rotated straight line substending an angle at the x-y axis
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We have a straight line situated on the x-axis and it starts from the origin and its endpoints can be considered to be $(0,0)$ and $(d,0)$. We move this line through an angle $theta$ and now we have its length $d_1$. We know the value of $theta$ and also $d_1$. How can we proceed to find $d$? Making a triangle and doing $cos d_1$ doesn't seem to give a correct result.
trigonometry coordinate-systems
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up vote
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We have a straight line situated on the x-axis and it starts from the origin and its endpoints can be considered to be $(0,0)$ and $(d,0)$. We move this line through an angle $theta$ and now we have its length $d_1$. We know the value of $theta$ and also $d_1$. How can we proceed to find $d$? Making a triangle and doing $cos d_1$ doesn't seem to give a correct result.
trigonometry coordinate-systems
Umm it seems that $d=d_1$
â Mohammad Zuhair Khan
Sep 7 at 10:21
Can you explain the problem better? The hands of a clock do not change their length when rotated. Do you mean that the line $d$ is stretched straight up from point $(d,0)$?
â Narlin
Sep 7 at 12:13
add a comment |Â
up vote
0
down vote
favorite
up vote
0
down vote
favorite
We have a straight line situated on the x-axis and it starts from the origin and its endpoints can be considered to be $(0,0)$ and $(d,0)$. We move this line through an angle $theta$ and now we have its length $d_1$. We know the value of $theta$ and also $d_1$. How can we proceed to find $d$? Making a triangle and doing $cos d_1$ doesn't seem to give a correct result.
trigonometry coordinate-systems
We have a straight line situated on the x-axis and it starts from the origin and its endpoints can be considered to be $(0,0)$ and $(d,0)$. We move this line through an angle $theta$ and now we have its length $d_1$. We know the value of $theta$ and also $d_1$. How can we proceed to find $d$? Making a triangle and doing $cos d_1$ doesn't seem to give a correct result.
trigonometry coordinate-systems
trigonometry coordinate-systems
edited Sep 7 at 11:09
bjcolby15
8751816
8751816
asked Sep 7 at 10:14
satyajeet jha
11
11
Umm it seems that $d=d_1$
â Mohammad Zuhair Khan
Sep 7 at 10:21
Can you explain the problem better? The hands of a clock do not change their length when rotated. Do you mean that the line $d$ is stretched straight up from point $(d,0)$?
â Narlin
Sep 7 at 12:13
add a comment |Â
Umm it seems that $d=d_1$
â Mohammad Zuhair Khan
Sep 7 at 10:21
Can you explain the problem better? The hands of a clock do not change their length when rotated. Do you mean that the line $d$ is stretched straight up from point $(d,0)$?
â Narlin
Sep 7 at 12:13
Umm it seems that $d=d_1$
â Mohammad Zuhair Khan
Sep 7 at 10:21
Umm it seems that $d=d_1$
â Mohammad Zuhair Khan
Sep 7 at 10:21
Can you explain the problem better? The hands of a clock do not change their length when rotated. Do you mean that the line $d$ is stretched straight up from point $(d,0)$?
â Narlin
Sep 7 at 12:13
Can you explain the problem better? The hands of a clock do not change their length when rotated. Do you mean that the line $d$ is stretched straight up from point $(d,0)$?
â Narlin
Sep 7 at 12:13
add a comment |Â
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Umm it seems that $d=d_1$
â Mohammad Zuhair Khan
Sep 7 at 10:21
Can you explain the problem better? The hands of a clock do not change their length when rotated. Do you mean that the line $d$ is stretched straight up from point $(d,0)$?
â Narlin
Sep 7 at 12:13