How do I calculate the inclined area of a roof?

The name of the pictureThe name of the pictureThe name of the pictureClash Royale CLAN TAG#URR8PPP











up vote
1
down vote

favorite












I think I already know the formula, but wanted to check if there are any instances where this may not work. I have been estimating construction costs for 5 years and haven’t found one instance where the following formula doesn’t give the correct answer:



Incline area = flat area (measured on plan)/cos (pitch in degrees)



So far this has worked for:



  • Square, rectangular, hexagonal, circular, curved edge roofs

  • Roofs of varying pitches eg. 5 degrees one side, 10 degrees the other. Just measure 2 separate areas and use the formula

It wouldn’t work for:
- Roofs that are arced or domed vertically



Can anyone prove me wrong because I’ve seen so many people losing their mind over something so simple?







share|cite|improve this question




















  • For spherical domed roof, if the pitch is $theta$ at the edge, the surface area is given by 2$pi r^2 (1- cos(theta))$. See here for more details: en.wikipedia.org/wiki/Spherical_cap where r is the radius of the dome. If you have the plan view radius (a) instead, you can use $r = fracacos(theta)$ as you are already doing before to get radius.
    – user625
    Jun 21 at 12:43











  • For an arced dome, it is a portion of a cylinder. So, you can use $2rtheta cdot$ length where $r$ is the radius of the cylinder. Again, you can convert radius $r$ into plan view width by using $r = fracacos(theta)$
    – user625
    Jun 21 at 12:50















up vote
1
down vote

favorite












I think I already know the formula, but wanted to check if there are any instances where this may not work. I have been estimating construction costs for 5 years and haven’t found one instance where the following formula doesn’t give the correct answer:



Incline area = flat area (measured on plan)/cos (pitch in degrees)



So far this has worked for:



  • Square, rectangular, hexagonal, circular, curved edge roofs

  • Roofs of varying pitches eg. 5 degrees one side, 10 degrees the other. Just measure 2 separate areas and use the formula

It wouldn’t work for:
- Roofs that are arced or domed vertically



Can anyone prove me wrong because I’ve seen so many people losing their mind over something so simple?







share|cite|improve this question




















  • For spherical domed roof, if the pitch is $theta$ at the edge, the surface area is given by 2$pi r^2 (1- cos(theta))$. See here for more details: en.wikipedia.org/wiki/Spherical_cap where r is the radius of the dome. If you have the plan view radius (a) instead, you can use $r = fracacos(theta)$ as you are already doing before to get radius.
    – user625
    Jun 21 at 12:43











  • For an arced dome, it is a portion of a cylinder. So, you can use $2rtheta cdot$ length where $r$ is the radius of the cylinder. Again, you can convert radius $r$ into plan view width by using $r = fracacos(theta)$
    – user625
    Jun 21 at 12:50













up vote
1
down vote

favorite









up vote
1
down vote

favorite











I think I already know the formula, but wanted to check if there are any instances where this may not work. I have been estimating construction costs for 5 years and haven’t found one instance where the following formula doesn’t give the correct answer:



Incline area = flat area (measured on plan)/cos (pitch in degrees)



So far this has worked for:



  • Square, rectangular, hexagonal, circular, curved edge roofs

  • Roofs of varying pitches eg. 5 degrees one side, 10 degrees the other. Just measure 2 separate areas and use the formula

It wouldn’t work for:
- Roofs that are arced or domed vertically



Can anyone prove me wrong because I’ve seen so many people losing their mind over something so simple?







share|cite|improve this question












I think I already know the formula, but wanted to check if there are any instances where this may not work. I have been estimating construction costs for 5 years and haven’t found one instance where the following formula doesn’t give the correct answer:



Incline area = flat area (measured on plan)/cos (pitch in degrees)



So far this has worked for:



  • Square, rectangular, hexagonal, circular, curved edge roofs

  • Roofs of varying pitches eg. 5 degrees one side, 10 degrees the other. Just measure 2 separate areas and use the formula

It wouldn’t work for:
- Roofs that are arced or domed vertically



Can anyone prove me wrong because I’ve seen so many people losing their mind over something so simple?









share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Jun 21 at 12:19









Jmel93

61




61











  • For spherical domed roof, if the pitch is $theta$ at the edge, the surface area is given by 2$pi r^2 (1- cos(theta))$. See here for more details: en.wikipedia.org/wiki/Spherical_cap where r is the radius of the dome. If you have the plan view radius (a) instead, you can use $r = fracacos(theta)$ as you are already doing before to get radius.
    – user625
    Jun 21 at 12:43











  • For an arced dome, it is a portion of a cylinder. So, you can use $2rtheta cdot$ length where $r$ is the radius of the cylinder. Again, you can convert radius $r$ into plan view width by using $r = fracacos(theta)$
    – user625
    Jun 21 at 12:50

















  • For spherical domed roof, if the pitch is $theta$ at the edge, the surface area is given by 2$pi r^2 (1- cos(theta))$. See here for more details: en.wikipedia.org/wiki/Spherical_cap where r is the radius of the dome. If you have the plan view radius (a) instead, you can use $r = fracacos(theta)$ as you are already doing before to get radius.
    – user625
    Jun 21 at 12:43











  • For an arced dome, it is a portion of a cylinder. So, you can use $2rtheta cdot$ length where $r$ is the radius of the cylinder. Again, you can convert radius $r$ into plan view width by using $r = fracacos(theta)$
    – user625
    Jun 21 at 12:50
















For spherical domed roof, if the pitch is $theta$ at the edge, the surface area is given by 2$pi r^2 (1- cos(theta))$. See here for more details: en.wikipedia.org/wiki/Spherical_cap where r is the radius of the dome. If you have the plan view radius (a) instead, you can use $r = fracacos(theta)$ as you are already doing before to get radius.
– user625
Jun 21 at 12:43





For spherical domed roof, if the pitch is $theta$ at the edge, the surface area is given by 2$pi r^2 (1- cos(theta))$. See here for more details: en.wikipedia.org/wiki/Spherical_cap where r is the radius of the dome. If you have the plan view radius (a) instead, you can use $r = fracacos(theta)$ as you are already doing before to get radius.
– user625
Jun 21 at 12:43













For an arced dome, it is a portion of a cylinder. So, you can use $2rtheta cdot$ length where $r$ is the radius of the cylinder. Again, you can convert radius $r$ into plan view width by using $r = fracacos(theta)$
– user625
Jun 21 at 12:50





For an arced dome, it is a portion of a cylinder. So, you can use $2rtheta cdot$ length where $r$ is the radius of the cylinder. Again, you can convert radius $r$ into plan view width by using $r = fracacos(theta)$
– user625
Jun 21 at 12:50











1 Answer
1






active

oldest

votes

















up vote
0
down vote













Just combining the comments above as an answer.




  1. Spherical domed roof (shaped like a cap):

$theta$ is the angle of the roof with the horizontal at the edge



$a$ = plan view radius



Area = $2picdot a^2cdotfrac1-cos(theta)cos(theta)$



  1. Arced dome (portion of a cylinder):

$theta$ is the angle of the roof with the horizontal at the edge in radians



$a$ = plan view width



$l$ = plan view length



Area = $2thetacdotfracalcos(theta)$






share|cite|improve this answer






















    Your Answer




    StackExchange.ifUsing("editor", function ()
    return StackExchange.using("mathjaxEditing", function ()
    StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix)
    StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
    );
    );
    , "mathjax-editing");

    StackExchange.ready(function()
    var channelOptions =
    tags: "".split(" "),
    id: "69"
    ;
    initTagRenderer("".split(" "), "".split(" "), channelOptions);

    StackExchange.using("externalEditor", function()
    // Have to fire editor after snippets, if snippets enabled
    if (StackExchange.settings.snippets.snippetsEnabled)
    StackExchange.using("snippets", function()
    createEditor();
    );

    else
    createEditor();

    );

    function createEditor()
    StackExchange.prepareEditor(
    heartbeatType: 'answer',
    convertImagesToLinks: true,
    noModals: false,
    showLowRepImageUploadWarning: true,
    reputationToPostImages: 10,
    bindNavPrevention: true,
    postfix: "",
    noCode: true, onDemand: true,
    discardSelector: ".discard-answer"
    ,immediatelyShowMarkdownHelp:true
    );



    );








     

    draft saved


    draft discarded


















    StackExchange.ready(
    function ()
    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f2827235%2fhow-do-i-calculate-the-inclined-area-of-a-roof%23new-answer', 'question_page');

    );

    Post as a guest






























    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes








    up vote
    0
    down vote













    Just combining the comments above as an answer.




    1. Spherical domed roof (shaped like a cap):

    $theta$ is the angle of the roof with the horizontal at the edge



    $a$ = plan view radius



    Area = $2picdot a^2cdotfrac1-cos(theta)cos(theta)$



    1. Arced dome (portion of a cylinder):

    $theta$ is the angle of the roof with the horizontal at the edge in radians



    $a$ = plan view width



    $l$ = plan view length



    Area = $2thetacdotfracalcos(theta)$






    share|cite|improve this answer


























      up vote
      0
      down vote













      Just combining the comments above as an answer.




      1. Spherical domed roof (shaped like a cap):

      $theta$ is the angle of the roof with the horizontal at the edge



      $a$ = plan view radius



      Area = $2picdot a^2cdotfrac1-cos(theta)cos(theta)$



      1. Arced dome (portion of a cylinder):

      $theta$ is the angle of the roof with the horizontal at the edge in radians



      $a$ = plan view width



      $l$ = plan view length



      Area = $2thetacdotfracalcos(theta)$






      share|cite|improve this answer
























        up vote
        0
        down vote










        up vote
        0
        down vote









        Just combining the comments above as an answer.




        1. Spherical domed roof (shaped like a cap):

        $theta$ is the angle of the roof with the horizontal at the edge



        $a$ = plan view radius



        Area = $2picdot a^2cdotfrac1-cos(theta)cos(theta)$



        1. Arced dome (portion of a cylinder):

        $theta$ is the angle of the roof with the horizontal at the edge in radians



        $a$ = plan view width



        $l$ = plan view length



        Area = $2thetacdotfracalcos(theta)$






        share|cite|improve this answer














        Just combining the comments above as an answer.




        1. Spherical domed roof (shaped like a cap):

        $theta$ is the angle of the roof with the horizontal at the edge



        $a$ = plan view radius



        Area = $2picdot a^2cdotfrac1-cos(theta)cos(theta)$



        1. Arced dome (portion of a cylinder):

        $theta$ is the angle of the roof with the horizontal at the edge in radians



        $a$ = plan view width



        $l$ = plan view length



        Area = $2thetacdotfracalcos(theta)$







        share|cite|improve this answer














        share|cite|improve this answer



        share|cite|improve this answer








        edited Aug 10 at 20:41









        Robert Howard

        1,331620




        1,331620










        answered Jun 21 at 13:48









        user625

        40011




        40011






















             

            draft saved


            draft discarded


























             


            draft saved


            draft discarded














            StackExchange.ready(
            function ()
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f2827235%2fhow-do-i-calculate-the-inclined-area-of-a-roof%23new-answer', 'question_page');

            );

            Post as a guest













































































            這個網誌中的熱門文章

            How to combine Bézier curves to a surface?

            Carbon dioxide

            Why am i infinitely getting the same tweet with the Twitter Search API?