    – Mohammad Zuhair Khan
    Sep 7 at 10:21










  • Can you explain the problem better? The hands of a clock do not change their length when rotated. Do you mean that the line $d$ is stretched straight up from point $(d,0)$?
    – Narlin
    Sep 7 at 12:13















Umm it seems that $d=d_1$
– Mohammad Zuhair Khan
Sep 7 at 10:21




Umm it seems that $d=d_1$
– Mohammad Zuhair Khan
Sep 7 at 10:21












Can you explain the problem better? The hands of a clock do not change their length when rotated. Do you mean that the line $d$ is stretched straight up from point $(d,0)$?
– Narlin
Sep 7 at 12:13




Can you explain the problem better? The hands of a clock do not change their length when rotated. Do you mean that the line $d$ is stretched straight up from point $(d,0)$?
– Narlin
Sep 7 at 12:13















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