Decide whether each triangle below lies in the Euclidean plane, on a sphere (of radius 1), or in the hyperbolic plane
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A triangle has sides of length $a$, $b$, $c$ (given correct to $2$dp) and a right angle opposite $c$. Decide whether each triangle below lies in the Euclidean plane, on a sphere (of radius $1$), or in the hyperbolic plane
- $a=b=1.00, c=1.27$
- $a=0.50, b=1.20, c=1.34$
- $a=1.0, b=2.40, c=2.60$
- $a=b=3.00, c=0.20$
In each case, answer "Euclidean", "spherical" or "hyperbolic".
How to do this without calculator? I have an exam tomorrow please help.
geometry euclidean-geometry hyperbolic-geometry spherical-geometry
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up vote
-1
down vote
favorite
A triangle has sides of length $a$, $b$, $c$ (given correct to $2$dp) and a right angle opposite $c$. Decide whether each triangle below lies in the Euclidean plane, on a sphere (of radius $1$), or in the hyperbolic plane
- $a=b=1.00, c=1.27$
- $a=0.50, b=1.20, c=1.34$
- $a=1.0, b=2.40, c=2.60$
- $a=b=3.00, c=0.20$
In each case, answer "Euclidean", "spherical" or "hyperbolic".
How to do this without calculator? I have an exam tomorrow please help.
geometry euclidean-geometry hyperbolic-geometry spherical-geometry
add a comment |Â
up vote
-1
down vote
favorite
up vote
-1
down vote
favorite
A triangle has sides of length $a$, $b$, $c$ (given correct to $2$dp) and a right angle opposite $c$. Decide whether each triangle below lies in the Euclidean plane, on a sphere (of radius $1$), or in the hyperbolic plane
- $a=b=1.00, c=1.27$
- $a=0.50, b=1.20, c=1.34$
- $a=1.0, b=2.40, c=2.60$
- $a=b=3.00, c=0.20$
In each case, answer "Euclidean", "spherical" or "hyperbolic".
How to do this without calculator? I have an exam tomorrow please help.
geometry euclidean-geometry hyperbolic-geometry spherical-geometry
A triangle has sides of length $a$, $b$, $c$ (given correct to $2$dp) and a right angle opposite $c$. Decide whether each triangle below lies in the Euclidean plane, on a sphere (of radius $1$), or in the hyperbolic plane
- $a=b=1.00, c=1.27$
- $a=0.50, b=1.20, c=1.34$
- $a=1.0, b=2.40, c=2.60$
- $a=b=3.00, c=0.20$
In each case, answer "Euclidean", "spherical" or "hyperbolic".
How to do this without calculator? I have an exam tomorrow please help.
geometry euclidean-geometry hyperbolic-geometry spherical-geometry
edited Aug 7 at 18:12
asked Aug 7 at 17:46
mathsnerd22
12
12
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1 Answer
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The Pythagorean theorem says $a^2+b^2=c^2$ for the Euclidean case, the left hand side would be larger than the right one in spherical geomatry and smaller for the hyperbolic one. Thus you would have to calculate simply $sqrta^2+b^2$ and compare that to $c$.
That root would become $1.41$, $ 1.3$, $ 2.6$, $ 4.23$ respectively.
You even could do all this without calculator. Because of $sqrt2=1.41$ respectively $13^2=169$. The remainder is just a multiplication by $2$ respectively $3$.
--- rk
ah thanks that makes sense! :)
â mathsnerd22
Aug 7 at 19:06
add a comment |Â
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
The Pythagorean theorem says $a^2+b^2=c^2$ for the Euclidean case, the left hand side would be larger than the right one in spherical geomatry and smaller for the hyperbolic one. Thus you would have to calculate simply $sqrta^2+b^2$ and compare that to $c$.
That root would become $1.41$, $ 1.3$, $ 2.6$, $ 4.23$ respectively.
You even could do all this without calculator. Because of $sqrt2=1.41$ respectively $13^2=169$. The remainder is just a multiplication by $2$ respectively $3$.
--- rk
ah thanks that makes sense! :)
â mathsnerd22
Aug 7 at 19:06
add a comment |Â
up vote
0
down vote
The Pythagorean theorem says $a^2+b^2=c^2$ for the Euclidean case, the left hand side would be larger than the right one in spherical geomatry and smaller for the hyperbolic one. Thus you would have to calculate simply $sqrta^2+b^2$ and compare that to $c$.
That root would become $1.41$, $ 1.3$, $ 2.6$, $ 4.23$ respectively.
You even could do all this without calculator. Because of $sqrt2=1.41$ respectively $13^2=169$. The remainder is just a multiplication by $2$ respectively $3$.
--- rk
ah thanks that makes sense! :)
â mathsnerd22
Aug 7 at 19:06
add a comment |Â
up vote
0
down vote
up vote
0
down vote
The Pythagorean theorem says $a^2+b^2=c^2$ for the Euclidean case, the left hand side would be larger than the right one in spherical geomatry and smaller for the hyperbolic one. Thus you would have to calculate simply $sqrta^2+b^2$ and compare that to $c$.
That root would become $1.41$, $ 1.3$, $ 2.6$, $ 4.23$ respectively.
You even could do all this without calculator. Because of $sqrt2=1.41$ respectively $13^2=169$. The remainder is just a multiplication by $2$ respectively $3$.
--- rk
The Pythagorean theorem says $a^2+b^2=c^2$ for the Euclidean case, the left hand side would be larger than the right one in spherical geomatry and smaller for the hyperbolic one. Thus you would have to calculate simply $sqrta^2+b^2$ and compare that to $c$.
That root would become $1.41$, $ 1.3$, $ 2.6$, $ 4.23$ respectively.
You even could do all this without calculator. Because of $sqrt2=1.41$ respectively $13^2=169$. The remainder is just a multiplication by $2$ respectively $3$.
--- rk
edited Aug 7 at 18:52
answered Aug 7 at 18:45
Dr. Richard Klitzing
7566
7566
ah thanks that makes sense! :)
â mathsnerd22
Aug 7 at 19:06
add a comment |Â
ah thanks that makes sense! :)
â mathsnerd22
Aug 7 at 19:06
ah thanks that makes sense! :)
â mathsnerd22
Aug 7 at 19:06
ah thanks that makes sense! :)
â mathsnerd22
Aug 7 at 19:06
add a comment |Â
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