Evaluate integral (Chern article)

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My question is evaluate some integral of the article "A Simple Intrinsic Proof of the Gauss-Bonnet Formula for Closed Riemannian Manifolds" write by Chern.
Let's go:
If $(M^n,g)$ is a closed even dimension Riemann manifold with $nabla$ Levi-Civita connection, we can write locally $nabla_X V = theta^i(X)e_i$, where $V = v^ie_i$, $theta^i = dv^i(X) + v^jomega_j^i$ and $omega_i^j$ connection forms. In the same way for Riemann curvature, we have $Omega_i^j$ curvature forms, satisfying $domega_i^j = omega_i^k wedge omega_k^j + Omega_i^j$.
So, pulling-back $theta_i$ and $Omega_i^j$ by $rho: SM rightarrow M$, where $SM$ is the unit-sphere bundle, we define two kind of intrinsic forms in $SM$, namely
$$Phi_k = sum_sigma in S_n sgn(sigma)v_sigma(1)theta_sigma(2) wedge cdots wedge theta_sigma(n-2k)wedgeOmega_sigma(n-2k+1)^sigma(n-2k+1)wedge cdots wedge Omega_sigma(n-1)^sigma(n)$$
and
$$ Psi_k = sum_sigma in S_n sgn(sigma) Omega_sigma(1)^sigma(2)wedgetheta_sigma(3)wedge cdots wedge theta_sigma(n-2k)wedgeOmega_sigma(n-2k+1)^sigma(n-2k+1)wedge cdots wedge Omega_sigma(n-1)^sigma(n)$$
$k = 0, cdots fracn2 -1 $. It's not too hard to show the following recurrent relation: $$ dPhi_k = Psi_k-1 + fracn - 2k - 12(k+1)Psi_k$$
Where $Psi_-1 equiv 0$.
Define the form, in $M$, $Omega = displaystyle (-1)^fracn2-1frac1(2pi)^fracn2Pf(Omega_i^j)$ (called Euler form), definition of Pfaffian polynomial here , obviously $rho^*Omega = displaystyle (-1)^fracn2-1frac12^npi^fracn2left(fracn2right)!Psi_fracn2-1$, write $Psi_fracn2-1$ in terms of $dPhi_k's$ we obtain $dPi = Omega$ in $SM$, with $Pi = displaystyle frac1pi^fracn2sum_t=0^fracn2-1(-1)^t frac11 cdot 3 cdots (n - 2t - 1)t!2^fracn2+tPhi_t$.
With some tricks and Stokes' theorem we show $$displaystyle int_M Omega = sum_i=1^sind_x_s(nabla_gf)int_SM_x_sPi|_SM_x_s $$
for $x_1, cdots, x_s$ singularities of $nabla_g f$, $f$ a Morse's function. I'd like $int_SM_x_s Pi|_SM_x_s = 1$ to use the Hopf index theorem.
In the paper, Chern claims $$ int_SM_x_s Pi|_SM_x_s = frac11cdot3 cdots (n-1)(2pi)^fracn2 int_SM_x_sPhi_0|_SM_x_s$$
and of course it's equal 1, essentially, I don't know why $ displaystyle int_SM_x_s Phi_k = 0$, for $k geq 1$.
Thanks!
differential-geometry riemannian-geometry differential-forms
add a comment |Â
up vote
6
down vote
favorite
My question is evaluate some integral of the article "A Simple Intrinsic Proof of the Gauss-Bonnet Formula for Closed Riemannian Manifolds" write by Chern.
Let's go:
If $(M^n,g)$ is a closed even dimension Riemann manifold with $nabla$ Levi-Civita connection, we can write locally $nabla_X V = theta^i(X)e_i$, where $V = v^ie_i$, $theta^i = dv^i(X) + v^jomega_j^i$ and $omega_i^j$ connection forms. In the same way for Riemann curvature, we have $Omega_i^j$ curvature forms, satisfying $domega_i^j = omega_i^k wedge omega_k^j + Omega_i^j$.
So, pulling-back $theta_i$ and $Omega_i^j$ by $rho: SM rightarrow M$, where $SM$ is the unit-sphere bundle, we define two kind of intrinsic forms in $SM$, namely
$$Phi_k = sum_sigma in S_n sgn(sigma)v_sigma(1)theta_sigma(2) wedge cdots wedge theta_sigma(n-2k)wedgeOmega_sigma(n-2k+1)^sigma(n-2k+1)wedge cdots wedge Omega_sigma(n-1)^sigma(n)$$
and
$$ Psi_k = sum_sigma in S_n sgn(sigma) Omega_sigma(1)^sigma(2)wedgetheta_sigma(3)wedge cdots wedge theta_sigma(n-2k)wedgeOmega_sigma(n-2k+1)^sigma(n-2k+1)wedge cdots wedge Omega_sigma(n-1)^sigma(n)$$
$k = 0, cdots fracn2 -1 $. It's not too hard to show the following recurrent relation: $$ dPhi_k = Psi_k-1 + fracn - 2k - 12(k+1)Psi_k$$
Where $Psi_-1 equiv 0$.
Define the form, in $M$, $Omega = displaystyle (-1)^fracn2-1frac1(2pi)^fracn2Pf(Omega_i^j)$ (called Euler form), definition of Pfaffian polynomial here , obviously $rho^*Omega = displaystyle (-1)^fracn2-1frac12^npi^fracn2left(fracn2right)!Psi_fracn2-1$, write $Psi_fracn2-1$ in terms of $dPhi_k's$ we obtain $dPi = Omega$ in $SM$, with $Pi = displaystyle frac1pi^fracn2sum_t=0^fracn2-1(-1)^t frac11 cdot 3 cdots (n - 2t - 1)t!2^fracn2+tPhi_t$.
With some tricks and Stokes' theorem we show $$displaystyle int_M Omega = sum_i=1^sind_x_s(nabla_gf)int_SM_x_sPi|_SM_x_s $$
for $x_1, cdots, x_s$ singularities of $nabla_g f$, $f$ a Morse's function. I'd like $int_SM_x_s Pi|_SM_x_s = 1$ to use the Hopf index theorem.
In the paper, Chern claims $$ int_SM_x_s Pi|_SM_x_s = frac11cdot3 cdots (n-1)(2pi)^fracn2 int_SM_x_sPhi_0|_SM_x_s$$
and of course it's equal 1, essentially, I don't know why $ displaystyle int_SM_x_s Phi_k = 0$, for $k geq 1$.
Thanks!
differential-geometry riemannian-geometry differential-forms
add a comment |Â
up vote
6
down vote
favorite
up vote
6
down vote
favorite
My question is evaluate some integral of the article "A Simple Intrinsic Proof of the Gauss-Bonnet Formula for Closed Riemannian Manifolds" write by Chern.
Let's go:
If $(M^n,g)$ is a closed even dimension Riemann manifold with $nabla$ Levi-Civita connection, we can write locally $nabla_X V = theta^i(X)e_i$, where $V = v^ie_i$, $theta^i = dv^i(X) + v^jomega_j^i$ and $omega_i^j$ connection forms. In the same way for Riemann curvature, we have $Omega_i^j$ curvature forms, satisfying $domega_i^j = omega_i^k wedge omega_k^j + Omega_i^j$.
So, pulling-back $theta_i$ and $Omega_i^j$ by $rho: SM rightarrow M$, where $SM$ is the unit-sphere bundle, we define two kind of intrinsic forms in $SM$, namely
$$Phi_k = sum_sigma in S_n sgn(sigma)v_sigma(1)theta_sigma(2) wedge cdots wedge theta_sigma(n-2k)wedgeOmega_sigma(n-2k+1)^sigma(n-2k+1)wedge cdots wedge Omega_sigma(n-1)^sigma(n)$$
and
$$ Psi_k = sum_sigma in S_n sgn(sigma) Omega_sigma(1)^sigma(2)wedgetheta_sigma(3)wedge cdots wedge theta_sigma(n-2k)wedgeOmega_sigma(n-2k+1)^sigma(n-2k+1)wedge cdots wedge Omega_sigma(n-1)^sigma(n)$$
$k = 0, cdots fracn2 -1 $. It's not too hard to show the following recurrent relation: $$ dPhi_k = Psi_k-1 + fracn - 2k - 12(k+1)Psi_k$$
Where $Psi_-1 equiv 0$.
Define the form, in $M$, $Omega = displaystyle (-1)^fracn2-1frac1(2pi)^fracn2Pf(Omega_i^j)$ (called Euler form), definition of Pfaffian polynomial here , obviously $rho^*Omega = displaystyle (-1)^fracn2-1frac12^npi^fracn2left(fracn2right)!Psi_fracn2-1$, write $Psi_fracn2-1$ in terms of $dPhi_k's$ we obtain $dPi = Omega$ in $SM$, with $Pi = displaystyle frac1pi^fracn2sum_t=0^fracn2-1(-1)^t frac11 cdot 3 cdots (n - 2t - 1)t!2^fracn2+tPhi_t$.
With some tricks and Stokes' theorem we show $$displaystyle int_M Omega = sum_i=1^sind_x_s(nabla_gf)int_SM_x_sPi|_SM_x_s $$
for $x_1, cdots, x_s$ singularities of $nabla_g f$, $f$ a Morse's function. I'd like $int_SM_x_s Pi|_SM_x_s = 1$ to use the Hopf index theorem.
In the paper, Chern claims $$ int_SM_x_s Pi|_SM_x_s = frac11cdot3 cdots (n-1)(2pi)^fracn2 int_SM_x_sPhi_0|_SM_x_s$$
and of course it's equal 1, essentially, I don't know why $ displaystyle int_SM_x_s Phi_k = 0$, for $k geq 1$.
Thanks!
differential-geometry riemannian-geometry differential-forms
My question is evaluate some integral of the article "A Simple Intrinsic Proof of the Gauss-Bonnet Formula for Closed Riemannian Manifolds" write by Chern.
Let's go:
If $(M^n,g)$ is a closed even dimension Riemann manifold with $nabla$ Levi-Civita connection, we can write locally $nabla_X V = theta^i(X)e_i$, where $V = v^ie_i$, $theta^i = dv^i(X) + v^jomega_j^i$ and $omega_i^j$ connection forms. In the same way for Riemann curvature, we have $Omega_i^j$ curvature forms, satisfying $domega_i^j = omega_i^k wedge omega_k^j + Omega_i^j$.
So, pulling-back $theta_i$ and $Omega_i^j$ by $rho: SM rightarrow M$, where $SM$ is the unit-sphere bundle, we define two kind of intrinsic forms in $SM$, namely
$$Phi_k = sum_sigma in S_n sgn(sigma)v_sigma(1)theta_sigma(2) wedge cdots wedge theta_sigma(n-2k)wedgeOmega_sigma(n-2k+1)^sigma(n-2k+1)wedge cdots wedge Omega_sigma(n-1)^sigma(n)$$
and
$$ Psi_k = sum_sigma in S_n sgn(sigma) Omega_sigma(1)^sigma(2)wedgetheta_sigma(3)wedge cdots wedge theta_sigma(n-2k)wedgeOmega_sigma(n-2k+1)^sigma(n-2k+1)wedge cdots wedge Omega_sigma(n-1)^sigma(n)$$
$k = 0, cdots fracn2 -1 $. It's not too hard to show the following recurrent relation: $$ dPhi_k = Psi_k-1 + fracn - 2k - 12(k+1)Psi_k$$
Where $Psi_-1 equiv 0$.
Define the form, in $M$, $Omega = displaystyle (-1)^fracn2-1frac1(2pi)^fracn2Pf(Omega_i^j)$ (called Euler form), definition of Pfaffian polynomial here , obviously $rho^*Omega = displaystyle (-1)^fracn2-1frac12^npi^fracn2left(fracn2right)!Psi_fracn2-1$, write $Psi_fracn2-1$ in terms of $dPhi_k's$ we obtain $dPi = Omega$ in $SM$, with $Pi = displaystyle frac1pi^fracn2sum_t=0^fracn2-1(-1)^t frac11 cdot 3 cdots (n - 2t - 1)t!2^fracn2+tPhi_t$.
With some tricks and Stokes' theorem we show $$displaystyle int_M Omega = sum_i=1^sind_x_s(nabla_gf)int_SM_x_sPi|_SM_x_s $$
for $x_1, cdots, x_s$ singularities of $nabla_g f$, $f$ a Morse's function. I'd like $int_SM_x_s Pi|_SM_x_s = 1$ to use the Hopf index theorem.
In the paper, Chern claims $$ int_SM_x_s Pi|_SM_x_s = frac11cdot3 cdots (n-1)(2pi)^fracn2 int_SM_x_sPhi_0|_SM_x_s$$
and of course it's equal 1, essentially, I don't know why $ displaystyle int_SM_x_s Phi_k = 0$, for $k geq 1$.
Thanks!
differential-geometry riemannian-geometry differential-forms
edited Aug 30 at 23:51
asked Aug 27 at 12:32
Carlos Alcantara
896
896
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It's not so scary, after all :) You're integrating the forms $Phi_k$ over the unit sphere bundle at a fixed point $x_0$ of $M$ (your notation is different from his, since for him $M$ is the unit sphere bundle of the manifold $R$). For $kge 1$, the form $Phi_k$ will involve at least one curvature form $Omega_i^j$. The curvature forms are horizontal for the fibration $SMto M$, and you're integrating over a fiber. So those integrals all vanish.
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
2
down vote
accepted
It's not so scary, after all :) You're integrating the forms $Phi_k$ over the unit sphere bundle at a fixed point $x_0$ of $M$ (your notation is different from his, since for him $M$ is the unit sphere bundle of the manifold $R$). For $kge 1$, the form $Phi_k$ will involve at least one curvature form $Omega_i^j$. The curvature forms are horizontal for the fibration $SMto M$, and you're integrating over a fiber. So those integrals all vanish.
add a comment |Â
up vote
2
down vote
accepted
It's not so scary, after all :) You're integrating the forms $Phi_k$ over the unit sphere bundle at a fixed point $x_0$ of $M$ (your notation is different from his, since for him $M$ is the unit sphere bundle of the manifold $R$). For $kge 1$, the form $Phi_k$ will involve at least one curvature form $Omega_i^j$. The curvature forms are horizontal for the fibration $SMto M$, and you're integrating over a fiber. So those integrals all vanish.
add a comment |Â
up vote
2
down vote
accepted
up vote
2
down vote
accepted
It's not so scary, after all :) You're integrating the forms $Phi_k$ over the unit sphere bundle at a fixed point $x_0$ of $M$ (your notation is different from his, since for him $M$ is the unit sphere bundle of the manifold $R$). For $kge 1$, the form $Phi_k$ will involve at least one curvature form $Omega_i^j$. The curvature forms are horizontal for the fibration $SMto M$, and you're integrating over a fiber. So those integrals all vanish.
It's not so scary, after all :) You're integrating the forms $Phi_k$ over the unit sphere bundle at a fixed point $x_0$ of $M$ (your notation is different from his, since for him $M$ is the unit sphere bundle of the manifold $R$). For $kge 1$, the form $Phi_k$ will involve at least one curvature form $Omega_i^j$. The curvature forms are horizontal for the fibration $SMto M$, and you're integrating over a fiber. So those integrals all vanish.
answered Aug 27 at 16:30
Ted Shifrin
60.4k44387
60.4k44387
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