How to evaluate indefinite integrals $intfrace^m arctan x(1+x)^3/2 dx$.

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$$intfrace^m arctan x(1+x)^3/2 operatornamedx$$




I tried solving with identities and searched around a bit but couldn't find a solution. How do we proceed?







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    Welcome to MSE. It will be more likely that you will get an answer if you show us that you made an effort. This should be added to the question rather than in the comments.
    – José Carlos Santos
    Aug 7 at 14:22










  • Are you sure that you made no typo in the integral? For example shouldnt it be: $intfrace^m arctan x(1+x^2)^3/2 operatornamedx?$
    – Zacky
    Aug 9 at 9:47











  • yes, I'm sure the denominator has the term (1+x)^3/2
    – CJamie
    Aug 9 at 15:54














up vote
1
down vote

favorite
1













$$intfrace^m arctan x(1+x)^3/2 operatornamedx$$




I tried solving with identities and searched around a bit but couldn't find a solution. How do we proceed?







share|cite|improve this question

















  • 2




    Welcome to MSE. It will be more likely that you will get an answer if you show us that you made an effort. This should be added to the question rather than in the comments.
    – José Carlos Santos
    Aug 7 at 14:22










  • Are you sure that you made no typo in the integral? For example shouldnt it be: $intfrace^m arctan x(1+x^2)^3/2 operatornamedx?$
    – Zacky
    Aug 9 at 9:47











  • yes, I'm sure the denominator has the term (1+x)^3/2
    – CJamie
    Aug 9 at 15:54












up vote
1
down vote

favorite
1









up vote
1
down vote

favorite
1






1






$$intfrace^m arctan x(1+x)^3/2 operatornamedx$$




I tried solving with identities and searched around a bit but couldn't find a solution. How do we proceed?







share|cite|improve this question














$$intfrace^m arctan x(1+x)^3/2 operatornamedx$$




I tried solving with identities and searched around a bit but couldn't find a solution. How do we proceed?









share|cite|improve this question












share|cite|improve this question




share|cite|improve this question








edited Aug 9 at 7:14









Nosrati

20.2k41644




20.2k41644









asked Aug 7 at 14:06









CJamie

92




92







  • 2




    Welcome to MSE. It will be more likely that you will get an answer if you show us that you made an effort. This should be added to the question rather than in the comments.
    – José Carlos Santos
    Aug 7 at 14:22










  • Are you sure that you made no typo in the integral? For example shouldnt it be: $intfrace^m arctan x(1+x^2)^3/2 operatornamedx?$
    – Zacky
    Aug 9 at 9:47











  • yes, I'm sure the denominator has the term (1+x)^3/2
    – CJamie
    Aug 9 at 15:54












  • 2




    Welcome to MSE. It will be more likely that you will get an answer if you show us that you made an effort. This should be added to the question rather than in the comments.
    – José Carlos Santos
    Aug 7 at 14:22










  • Are you sure that you made no typo in the integral? For example shouldnt it be: $intfrace^m arctan x(1+x^2)^3/2 operatornamedx?$
    – Zacky
    Aug 9 at 9:47











  • yes, I'm sure the denominator has the term (1+x)^3/2
    – CJamie
    Aug 9 at 15:54







2




2




Welcome to MSE. It will be more likely that you will get an answer if you show us that you made an effort. This should be added to the question rather than in the comments.
– José Carlos Santos
Aug 7 at 14:22




Welcome to MSE. It will be more likely that you will get an answer if you show us that you made an effort. This should be added to the question rather than in the comments.
– José Carlos Santos
Aug 7 at 14:22












Are you sure that you made no typo in the integral? For example shouldnt it be: $intfrace^m arctan x(1+x^2)^3/2 operatornamedx?$
– Zacky
Aug 9 at 9:47





Are you sure that you made no typo in the integral? For example shouldnt it be: $intfrace^m arctan x(1+x^2)^3/2 operatornamedx?$
– Zacky
Aug 9 at 9:47













yes, I'm sure the denominator has the term (1+x)^3/2
– CJamie
Aug 9 at 15:54




yes, I'm sure the denominator has the term (1+x)^3/2
– CJamie
Aug 9 at 15:54















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