Gaussian elimination with partial pivoting

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GEPP( Gaussian elimination with partial pivoting) is a method used to solve Ax=b.



Let us assume that A is non singular matrix and GEPP is backward stable.



Let x* be the approximate solution computed with GEPP and x is the exact solution.



I want to give a bound for the error in the solution.



Here is my attempt, since GEPP is backward stable, then we have:



||x*-x||/||x|| = O(eps machine), then ||x*-x||=O(||x|| eps machine).



Since x=inv(A)b, then ||x-x||=O(||inv(A)*b|| eps machine) < O(||b||/sigma m eps machine)



where sigma m is the smallest singular value of A.



Does his seem correct bound ?







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  • An approximate solution $x^*$ of $Ax=b$ is backward stable, if $(A+E)x^*=b+f$ such that $|E|/|A|=mathcalO(epsilon_mathrmmach)$ and $|f|/|b|=mathcalO(epsilon_mathrmmach)$ in some suitable norms.
    – Algebraic Pavel
    Aug 10 at 11:25














up vote
0
down vote

favorite












GEPP( Gaussian elimination with partial pivoting) is a method used to solve Ax=b.



Let us assume that A is non singular matrix and GEPP is backward stable.



Let x* be the approximate solution computed with GEPP and x is the exact solution.



I want to give a bound for the error in the solution.



Here is my attempt, since GEPP is backward stable, then we have:



||x*-x||/||x|| = O(eps machine), then ||x*-x||=O(||x|| eps machine).



Since x=inv(A)b, then ||x-x||=O(||inv(A)*b|| eps machine) < O(||b||/sigma m eps machine)



where sigma m is the smallest singular value of A.



Does his seem correct bound ?







share|cite|improve this question




















  • An approximate solution $x^*$ of $Ax=b$ is backward stable, if $(A+E)x^*=b+f$ such that $|E|/|A|=mathcalO(epsilon_mathrmmach)$ and $|f|/|b|=mathcalO(epsilon_mathrmmach)$ in some suitable norms.
    – Algebraic Pavel
    Aug 10 at 11:25












up vote
0
down vote

favorite









up vote
0
down vote

favorite











GEPP( Gaussian elimination with partial pivoting) is a method used to solve Ax=b.



Let us assume that A is non singular matrix and GEPP is backward stable.



Let x* be the approximate solution computed with GEPP and x is the exact solution.



I want to give a bound for the error in the solution.



Here is my attempt, since GEPP is backward stable, then we have:



||x*-x||/||x|| = O(eps machine), then ||x*-x||=O(||x|| eps machine).



Since x=inv(A)b, then ||x-x||=O(||inv(A)*b|| eps machine) < O(||b||/sigma m eps machine)



where sigma m is the smallest singular value of A.



Does his seem correct bound ?







share|cite|improve this question












GEPP( Gaussian elimination with partial pivoting) is a method used to solve Ax=b.



Let us assume that A is non singular matrix and GEPP is backward stable.



Let x* be the approximate solution computed with GEPP and x is the exact solution.



I want to give a bound for the error in the solution.



Here is my attempt, since GEPP is backward stable, then we have:



||x*-x||/||x|| = O(eps machine), then ||x*-x||=O(||x|| eps machine).



Since x=inv(A)b, then ||x-x||=O(||inv(A)*b|| eps machine) < O(||b||/sigma m eps machine)



where sigma m is the smallest singular value of A.



Does his seem correct bound ?









share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Aug 8 at 19:22









Mike

414




414











  • An approximate solution $x^*$ of $Ax=b$ is backward stable, if $(A+E)x^*=b+f$ such that $|E|/|A|=mathcalO(epsilon_mathrmmach)$ and $|f|/|b|=mathcalO(epsilon_mathrmmach)$ in some suitable norms.
    – Algebraic Pavel
    Aug 10 at 11:25
















  • An approximate solution $x^*$ of $Ax=b$ is backward stable, if $(A+E)x^*=b+f$ such that $|E|/|A|=mathcalO(epsilon_mathrmmach)$ and $|f|/|b|=mathcalO(epsilon_mathrmmach)$ in some suitable norms.
    – Algebraic Pavel
    Aug 10 at 11:25















An approximate solution $x^*$ of $Ax=b$ is backward stable, if $(A+E)x^*=b+f$ such that $|E|/|A|=mathcalO(epsilon_mathrmmach)$ and $|f|/|b|=mathcalO(epsilon_mathrmmach)$ in some suitable norms.
– Algebraic Pavel
Aug 10 at 11:25




An approximate solution $x^*$ of $Ax=b$ is backward stable, if $(A+E)x^*=b+f$ such that $|E|/|A|=mathcalO(epsilon_mathrmmach)$ and $|f|/|b|=mathcalO(epsilon_mathrmmach)$ in some suitable norms.
– Algebraic Pavel
Aug 10 at 11:25















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