Can this notation be used to describe relations that are not functions?

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I have only seen the notation $f : A rightarrow B$ used for discussing functions. Can this notation be used for relations that are not functions?



For example, $tan : mathbb R rightarrow mathbb R$ appears to define a relation that is not left-total (for example $frac pi 2in mathbb R$ is not mapped to anything in codomain $mathbb R$) and hence not a function. Would it be incorrect to express this relation, that is not a function, using this notation?



Edit: To borrow a great example from Arthur's answer below, consider the notation $le; : mathbb R rightarrow mathbb R$. This seems to me to unambiguously express a relation that, while left-total is certainly not functional (e.g. $(3, 3), (3, 4) in ;le$) and hence not a function. If it's unambiguous, surely this notation can be used to express this relation that is not a function...



I guess I could express my question more clearly as: is there anything in the expression $f:Arightarrow B$ that asserts that $f$ is not merely a relation but specifically a function?







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    up vote
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    down vote

    favorite












    I have only seen the notation $f : A rightarrow B$ used for discussing functions. Can this notation be used for relations that are not functions?



    For example, $tan : mathbb R rightarrow mathbb R$ appears to define a relation that is not left-total (for example $frac pi 2in mathbb R$ is not mapped to anything in codomain $mathbb R$) and hence not a function. Would it be incorrect to express this relation, that is not a function, using this notation?



    Edit: To borrow a great example from Arthur's answer below, consider the notation $le; : mathbb R rightarrow mathbb R$. This seems to me to unambiguously express a relation that, while left-total is certainly not functional (e.g. $(3, 3), (3, 4) in ;le$) and hence not a function. If it's unambiguous, surely this notation can be used to express this relation that is not a function...



    I guess I could express my question more clearly as: is there anything in the expression $f:Arightarrow B$ that asserts that $f$ is not merely a relation but specifically a function?







    share|cite|improve this question
























      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      I have only seen the notation $f : A rightarrow B$ used for discussing functions. Can this notation be used for relations that are not functions?



      For example, $tan : mathbb R rightarrow mathbb R$ appears to define a relation that is not left-total (for example $frac pi 2in mathbb R$ is not mapped to anything in codomain $mathbb R$) and hence not a function. Would it be incorrect to express this relation, that is not a function, using this notation?



      Edit: To borrow a great example from Arthur's answer below, consider the notation $le; : mathbb R rightarrow mathbb R$. This seems to me to unambiguously express a relation that, while left-total is certainly not functional (e.g. $(3, 3), (3, 4) in ;le$) and hence not a function. If it's unambiguous, surely this notation can be used to express this relation that is not a function...



      I guess I could express my question more clearly as: is there anything in the expression $f:Arightarrow B$ that asserts that $f$ is not merely a relation but specifically a function?







      share|cite|improve this question














      I have only seen the notation $f : A rightarrow B$ used for discussing functions. Can this notation be used for relations that are not functions?



      For example, $tan : mathbb R rightarrow mathbb R$ appears to define a relation that is not left-total (for example $frac pi 2in mathbb R$ is not mapped to anything in codomain $mathbb R$) and hence not a function. Would it be incorrect to express this relation, that is not a function, using this notation?



      Edit: To borrow a great example from Arthur's answer below, consider the notation $le; : mathbb R rightarrow mathbb R$. This seems to me to unambiguously express a relation that, while left-total is certainly not functional (e.g. $(3, 3), (3, 4) in ;le$) and hence not a function. If it's unambiguous, surely this notation can be used to express this relation that is not a function...



      I guess I could express my question more clearly as: is there anything in the expression $f:Arightarrow B$ that asserts that $f$ is not merely a relation but specifically a function?









      share|cite|improve this question













      share|cite|improve this question




      share|cite|improve this question








      edited Aug 24 at 7:39

























      asked Aug 24 at 7:11









      Richard Ambler

      1,026514




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          2 Answers
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          There is a category of relations having sets as objects and binary relations as arrows.



          In that context the notation: $$R:Ato B$$ where $Rsubseteq Atimes B$, is fine.




          In my view (somewhat coloured by categories) the expression $f:Ato B$ on its own is not enough to state that we are dealing with a function (or a relation).



          I do recognize it as an arrow in a category and the context must make clear which category.



          So my answer to your last question is: "no".






          share|cite|improve this answer





























            up vote
            2
            down vote













            An entirely correct way would be $tansubseteq Bbb RtimesBbb R$. I think $tan: Bbb RtoBbb R$ would be considered technically incorrect but in many circumstances within allowable abuse of notation, mostly because $tan$ is still a partial function defined on most of the given domain. Writing something like $leq:Bbb RtoBbb R$ is probably taking it too far.






            share|cite|improve this answer


















            • 1




              Rather then "function-like" would "Partial function" be more useful?
              – Q the Platypus
              Aug 24 at 7:21










            • @QthePlatypus You're right. I fixed it up.
              – Arthur
              Aug 24 at 7:22










            • Hmm. I think the $tan$ you are referring to (when you say it is a subset of $mathbb R times mathbb R$) is not just function-like, but a function in all senses, because $frac pi 2$, for example, is (usually implicitly) not part of the domain. In my example I explicitly said that the domain was the entire $mathbb R$... My example is not the relation we generally understand by $tan$ stated on its own.
              – Richard Ambler
              Aug 24 at 7:23











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            2 Answers
            2






            active

            oldest

            votes








            2 Answers
            2






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes








            up vote
            4
            down vote



            accepted










            There is a category of relations having sets as objects and binary relations as arrows.



            In that context the notation: $$R:Ato B$$ where $Rsubseteq Atimes B$, is fine.




            In my view (somewhat coloured by categories) the expression $f:Ato B$ on its own is not enough to state that we are dealing with a function (or a relation).



            I do recognize it as an arrow in a category and the context must make clear which category.



            So my answer to your last question is: "no".






            share|cite|improve this answer


























              up vote
              4
              down vote



              accepted










              There is a category of relations having sets as objects and binary relations as arrows.



              In that context the notation: $$R:Ato B$$ where $Rsubseteq Atimes B$, is fine.




              In my view (somewhat coloured by categories) the expression $f:Ato B$ on its own is not enough to state that we are dealing with a function (or a relation).



              I do recognize it as an arrow in a category and the context must make clear which category.



              So my answer to your last question is: "no".






              share|cite|improve this answer
























                up vote
                4
                down vote



                accepted







                up vote
                4
                down vote



                accepted






                There is a category of relations having sets as objects and binary relations as arrows.



                In that context the notation: $$R:Ato B$$ where $Rsubseteq Atimes B$, is fine.




                In my view (somewhat coloured by categories) the expression $f:Ato B$ on its own is not enough to state that we are dealing with a function (or a relation).



                I do recognize it as an arrow in a category and the context must make clear which category.



                So my answer to your last question is: "no".






                share|cite|improve this answer














                There is a category of relations having sets as objects and binary relations as arrows.



                In that context the notation: $$R:Ato B$$ where $Rsubseteq Atimes B$, is fine.




                In my view (somewhat coloured by categories) the expression $f:Ato B$ on its own is not enough to state that we are dealing with a function (or a relation).



                I do recognize it as an arrow in a category and the context must make clear which category.



                So my answer to your last question is: "no".







                share|cite|improve this answer














                share|cite|improve this answer



                share|cite|improve this answer








                edited Aug 24 at 7:51

























                answered Aug 24 at 7:40









                drhab

                88.3k541120




                88.3k541120




















                    up vote
                    2
                    down vote













                    An entirely correct way would be $tansubseteq Bbb RtimesBbb R$. I think $tan: Bbb RtoBbb R$ would be considered technically incorrect but in many circumstances within allowable abuse of notation, mostly because $tan$ is still a partial function defined on most of the given domain. Writing something like $leq:Bbb RtoBbb R$ is probably taking it too far.






                    share|cite|improve this answer


















                    • 1




                      Rather then "function-like" would "Partial function" be more useful?
                      – Q the Platypus
                      Aug 24 at 7:21










                    • @QthePlatypus You're right. I fixed it up.
                      – Arthur
                      Aug 24 at 7:22










                    • Hmm. I think the $tan$ you are referring to (when you say it is a subset of $mathbb R times mathbb R$) is not just function-like, but a function in all senses, because $frac pi 2$, for example, is (usually implicitly) not part of the domain. In my example I explicitly said that the domain was the entire $mathbb R$... My example is not the relation we generally understand by $tan$ stated on its own.
                      – Richard Ambler
                      Aug 24 at 7:23















                    up vote
                    2
                    down vote













                    An entirely correct way would be $tansubseteq Bbb RtimesBbb R$. I think $tan: Bbb RtoBbb R$ would be considered technically incorrect but in many circumstances within allowable abuse of notation, mostly because $tan$ is still a partial function defined on most of the given domain. Writing something like $leq:Bbb RtoBbb R$ is probably taking it too far.






                    share|cite|improve this answer


















                    • 1




                      Rather then "function-like" would "Partial function" be more useful?
                      – Q the Platypus
                      Aug 24 at 7:21










                    • @QthePlatypus You're right. I fixed it up.
                      – Arthur
                      Aug 24 at 7:22










                    • Hmm. I think the $tan$ you are referring to (when you say it is a subset of $mathbb R times mathbb R$) is not just function-like, but a function in all senses, because $frac pi 2$, for example, is (usually implicitly) not part of the domain. In my example I explicitly said that the domain was the entire $mathbb R$... My example is not the relation we generally understand by $tan$ stated on its own.
                      – Richard Ambler
                      Aug 24 at 7:23













                    up vote
                    2
                    down vote










                    up vote
                    2
                    down vote









                    An entirely correct way would be $tansubseteq Bbb RtimesBbb R$. I think $tan: Bbb RtoBbb R$ would be considered technically incorrect but in many circumstances within allowable abuse of notation, mostly because $tan$ is still a partial function defined on most of the given domain. Writing something like $leq:Bbb RtoBbb R$ is probably taking it too far.






                    share|cite|improve this answer














                    An entirely correct way would be $tansubseteq Bbb RtimesBbb R$. I think $tan: Bbb RtoBbb R$ would be considered technically incorrect but in many circumstances within allowable abuse of notation, mostly because $tan$ is still a partial function defined on most of the given domain. Writing something like $leq:Bbb RtoBbb R$ is probably taking it too far.







                    share|cite|improve this answer














                    share|cite|improve this answer



                    share|cite|improve this answer








                    edited Aug 24 at 7:22

























                    answered Aug 24 at 7:16









                    Arthur

                    101k795176




                    101k795176







                    • 1




                      Rather then "function-like" would "Partial function" be more useful?
                      – Q the Platypus
                      Aug 24 at 7:21










                    • @QthePlatypus You're right. I fixed it up.
                      – Arthur
                      Aug 24 at 7:22










                    • Hmm. I think the $tan$ you are referring to (when you say it is a subset of $mathbb R times mathbb R$) is not just function-like, but a function in all senses, because $frac pi 2$, for example, is (usually implicitly) not part of the domain. In my example I explicitly said that the domain was the entire $mathbb R$... My example is not the relation we generally understand by $tan$ stated on its own.
                      – Richard Ambler
                      Aug 24 at 7:23













                    • 1




                      Rather then "function-like" would "Partial function" be more useful?
                      – Q the Platypus
                      Aug 24 at 7:21










                    • @QthePlatypus You're right. I fixed it up.
                      – Arthur
                      Aug 24 at 7:22










                    • Hmm. I think the $tan$ you are referring to (when you say it is a subset of $mathbb R times mathbb R$) is not just function-like, but a function in all senses, because $frac pi 2$, for example, is (usually implicitly) not part of the domain. In my example I explicitly said that the domain was the entire $mathbb R$... My example is not the relation we generally understand by $tan$ stated on its own.
                      – Richard Ambler
                      Aug 24 at 7:23








                    1




                    1




                    Rather then "function-like" would "Partial function" be more useful?
                    – Q the Platypus
                    Aug 24 at 7:21




                    Rather then "function-like" would "Partial function" be more useful?
                    – Q the Platypus
                    Aug 24 at 7:21












                    @QthePlatypus You're right. I fixed it up.
                    – Arthur
                    Aug 24 at 7:22




                    @QthePlatypus You're right. I fixed it up.
                    – Arthur
                    Aug 24 at 7:22












                    Hmm. I think the $tan$ you are referring to (when you say it is a subset of $mathbb R times mathbb R$) is not just function-like, but a function in all senses, because $frac pi 2$, for example, is (usually implicitly) not part of the domain. In my example I explicitly said that the domain was the entire $mathbb R$... My example is not the relation we generally understand by $tan$ stated on its own.
                    – Richard Ambler
                    Aug 24 at 7:23





                    Hmm. I think the $tan$ you are referring to (when you say it is a subset of $mathbb R times mathbb R$) is not just function-like, but a function in all senses, because $frac pi 2$, for example, is (usually implicitly) not part of the domain. In my example I explicitly said that the domain was the entire $mathbb R$... My example is not the relation we generally understand by $tan$ stated on its own.
                    – Richard Ambler
                    Aug 24 at 7:23


















                     

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