Shaded rectangle within a rectangle [closed]

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Shaded Rectangle



The two shaded rectangles have the same area, what is the total shaded area in cm$^2$? I tried to reason it out to 49 cm$^2$ but apparently thats not correct.







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closed as off-topic by Xander Henderson, amWhy, Jendrik Stelzner, Leucippus, Key Flex Aug 9 at 2:18


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Xander Henderson, amWhy, Jendrik Stelzner, Leucippus, Key Flex
If this question can be reworded to fit the rules in the help center, please edit the question.








  • 4




    If the upper rectangle is $x$ cm wide, how wide is the lower rectangle? Can you compute the area in terms of that width $x$? What, specifically, are you stuck on?
    – Xander Henderson
    Aug 8 at 20:59










  • Specifically I am stuck on the width of both the shaded areas.
    – Local Worker
    Aug 8 at 21:16






  • 1




    So answer my first question: if the top rectangle is $x$ cm wide, how wide is the bottom rectangle? Can you use that to write down a formula for the area of each of the two rectangles?
    – Xander Henderson
    Aug 8 at 21:17






  • 1




    if the top shaded rectangle's width is x, then its area is 4*x. The lower shaded rectangle is then 3*(14-x)? So then you have 4*x = 3*14-x?
    – Local Worker
    Aug 8 at 21:21







  • 1




    Exactly. So what next? (Also, it would be useful if you edited your question to include any new thoughts that you have---such edits add context to the question.)
    – Xander Henderson
    Aug 8 at 21:23














up vote
-2
down vote

favorite












Shaded Rectangle



The two shaded rectangles have the same area, what is the total shaded area in cm$^2$? I tried to reason it out to 49 cm$^2$ but apparently thats not correct.







share|cite|improve this question














closed as off-topic by Xander Henderson, amWhy, Jendrik Stelzner, Leucippus, Key Flex Aug 9 at 2:18


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Xander Henderson, amWhy, Jendrik Stelzner, Leucippus, Key Flex
If this question can be reworded to fit the rules in the help center, please edit the question.








  • 4




    If the upper rectangle is $x$ cm wide, how wide is the lower rectangle? Can you compute the area in terms of that width $x$? What, specifically, are you stuck on?
    – Xander Henderson
    Aug 8 at 20:59










  • Specifically I am stuck on the width of both the shaded areas.
    – Local Worker
    Aug 8 at 21:16






  • 1




    So answer my first question: if the top rectangle is $x$ cm wide, how wide is the bottom rectangle? Can you use that to write down a formula for the area of each of the two rectangles?
    – Xander Henderson
    Aug 8 at 21:17






  • 1




    if the top shaded rectangle's width is x, then its area is 4*x. The lower shaded rectangle is then 3*(14-x)? So then you have 4*x = 3*14-x?
    – Local Worker
    Aug 8 at 21:21







  • 1




    Exactly. So what next? (Also, it would be useful if you edited your question to include any new thoughts that you have---such edits add context to the question.)
    – Xander Henderson
    Aug 8 at 21:23












up vote
-2
down vote

favorite









up vote
-2
down vote

favorite











Shaded Rectangle



The two shaded rectangles have the same area, what is the total shaded area in cm$^2$? I tried to reason it out to 49 cm$^2$ but apparently thats not correct.







share|cite|improve this question














Shaded Rectangle



The two shaded rectangles have the same area, what is the total shaded area in cm$^2$? I tried to reason it out to 49 cm$^2$ but apparently thats not correct.









share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Aug 8 at 21:24









Jaroslaw Matlak

3,900830




3,900830










asked Aug 8 at 20:55









Local Worker

132




132




closed as off-topic by Xander Henderson, amWhy, Jendrik Stelzner, Leucippus, Key Flex Aug 9 at 2:18


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Xander Henderson, amWhy, Jendrik Stelzner, Leucippus, Key Flex
If this question can be reworded to fit the rules in the help center, please edit the question.




closed as off-topic by Xander Henderson, amWhy, Jendrik Stelzner, Leucippus, Key Flex Aug 9 at 2:18


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Xander Henderson, amWhy, Jendrik Stelzner, Leucippus, Key Flex
If this question can be reworded to fit the rules in the help center, please edit the question.







  • 4




    If the upper rectangle is $x$ cm wide, how wide is the lower rectangle? Can you compute the area in terms of that width $x$? What, specifically, are you stuck on?
    – Xander Henderson
    Aug 8 at 20:59










  • Specifically I am stuck on the width of both the shaded areas.
    – Local Worker
    Aug 8 at 21:16






  • 1




    So answer my first question: if the top rectangle is $x$ cm wide, how wide is the bottom rectangle? Can you use that to write down a formula for the area of each of the two rectangles?
    – Xander Henderson
    Aug 8 at 21:17






  • 1




    if the top shaded rectangle's width is x, then its area is 4*x. The lower shaded rectangle is then 3*(14-x)? So then you have 4*x = 3*14-x?
    – Local Worker
    Aug 8 at 21:21







  • 1




    Exactly. So what next? (Also, it would be useful if you edited your question to include any new thoughts that you have---such edits add context to the question.)
    – Xander Henderson
    Aug 8 at 21:23












  • 4




    If the upper rectangle is $x$ cm wide, how wide is the lower rectangle? Can you compute the area in terms of that width $x$? What, specifically, are you stuck on?
    – Xander Henderson
    Aug 8 at 20:59










  • Specifically I am stuck on the width of both the shaded areas.
    – Local Worker
    Aug 8 at 21:16






  • 1




    So answer my first question: if the top rectangle is $x$ cm wide, how wide is the bottom rectangle? Can you use that to write down a formula for the area of each of the two rectangles?
    – Xander Henderson
    Aug 8 at 21:17






  • 1




    if the top shaded rectangle's width is x, then its area is 4*x. The lower shaded rectangle is then 3*(14-x)? So then you have 4*x = 3*14-x?
    – Local Worker
    Aug 8 at 21:21







  • 1




    Exactly. So what next? (Also, it would be useful if you edited your question to include any new thoughts that you have---such edits add context to the question.)
    – Xander Henderson
    Aug 8 at 21:23







4




4




If the upper rectangle is $x$ cm wide, how wide is the lower rectangle? Can you compute the area in terms of that width $x$? What, specifically, are you stuck on?
– Xander Henderson
Aug 8 at 20:59




If the upper rectangle is $x$ cm wide, how wide is the lower rectangle? Can you compute the area in terms of that width $x$? What, specifically, are you stuck on?
– Xander Henderson
Aug 8 at 20:59












Specifically I am stuck on the width of both the shaded areas.
– Local Worker
Aug 8 at 21:16




Specifically I am stuck on the width of both the shaded areas.
– Local Worker
Aug 8 at 21:16




1




1




So answer my first question: if the top rectangle is $x$ cm wide, how wide is the bottom rectangle? Can you use that to write down a formula for the area of each of the two rectangles?
– Xander Henderson
Aug 8 at 21:17




So answer my first question: if the top rectangle is $x$ cm wide, how wide is the bottom rectangle? Can you use that to write down a formula for the area of each of the two rectangles?
– Xander Henderson
Aug 8 at 21:17




1




1




if the top shaded rectangle's width is x, then its area is 4*x. The lower shaded rectangle is then 3*(14-x)? So then you have 4*x = 3*14-x?
– Local Worker
Aug 8 at 21:21





if the top shaded rectangle's width is x, then its area is 4*x. The lower shaded rectangle is then 3*(14-x)? So then you have 4*x = 3*14-x?
– Local Worker
Aug 8 at 21:21





1




1




Exactly. So what next? (Also, it would be useful if you edited your question to include any new thoughts that you have---such edits add context to the question.)
– Xander Henderson
Aug 8 at 21:23




Exactly. So what next? (Also, it would be useful if you edited your question to include any new thoughts that you have---such edits add context to the question.)
– Xander Henderson
Aug 8 at 21:23










1 Answer
1






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votes

















up vote
1
down vote













You have to solve the equation:
$$3x=4(14-x)$$
After that you can compute the shaded area as
$$A=2cdot 3x$$






share|cite|improve this answer



























    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes








    up vote
    1
    down vote













    You have to solve the equation:
    $$3x=4(14-x)$$
    After that you can compute the shaded area as
    $$A=2cdot 3x$$






    share|cite|improve this answer
























      up vote
      1
      down vote













      You have to solve the equation:
      $$3x=4(14-x)$$
      After that you can compute the shaded area as
      $$A=2cdot 3x$$






      share|cite|improve this answer






















        up vote
        1
        down vote










        up vote
        1
        down vote









        You have to solve the equation:
        $$3x=4(14-x)$$
        After that you can compute the shaded area as
        $$A=2cdot 3x$$






        share|cite|improve this answer












        You have to solve the equation:
        $$3x=4(14-x)$$
        After that you can compute the shaded area as
        $$A=2cdot 3x$$







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered Aug 8 at 21:23









        Jaroslaw Matlak

        3,900830




        3,900830












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