Weird Notation for Trace of an Endomorphism

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I am having some difficulty understanding a piece of notation from Riemannian Geometry: and Introduction to Curvature by John M. Lee.



In Section 2 just under equation 2.3 Lee defines the trace operator which lowers the rank of a tensor by 2.




He defines the map:
$$mathrmtr:T_l+1^k+1(V)longrightarrow T_l^k(V)$$
By letting:
$$mathrmtr; F(omega^1,dotsomega^l,V_1,dots,V_k)$$
be the trace of the endomorphism:
$$F(omega^1,dots,omega^l,bullet,V_1,dots,V_k,bullet)$$




But how is it that $F(omega^1,dots,omega^l,bullet,V_1,dots,V_k,bullet) inmathrmEnd(V)$, it looks like it should belong to $T_l+1^k+1$, I think my confusion lies with the $bullet$ in the above expression. Unforturnately I cannot find any explanation of this notation in the textbook. Is this notation common for something that I am not aware of?







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    up vote
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    favorite












    I am having some difficulty understanding a piece of notation from Riemannian Geometry: and Introduction to Curvature by John M. Lee.



    In Section 2 just under equation 2.3 Lee defines the trace operator which lowers the rank of a tensor by 2.




    He defines the map:
    $$mathrmtr:T_l+1^k+1(V)longrightarrow T_l^k(V)$$
    By letting:
    $$mathrmtr; F(omega^1,dotsomega^l,V_1,dots,V_k)$$
    be the trace of the endomorphism:
    $$F(omega^1,dots,omega^l,bullet,V_1,dots,V_k,bullet)$$




    But how is it that $F(omega^1,dots,omega^l,bullet,V_1,dots,V_k,bullet) inmathrmEnd(V)$, it looks like it should belong to $T_l+1^k+1$, I think my confusion lies with the $bullet$ in the above expression. Unforturnately I cannot find any explanation of this notation in the textbook. Is this notation common for something that I am not aware of?







    share|cite|improve this question





















      up vote
      3
      down vote

      favorite









      up vote
      3
      down vote

      favorite











      I am having some difficulty understanding a piece of notation from Riemannian Geometry: and Introduction to Curvature by John M. Lee.



      In Section 2 just under equation 2.3 Lee defines the trace operator which lowers the rank of a tensor by 2.




      He defines the map:
      $$mathrmtr:T_l+1^k+1(V)longrightarrow T_l^k(V)$$
      By letting:
      $$mathrmtr; F(omega^1,dotsomega^l,V_1,dots,V_k)$$
      be the trace of the endomorphism:
      $$F(omega^1,dots,omega^l,bullet,V_1,dots,V_k,bullet)$$




      But how is it that $F(omega^1,dots,omega^l,bullet,V_1,dots,V_k,bullet) inmathrmEnd(V)$, it looks like it should belong to $T_l+1^k+1$, I think my confusion lies with the $bullet$ in the above expression. Unforturnately I cannot find any explanation of this notation in the textbook. Is this notation common for something that I am not aware of?







      share|cite|improve this question











      I am having some difficulty understanding a piece of notation from Riemannian Geometry: and Introduction to Curvature by John M. Lee.



      In Section 2 just under equation 2.3 Lee defines the trace operator which lowers the rank of a tensor by 2.




      He defines the map:
      $$mathrmtr:T_l+1^k+1(V)longrightarrow T_l^k(V)$$
      By letting:
      $$mathrmtr; F(omega^1,dotsomega^l,V_1,dots,V_k)$$
      be the trace of the endomorphism:
      $$F(omega^1,dots,omega^l,bullet,V_1,dots,V_k,bullet)$$




      But how is it that $F(omega^1,dots,omega^l,bullet,V_1,dots,V_k,bullet) inmathrmEnd(V)$, it looks like it should belong to $T_l+1^k+1$, I think my confusion lies with the $bullet$ in the above expression. Unforturnately I cannot find any explanation of this notation in the textbook. Is this notation common for something that I am not aware of?









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      asked Aug 7 at 18:44









      Logan Toll

      658415




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          For fixed $omega^1, ldots, omega^l in V^*$ and $V_1, ldots, V_k in V$ the notation $F(omega^1,dots,omega^l,bullet,V_1,dots,V_k,bullet)$ signifies an element $G in T_1^1(V)$ such that
          $$G(omega^l+1, V_k+1) = F(omega^1, ldots, omega^l, omega^l+1, V_1, ldots, V_k, V_k+1).$$



          Then $operatornametr F in T_l^k(V)$ is defined by
          $$(operatornametr F)(omega^1, ldots, omega^l, V_1, ldots, V_k) = operatornametrG.$$






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            1 Answer
            1






            active

            oldest

            votes








            1 Answer
            1






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes








            up vote
            2
            down vote



            accepted










            For fixed $omega^1, ldots, omega^l in V^*$ and $V_1, ldots, V_k in V$ the notation $F(omega^1,dots,omega^l,bullet,V_1,dots,V_k,bullet)$ signifies an element $G in T_1^1(V)$ such that
            $$G(omega^l+1, V_k+1) = F(omega^1, ldots, omega^l, omega^l+1, V_1, ldots, V_k, V_k+1).$$



            Then $operatornametr F in T_l^k(V)$ is defined by
            $$(operatornametr F)(omega^1, ldots, omega^l, V_1, ldots, V_k) = operatornametrG.$$






            share|cite|improve this answer

























              up vote
              2
              down vote



              accepted










              For fixed $omega^1, ldots, omega^l in V^*$ and $V_1, ldots, V_k in V$ the notation $F(omega^1,dots,omega^l,bullet,V_1,dots,V_k,bullet)$ signifies an element $G in T_1^1(V)$ such that
              $$G(omega^l+1, V_k+1) = F(omega^1, ldots, omega^l, omega^l+1, V_1, ldots, V_k, V_k+1).$$



              Then $operatornametr F in T_l^k(V)$ is defined by
              $$(operatornametr F)(omega^1, ldots, omega^l, V_1, ldots, V_k) = operatornametrG.$$






              share|cite|improve this answer























                up vote
                2
                down vote



                accepted







                up vote
                2
                down vote



                accepted






                For fixed $omega^1, ldots, omega^l in V^*$ and $V_1, ldots, V_k in V$ the notation $F(omega^1,dots,omega^l,bullet,V_1,dots,V_k,bullet)$ signifies an element $G in T_1^1(V)$ such that
                $$G(omega^l+1, V_k+1) = F(omega^1, ldots, omega^l, omega^l+1, V_1, ldots, V_k, V_k+1).$$



                Then $operatornametr F in T_l^k(V)$ is defined by
                $$(operatornametr F)(omega^1, ldots, omega^l, V_1, ldots, V_k) = operatornametrG.$$






                share|cite|improve this answer













                For fixed $omega^1, ldots, omega^l in V^*$ and $V_1, ldots, V_k in V$ the notation $F(omega^1,dots,omega^l,bullet,V_1,dots,V_k,bullet)$ signifies an element $G in T_1^1(V)$ such that
                $$G(omega^l+1, V_k+1) = F(omega^1, ldots, omega^l, omega^l+1, V_1, ldots, V_k, V_k+1).$$



                Then $operatornametr F in T_l^k(V)$ is defined by
                $$(operatornametr F)(omega^1, ldots, omega^l, V_1, ldots, V_k) = operatornametrG.$$







                share|cite|improve this answer













                share|cite|improve this answer



                share|cite|improve this answer











                answered Aug 7 at 21:51









                md2perpe

                6,07111022




                6,07111022






















                     

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