Comparing Numerical Methods for Differential Equations

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Why the 3-step Adams Moulton method is better than the 2-step Adams Moulton method?




Noted that the local truncation error of 3-step Adams Moulton method is $O(h^4)$, while the local truncation error of 2-step Adams Moulton method is $O(h^3)$.




Are there other reasons or tools to compare between two previous numerical methods, e.g. factors and measures that need to be studied like computational cost, efficiency, convergence, simplicity and other factors that might be proper to determine which method is better.











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  • Order of accuracy, stability, and computational cost are the three main criteria on which numerical methods are evaluated. Another might be conservation of invariants, for example one might prefer symplectic methods for Hamiltonian systems since they approximately preserve the energy of the system.
    – Rahul
    Sep 1 at 3:21














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down vote

favorite













Why the 3-step Adams Moulton method is better than the 2-step Adams Moulton method?




Noted that the local truncation error of 3-step Adams Moulton method is $O(h^4)$, while the local truncation error of 2-step Adams Moulton method is $O(h^3)$.




Are there other reasons or tools to compare between two previous numerical methods, e.g. factors and measures that need to be studied like computational cost, efficiency, convergence, simplicity and other factors that might be proper to determine which method is better.











share|cite|improve this question























  • Order of accuracy, stability, and computational cost are the three main criteria on which numerical methods are evaluated. Another might be conservation of invariants, for example one might prefer symplectic methods for Hamiltonian systems since they approximately preserve the energy of the system.
    – Rahul
    Sep 1 at 3:21












up vote
0
down vote

favorite









up vote
0
down vote

favorite












Why the 3-step Adams Moulton method is better than the 2-step Adams Moulton method?




Noted that the local truncation error of 3-step Adams Moulton method is $O(h^4)$, while the local truncation error of 2-step Adams Moulton method is $O(h^3)$.




Are there other reasons or tools to compare between two previous numerical methods, e.g. factors and measures that need to be studied like computational cost, efficiency, convergence, simplicity and other factors that might be proper to determine which method is better.











share|cite|improve this question
















Why the 3-step Adams Moulton method is better than the 2-step Adams Moulton method?




Noted that the local truncation error of 3-step Adams Moulton method is $O(h^4)$, while the local truncation error of 2-step Adams Moulton method is $O(h^3)$.




Are there other reasons or tools to compare between two previous numerical methods, e.g. factors and measures that need to be studied like computational cost, efficiency, convergence, simplicity and other factors that might be proper to determine which method is better.








convergence numerical-methods truncation-error






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edited Sep 1 at 2:15

























asked Sep 1 at 1:23









workwolf

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  • Order of accuracy, stability, and computational cost are the three main criteria on which numerical methods are evaluated. Another might be conservation of invariants, for example one might prefer symplectic methods for Hamiltonian systems since they approximately preserve the energy of the system.
    – Rahul
    Sep 1 at 3:21
















  • Order of accuracy, stability, and computational cost are the three main criteria on which numerical methods are evaluated. Another might be conservation of invariants, for example one might prefer symplectic methods for Hamiltonian systems since they approximately preserve the energy of the system.
    – Rahul
    Sep 1 at 3:21















Order of accuracy, stability, and computational cost are the three main criteria on which numerical methods are evaluated. Another might be conservation of invariants, for example one might prefer symplectic methods for Hamiltonian systems since they approximately preserve the energy of the system.
– Rahul
Sep 1 at 3:21




Order of accuracy, stability, and computational cost are the three main criteria on which numerical methods are evaluated. Another might be conservation of invariants, for example one might prefer symplectic methods for Hamiltonian systems since they approximately preserve the energy of the system.
– Rahul
Sep 1 at 3:21















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