Extending inner product from subspace to whole space

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Suppose that V is a vector space over either R or C, W is a
subspace of V , and we are given an inner product on W. Show that there
is at least one way to extend this function to an inner product on all of
V . Do not assume that V is finite-dimensional.



My best guess is saying V=W+U f(u+w)=w where f linear but that gives then $langle f(u+w),f(u+w) rangle$=0 if v is an element u or or v=0 which contradicts one of the axioms of an inner product







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    Suppose that V is a vector space over either R or C, W is a
    subspace of V , and we are given an inner product on W. Show that there
    is at least one way to extend this function to an inner product on all of
    V . Do not assume that V is finite-dimensional.



    My best guess is saying V=W+U f(u+w)=w where f linear but that gives then $langle f(u+w),f(u+w) rangle$=0 if v is an element u or or v=0 which contradicts one of the axioms of an inner product







    share|cite|improve this question






















      up vote
      -1
      down vote

      favorite









      up vote
      -1
      down vote

      favorite











      Suppose that V is a vector space over either R or C, W is a
      subspace of V , and we are given an inner product on W. Show that there
      is at least one way to extend this function to an inner product on all of
      V . Do not assume that V is finite-dimensional.



      My best guess is saying V=W+U f(u+w)=w where f linear but that gives then $langle f(u+w),f(u+w) rangle$=0 if v is an element u or or v=0 which contradicts one of the axioms of an inner product







      share|cite|improve this question












      Suppose that V is a vector space over either R or C, W is a
      subspace of V , and we are given an inner product on W. Show that there
      is at least one way to extend this function to an inner product on all of
      V . Do not assume that V is finite-dimensional.



      My best guess is saying V=W+U f(u+w)=w where f linear but that gives then $langle f(u+w),f(u+w) rangle$=0 if v is an element u or or v=0 which contradicts one of the axioms of an inner product









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      asked Aug 17 at 22:13









      user3555068

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          Take a subspace $W'$ of $V$ such that $V=Wbigoplus W'$. Define an inner product $g$ on $W'$. If $f$ is the inner product on $W$, you can extend it to the whole space by$$langle v+v',w+w'rangle=f(v,w)+g(v',w').$$






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            1 Answer
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            1 Answer
            1






            active

            oldest

            votes









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            oldest

            votes






            active

            oldest

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            up vote
            1
            down vote



            accepted










            Take a subspace $W'$ of $V$ such that $V=Wbigoplus W'$. Define an inner product $g$ on $W'$. If $f$ is the inner product on $W$, you can extend it to the whole space by$$langle v+v',w+w'rangle=f(v,w)+g(v',w').$$






            share|cite|improve this answer


























              up vote
              1
              down vote



              accepted










              Take a subspace $W'$ of $V$ such that $V=Wbigoplus W'$. Define an inner product $g$ on $W'$. If $f$ is the inner product on $W$, you can extend it to the whole space by$$langle v+v',w+w'rangle=f(v,w)+g(v',w').$$






              share|cite|improve this answer
























                up vote
                1
                down vote



                accepted







                up vote
                1
                down vote



                accepted






                Take a subspace $W'$ of $V$ such that $V=Wbigoplus W'$. Define an inner product $g$ on $W'$. If $f$ is the inner product on $W$, you can extend it to the whole space by$$langle v+v',w+w'rangle=f(v,w)+g(v',w').$$






                share|cite|improve this answer














                Take a subspace $W'$ of $V$ such that $V=Wbigoplus W'$. Define an inner product $g$ on $W'$. If $f$ is the inner product on $W$, you can extend it to the whole space by$$langle v+v',w+w'rangle=f(v,w)+g(v',w').$$







                share|cite|improve this answer














                share|cite|improve this answer



                share|cite|improve this answer








                edited Aug 17 at 22:29

























                answered Aug 17 at 22:23









                José Carlos Santos

                117k16101180




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