Partitions of unity, smooth manifolds. Is this proof wrong?

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I need help in a passage of a proof.



I want to show :




Let $M$ be a smooth manifold, and let $U_alpha_alpha$ be an open cover of $M$. Then exists a partition of unity subordinate to $U_alpha$, i.e. a collection $rho_alphacolon Mto mathbbR _alpha$ of $C^infty$ functions such that:



1) for each $alpha$ we have Image$rho_alphasubseteq[0,1]$



2) for each $alpha$ we have supp$rho_alphasubseteq U_alpha$



3) for each point $pin M$ exists an open neighborhood $A_p$ of $p$ such that $A_p cap$ supp$rho_alphaneemptyset$ at most for finitely many indices $alpha$.



4) for each point $pin M$ we have $sum_alphamid rho_alpha(p)ne0rho_alpha(p)=1$.




Proof.



Let $M$ be a smooth manifold, and let $U_alpha_alpha$ be an open cover of $M$. I already know that exists $Vj$ and $Wj$ countable open cover of $M$, such that



1) for each $j$, $overlineV_j$ is compact and $overlineV_jsubseteq W_j$



2) $W_j$ is a locally finite refinement of $U_alpha$, i.e. each $W_j$ is contained in some $U_alpha$ and for each point $pin M$ exists an open neighborhood $A_p$ of $p$ such that $A_p cap W_jneemptyset$ at most for finitely many indices $j$.



For each $j$ let $phi_jcolon M to mathbbR$ be a smooth bump function for the couple $(overlineV_j,W_j)$, i.e.



1) $phi_j$ is $C^infty$ in $M$



2) Im$phi_j subseteq [0,1]$



3) supp$phi_j subseteq W_j$



4) $phi_j|_overlineV_jequiv 1$.



Let $phi colon M to mathbbR$ be such that for each $p in M$ we have $phi (p)=sum_j: pin Wj phi_j(p)$.



Then, $phi$ is $C^infty$ and $phi(p)ge 1$ for every $p in M$.



Finally, let $rho_alpha colon M to mathbbR$ be such that



$$rho_alpha(p)=fracsum_j : W_j subseteq U_alpha textand ; pin W_j phi_j(p)phi(p)$$



I want to show that $rho_alphacolon Mto mathbbR _alpha$ verify the properties 1) 2) 3) 4) of the yellow rectangle.



I have problem with showing property 3)



If I am correct, i have shown that $pin M mid rho_alpha(p)ne 0=bigcup_j: W_j subseteq U_alpha pin M mid phi_j(p)ne 0$ and taking the closure in $M$ i have supp$rho_alpha=bigcup_j: W_j subseteq U_alpha$ supp$phi_j subseteq bigcup_j: W_j subseteq U_alpha W_j subseteq U_alpha$.



P.S. I don't know if $j: W_j subseteq U_alpha$ is finite or non, but i can take the closure and preserve the "$=$" in the equation
$$pin M mid rho_alpha(p)ne 0=bigcup_j: W_j subseteq U_alpha pin M mid phi_j(p)ne 0$$
even if in general "closure of union $ne$ union of closures" if the union is infnite. This because of the following Lemma: if $mathfrakX$ is a locally finite collection of subsets of a topolofical space $M$, then $$overlinebigcup_XinmathfrakXX=bigcup_XinmathfrakXoverlineX$$




But I'm being unable to show property 3).



Thank you for your help.




Edit



Here is my reasoning.
Suppose that $p$ is a point in $M$ such that $rho_alpha(p)ne 0$ for some index $alpha$. This means that there is an index $j$ such that $W_j subseteq U_alpha$ and $phi_j(p)ne 0$. Let $A:= betamid W_j subseteq U_beta$. Then $Ane emptyset$ since $alpha in A$. We have $rho_beta(p)ne0 ; forall beta in A$. So, if $A$ is infinite, then $pin$ supp$rho_beta ;forall beta in A$ and so it is not possible that property 3 is true. So I think I should prove that $A$ must be finite, but $U_alpha$ is an arbitrary open cover of $M$, so why should $A$ be finite?




I'm in total confusion. Maybe the proof is wrong?




Edit n.2 , 17/05/2018



I'm having doubts also for property 4).



Suppose that $rho_alpha(p)ne 0$ for some index $alpha$. This means that there is an index $j$ such that $W_jsubseteq U_alpha$ and $phi_j(p)ne0$. If $betanealpha$ is another index such that also $W_jsubseteq U_beta$, then the addend $phi_j(p)$ appears also in $rho_beta (p)$ and so $phi_j(p)$ appears at least twice in $$sum_gammamid rho_gamma(p)ne0rho_gamma(p)$$ and this would imply that $$sum_alphamid rho_alpha(p)ne0rho_alpha(p)ge1$$ So also property 4) is not true.




Where does my reasoning falls?



Thank-you for your help.








share|cite|improve this question

























    up vote
    0
    down vote

    favorite












    I need help in a passage of a proof.



    I want to show :




    Let $M$ be a smooth manifold, and let $U_alpha_alpha$ be an open cover of $M$. Then exists a partition of unity subordinate to $U_alpha$, i.e. a collection $rho_alphacolon Mto mathbbR _alpha$ of $C^infty$ functions such that:



    1) for each $alpha$ we have Image$rho_alphasubseteq[0,1]$



    2) for each $alpha$ we have supp$rho_alphasubseteq U_alpha$



    3) for each point $pin M$ exists an open neighborhood $A_p$ of $p$ such that $A_p cap$ supp$rho_alphaneemptyset$ at most for finitely many indices $alpha$.



    4) for each point $pin M$ we have $sum_alphamid rho_alpha(p)ne0rho_alpha(p)=1$.




    Proof.



    Let $M$ be a smooth manifold, and let $U_alpha_alpha$ be an open cover of $M$. I already know that exists $Vj$ and $Wj$ countable open cover of $M$, such that



    1) for each $j$, $overlineV_j$ is compact and $overlineV_jsubseteq W_j$



    2) $W_j$ is a locally finite refinement of $U_alpha$, i.e. each $W_j$ is contained in some $U_alpha$ and for each point $pin M$ exists an open neighborhood $A_p$ of $p$ such that $A_p cap W_jneemptyset$ at most for finitely many indices $j$.



    For each $j$ let $phi_jcolon M to mathbbR$ be a smooth bump function for the couple $(overlineV_j,W_j)$, i.e.



    1) $phi_j$ is $C^infty$ in $M$



    2) Im$phi_j subseteq [0,1]$



    3) supp$phi_j subseteq W_j$



    4) $phi_j|_overlineV_jequiv 1$.



    Let $phi colon M to mathbbR$ be such that for each $p in M$ we have $phi (p)=sum_j: pin Wj phi_j(p)$.



    Then, $phi$ is $C^infty$ and $phi(p)ge 1$ for every $p in M$.



    Finally, let $rho_alpha colon M to mathbbR$ be such that



    $$rho_alpha(p)=fracsum_j : W_j subseteq U_alpha textand ; pin W_j phi_j(p)phi(p)$$



    I want to show that $rho_alphacolon Mto mathbbR _alpha$ verify the properties 1) 2) 3) 4) of the yellow rectangle.



    I have problem with showing property 3)



    If I am correct, i have shown that $pin M mid rho_alpha(p)ne 0=bigcup_j: W_j subseteq U_alpha pin M mid phi_j(p)ne 0$ and taking the closure in $M$ i have supp$rho_alpha=bigcup_j: W_j subseteq U_alpha$ supp$phi_j subseteq bigcup_j: W_j subseteq U_alpha W_j subseteq U_alpha$.



    P.S. I don't know if $j: W_j subseteq U_alpha$ is finite or non, but i can take the closure and preserve the "$=$" in the equation
    $$pin M mid rho_alpha(p)ne 0=bigcup_j: W_j subseteq U_alpha pin M mid phi_j(p)ne 0$$
    even if in general "closure of union $ne$ union of closures" if the union is infnite. This because of the following Lemma: if $mathfrakX$ is a locally finite collection of subsets of a topolofical space $M$, then $$overlinebigcup_XinmathfrakXX=bigcup_XinmathfrakXoverlineX$$




    But I'm being unable to show property 3).



    Thank you for your help.




    Edit



    Here is my reasoning.
    Suppose that $p$ is a point in $M$ such that $rho_alpha(p)ne 0$ for some index $alpha$. This means that there is an index $j$ such that $W_j subseteq U_alpha$ and $phi_j(p)ne 0$. Let $A:= betamid W_j subseteq U_beta$. Then $Ane emptyset$ since $alpha in A$. We have $rho_beta(p)ne0 ; forall beta in A$. So, if $A$ is infinite, then $pin$ supp$rho_beta ;forall beta in A$ and so it is not possible that property 3 is true. So I think I should prove that $A$ must be finite, but $U_alpha$ is an arbitrary open cover of $M$, so why should $A$ be finite?




    I'm in total confusion. Maybe the proof is wrong?




    Edit n.2 , 17/05/2018



    I'm having doubts also for property 4).



    Suppose that $rho_alpha(p)ne 0$ for some index $alpha$. This means that there is an index $j$ such that $W_jsubseteq U_alpha$ and $phi_j(p)ne0$. If $betanealpha$ is another index such that also $W_jsubseteq U_beta$, then the addend $phi_j(p)$ appears also in $rho_beta (p)$ and so $phi_j(p)$ appears at least twice in $$sum_gammamid rho_gamma(p)ne0rho_gamma(p)$$ and this would imply that $$sum_alphamid rho_alpha(p)ne0rho_alpha(p)ge1$$ So also property 4) is not true.




    Where does my reasoning falls?



    Thank-you for your help.








    share|cite|improve this question























      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      I need help in a passage of a proof.



      I want to show :




      Let $M$ be a smooth manifold, and let $U_alpha_alpha$ be an open cover of $M$. Then exists a partition of unity subordinate to $U_alpha$, i.e. a collection $rho_alphacolon Mto mathbbR _alpha$ of $C^infty$ functions such that:



      1) for each $alpha$ we have Image$rho_alphasubseteq[0,1]$



      2) for each $alpha$ we have supp$rho_alphasubseteq U_alpha$



      3) for each point $pin M$ exists an open neighborhood $A_p$ of $p$ such that $A_p cap$ supp$rho_alphaneemptyset$ at most for finitely many indices $alpha$.



      4) for each point $pin M$ we have $sum_alphamid rho_alpha(p)ne0rho_alpha(p)=1$.




      Proof.



      Let $M$ be a smooth manifold, and let $U_alpha_alpha$ be an open cover of $M$. I already know that exists $Vj$ and $Wj$ countable open cover of $M$, such that



      1) for each $j$, $overlineV_j$ is compact and $overlineV_jsubseteq W_j$



      2) $W_j$ is a locally finite refinement of $U_alpha$, i.e. each $W_j$ is contained in some $U_alpha$ and for each point $pin M$ exists an open neighborhood $A_p$ of $p$ such that $A_p cap W_jneemptyset$ at most for finitely many indices $j$.



      For each $j$ let $phi_jcolon M to mathbbR$ be a smooth bump function for the couple $(overlineV_j,W_j)$, i.e.



      1) $phi_j$ is $C^infty$ in $M$



      2) Im$phi_j subseteq [0,1]$



      3) supp$phi_j subseteq W_j$



      4) $phi_j|_overlineV_jequiv 1$.



      Let $phi colon M to mathbbR$ be such that for each $p in M$ we have $phi (p)=sum_j: pin Wj phi_j(p)$.



      Then, $phi$ is $C^infty$ and $phi(p)ge 1$ for every $p in M$.



      Finally, let $rho_alpha colon M to mathbbR$ be such that



      $$rho_alpha(p)=fracsum_j : W_j subseteq U_alpha textand ; pin W_j phi_j(p)phi(p)$$



      I want to show that $rho_alphacolon Mto mathbbR _alpha$ verify the properties 1) 2) 3) 4) of the yellow rectangle.



      I have problem with showing property 3)



      If I am correct, i have shown that $pin M mid rho_alpha(p)ne 0=bigcup_j: W_j subseteq U_alpha pin M mid phi_j(p)ne 0$ and taking the closure in $M$ i have supp$rho_alpha=bigcup_j: W_j subseteq U_alpha$ supp$phi_j subseteq bigcup_j: W_j subseteq U_alpha W_j subseteq U_alpha$.



      P.S. I don't know if $j: W_j subseteq U_alpha$ is finite or non, but i can take the closure and preserve the "$=$" in the equation
      $$pin M mid rho_alpha(p)ne 0=bigcup_j: W_j subseteq U_alpha pin M mid phi_j(p)ne 0$$
      even if in general "closure of union $ne$ union of closures" if the union is infnite. This because of the following Lemma: if $mathfrakX$ is a locally finite collection of subsets of a topolofical space $M$, then $$overlinebigcup_XinmathfrakXX=bigcup_XinmathfrakXoverlineX$$




      But I'm being unable to show property 3).



      Thank you for your help.




      Edit



      Here is my reasoning.
      Suppose that $p$ is a point in $M$ such that $rho_alpha(p)ne 0$ for some index $alpha$. This means that there is an index $j$ such that $W_j subseteq U_alpha$ and $phi_j(p)ne 0$. Let $A:= betamid W_j subseteq U_beta$. Then $Ane emptyset$ since $alpha in A$. We have $rho_beta(p)ne0 ; forall beta in A$. So, if $A$ is infinite, then $pin$ supp$rho_beta ;forall beta in A$ and so it is not possible that property 3 is true. So I think I should prove that $A$ must be finite, but $U_alpha$ is an arbitrary open cover of $M$, so why should $A$ be finite?




      I'm in total confusion. Maybe the proof is wrong?




      Edit n.2 , 17/05/2018



      I'm having doubts also for property 4).



      Suppose that $rho_alpha(p)ne 0$ for some index $alpha$. This means that there is an index $j$ such that $W_jsubseteq U_alpha$ and $phi_j(p)ne0$. If $betanealpha$ is another index such that also $W_jsubseteq U_beta$, then the addend $phi_j(p)$ appears also in $rho_beta (p)$ and so $phi_j(p)$ appears at least twice in $$sum_gammamid rho_gamma(p)ne0rho_gamma(p)$$ and this would imply that $$sum_alphamid rho_alpha(p)ne0rho_alpha(p)ge1$$ So also property 4) is not true.




      Where does my reasoning falls?



      Thank-you for your help.








      share|cite|improve this question













      I need help in a passage of a proof.



      I want to show :




      Let $M$ be a smooth manifold, and let $U_alpha_alpha$ be an open cover of $M$. Then exists a partition of unity subordinate to $U_alpha$, i.e. a collection $rho_alphacolon Mto mathbbR _alpha$ of $C^infty$ functions such that:



      1) for each $alpha$ we have Image$rho_alphasubseteq[0,1]$



      2) for each $alpha$ we have supp$rho_alphasubseteq U_alpha$



      3) for each point $pin M$ exists an open neighborhood $A_p$ of $p$ such that $A_p cap$ supp$rho_alphaneemptyset$ at most for finitely many indices $alpha$.



      4) for each point $pin M$ we have $sum_alphamid rho_alpha(p)ne0rho_alpha(p)=1$.




      Proof.



      Let $M$ be a smooth manifold, and let $U_alpha_alpha$ be an open cover of $M$. I already know that exists $Vj$ and $Wj$ countable open cover of $M$, such that



      1) for each $j$, $overlineV_j$ is compact and $overlineV_jsubseteq W_j$



      2) $W_j$ is a locally finite refinement of $U_alpha$, i.e. each $W_j$ is contained in some $U_alpha$ and for each point $pin M$ exists an open neighborhood $A_p$ of $p$ such that $A_p cap W_jneemptyset$ at most for finitely many indices $j$.



      For each $j$ let $phi_jcolon M to mathbbR$ be a smooth bump function for the couple $(overlineV_j,W_j)$, i.e.



      1) $phi_j$ is $C^infty$ in $M$



      2) Im$phi_j subseteq [0,1]$



      3) supp$phi_j subseteq W_j$



      4) $phi_j|_overlineV_jequiv 1$.



      Let $phi colon M to mathbbR$ be such that for each $p in M$ we have $phi (p)=sum_j: pin Wj phi_j(p)$.



      Then, $phi$ is $C^infty$ and $phi(p)ge 1$ for every $p in M$.



      Finally, let $rho_alpha colon M to mathbbR$ be such that



      $$rho_alpha(p)=fracsum_j : W_j subseteq U_alpha textand ; pin W_j phi_j(p)phi(p)$$



      I want to show that $rho_alphacolon Mto mathbbR _alpha$ verify the properties 1) 2) 3) 4) of the yellow rectangle.



      I have problem with showing property 3)



      If I am correct, i have shown that $pin M mid rho_alpha(p)ne 0=bigcup_j: W_j subseteq U_alpha pin M mid phi_j(p)ne 0$ and taking the closure in $M$ i have supp$rho_alpha=bigcup_j: W_j subseteq U_alpha$ supp$phi_j subseteq bigcup_j: W_j subseteq U_alpha W_j subseteq U_alpha$.



      P.S. I don't know if $j: W_j subseteq U_alpha$ is finite or non, but i can take the closure and preserve the "$=$" in the equation
      $$pin M mid rho_alpha(p)ne 0=bigcup_j: W_j subseteq U_alpha pin M mid phi_j(p)ne 0$$
      even if in general "closure of union $ne$ union of closures" if the union is infnite. This because of the following Lemma: if $mathfrakX$ is a locally finite collection of subsets of a topolofical space $M$, then $$overlinebigcup_XinmathfrakXX=bigcup_XinmathfrakXoverlineX$$




      But I'm being unable to show property 3).



      Thank you for your help.




      Edit



      Here is my reasoning.
      Suppose that $p$ is a point in $M$ such that $rho_alpha(p)ne 0$ for some index $alpha$. This means that there is an index $j$ such that $W_j subseteq U_alpha$ and $phi_j(p)ne 0$. Let $A:= betamid W_j subseteq U_beta$. Then $Ane emptyset$ since $alpha in A$. We have $rho_beta(p)ne0 ; forall beta in A$. So, if $A$ is infinite, then $pin$ supp$rho_beta ;forall beta in A$ and so it is not possible that property 3 is true. So I think I should prove that $A$ must be finite, but $U_alpha$ is an arbitrary open cover of $M$, so why should $A$ be finite?




      I'm in total confusion. Maybe the proof is wrong?




      Edit n.2 , 17/05/2018



      I'm having doubts also for property 4).



      Suppose that $rho_alpha(p)ne 0$ for some index $alpha$. This means that there is an index $j$ such that $W_jsubseteq U_alpha$ and $phi_j(p)ne0$. If $betanealpha$ is another index such that also $W_jsubseteq U_beta$, then the addend $phi_j(p)$ appears also in $rho_beta (p)$ and so $phi_j(p)$ appears at least twice in $$sum_gammamid rho_gamma(p)ne0rho_gamma(p)$$ and this would imply that $$sum_alphamid rho_alpha(p)ne0rho_alpha(p)ge1$$ So also property 4) is not true.




      Where does my reasoning falls?



      Thank-you for your help.










      share|cite|improve this question












      share|cite|improve this question




      share|cite|improve this question








      edited Aug 7 at 17:02
























      asked May 16 at 11:07









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