Given an annulus with known dimensions how would I find the length of a line connecting the inner and outer edges at an arbitrary angle?

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Given an annulus with origin A and radii R1 & R2, a point on the inner radius B, and an angle theta to an unknown point on the outer radius C I need to find the length of line segment BC.



I'm working in OpenSCAD so I must solve this problem mathematically but I have diagrammed it in FreeCAD below.



enter image description here



  • knowns: A, B, R1, R2, theta

  • unknowns: C









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  • 1




    in triangle $ABC$ we know side $AB$, side $AC$, and angle $ABC$. We want to find the third side $BC$
    – Lozenges
    Sep 1 at 7:05










  • Lozenges... thank you. I made this way too hard in my head /facepalm
    – rennat
    Sep 1 at 7:07










  • For anyone else who stumbles onto this page, here is the solution directly from my openscad file: theta = 180 - vaneAngle; chordLength = innerRadius * cos(theta) + sqrt(pow(outerRadius, 2) - pow(innerRadius, 2) * pow(sin(theta), 2)); and yes it is for a centrifugal blower :)
    – rennat
    Sep 1 at 7:38















up vote
0
down vote

favorite












Given an annulus with origin A and radii R1 & R2, a point on the inner radius B, and an angle theta to an unknown point on the outer radius C I need to find the length of line segment BC.



I'm working in OpenSCAD so I must solve this problem mathematically but I have diagrammed it in FreeCAD below.



enter image description here



  • knowns: A, B, R1, R2, theta

  • unknowns: C









share|cite|improve this question



















  • 1




    in triangle $ABC$ we know side $AB$, side $AC$, and angle $ABC$. We want to find the third side $BC$
    – Lozenges
    Sep 1 at 7:05










  • Lozenges... thank you. I made this way too hard in my head /facepalm
    – rennat
    Sep 1 at 7:07










  • For anyone else who stumbles onto this page, here is the solution directly from my openscad file: theta = 180 - vaneAngle; chordLength = innerRadius * cos(theta) + sqrt(pow(outerRadius, 2) - pow(innerRadius, 2) * pow(sin(theta), 2)); and yes it is for a centrifugal blower :)
    – rennat
    Sep 1 at 7:38













up vote
0
down vote

favorite









up vote
0
down vote

favorite











Given an annulus with origin A and radii R1 & R2, a point on the inner radius B, and an angle theta to an unknown point on the outer radius C I need to find the length of line segment BC.



I'm working in OpenSCAD so I must solve this problem mathematically but I have diagrammed it in FreeCAD below.



enter image description here



  • knowns: A, B, R1, R2, theta

  • unknowns: C









share|cite|improve this question















Given an annulus with origin A and radii R1 & R2, a point on the inner radius B, and an angle theta to an unknown point on the outer radius C I need to find the length of line segment BC.



I'm working in OpenSCAD so I must solve this problem mathematically but I have diagrammed it in FreeCAD below.



enter image description here



  • knowns: A, B, R1, R2, theta

  • unknowns: C






geometry






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share|cite|improve this question













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edited Sep 1 at 6:38

























asked Sep 1 at 6:11









rennat

1013




1013







  • 1




    in triangle $ABC$ we know side $AB$, side $AC$, and angle $ABC$. We want to find the third side $BC$
    – Lozenges
    Sep 1 at 7:05










  • Lozenges... thank you. I made this way too hard in my head /facepalm
    – rennat
    Sep 1 at 7:07










  • For anyone else who stumbles onto this page, here is the solution directly from my openscad file: theta = 180 - vaneAngle; chordLength = innerRadius * cos(theta) + sqrt(pow(outerRadius, 2) - pow(innerRadius, 2) * pow(sin(theta), 2)); and yes it is for a centrifugal blower :)
    – rennat
    Sep 1 at 7:38













  • 1




    in triangle $ABC$ we know side $AB$, side $AC$, and angle $ABC$. We want to find the third side $BC$
    – Lozenges
    Sep 1 at 7:05










  • Lozenges... thank you. I made this way too hard in my head /facepalm
    – rennat
    Sep 1 at 7:07










  • For anyone else who stumbles onto this page, here is the solution directly from my openscad file: theta = 180 - vaneAngle; chordLength = innerRadius * cos(theta) + sqrt(pow(outerRadius, 2) - pow(innerRadius, 2) * pow(sin(theta), 2)); and yes it is for a centrifugal blower :)
    – rennat
    Sep 1 at 7:38








1




1




in triangle $ABC$ we know side $AB$, side $AC$, and angle $ABC$. We want to find the third side $BC$
– Lozenges
Sep 1 at 7:05




in triangle $ABC$ we know side $AB$, side $AC$, and angle $ABC$. We want to find the third side $BC$
– Lozenges
Sep 1 at 7:05












Lozenges... thank you. I made this way too hard in my head /facepalm
– rennat
Sep 1 at 7:07




Lozenges... thank you. I made this way too hard in my head /facepalm
– rennat
Sep 1 at 7:07












For anyone else who stumbles onto this page, here is the solution directly from my openscad file: theta = 180 - vaneAngle; chordLength = innerRadius * cos(theta) + sqrt(pow(outerRadius, 2) - pow(innerRadius, 2) * pow(sin(theta), 2)); and yes it is for a centrifugal blower :)
– rennat
Sep 1 at 7:38





For anyone else who stumbles onto this page, here is the solution directly from my openscad file: theta = 180 - vaneAngle; chordLength = innerRadius * cos(theta) + sqrt(pow(outerRadius, 2) - pow(innerRadius, 2) * pow(sin(theta), 2)); and yes it is for a centrifugal blower :)
– rennat
Sep 1 at 7:38
















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