Hookes law Bungee jumping question

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ive seen a few forums with answers for these but im finding a fair few different results and im getting confused. Perhaps someone here can help:



A bungee rope is specially designed and its modulus of elasticity is such that the rope is stretched to twice its natural length by a person of 75kg hanging at rest from the free end.



for a person of m kg, calculate the depth to which the person would fall if attached to a rope of the type described above. Assume the jumper is a particle so that their height can be ignored.




mathematical-physics




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  • Please edit it and make it more readable.
    – tarit goswami
    Aug 29 at 4:38










  • If it helps any, this is a link to the same question answered by other people, however i am just unsure how he got to his depth equation. any help would be appreciated! math.stackexchange.com/questions/2396485/…
    – EthanOliver
    Aug 29 at 11:10














up vote
0
down vote

favorite












ive seen a few forums with answers for these but im finding a fair few different results and im getting confused. Perhaps someone here can help:



A bungee rope is specially designed and its modulus of elasticity is such that the rope is stretched to twice its natural length by a person of 75kg hanging at rest from the free end.



for a person of m kg, calculate the depth to which the person would fall if attached to a rope of the type described above. Assume the jumper is a particle so that their height can be ignored.




mathematical-physics




share|cite|improve this question






















  • Please edit it and make it more readable.
    – tarit goswami
    Aug 29 at 4:38










  • If it helps any, this is a link to the same question answered by other people, however i am just unsure how he got to his depth equation. any help would be appreciated! math.stackexchange.com/questions/2396485/…
    – EthanOliver
    Aug 29 at 11:10












up vote
0
down vote

favorite









up vote
0
down vote

favorite











ive seen a few forums with answers for these but im finding a fair few different results and im getting confused. Perhaps someone here can help:



A bungee rope is specially designed and its modulus of elasticity is such that the rope is stretched to twice its natural length by a person of 75kg hanging at rest from the free end.



for a person of m kg, calculate the depth to which the person would fall if attached to a rope of the type described above. Assume the jumper is a particle so that their height can be ignored.




mathematical-physics




share|cite|improve this question














ive seen a few forums with answers for these but im finding a fair few different results and im getting confused. Perhaps someone here can help:



A bungee rope is specially designed and its modulus of elasticity is such that the rope is stretched to twice its natural length by a person of 75kg hanging at rest from the free end.



for a person of m kg, calculate the depth to which the person would fall if attached to a rope of the type described above. Assume the jumper is a particle so that their height can be ignored.





mathematical-physics





share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Aug 29 at 4:40

























asked Aug 29 at 4:00









EthanOliver

11




11











  • Please edit it and make it more readable.
    – tarit goswami
    Aug 29 at 4:38










  • If it helps any, this is a link to the same question answered by other people, however i am just unsure how he got to his depth equation. any help would be appreciated! math.stackexchange.com/questions/2396485/…
    – EthanOliver
    Aug 29 at 11:10
















  • Please edit it and make it more readable.
    – tarit goswami
    Aug 29 at 4:38










  • If it helps any, this is a link to the same question answered by other people, however i am just unsure how he got to his depth equation. any help would be appreciated! math.stackexchange.com/questions/2396485/…
    – EthanOliver
    Aug 29 at 11:10















Please edit it and make it more readable.
– tarit goswami
Aug 29 at 4:38




Please edit it and make it more readable.
– tarit goswami
Aug 29 at 4:38












If it helps any, this is a link to the same question answered by other people, however i am just unsure how he got to his depth equation. any help would be appreciated! math.stackexchange.com/questions/2396485/…
– EthanOliver
Aug 29 at 11:10




If it helps any, this is a link to the same question answered by other people, however i am just unsure how he got to his depth equation. any help would be appreciated! math.stackexchange.com/questions/2396485/…
– EthanOliver
Aug 29 at 11:10










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Hint: use conservation of energy. Neglecting friction, when the jumper reaches the lowest depth, the potential energy lost in the fall is equal to the potential energy from stretching of the rope.






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    Hint: use conservation of energy. Neglecting friction, when the jumper reaches the lowest depth, the potential energy lost in the fall is equal to the potential energy from stretching of the rope.






    share|cite|improve this answer
























      up vote
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      down vote













      Hint: use conservation of energy. Neglecting friction, when the jumper reaches the lowest depth, the potential energy lost in the fall is equal to the potential energy from stretching of the rope.






      share|cite|improve this answer






















        up vote
        0
        down vote










        up vote
        0
        down vote









        Hint: use conservation of energy. Neglecting friction, when the jumper reaches the lowest depth, the potential energy lost in the fall is equal to the potential energy from stretching of the rope.






        share|cite|improve this answer












        Hint: use conservation of energy. Neglecting friction, when the jumper reaches the lowest depth, the potential energy lost in the fall is equal to the potential energy from stretching of the rope.







        share|cite|improve this answer












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        share|cite|improve this answer










        answered Aug 29 at 4:16









        Robert Israel

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