Prove transpose property

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Prove $(AB)^T = B^T A^T$
I saw this: Alternative proof of a transpose property
I don't understand the solution given, and I was wondering what the "simple" way to prove this property is. I can just write out the representations of the left and right hand side using general scalar variables (such as the top left scalar of the final matrix product being $a_11 b_11 + a_12 b_21$) but I'd like to see a nicer way to prove it.
linear-algebra
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up vote
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favorite
Prove $(AB)^T = B^T A^T$
I saw this: Alternative proof of a transpose property
I don't understand the solution given, and I was wondering what the "simple" way to prove this property is. I can just write out the representations of the left and right hand side using general scalar variables (such as the top left scalar of the final matrix product being $a_11 b_11 + a_12 b_21$) but I'd like to see a nicer way to prove it.
linear-algebra
The solution has a small typo, which I corrected. Try again this time. It just utilizes the property given to the OP, twice. And if you read through question itself, then you will find out that the reason why the OP asked for a proof that way is simply she was given that challenge. I suppose no claim on whether it is "simple" or not.
â Gary Moore
Sep 1 at 1:53
add a comment |Â
up vote
0
down vote
favorite
up vote
0
down vote
favorite
Prove $(AB)^T = B^T A^T$
I saw this: Alternative proof of a transpose property
I don't understand the solution given, and I was wondering what the "simple" way to prove this property is. I can just write out the representations of the left and right hand side using general scalar variables (such as the top left scalar of the final matrix product being $a_11 b_11 + a_12 b_21$) but I'd like to see a nicer way to prove it.
linear-algebra
Prove $(AB)^T = B^T A^T$
I saw this: Alternative proof of a transpose property
I don't understand the solution given, and I was wondering what the "simple" way to prove this property is. I can just write out the representations of the left and right hand side using general scalar variables (such as the top left scalar of the final matrix product being $a_11 b_11 + a_12 b_21$) but I'd like to see a nicer way to prove it.
linear-algebra
linear-algebra
asked Sep 1 at 1:26
user3180
175
175
The solution has a small typo, which I corrected. Try again this time. It just utilizes the property given to the OP, twice. And if you read through question itself, then you will find out that the reason why the OP asked for a proof that way is simply she was given that challenge. I suppose no claim on whether it is "simple" or not.
â Gary Moore
Sep 1 at 1:53
add a comment |Â
The solution has a small typo, which I corrected. Try again this time. It just utilizes the property given to the OP, twice. And if you read through question itself, then you will find out that the reason why the OP asked for a proof that way is simply she was given that challenge. I suppose no claim on whether it is "simple" or not.
â Gary Moore
Sep 1 at 1:53
The solution has a small typo, which I corrected. Try again this time. It just utilizes the property given to the OP, twice. And if you read through question itself, then you will find out that the reason why the OP asked for a proof that way is simply she was given that challenge. I suppose no claim on whether it is "simple" or not.
â Gary Moore
Sep 1 at 1:53
The solution has a small typo, which I corrected. Try again this time. It just utilizes the property given to the OP, twice. And if you read through question itself, then you will find out that the reason why the OP asked for a proof that way is simply she was given that challenge. I suppose no claim on whether it is "simple" or not.
â Gary Moore
Sep 1 at 1:53
add a comment |Â
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The solution has a small typo, which I corrected. Try again this time. It just utilizes the property given to the OP, twice. And if you read through question itself, then you will find out that the reason why the OP asked for a proof that way is simply she was given that challenge. I suppose no claim on whether it is "simple" or not.
â Gary Moore
Sep 1 at 1:53