I am not being able to solve this problem of Continuity. [closed]
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Prove that $[x] sin^2(pi x)$ is continuous at every integer point and
$[x] cos^2 (pi x)$ is discontinuous at every integer point.
real-analysis continuity discontinuous-functions
closed as off-topic by Andrés E. Caicedo, José Carlos Santos, Tanner Swett, amWhy, Xander Henderson Aug 28 at 0:27
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." â José Carlos Santos, Tanner Swett, amWhy, Xander Henderson
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up vote
-2
down vote
favorite
Prove that $[x] sin^2(pi x)$ is continuous at every integer point and
$[x] cos^2 (pi x)$ is discontinuous at every integer point.
real-analysis continuity discontinuous-functions
closed as off-topic by Andrés E. Caicedo, José Carlos Santos, Tanner Swett, amWhy, Xander Henderson Aug 28 at 0:27
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." â José Carlos Santos, Tanner Swett, amWhy, Xander Henderson
What does $[x]$ mean?
â Arthur
Aug 27 at 14:07
Please use MathJax, I actually don't know what this [x] in brackets is supposed to denote.
â Luke
Aug 27 at 14:07
I'm guessing it should be the nearest integer to $x$.
â Sobi
Aug 27 at 14:11
It is common notation for the floor function, the greatest integer $leq x$.
â Clayton
Aug 27 at 14:20
add a comment |Â
up vote
-2
down vote
favorite
up vote
-2
down vote
favorite
Prove that $[x] sin^2(pi x)$ is continuous at every integer point and
$[x] cos^2 (pi x)$ is discontinuous at every integer point.
real-analysis continuity discontinuous-functions
Prove that $[x] sin^2(pi x)$ is continuous at every integer point and
$[x] cos^2 (pi x)$ is discontinuous at every integer point.
real-analysis continuity discontinuous-functions
edited Aug 27 at 14:20
Clayton
18.3k22883
18.3k22883
asked Aug 27 at 14:05
Sragdharamalini Das
227
227
closed as off-topic by Andrés E. Caicedo, José Carlos Santos, Tanner Swett, amWhy, Xander Henderson Aug 28 at 0:27
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." â José Carlos Santos, Tanner Swett, amWhy, Xander Henderson
closed as off-topic by Andrés E. Caicedo, José Carlos Santos, Tanner Swett, amWhy, Xander Henderson Aug 28 at 0:27
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." â José Carlos Santos, Tanner Swett, amWhy, Xander Henderson
What does $[x]$ mean?
â Arthur
Aug 27 at 14:07
Please use MathJax, I actually don't know what this [x] in brackets is supposed to denote.
â Luke
Aug 27 at 14:07
I'm guessing it should be the nearest integer to $x$.
â Sobi
Aug 27 at 14:11
It is common notation for the floor function, the greatest integer $leq x$.
â Clayton
Aug 27 at 14:20
add a comment |Â
What does $[x]$ mean?
â Arthur
Aug 27 at 14:07
Please use MathJax, I actually don't know what this [x] in brackets is supposed to denote.
â Luke
Aug 27 at 14:07
I'm guessing it should be the nearest integer to $x$.
â Sobi
Aug 27 at 14:11
It is common notation for the floor function, the greatest integer $leq x$.
â Clayton
Aug 27 at 14:20
What does $[x]$ mean?
â Arthur
Aug 27 at 14:07
What does $[x]$ mean?
â Arthur
Aug 27 at 14:07
Please use MathJax, I actually don't know what this [x] in brackets is supposed to denote.
â Luke
Aug 27 at 14:07
Please use MathJax, I actually don't know what this [x] in brackets is supposed to denote.
â Luke
Aug 27 at 14:07
I'm guessing it should be the nearest integer to $x$.
â Sobi
Aug 27 at 14:11
I'm guessing it should be the nearest integer to $x$.
â Sobi
Aug 27 at 14:11
It is common notation for the floor function, the greatest integer $leq x$.
â Clayton
Aug 27 at 14:20
It is common notation for the floor function, the greatest integer $leq x$.
â Clayton
Aug 27 at 14:20
add a comment |Â
1 Answer
1
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1
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accepted
Hint: $sin(pi x) = 0$ whenever $xinmathbbZ$ and $|cos(pi x)| = 1 not= 0$ whenever $x in mathbbZ.$
add a comment |Â
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
accepted
Hint: $sin(pi x) = 0$ whenever $xinmathbbZ$ and $|cos(pi x)| = 1 not= 0$ whenever $x in mathbbZ.$
add a comment |Â
up vote
1
down vote
accepted
Hint: $sin(pi x) = 0$ whenever $xinmathbbZ$ and $|cos(pi x)| = 1 not= 0$ whenever $x in mathbbZ.$
add a comment |Â
up vote
1
down vote
accepted
up vote
1
down vote
accepted
Hint: $sin(pi x) = 0$ whenever $xinmathbbZ$ and $|cos(pi x)| = 1 not= 0$ whenever $x in mathbbZ.$
Hint: $sin(pi x) = 0$ whenever $xinmathbbZ$ and $|cos(pi x)| = 1 not= 0$ whenever $x in mathbbZ.$
answered Aug 27 at 14:10
Sobi
2,428315
2,428315
add a comment |Â
add a comment |Â
What does $[x]$ mean?
â Arthur
Aug 27 at 14:07
Please use MathJax, I actually don't know what this [x] in brackets is supposed to denote.
â Luke
Aug 27 at 14:07
I'm guessing it should be the nearest integer to $x$.
â Sobi
Aug 27 at 14:11
It is common notation for the floor function, the greatest integer $leq x$.
â Clayton
Aug 27 at 14:20