Shaded rectangle within a rectangle [closed]
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The two shaded rectangles have the same area, what is the total shaded area in cm$^2$? I tried to reason it out to 49 cm$^2$ but apparently thats not correct.
geometry rectangles
closed as off-topic by Xander Henderson, amWhy, Jendrik Stelzner, Leucippus, Key Flex Aug 9 at 2:18
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." â Xander Henderson, amWhy, Jendrik Stelzner, Leucippus, Key Flex
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up vote
-2
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The two shaded rectangles have the same area, what is the total shaded area in cm$^2$? I tried to reason it out to 49 cm$^2$ but apparently thats not correct.
geometry rectangles
closed as off-topic by Xander Henderson, amWhy, Jendrik Stelzner, Leucippus, Key Flex Aug 9 at 2:18
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." â Xander Henderson, amWhy, Jendrik Stelzner, Leucippus, Key Flex
4
If the upper rectangle is $x$ cm wide, how wide is the lower rectangle? Can you compute the area in terms of that width $x$? What, specifically, are you stuck on?
â Xander Henderson
Aug 8 at 20:59
Specifically I am stuck on the width of both the shaded areas.
â Local Worker
Aug 8 at 21:16
1
So answer my first question: if the top rectangle is $x$ cm wide, how wide is the bottom rectangle? Can you use that to write down a formula for the area of each of the two rectangles?
â Xander Henderson
Aug 8 at 21:17
1
if the top shaded rectangle's width is x, then its area is 4*x. The lower shaded rectangle is then 3*(14-x)? So then you have 4*x = 3*14-x?
â Local Worker
Aug 8 at 21:21
1
Exactly. So what next? (Also, it would be useful if you edited your question to include any new thoughts that you have---such edits add context to the question.)
â Xander Henderson
Aug 8 at 21:23
 |Â
show 5 more comments
up vote
-2
down vote
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up vote
-2
down vote
favorite
The two shaded rectangles have the same area, what is the total shaded area in cm$^2$? I tried to reason it out to 49 cm$^2$ but apparently thats not correct.
geometry rectangles
The two shaded rectangles have the same area, what is the total shaded area in cm$^2$? I tried to reason it out to 49 cm$^2$ but apparently thats not correct.
geometry rectangles
edited Aug 8 at 21:24
Jaroslaw Matlak
3,900830
3,900830
asked Aug 8 at 20:55
Local Worker
132
132
closed as off-topic by Xander Henderson, amWhy, Jendrik Stelzner, Leucippus, Key Flex Aug 9 at 2:18
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." â Xander Henderson, amWhy, Jendrik Stelzner, Leucippus, Key Flex
closed as off-topic by Xander Henderson, amWhy, Jendrik Stelzner, Leucippus, Key Flex Aug 9 at 2:18
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." â Xander Henderson, amWhy, Jendrik Stelzner, Leucippus, Key Flex
4
If the upper rectangle is $x$ cm wide, how wide is the lower rectangle? Can you compute the area in terms of that width $x$? What, specifically, are you stuck on?
â Xander Henderson
Aug 8 at 20:59
Specifically I am stuck on the width of both the shaded areas.
â Local Worker
Aug 8 at 21:16
1
So answer my first question: if the top rectangle is $x$ cm wide, how wide is the bottom rectangle? Can you use that to write down a formula for the area of each of the two rectangles?
â Xander Henderson
Aug 8 at 21:17
1
if the top shaded rectangle's width is x, then its area is 4*x. The lower shaded rectangle is then 3*(14-x)? So then you have 4*x = 3*14-x?
â Local Worker
Aug 8 at 21:21
1
Exactly. So what next? (Also, it would be useful if you edited your question to include any new thoughts that you have---such edits add context to the question.)
â Xander Henderson
Aug 8 at 21:23
 |Â
show 5 more comments
4
If the upper rectangle is $x$ cm wide, how wide is the lower rectangle? Can you compute the area in terms of that width $x$? What, specifically, are you stuck on?
â Xander Henderson
Aug 8 at 20:59
Specifically I am stuck on the width of both the shaded areas.
â Local Worker
Aug 8 at 21:16
1
So answer my first question: if the top rectangle is $x$ cm wide, how wide is the bottom rectangle? Can you use that to write down a formula for the area of each of the two rectangles?
â Xander Henderson
Aug 8 at 21:17
1
if the top shaded rectangle's width is x, then its area is 4*x. The lower shaded rectangle is then 3*(14-x)? So then you have 4*x = 3*14-x?
â Local Worker
Aug 8 at 21:21
1
Exactly. So what next? (Also, it would be useful if you edited your question to include any new thoughts that you have---such edits add context to the question.)
â Xander Henderson
Aug 8 at 21:23
4
4
If the upper rectangle is $x$ cm wide, how wide is the lower rectangle? Can you compute the area in terms of that width $x$? What, specifically, are you stuck on?
â Xander Henderson
Aug 8 at 20:59
If the upper rectangle is $x$ cm wide, how wide is the lower rectangle? Can you compute the area in terms of that width $x$? What, specifically, are you stuck on?
â Xander Henderson
Aug 8 at 20:59
Specifically I am stuck on the width of both the shaded areas.
â Local Worker
Aug 8 at 21:16
Specifically I am stuck on the width of both the shaded areas.
â Local Worker
Aug 8 at 21:16
1
1
So answer my first question: if the top rectangle is $x$ cm wide, how wide is the bottom rectangle? Can you use that to write down a formula for the area of each of the two rectangles?
â Xander Henderson
Aug 8 at 21:17
So answer my first question: if the top rectangle is $x$ cm wide, how wide is the bottom rectangle? Can you use that to write down a formula for the area of each of the two rectangles?
â Xander Henderson
Aug 8 at 21:17
1
1
if the top shaded rectangle's width is x, then its area is 4*x. The lower shaded rectangle is then 3*(14-x)? So then you have 4*x = 3*14-x?
â Local Worker
Aug 8 at 21:21
if the top shaded rectangle's width is x, then its area is 4*x. The lower shaded rectangle is then 3*(14-x)? So then you have 4*x = 3*14-x?
â Local Worker
Aug 8 at 21:21
1
1
Exactly. So what next? (Also, it would be useful if you edited your question to include any new thoughts that you have---such edits add context to the question.)
â Xander Henderson
Aug 8 at 21:23
Exactly. So what next? (Also, it would be useful if you edited your question to include any new thoughts that you have---such edits add context to the question.)
â Xander Henderson
Aug 8 at 21:23
 |Â
show 5 more comments
1 Answer
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You have to solve the equation:
$$3x=4(14-x)$$
After that you can compute the shaded area as
$$A=2cdot 3x$$
add a comment |Â
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
You have to solve the equation:
$$3x=4(14-x)$$
After that you can compute the shaded area as
$$A=2cdot 3x$$
add a comment |Â
up vote
1
down vote
You have to solve the equation:
$$3x=4(14-x)$$
After that you can compute the shaded area as
$$A=2cdot 3x$$
add a comment |Â
up vote
1
down vote
up vote
1
down vote
You have to solve the equation:
$$3x=4(14-x)$$
After that you can compute the shaded area as
$$A=2cdot 3x$$
You have to solve the equation:
$$3x=4(14-x)$$
After that you can compute the shaded area as
$$A=2cdot 3x$$
answered Aug 8 at 21:23
Jaroslaw Matlak
3,900830
3,900830
add a comment |Â
add a comment |Â
4
If the upper rectangle is $x$ cm wide, how wide is the lower rectangle? Can you compute the area in terms of that width $x$? What, specifically, are you stuck on?
â Xander Henderson
Aug 8 at 20:59
Specifically I am stuck on the width of both the shaded areas.
â Local Worker
Aug 8 at 21:16
1
So answer my first question: if the top rectangle is $x$ cm wide, how wide is the bottom rectangle? Can you use that to write down a formula for the area of each of the two rectangles?
â Xander Henderson
Aug 8 at 21:17
1
if the top shaded rectangle's width is x, then its area is 4*x. The lower shaded rectangle is then 3*(14-x)? So then you have 4*x = 3*14-x?
â Local Worker
Aug 8 at 21:21
1
Exactly. So what next? (Also, it would be useful if you edited your question to include any new thoughts that you have---such edits add context to the question.)
â Xander Henderson
Aug 8 at 21:23