Time gap between two cars
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Lets say there is car A which average speed is 20 m/s and is ahead of car b by 200 meters while car b average speed is 21 m/s and both are on a racing track that is 1700 meters in length. what is time gap between them? by time gap I mean by how many seconds.
Notice their average speed isn't constant and can vary.
How do I solve this and what formula should I use?
calculus real-analysis physics
 |Â
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up vote
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down vote
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Lets say there is car A which average speed is 20 m/s and is ahead of car b by 200 meters while car b average speed is 21 m/s and both are on a racing track that is 1700 meters in length. what is time gap between them? by time gap I mean by how many seconds.
Notice their average speed isn't constant and can vary.
How do I solve this and what formula should I use?
calculus real-analysis physics
Welcome to Mathematics Stack Exchange !! We are here to help you with any kind of mathematical problems, but you have to show what you have tried. :)
â Anik Bhowmick
Aug 18 at 9:35
You have to define "time gap" - there are two plausible meanings.
â Craig Hicks
Aug 18 at 9:35
@craig I mean like how many seconds between them or the interval
â user7716943
Aug 18 at 9:41
For example, if $A$ is at the finish line now, then how many seconds until until $B$ crosses the finish line - is that your question? (As opposed to how long it takes for $A$ to catch up to $B$).
â Craig Hicks
Aug 18 at 9:47
You can define $t_g=fracdv_B-v_A=frac20021-20=200$ as the time that car B would need to reach car A if no condition changes.
â N74
Aug 18 at 9:51
 |Â
show 1 more comment
up vote
-1
down vote
favorite
up vote
-1
down vote
favorite
Lets say there is car A which average speed is 20 m/s and is ahead of car b by 200 meters while car b average speed is 21 m/s and both are on a racing track that is 1700 meters in length. what is time gap between them? by time gap I mean by how many seconds.
Notice their average speed isn't constant and can vary.
How do I solve this and what formula should I use?
calculus real-analysis physics
Lets say there is car A which average speed is 20 m/s and is ahead of car b by 200 meters while car b average speed is 21 m/s and both are on a racing track that is 1700 meters in length. what is time gap between them? by time gap I mean by how many seconds.
Notice their average speed isn't constant and can vary.
How do I solve this and what formula should I use?
calculus real-analysis physics
edited Aug 18 at 9:38
asked Aug 18 at 9:30
user7716943
11
11
Welcome to Mathematics Stack Exchange !! We are here to help you with any kind of mathematical problems, but you have to show what you have tried. :)
â Anik Bhowmick
Aug 18 at 9:35
You have to define "time gap" - there are two plausible meanings.
â Craig Hicks
Aug 18 at 9:35
@craig I mean like how many seconds between them or the interval
â user7716943
Aug 18 at 9:41
For example, if $A$ is at the finish line now, then how many seconds until until $B$ crosses the finish line - is that your question? (As opposed to how long it takes for $A$ to catch up to $B$).
â Craig Hicks
Aug 18 at 9:47
You can define $t_g=fracdv_B-v_A=frac20021-20=200$ as the time that car B would need to reach car A if no condition changes.
â N74
Aug 18 at 9:51
 |Â
show 1 more comment
Welcome to Mathematics Stack Exchange !! We are here to help you with any kind of mathematical problems, but you have to show what you have tried. :)
â Anik Bhowmick
Aug 18 at 9:35
You have to define "time gap" - there are two plausible meanings.
â Craig Hicks
Aug 18 at 9:35
@craig I mean like how many seconds between them or the interval
â user7716943
Aug 18 at 9:41
For example, if $A$ is at the finish line now, then how many seconds until until $B$ crosses the finish line - is that your question? (As opposed to how long it takes for $A$ to catch up to $B$).
â Craig Hicks
Aug 18 at 9:47
You can define $t_g=fracdv_B-v_A=frac20021-20=200$ as the time that car B would need to reach car A if no condition changes.
â N74
Aug 18 at 9:51
Welcome to Mathematics Stack Exchange !! We are here to help you with any kind of mathematical problems, but you have to show what you have tried. :)
â Anik Bhowmick
Aug 18 at 9:35
Welcome to Mathematics Stack Exchange !! We are here to help you with any kind of mathematical problems, but you have to show what you have tried. :)
â Anik Bhowmick
Aug 18 at 9:35
You have to define "time gap" - there are two plausible meanings.
â Craig Hicks
Aug 18 at 9:35
You have to define "time gap" - there are two plausible meanings.
â Craig Hicks
Aug 18 at 9:35
@craig I mean like how many seconds between them or the interval
â user7716943
Aug 18 at 9:41
@craig I mean like how many seconds between them or the interval
â user7716943
Aug 18 at 9:41
For example, if $A$ is at the finish line now, then how many seconds until until $B$ crosses the finish line - is that your question? (As opposed to how long it takes for $A$ to catch up to $B$).
â Craig Hicks
Aug 18 at 9:47
For example, if $A$ is at the finish line now, then how many seconds until until $B$ crosses the finish line - is that your question? (As opposed to how long it takes for $A$ to catch up to $B$).
â Craig Hicks
Aug 18 at 9:47
You can define $t_g=fracdv_B-v_A=frac20021-20=200$ as the time that car B would need to reach car A if no condition changes.
â N74
Aug 18 at 9:51
You can define $t_g=fracdv_B-v_A=frac20021-20=200$ as the time that car B would need to reach car A if no condition changes.
â N74
Aug 18 at 9:51
 |Â
show 1 more comment
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Welcome to Mathematics Stack Exchange !! We are here to help you with any kind of mathematical problems, but you have to show what you have tried. :)
â Anik Bhowmick
Aug 18 at 9:35
You have to define "time gap" - there are two plausible meanings.
â Craig Hicks
Aug 18 at 9:35
@craig I mean like how many seconds between them or the interval
â user7716943
Aug 18 at 9:41
For example, if $A$ is at the finish line now, then how many seconds until until $B$ crosses the finish line - is that your question? (As opposed to how long it takes for $A$ to catch up to $B$).
â Craig Hicks
Aug 18 at 9:47
You can define $t_g=fracdv_B-v_A=frac20021-20=200$ as the time that car B would need to reach car A if no condition changes.
â N74
Aug 18 at 9:51