Elements over transcendental extension

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Let $F$ a field and suppose that $E$ is a extension field of $F$. Now, take $alphain E$ trascendental over $F$. My question is about the form of the elements of $F(alpha)$. I think that $$F(alpha)=leftfracf(alpha)g(alpha):f,gin F[x]right$$.
Am I right?
abstract-algebra soft-question extension-field
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Let $F$ a field and suppose that $E$ is a extension field of $F$. Now, take $alphain E$ trascendental over $F$. My question is about the form of the elements of $F(alpha)$. I think that $$F(alpha)=leftfracf(alpha)g(alpha):f,gin F[x]right$$.
Am I right?
abstract-algebra soft-question extension-field
I think you meant "transcendental over $F$". As to your collection, it isn't clear what you mean. If $f,gin F[x]$ then $lambda f, lambda g$ define the same element of $F(alpha)$. And if you allow multiple expressions for the same element then your collection defines $F(alpha)$ even if $alpha $ is algebraic.
â lulu
Aug 7 at 17:10
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up vote
0
down vote
favorite
up vote
0
down vote
favorite
Let $F$ a field and suppose that $E$ is a extension field of $F$. Now, take $alphain E$ trascendental over $F$. My question is about the form of the elements of $F(alpha)$. I think that $$F(alpha)=leftfracf(alpha)g(alpha):f,gin F[x]right$$.
Am I right?
abstract-algebra soft-question extension-field
Let $F$ a field and suppose that $E$ is a extension field of $F$. Now, take $alphain E$ trascendental over $F$. My question is about the form of the elements of $F(alpha)$. I think that $$F(alpha)=leftfracf(alpha)g(alpha):f,gin F[x]right$$.
Am I right?
abstract-algebra soft-question extension-field
edited Aug 7 at 17:12
asked Aug 7 at 17:05
Gödel
1,145319
1,145319
I think you meant "transcendental over $F$". As to your collection, it isn't clear what you mean. If $f,gin F[x]$ then $lambda f, lambda g$ define the same element of $F(alpha)$. And if you allow multiple expressions for the same element then your collection defines $F(alpha)$ even if $alpha $ is algebraic.
â lulu
Aug 7 at 17:10
add a comment |Â
I think you meant "transcendental over $F$". As to your collection, it isn't clear what you mean. If $f,gin F[x]$ then $lambda f, lambda g$ define the same element of $F(alpha)$. And if you allow multiple expressions for the same element then your collection defines $F(alpha)$ even if $alpha $ is algebraic.
â lulu
Aug 7 at 17:10
I think you meant "transcendental over $F$". As to your collection, it isn't clear what you mean. If $f,gin F[x]$ then $lambda f, lambda g$ define the same element of $F(alpha)$. And if you allow multiple expressions for the same element then your collection defines $F(alpha)$ even if $alpha $ is algebraic.
â lulu
Aug 7 at 17:10
I think you meant "transcendental over $F$". As to your collection, it isn't clear what you mean. If $f,gin F[x]$ then $lambda f, lambda g$ define the same element of $F(alpha)$. And if you allow multiple expressions for the same element then your collection defines $F(alpha)$ even if $alpha $ is algebraic.
â lulu
Aug 7 at 17:10
add a comment |Â
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I think you meant "transcendental over $F$". As to your collection, it isn't clear what you mean. If $f,gin F[x]$ then $lambda f, lambda g$ define the same element of $F(alpha)$. And if you allow multiple expressions for the same element then your collection defines $F(alpha)$ even if $alpha $ is algebraic.
â lulu
Aug 7 at 17:10