Existence of Bounded Approximate Identities for Modules of a Normed Algebra

The name of the pictureThe name of the pictureThe name of the pictureClash Royale CLAN TAG#URR8PPP











up vote
0
down vote

favorite












In Chapter 11 of "Complete Normed Algebras" by Bonsall and Duncan, the following definitions are given:



Definition Let $ A $ be a normed algebra. A Bounded Approximate Identity for $ A $ is a bounded net $ e(lambda) $ in $ A $ such that $ e(lambda)a oversetlambda to a $ and $ ae(lambda) oversetlambda to a $ for each $ a in A $.



Definition Let $ A $ be a normed algebra and let $ X $ be a normed $ A $-module. A Bounded Approximate Identity in $ A $ for $ X $ is a bounded net $ e(lambda) $ in $ A $ such that $ e(lambda)x oversetlambda to x $ and $ xe(lambda) oversetlambda to x $ for each $ x in X $.



My question is, if $ A $ is a normed algebra that has a bounded approximate identity, then must it have a bounded approximate identity for each of its normed $ A $-modules?



Is it true if $ A $ is a Banach algebra and $ X $ is a Banach $ A $-module?







share|cite|improve this question




















  • Are you sure your second definition (for modules) is correct? I don't have the book with me at the moment, but modules are typically one-sided...
    – zipirovich
    Aug 19 at 4:12










  • Perhaps my definition is wrong. I assumed that the definition of a left bounded approximate identity in $ A $ for a left normed $ A $-module and a right bounded approximate in $ A $ for a right normed $ A $-module would naturally extend to a "bounded approximate identity in $ A $" for a normed $ A $-bimodule/module. Is this wrong?
    – LMW
    Aug 19 at 5:39










  • Of course, we can speak of bimodules, but you didn't say so -- you only said that $X$ is a module. And even then, i.e. if $X$ is an $A$-$A$-bimodule, things may work differently from the two sides.
    – zipirovich
    Aug 19 at 5:43










  • Hm, I thought the terms "module" and "bimodule" were synonymous.
    – LMW
    Aug 19 at 6:04














up vote
0
down vote

favorite












In Chapter 11 of "Complete Normed Algebras" by Bonsall and Duncan, the following definitions are given:



Definition Let $ A $ be a normed algebra. A Bounded Approximate Identity for $ A $ is a bounded net $ e(lambda) $ in $ A $ such that $ e(lambda)a oversetlambda to a $ and $ ae(lambda) oversetlambda to a $ for each $ a in A $.



Definition Let $ A $ be a normed algebra and let $ X $ be a normed $ A $-module. A Bounded Approximate Identity in $ A $ for $ X $ is a bounded net $ e(lambda) $ in $ A $ such that $ e(lambda)x oversetlambda to x $ and $ xe(lambda) oversetlambda to x $ for each $ x in X $.



My question is, if $ A $ is a normed algebra that has a bounded approximate identity, then must it have a bounded approximate identity for each of its normed $ A $-modules?



Is it true if $ A $ is a Banach algebra and $ X $ is a Banach $ A $-module?







share|cite|improve this question




















  • Are you sure your second definition (for modules) is correct? I don't have the book with me at the moment, but modules are typically one-sided...
    – zipirovich
    Aug 19 at 4:12










  • Perhaps my definition is wrong. I assumed that the definition of a left bounded approximate identity in $ A $ for a left normed $ A $-module and a right bounded approximate in $ A $ for a right normed $ A $-module would naturally extend to a "bounded approximate identity in $ A $" for a normed $ A $-bimodule/module. Is this wrong?
    – LMW
    Aug 19 at 5:39










  • Of course, we can speak of bimodules, but you didn't say so -- you only said that $X$ is a module. And even then, i.e. if $X$ is an $A$-$A$-bimodule, things may work differently from the two sides.
    – zipirovich
    Aug 19 at 5:43










  • Hm, I thought the terms "module" and "bimodule" were synonymous.
    – LMW
    Aug 19 at 6:04












up vote
0
down vote

favorite









up vote
0
down vote

favorite











In Chapter 11 of "Complete Normed Algebras" by Bonsall and Duncan, the following definitions are given:



Definition Let $ A $ be a normed algebra. A Bounded Approximate Identity for $ A $ is a bounded net $ e(lambda) $ in $ A $ such that $ e(lambda)a oversetlambda to a $ and $ ae(lambda) oversetlambda to a $ for each $ a in A $.



Definition Let $ A $ be a normed algebra and let $ X $ be a normed $ A $-module. A Bounded Approximate Identity in $ A $ for $ X $ is a bounded net $ e(lambda) $ in $ A $ such that $ e(lambda)x oversetlambda to x $ and $ xe(lambda) oversetlambda to x $ for each $ x in X $.



My question is, if $ A $ is a normed algebra that has a bounded approximate identity, then must it have a bounded approximate identity for each of its normed $ A $-modules?



Is it true if $ A $ is a Banach algebra and $ X $ is a Banach $ A $-module?







share|cite|improve this question












In Chapter 11 of "Complete Normed Algebras" by Bonsall and Duncan, the following definitions are given:



Definition Let $ A $ be a normed algebra. A Bounded Approximate Identity for $ A $ is a bounded net $ e(lambda) $ in $ A $ such that $ e(lambda)a oversetlambda to a $ and $ ae(lambda) oversetlambda to a $ for each $ a in A $.



Definition Let $ A $ be a normed algebra and let $ X $ be a normed $ A $-module. A Bounded Approximate Identity in $ A $ for $ X $ is a bounded net $ e(lambda) $ in $ A $ such that $ e(lambda)x oversetlambda to x $ and $ xe(lambda) oversetlambda to x $ for each $ x in X $.



My question is, if $ A $ is a normed algebra that has a bounded approximate identity, then must it have a bounded approximate identity for each of its normed $ A $-modules?



Is it true if $ A $ is a Banach algebra and $ X $ is a Banach $ A $-module?









share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Aug 19 at 3:32









LMW

987




987











  • Are you sure your second definition (for modules) is correct? I don't have the book with me at the moment, but modules are typically one-sided...
    – zipirovich
    Aug 19 at 4:12










  • Perhaps my definition is wrong. I assumed that the definition of a left bounded approximate identity in $ A $ for a left normed $ A $-module and a right bounded approximate in $ A $ for a right normed $ A $-module would naturally extend to a "bounded approximate identity in $ A $" for a normed $ A $-bimodule/module. Is this wrong?
    – LMW
    Aug 19 at 5:39










  • Of course, we can speak of bimodules, but you didn't say so -- you only said that $X$ is a module. And even then, i.e. if $X$ is an $A$-$A$-bimodule, things may work differently from the two sides.
    – zipirovich
    Aug 19 at 5:43










  • Hm, I thought the terms "module" and "bimodule" were synonymous.
    – LMW
    Aug 19 at 6:04
















  • Are you sure your second definition (for modules) is correct? I don't have the book with me at the moment, but modules are typically one-sided...
    – zipirovich
    Aug 19 at 4:12










  • Perhaps my definition is wrong. I assumed that the definition of a left bounded approximate identity in $ A $ for a left normed $ A $-module and a right bounded approximate in $ A $ for a right normed $ A $-module would naturally extend to a "bounded approximate identity in $ A $" for a normed $ A $-bimodule/module. Is this wrong?
    – LMW
    Aug 19 at 5:39










  • Of course, we can speak of bimodules, but you didn't say so -- you only said that $X$ is a module. And even then, i.e. if $X$ is an $A$-$A$-bimodule, things may work differently from the two sides.
    – zipirovich
    Aug 19 at 5:43










  • Hm, I thought the terms "module" and "bimodule" were synonymous.
    – LMW
    Aug 19 at 6:04















Are you sure your second definition (for modules) is correct? I don't have the book with me at the moment, but modules are typically one-sided...
– zipirovich
Aug 19 at 4:12




Are you sure your second definition (for modules) is correct? I don't have the book with me at the moment, but modules are typically one-sided...
– zipirovich
Aug 19 at 4:12












Perhaps my definition is wrong. I assumed that the definition of a left bounded approximate identity in $ A $ for a left normed $ A $-module and a right bounded approximate in $ A $ for a right normed $ A $-module would naturally extend to a "bounded approximate identity in $ A $" for a normed $ A $-bimodule/module. Is this wrong?
– LMW
Aug 19 at 5:39




Perhaps my definition is wrong. I assumed that the definition of a left bounded approximate identity in $ A $ for a left normed $ A $-module and a right bounded approximate in $ A $ for a right normed $ A $-module would naturally extend to a "bounded approximate identity in $ A $" for a normed $ A $-bimodule/module. Is this wrong?
– LMW
Aug 19 at 5:39












Of course, we can speak of bimodules, but you didn't say so -- you only said that $X$ is a module. And even then, i.e. if $X$ is an $A$-$A$-bimodule, things may work differently from the two sides.
– zipirovich
Aug 19 at 5:43




Of course, we can speak of bimodules, but you didn't say so -- you only said that $X$ is a module. And even then, i.e. if $X$ is an $A$-$A$-bimodule, things may work differently from the two sides.
– zipirovich
Aug 19 at 5:43












Hm, I thought the terms "module" and "bimodule" were synonymous.
– LMW
Aug 19 at 6:04




Hm, I thought the terms "module" and "bimodule" were synonymous.
– LMW
Aug 19 at 6:04















active

oldest

votes











Your Answer




StackExchange.ifUsing("editor", function ()
return StackExchange.using("mathjaxEditing", function ()
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix)
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
);
);
, "mathjax-editing");

StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "69"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);

else
createEditor();

);

function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
convertImagesToLinks: true,
noModals: false,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);



);








 

draft saved


draft discarded


















StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f2887327%2fexistence-of-bounded-approximate-identities-for-modules-of-a-normed-algebra%23new-answer', 'question_page');

);

Post as a guest



































active

oldest

votes













active

oldest

votes









active

oldest

votes






active

oldest

votes










 

draft saved


draft discarded


























 


draft saved


draft discarded














StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f2887327%2fexistence-of-bounded-approximate-identities-for-modules-of-a-normed-algebra%23new-answer', 'question_page');

);

Post as a guest













































































這個網誌中的熱門文章

tkz-euclide: tkzDrawCircle[R] not working

How to combine Bézier curves to a surface?

1st Magritte Awards