Automorphism group of union of varieties

The name of the pictureThe name of the pictureThe name of the pictureClash Royale CLAN TAG#URR8PPP











up vote
3
down vote

favorite












A projective hypersurface $mathcalV(F)$, given by a homogeneous polynomial $F$, can always be expressed as the union of its affine components $mathcalV(F_i)$, where $F_i=F(x_1,ldots,x_i-1,1,x_i+1,ldots,x_n)$ is the $i$-th dehomogenisation. That is we have
$$mathcalV(F)=bigcup_i=1^nmathcalV(F_i).$$
My question is; is there any relationship between the automorphism group of the projective hypersurface, $mathrmAut(mathcalV(F))$, and the affine automorphism groups, $mathrmAut(mathcalV(F_i))$?



To me it seems that each automorphism of $mathcalV(F)$ should act either as an isomorphism between pairs of its affine components $mathcalV(F_i)$ and $mathcalV(F_j)$, $ineq j$, or as an automorphism on each $mathcalV(F_i)$.



So then it should be the case that each $mathrmAut(mathcalV(F_i))$ is a subgroup of $mathrmAut(mathcalV(F))$?







share|cite|improve this question


























    up vote
    3
    down vote

    favorite












    A projective hypersurface $mathcalV(F)$, given by a homogeneous polynomial $F$, can always be expressed as the union of its affine components $mathcalV(F_i)$, where $F_i=F(x_1,ldots,x_i-1,1,x_i+1,ldots,x_n)$ is the $i$-th dehomogenisation. That is we have
    $$mathcalV(F)=bigcup_i=1^nmathcalV(F_i).$$
    My question is; is there any relationship between the automorphism group of the projective hypersurface, $mathrmAut(mathcalV(F))$, and the affine automorphism groups, $mathrmAut(mathcalV(F_i))$?



    To me it seems that each automorphism of $mathcalV(F)$ should act either as an isomorphism between pairs of its affine components $mathcalV(F_i)$ and $mathcalV(F_j)$, $ineq j$, or as an automorphism on each $mathcalV(F_i)$.



    So then it should be the case that each $mathrmAut(mathcalV(F_i))$ is a subgroup of $mathrmAut(mathcalV(F))$?







    share|cite|improve this question
























      up vote
      3
      down vote

      favorite









      up vote
      3
      down vote

      favorite











      A projective hypersurface $mathcalV(F)$, given by a homogeneous polynomial $F$, can always be expressed as the union of its affine components $mathcalV(F_i)$, where $F_i=F(x_1,ldots,x_i-1,1,x_i+1,ldots,x_n)$ is the $i$-th dehomogenisation. That is we have
      $$mathcalV(F)=bigcup_i=1^nmathcalV(F_i).$$
      My question is; is there any relationship between the automorphism group of the projective hypersurface, $mathrmAut(mathcalV(F))$, and the affine automorphism groups, $mathrmAut(mathcalV(F_i))$?



      To me it seems that each automorphism of $mathcalV(F)$ should act either as an isomorphism between pairs of its affine components $mathcalV(F_i)$ and $mathcalV(F_j)$, $ineq j$, or as an automorphism on each $mathcalV(F_i)$.



      So then it should be the case that each $mathrmAut(mathcalV(F_i))$ is a subgroup of $mathrmAut(mathcalV(F))$?







      share|cite|improve this question














      A projective hypersurface $mathcalV(F)$, given by a homogeneous polynomial $F$, can always be expressed as the union of its affine components $mathcalV(F_i)$, where $F_i=F(x_1,ldots,x_i-1,1,x_i+1,ldots,x_n)$ is the $i$-th dehomogenisation. That is we have
      $$mathcalV(F)=bigcup_i=1^nmathcalV(F_i).$$
      My question is; is there any relationship between the automorphism group of the projective hypersurface, $mathrmAut(mathcalV(F))$, and the affine automorphism groups, $mathrmAut(mathcalV(F_i))$?



      To me it seems that each automorphism of $mathcalV(F)$ should act either as an isomorphism between pairs of its affine components $mathcalV(F_i)$ and $mathcalV(F_j)$, $ineq j$, or as an automorphism on each $mathcalV(F_i)$.



      So then it should be the case that each $mathrmAut(mathcalV(F_i))$ is a subgroup of $mathrmAut(mathcalV(F))$?









      share|cite|improve this question













      share|cite|improve this question




      share|cite|improve this question








      edited Aug 29 at 5:38

























      asked Aug 29 at 5:32









      user551642

      674




      674




















          1 Answer
          1






          active

          oldest

          votes

















          up vote
          2
          down vote



          accepted










          For generic $F$, $mboxAut(mathcalV(F))< mboxAut(mathbbP^n-1)$ and there is a subgroup of $mboxAut(mathcalV(F))$ that acts on $mathcalV(F_i)$, namely the stabilizer of $x_i=0$.



          If you can find coordinates such that every atutomorphism in $mboxAut(mathcalV(F))$ permutes the $mathcalV(F_i)$, then $mboxAut(mathcalV(F))$ is called an imprimitive subgroup of $mboxAut(mathbbP^n-1$). It can defenitely happen but not always. (For curves it happens for the Fermat curves but not for the Klein quartic)



          The problem with $mboxAut(mathcalV(F_i)) < mboxAut(mathcalV(F))$ is what you want to the automorphism to preserve. You could have a birational self-map $T$ of $mathcalV(F)$ preserving $mathcalV(F_i)$ and this imply that $T in mboxAut(mathcalV(F_i))$ but $Tnotin mboxAut(mathcalV(F))$.



          Let me know if it helps you.






          share|cite|improve this answer




















          • Thanks for the answer.
            – user551642
            Aug 29 at 22:26










          Your Answer




          StackExchange.ifUsing("editor", function ()
          return StackExchange.using("mathjaxEditing", function ()
          StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix)
          StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
          );
          );
          , "mathjax-editing");

          StackExchange.ready(function()
          var channelOptions =
          tags: "".split(" "),
          id: "69"
          ;
          initTagRenderer("".split(" "), "".split(" "), channelOptions);

          StackExchange.using("externalEditor", function()
          // Have to fire editor after snippets, if snippets enabled
          if (StackExchange.settings.snippets.snippetsEnabled)
          StackExchange.using("snippets", function()
          createEditor();
          );

          else
          createEditor();

          );

          function createEditor()
          StackExchange.prepareEditor(
          heartbeatType: 'answer',
          convertImagesToLinks: true,
          noModals: false,
          showLowRepImageUploadWarning: true,
          reputationToPostImages: 10,
          bindNavPrevention: true,
          postfix: "",
          noCode: true, onDemand: true,
          discardSelector: ".discard-answer"
          ,immediatelyShowMarkdownHelp:true
          );



          );













           

          draft saved


          draft discarded


















          StackExchange.ready(
          function ()
          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f2897976%2fautomorphism-group-of-union-of-varieties%23new-answer', 'question_page');

          );

          Post as a guest






























          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes








          up vote
          2
          down vote



          accepted










          For generic $F$, $mboxAut(mathcalV(F))< mboxAut(mathbbP^n-1)$ and there is a subgroup of $mboxAut(mathcalV(F))$ that acts on $mathcalV(F_i)$, namely the stabilizer of $x_i=0$.



          If you can find coordinates such that every atutomorphism in $mboxAut(mathcalV(F))$ permutes the $mathcalV(F_i)$, then $mboxAut(mathcalV(F))$ is called an imprimitive subgroup of $mboxAut(mathbbP^n-1$). It can defenitely happen but not always. (For curves it happens for the Fermat curves but not for the Klein quartic)



          The problem with $mboxAut(mathcalV(F_i)) < mboxAut(mathcalV(F))$ is what you want to the automorphism to preserve. You could have a birational self-map $T$ of $mathcalV(F)$ preserving $mathcalV(F_i)$ and this imply that $T in mboxAut(mathcalV(F_i))$ but $Tnotin mboxAut(mathcalV(F))$.



          Let me know if it helps you.






          share|cite|improve this answer




















          • Thanks for the answer.
            – user551642
            Aug 29 at 22:26














          up vote
          2
          down vote



          accepted










          For generic $F$, $mboxAut(mathcalV(F))< mboxAut(mathbbP^n-1)$ and there is a subgroup of $mboxAut(mathcalV(F))$ that acts on $mathcalV(F_i)$, namely the stabilizer of $x_i=0$.



          If you can find coordinates such that every atutomorphism in $mboxAut(mathcalV(F))$ permutes the $mathcalV(F_i)$, then $mboxAut(mathcalV(F))$ is called an imprimitive subgroup of $mboxAut(mathbbP^n-1$). It can defenitely happen but not always. (For curves it happens for the Fermat curves but not for the Klein quartic)



          The problem with $mboxAut(mathcalV(F_i)) < mboxAut(mathcalV(F))$ is what you want to the automorphism to preserve. You could have a birational self-map $T$ of $mathcalV(F)$ preserving $mathcalV(F_i)$ and this imply that $T in mboxAut(mathcalV(F_i))$ but $Tnotin mboxAut(mathcalV(F))$.



          Let me know if it helps you.






          share|cite|improve this answer




















          • Thanks for the answer.
            – user551642
            Aug 29 at 22:26












          up vote
          2
          down vote



          accepted







          up vote
          2
          down vote



          accepted






          For generic $F$, $mboxAut(mathcalV(F))< mboxAut(mathbbP^n-1)$ and there is a subgroup of $mboxAut(mathcalV(F))$ that acts on $mathcalV(F_i)$, namely the stabilizer of $x_i=0$.



          If you can find coordinates such that every atutomorphism in $mboxAut(mathcalV(F))$ permutes the $mathcalV(F_i)$, then $mboxAut(mathcalV(F))$ is called an imprimitive subgroup of $mboxAut(mathbbP^n-1$). It can defenitely happen but not always. (For curves it happens for the Fermat curves but not for the Klein quartic)



          The problem with $mboxAut(mathcalV(F_i)) < mboxAut(mathcalV(F))$ is what you want to the automorphism to preserve. You could have a birational self-map $T$ of $mathcalV(F)$ preserving $mathcalV(F_i)$ and this imply that $T in mboxAut(mathcalV(F_i))$ but $Tnotin mboxAut(mathcalV(F))$.



          Let me know if it helps you.






          share|cite|improve this answer












          For generic $F$, $mboxAut(mathcalV(F))< mboxAut(mathbbP^n-1)$ and there is a subgroup of $mboxAut(mathcalV(F))$ that acts on $mathcalV(F_i)$, namely the stabilizer of $x_i=0$.



          If you can find coordinates such that every atutomorphism in $mboxAut(mathcalV(F))$ permutes the $mathcalV(F_i)$, then $mboxAut(mathcalV(F))$ is called an imprimitive subgroup of $mboxAut(mathbbP^n-1$). It can defenitely happen but not always. (For curves it happens for the Fermat curves but not for the Klein quartic)



          The problem with $mboxAut(mathcalV(F_i)) < mboxAut(mathcalV(F))$ is what you want to the automorphism to preserve. You could have a birational self-map $T$ of $mathcalV(F)$ preserving $mathcalV(F_i)$ and this imply that $T in mboxAut(mathcalV(F_i))$ but $Tnotin mboxAut(mathcalV(F))$.



          Let me know if it helps you.







          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered Aug 29 at 15:12









          Alan Muniz

          1,411622




          1,411622











          • Thanks for the answer.
            – user551642
            Aug 29 at 22:26
















          • Thanks for the answer.
            – user551642
            Aug 29 at 22:26















          Thanks for the answer.
          – user551642
          Aug 29 at 22:26




          Thanks for the answer.
          – user551642
          Aug 29 at 22:26

















           

          draft saved


          draft discarded















































           


          draft saved


          draft discarded














          StackExchange.ready(
          function ()
          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f2897976%2fautomorphism-group-of-union-of-varieties%23new-answer', 'question_page');

          );

          Post as a guest













































































          這個網誌中的熱門文章

          tkz-euclide: tkzDrawCircle[R] not working

          How to combine Bézier curves to a surface?

          1st Magritte Awards