order of operations for ambiguous vertical division

Clash Royale CLAN TAG#URR8PPP
up vote
1
down vote
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consider the following two problems from Princeton's Quant GRE prep
problem 1
problem 2
Why am i meant to assume that a/b/c should be read as a/(b/c)? I would assume it should be read as a ÷ b ÷ c, and therefore (a ÷ b) ÷ c, considering that the same operations are performed left to right.
Furthermore my answer to question 1 was identical to the question. Could this be a problem with the way my browser displays the questions?
Is Princeton correct in asserting that a/b/c should be assumed to state a/(b/c)?
Sorry about such a pedestrian question, I've been having trouble finding someone to answer it and my exam is tomorrow.
arithmetic divisibility
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up vote
1
down vote
favorite
consider the following two problems from Princeton's Quant GRE prep
problem 1
problem 2
Why am i meant to assume that a/b/c should be read as a/(b/c)? I would assume it should be read as a ÷ b ÷ c, and therefore (a ÷ b) ÷ c, considering that the same operations are performed left to right.
Furthermore my answer to question 1 was identical to the question. Could this be a problem with the way my browser displays the questions?
Is Princeton correct in asserting that a/b/c should be assumed to state a/(b/c)?
Sorry about such a pedestrian question, I've been having trouble finding someone to answer it and my exam is tomorrow.
arithmetic divisibility
add a comment |Â
up vote
1
down vote
favorite
up vote
1
down vote
favorite
consider the following two problems from Princeton's Quant GRE prep
problem 1
problem 2
Why am i meant to assume that a/b/c should be read as a/(b/c)? I would assume it should be read as a ÷ b ÷ c, and therefore (a ÷ b) ÷ c, considering that the same operations are performed left to right.
Furthermore my answer to question 1 was identical to the question. Could this be a problem with the way my browser displays the questions?
Is Princeton correct in asserting that a/b/c should be assumed to state a/(b/c)?
Sorry about such a pedestrian question, I've been having trouble finding someone to answer it and my exam is tomorrow.
arithmetic divisibility
consider the following two problems from Princeton's Quant GRE prep
problem 1
problem 2
Why am i meant to assume that a/b/c should be read as a/(b/c)? I would assume it should be read as a ÷ b ÷ c, and therefore (a ÷ b) ÷ c, considering that the same operations are performed left to right.
Furthermore my answer to question 1 was identical to the question. Could this be a problem with the way my browser displays the questions?
Is Princeton correct in asserting that a/b/c should be assumed to state a/(b/c)?
Sorry about such a pedestrian question, I've been having trouble finding someone to answer it and my exam is tomorrow.
arithmetic divisibility
asked Aug 24 at 1:39
Kama
134
134
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2 Answers
2
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0
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accepted
The division is in fact not ambiguous in those questions if you look very closely at the sizes of the vinculums( the line between numerator and denominator) it can be seen that one is larger than the other, granted it could stand to be much clearer ( i had to zoom in on paint for the second one ).
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0
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It seems to me that, in the first question, the $+$ signs indicate that they are of the form
$dfracaleft(dfrac bc right) $
In the second question, I really can't tell.
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
accepted
The division is in fact not ambiguous in those questions if you look very closely at the sizes of the vinculums( the line between numerator and denominator) it can be seen that one is larger than the other, granted it could stand to be much clearer ( i had to zoom in on paint for the second one ).
add a comment |Â
up vote
0
down vote
accepted
The division is in fact not ambiguous in those questions if you look very closely at the sizes of the vinculums( the line between numerator and denominator) it can be seen that one is larger than the other, granted it could stand to be much clearer ( i had to zoom in on paint for the second one ).
add a comment |Â
up vote
0
down vote
accepted
up vote
0
down vote
accepted
The division is in fact not ambiguous in those questions if you look very closely at the sizes of the vinculums( the line between numerator and denominator) it can be seen that one is larger than the other, granted it could stand to be much clearer ( i had to zoom in on paint for the second one ).
The division is in fact not ambiguous in those questions if you look very closely at the sizes of the vinculums( the line between numerator and denominator) it can be seen that one is larger than the other, granted it could stand to be much clearer ( i had to zoom in on paint for the second one ).
answered Aug 24 at 2:41
Ryski
314
314
add a comment |Â
add a comment |Â
up vote
0
down vote
It seems to me that, in the first question, the $+$ signs indicate that they are of the form
$dfracaleft(dfrac bc right) $
In the second question, I really can't tell.
add a comment |Â
up vote
0
down vote
It seems to me that, in the first question, the $+$ signs indicate that they are of the form
$dfracaleft(dfrac bc right) $
In the second question, I really can't tell.
add a comment |Â
up vote
0
down vote
up vote
0
down vote
It seems to me that, in the first question, the $+$ signs indicate that they are of the form
$dfracaleft(dfrac bc right) $
In the second question, I really can't tell.
It seems to me that, in the first question, the $+$ signs indicate that they are of the form
$dfracaleft(dfrac bc right) $
In the second question, I really can't tell.
edited Aug 24 at 23:53
answered Aug 24 at 23:47
steven gregory
16.7k22155
16.7k22155
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add a comment |Â
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