Elements over transcendental extension

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Let $F$ a field and suppose that $E$ is a extension field of $F$. Now, take $alphain E$ trascendental over $F$. My question is about the form of the elements of $F(alpha)$. I think that $$F(alpha)=leftfracf(alpha)g(alpha):f,gin F[x]right$$.



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  • I think you meant "transcendental over $F$". As to your collection, it isn't clear what you mean. If $f,gin F[x]$ then $lambda f, lambda g$ define the same element of $F(alpha)$. And if you allow multiple expressions for the same element then your collection defines $F(alpha)$ even if $alpha $ is algebraic.
    – lulu
    Aug 7 at 17:10















up vote
0
down vote

favorite












Let $F$ a field and suppose that $E$ is a extension field of $F$. Now, take $alphain E$ trascendental over $F$. My question is about the form of the elements of $F(alpha)$. I think that $$F(alpha)=leftfracf(alpha)g(alpha):f,gin F[x]right$$.



Am I right?







share|cite|improve this question





















  • I think you meant "transcendental over $F$". As to your collection, it isn't clear what you mean. If $f,gin F[x]$ then $lambda f, lambda g$ define the same element of $F(alpha)$. And if you allow multiple expressions for the same element then your collection defines $F(alpha)$ even if $alpha $ is algebraic.
    – lulu
    Aug 7 at 17:10













up vote
0
down vote

favorite









up vote
0
down vote

favorite











Let $F$ a field and suppose that $E$ is a extension field of $F$. Now, take $alphain E$ trascendental over $F$. My question is about the form of the elements of $F(alpha)$. I think that $$F(alpha)=leftfracf(alpha)g(alpha):f,gin F[x]right$$.



Am I right?







share|cite|improve this question













Let $F$ a field and suppose that $E$ is a extension field of $F$. Now, take $alphain E$ trascendental over $F$. My question is about the form of the elements of $F(alpha)$. I think that $$F(alpha)=leftfracf(alpha)g(alpha):f,gin F[x]right$$.



Am I right?









share|cite|improve this question












share|cite|improve this question




share|cite|improve this question








edited Aug 7 at 17:12
























asked Aug 7 at 17:05









Gödel

1,145319




1,145319











  • I think you meant "transcendental over $F$". As to your collection, it isn't clear what you mean. If $f,gin F[x]$ then $lambda f, lambda g$ define the same element of $F(alpha)$. And if you allow multiple expressions for the same element then your collection defines $F(alpha)$ even if $alpha $ is algebraic.
    – lulu
    Aug 7 at 17:10

















  • I think you meant "transcendental over $F$". As to your collection, it isn't clear what you mean. If $f,gin F[x]$ then $lambda f, lambda g$ define the same element of $F(alpha)$. And if you allow multiple expressions for the same element then your collection defines $F(alpha)$ even if $alpha $ is algebraic.
    – lulu
    Aug 7 at 17:10
















I think you meant "transcendental over $F$". As to your collection, it isn't clear what you mean. If $f,gin F[x]$ then $lambda f, lambda g$ define the same element of $F(alpha)$. And if you allow multiple expressions for the same element then your collection defines $F(alpha)$ even if $alpha $ is algebraic.
– lulu
Aug 7 at 17:10





I think you meant "transcendental over $F$". As to your collection, it isn't clear what you mean. If $f,gin F[x]$ then $lambda f, lambda g$ define the same element of $F(alpha)$. And if you allow multiple expressions for the same element then your collection defines $F(alpha)$ even if $alpha $ is algebraic.
– lulu
Aug 7 at 17:10
















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