Minimal polynomial and possible Jordan forms

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Let $A$ be an $8times 8$ complex matrix with characteristic polynomial $$p_A(x)=(x-1)^4(x+2)^2(x^2+1)$$ and minimal polynomial $$m_A(x)=(x-1)^2(x+2)^2(x^2+1).$$ Determine all possible Jordan canonical forms of $A$. Also, what is the dimension of the eigenspace for $lambda = 1$ for each case?




I haven't learned minimal polynomial yet, so I wanted to check if I am on the right track.



From the characteristic polynomial, the eigenvalues are $i,-i,-2,1$. From the minimal polynomial, the block sizes are $1,1,2$ for eigenvalues $i,-i,-2$ respectively. For $lambda = 1$, the largest block size is 2, so the possible block sizes are $2,2$, which has eigenspace dim of 2 ($J_1$). Or the sizes are $2,1,1$, which has eigenspace dim of 3 ($J_2$). Writing the full Jordan matrix:



$J_1=beginpmatrix1&1&0&0&0&0&0&0\0&1&0&0&0&0&0&0\0&0&1&1&0&0&0&0\0&0&0&1&0&0&0&0\0&0&0&0&-2&1&0&0\0&0&0&0&0&-2&0&0\0&0&0&0&0&0&i&0\0&0&0&0&0&0&0&-iendpmatrix$, $J_2=beginpmatrix1&1&0&0&0&0&0&0\0&1&0&0&0&0&0&0\0&0&1&0&0&0&0&0\0&0&0&1&0&0&0&0\0&0&0&0&-2&1&0&0\0&0&0&0&0&-2&0&0\0&0&0&0&0&0&i&0\0&0&0&0&0&0&0&-iendpmatrix$







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    Looks to me like you did everything right!
    – Christian
    Jul 19 '16 at 2:37










  • @Christian yay! thank you
    – Julie
    Jul 19 '16 at 2:52














up vote
3
down vote

favorite













Let $A$ be an $8times 8$ complex matrix with characteristic polynomial $$p_A(x)=(x-1)^4(x+2)^2(x^2+1)$$ and minimal polynomial $$m_A(x)=(x-1)^2(x+2)^2(x^2+1).$$ Determine all possible Jordan canonical forms of $A$. Also, what is the dimension of the eigenspace for $lambda = 1$ for each case?




I haven't learned minimal polynomial yet, so I wanted to check if I am on the right track.



From the characteristic polynomial, the eigenvalues are $i,-i,-2,1$. From the minimal polynomial, the block sizes are $1,1,2$ for eigenvalues $i,-i,-2$ respectively. For $lambda = 1$, the largest block size is 2, so the possible block sizes are $2,2$, which has eigenspace dim of 2 ($J_1$). Or the sizes are $2,1,1$, which has eigenspace dim of 3 ($J_2$). Writing the full Jordan matrix:



$J_1=beginpmatrix1&1&0&0&0&0&0&0\0&1&0&0&0&0&0&0\0&0&1&1&0&0&0&0\0&0&0&1&0&0&0&0\0&0&0&0&-2&1&0&0\0&0&0&0&0&-2&0&0\0&0&0&0&0&0&i&0\0&0&0&0&0&0&0&-iendpmatrix$, $J_2=beginpmatrix1&1&0&0&0&0&0&0\0&1&0&0&0&0&0&0\0&0&1&0&0&0&0&0\0&0&0&1&0&0&0&0\0&0&0&0&-2&1&0&0\0&0&0&0&0&-2&0&0\0&0&0&0&0&0&i&0\0&0&0&0&0&0&0&-iendpmatrix$







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  • 2




    Looks to me like you did everything right!
    – Christian
    Jul 19 '16 at 2:37










  • @Christian yay! thank you
    – Julie
    Jul 19 '16 at 2:52












up vote
3
down vote

favorite









up vote
3
down vote

favorite












Let $A$ be an $8times 8$ complex matrix with characteristic polynomial $$p_A(x)=(x-1)^4(x+2)^2(x^2+1)$$ and minimal polynomial $$m_A(x)=(x-1)^2(x+2)^2(x^2+1).$$ Determine all possible Jordan canonical forms of $A$. Also, what is the dimension of the eigenspace for $lambda = 1$ for each case?




I haven't learned minimal polynomial yet, so I wanted to check if I am on the right track.



From the characteristic polynomial, the eigenvalues are $i,-i,-2,1$. From the minimal polynomial, the block sizes are $1,1,2$ for eigenvalues $i,-i,-2$ respectively. For $lambda = 1$, the largest block size is 2, so the possible block sizes are $2,2$, which has eigenspace dim of 2 ($J_1$). Or the sizes are $2,1,1$, which has eigenspace dim of 3 ($J_2$). Writing the full Jordan matrix:



$J_1=beginpmatrix1&1&0&0&0&0&0&0\0&1&0&0&0&0&0&0\0&0&1&1&0&0&0&0\0&0&0&1&0&0&0&0\0&0&0&0&-2&1&0&0\0&0&0&0&0&-2&0&0\0&0&0&0&0&0&i&0\0&0&0&0&0&0&0&-iendpmatrix$, $J_2=beginpmatrix1&1&0&0&0&0&0&0\0&1&0&0&0&0&0&0\0&0&1&0&0&0&0&0\0&0&0&1&0&0&0&0\0&0&0&0&-2&1&0&0\0&0&0&0&0&-2&0&0\0&0&0&0&0&0&i&0\0&0&0&0&0&0&0&-iendpmatrix$







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Let $A$ be an $8times 8$ complex matrix with characteristic polynomial $$p_A(x)=(x-1)^4(x+2)^2(x^2+1)$$ and minimal polynomial $$m_A(x)=(x-1)^2(x+2)^2(x^2+1).$$ Determine all possible Jordan canonical forms of $A$. Also, what is the dimension of the eigenspace for $lambda = 1$ for each case?




I haven't learned minimal polynomial yet, so I wanted to check if I am on the right track.



From the characteristic polynomial, the eigenvalues are $i,-i,-2,1$. From the minimal polynomial, the block sizes are $1,1,2$ for eigenvalues $i,-i,-2$ respectively. For $lambda = 1$, the largest block size is 2, so the possible block sizes are $2,2$, which has eigenspace dim of 2 ($J_1$). Or the sizes are $2,1,1$, which has eigenspace dim of 3 ($J_2$). Writing the full Jordan matrix:



$J_1=beginpmatrix1&1&0&0&0&0&0&0\0&1&0&0&0&0&0&0\0&0&1&1&0&0&0&0\0&0&0&1&0&0&0&0\0&0&0&0&-2&1&0&0\0&0&0&0&0&-2&0&0\0&0&0&0&0&0&i&0\0&0&0&0&0&0&0&-iendpmatrix$, $J_2=beginpmatrix1&1&0&0&0&0&0&0\0&1&0&0&0&0&0&0\0&0&1&0&0&0&0&0\0&0&0&1&0&0&0&0\0&0&0&0&-2&1&0&0\0&0&0&0&0&-2&0&0\0&0&0&0&0&0&i&0\0&0&0&0&0&0&0&-iendpmatrix$









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asked Jul 19 '16 at 2:30









Julie

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  • 2




    Looks to me like you did everything right!
    – Christian
    Jul 19 '16 at 2:37










  • @Christian yay! thank you
    – Julie
    Jul 19 '16 at 2:52












  • 2




    Looks to me like you did everything right!
    – Christian
    Jul 19 '16 at 2:37










  • @Christian yay! thank you
    – Julie
    Jul 19 '16 at 2:52







2




2




Looks to me like you did everything right!
– Christian
Jul 19 '16 at 2:37




Looks to me like you did everything right!
– Christian
Jul 19 '16 at 2:37












@Christian yay! thank you
– Julie
Jul 19 '16 at 2:52




@Christian yay! thank you
– Julie
Jul 19 '16 at 2:52










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You identified the blocks and eigenspace dimensions correctly. The blocks for a given form, however, can be permuted. Thus, your first matrix represents 5!/2! = 60 forms, and your second matrix, 6!/2! = 360 forms for a total of 420 forms.






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    You identified the blocks and eigenspace dimensions correctly. The blocks for a given form, however, can be permuted. Thus, your first matrix represents 5!/2! = 60 forms, and your second matrix, 6!/2! = 360 forms for a total of 420 forms.






    share|cite|improve this answer
























      up vote
      0
      down vote













      You identified the blocks and eigenspace dimensions correctly. The blocks for a given form, however, can be permuted. Thus, your first matrix represents 5!/2! = 60 forms, and your second matrix, 6!/2! = 360 forms for a total of 420 forms.






      share|cite|improve this answer






















        up vote
        0
        down vote










        up vote
        0
        down vote









        You identified the blocks and eigenspace dimensions correctly. The blocks for a given form, however, can be permuted. Thus, your first matrix represents 5!/2! = 60 forms, and your second matrix, 6!/2! = 360 forms for a total of 420 forms.






        share|cite|improve this answer












        You identified the blocks and eigenspace dimensions correctly. The blocks for a given form, however, can be permuted. Thus, your first matrix represents 5!/2! = 60 forms, and your second matrix, 6!/2! = 360 forms for a total of 420 forms.







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered Aug 8 at 17:10









        Maurice P

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