Given the equation with constant b, what is the value of (600,000 + 100bu +400,000) in millions
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we have the given equtaion:
$6000 = bu + 4000$
We are trying to find the value of $600,000 + 100bu +400,000$ given the equation above, there fore i manipulated it by adding $99bu + 396000 + 600000$ to both sides of the eqation giving me:
$600000 + 100bu + 400000 = 606000 + 99bu +396000$
After simplifying the right side i got my answer:
$600000 + 100bu + 400000 = 1002000 + 99bu$
However this was wrong and the value to $600000 + 100bu + 400000$ is equal to $1.2$ million.
Where was my reasoning flawed?
algebra-precalculus
asked Aug 11 at 1:37
user196104
183
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up vote
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we have the given equtaion:
$6000 = bu + 4000$
We are trying to find the value of $600,000 + 100bu +400,000$ given the equation above, there fore i manipulated it by adding $99bu + 396000 + 600000$ to both sides of the eqation giving me:
$600000 + 100bu + 400000 = 606000 + 99bu +396000$
After simplifying the right side i got my answer:
$600000 + 100bu + 400000 = 1002000 + 99bu$
However this was wrong and the value to $600000 + 100bu + 400000$ is equal to $1.2$ million.
Where was my reasoning flawed?
algebra-precalculus
asked Aug 11 at 1:37
user196104
183
Wouldn't combining "like terms" 600,000 and 400,000 be the very first step? It seems strange that these would not be added. But how did you get to that expression from the "given equation" $6000 = (b)(u) + 4000$? I don't get the relationship.
– hardmath
Aug 11 at 1:42
i added 99bu + 396000 + 600000 to the right side of the original equation to get it in terms of (600,000 + 100bu +400,000). But I added the same quantity to the other side so the equality would hold.
– user196104
Aug 11 at 1:44
add a comment |Â
up vote
0
down vote
favorite
up vote
0
down vote
favorite
we have the given equtaion:
$6000 = bu + 4000$
We are trying to find the value of $600,000 + 100bu +400,000$ given the equation above, there fore i manipulated it by adding $99bu + 396000 + 600000$ to both sides of the eqation giving me:
$600000 + 100bu + 400000 = 606000 + 99bu +396000$
After simplifying the right side i got my answer:
$600000 + 100bu + 400000 = 1002000 + 99bu$
However this was wrong and the value to $600000 + 100bu + 400000$ is equal to $1.2$ million.
Where was my reasoning flawed?
algebra-precalculus
asked Aug 11 at 1:37
user196104
183
we have the given equtaion:
$6000 = bu + 4000$
We are trying to find the value of $600,000 + 100bu +400,000$ given the equation above, there fore i manipulated it by adding $99bu + 396000 + 600000$ to both sides of the eqation giving me:
$600000 + 100bu + 400000 = 606000 + 99bu +396000$
After simplifying the right side i got my answer:
$600000 + 100bu + 400000 = 1002000 + 99bu$
However this was wrong and the value to $600000 + 100bu + 400000$ is equal to $1.2$ million.
Where was my reasoning flawed?
algebra-precalculus
asked Aug 11 at 1:37
user196104
183
edited Aug 11 at 2:48
user529760
asked Aug 11 at 1:37
user196104
183
asked Aug 11 at 1:37
user196104
183
asked Aug 11 at 1:37
user196104
183
183
Wouldn't combining "like terms" 600,000 and 400,000 be the very first step? It seems strange that these would not be added. But how did you get to that expression from the "given equation" $6000 = (b)(u) + 4000$? I don't get the relationship.
– hardmath
Aug 11 at 1:42
i added 99bu + 396000 + 600000 to the right side of the original equation to get it in terms of (600,000 + 100bu +400,000). But I added the same quantity to the other side so the equality would hold.
– user196104
Aug 11 at 1:44
add a comment |Â
Wouldn't combining "like terms" 600,000 and 400,000 be the very first step? It seems strange that these would not be added. But how did you get to that expression from the "given equation" $6000 = (b)(u) + 4000$? I don't get the relationship.
– hardmath
Aug 11 at 1:42
i added 99bu + 396000 + 600000 to the right side of the original equation to get it in terms of (600,000 + 100bu +400,000). But I added the same quantity to the other side so the equality would hold.
– user196104
Aug 11 at 1:44
Wouldn't combining "like terms" 600,000 and 400,000 be the very first step? It seems strange that these would not be added. But how did you get to that expression from the "given equation" $6000 = (b)(u) + 4000$? I don't get the relationship.
– hardmath
Aug 11 at 1:42
Wouldn't combining "like terms" 600,000 and 400,000 be the very first step? It seems strange that these would not be added. But how did you get to that expression from the "given equation" $6000 = (b)(u) + 4000$? I don't get the relationship.
– hardmath
Aug 11 at 1:42
i added 99bu + 396000 + 600000 to the right side of the original equation to get it in terms of (600,000 + 100bu +400,000). But I added the same quantity to the other side so the equality would hold.
– user196104
Aug 11 at 1:44
i added 99bu + 396000 + 600000 to the right side of the original equation to get it in terms of (600,000 + 100bu +400,000). But I added the same quantity to the other side so the equality would hold.
– user196104
Aug 11 at 1:44
add a comment |Â
2 Answers
2
active
oldest
votes
up vote
0
down vote
accepted
Note that $bu=2000$, hence $1002000+99(2000)=1.2$ million. So nothing is wrong, just that you are not representing it explicitly.
Alternative computation:
$$600,000 + 100bu +400,000=100(6000+bu+4000)=100(6000+6000)$$
answered Aug 11 at 1:52
Siong Thye Goh
78.6k134997
add a comment |Â
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$6000 = bu + 4000$
$bu+4000-4000=6000 - 4000$
$bu=6000-4000=2000$
$600000 + 100bu + 400000 = 1002000 + 99bu=1002000 + 99times2000=1200000$
So you did nothing wrong. You just need to add the extra steps described above.
add a comment |Â
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
accepted
Note that $bu=2000$, hence $1002000+99(2000)=1.2$ million. So nothing is wrong, just that you are not representing it explicitly.
Alternative computation:
$$600,000 + 100bu +400,000=100(6000+bu+4000)=100(6000+6000)$$
answered Aug 11 at 1:52
Siong Thye Goh
78.6k134997
add a comment |Â
up vote
0
down vote
accepted
Note that $bu=2000$, hence $1002000+99(2000)=1.2$ million. So nothing is wrong, just that you are not representing it explicitly.
Alternative computation:
$$600,000 + 100bu +400,000=100(6000+bu+4000)=100(6000+6000)$$
answered Aug 11 at 1:52
Siong Thye Goh
78.6k134997
add a comment |Â
up vote
0
down vote
accepted
up vote
0
down vote
accepted
Note that $bu=2000$, hence $1002000+99(2000)=1.2$ million. So nothing is wrong, just that you are not representing it explicitly.
Alternative computation:
$$600,000 + 100bu +400,000=100(6000+bu+4000)=100(6000+6000)$$
answered Aug 11 at 1:52
Siong Thye Goh
78.6k134997
Note that $bu=2000$, hence $1002000+99(2000)=1.2$ million. So nothing is wrong, just that you are not representing it explicitly.
Alternative computation:
$$600,000 + 100bu +400,000=100(6000+bu+4000)=100(6000+6000)$$
answered Aug 11 at 1:52
Siong Thye Goh
78.6k134997
answered Aug 11 at 1:52
Siong Thye Goh
78.6k134997
answered Aug 11 at 1:52
Siong Thye Goh
78.6k134997
answered Aug 11 at 1:52
Siong Thye Goh
78.6k134997
78.6k134997
add a comment |Â
add a comment |Â
up vote
0
down vote
$6000 = bu + 4000$
$bu+4000-4000=6000 - 4000$
$bu=6000-4000=2000$
$600000 + 100bu + 400000 = 1002000 + 99bu=1002000 + 99times2000=1200000$
So you did nothing wrong. You just need to add the extra steps described above.
add a comment |Â
up vote
0
down vote
$6000 = bu + 4000$
$bu+4000-4000=6000 - 4000$
$bu=6000-4000=2000$
$600000 + 100bu + 400000 = 1002000 + 99bu=1002000 + 99times2000=1200000$
So you did nothing wrong. You just need to add the extra steps described above.
add a comment |Â
up vote
0
down vote
up vote
0
down vote
$6000 = bu + 4000$
$bu+4000-4000=6000 - 4000$
$bu=6000-4000=2000$
$600000 + 100bu + 400000 = 1002000 + 99bu=1002000 + 99times2000=1200000$
So you did nothing wrong. You just need to add the extra steps described above.
$6000 = bu + 4000$
$bu+4000-4000=6000 - 4000$
$bu=6000-4000=2000$
$600000 + 100bu + 400000 = 1002000 + 99bu=1002000 + 99times2000=1200000$
So you did nothing wrong. You just need to add the extra steps described above.
answered Aug 11 at 1:52
user529760
add a comment |Â
add a comment |Â
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Wouldn't combining "like terms" 600,000 and 400,000 be the very first step? It seems strange that these would not be added. But how did you get to that expression from the "given equation" $6000 = (b)(u) + 4000$? I don't get the relationship.
– hardmath
Aug 11 at 1:42
i added 99bu + 396000 + 600000 to the right side of the original equation to get it in terms of (600,000 + 100bu +400,000). But I added the same quantity to the other side so the equality would hold.
– user196104
Aug 11 at 1:44