surface area of a parametric curve or revolution

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I have the equations $x=9t-3t^3 $ and $ y=9t^2$ , $0le tle 2$ rotated about the x-axis



what I did to try and solve this was:



$ S= int^2_0 2pi(9t^2) sqrt(9-9t^2)^2+(18t)^2dt $



$S= int^2_0 18pi t^2 sqrt81t^4 +162t^2+81dt $



$ S=int^2_0 18pi t^2 (9-9t^2)dt $



$S= int^2_0 162pi t^2 (t^2+1) dt $



$ S= 162pi [fract^55 +fract^33] $



$ S= frac7344pi5$



I'm not sure where I went wrong , any help pointing that out is greatly appreciated.







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  • Hence you are claiming you went wrong somewhere I guess you know the right solution. Could you please add the right one somewhere? I think it is easier to seach for a mistake by knowing what the outcome should look like.
    – mrtaurho
    Aug 7 at 21:06










  • Furthermore I have to say that I cannot spot any mistake beside the typo with the third line where it should be $(9+9t^2)$.
    – mrtaurho
    Aug 7 at 21:12










  • Do you understand "How this curve is"? Your calculation is correct when x increase monotonically.
    – Takahiro Waki
    Aug 7 at 21:28










  • wolfram alpha show this curve need a few integrals. wolframalpha.com/input/?i=x%3D9t-3t%5E3,y%3D9t%5E2,+0%3Ct%3C2
    – Takahiro Waki
    Aug 7 at 21:35















up vote
0
down vote

favorite












I have the equations $x=9t-3t^3 $ and $ y=9t^2$ , $0le tle 2$ rotated about the x-axis



what I did to try and solve this was:



$ S= int^2_0 2pi(9t^2) sqrt(9-9t^2)^2+(18t)^2dt $



$S= int^2_0 18pi t^2 sqrt81t^4 +162t^2+81dt $



$ S=int^2_0 18pi t^2 (9-9t^2)dt $



$S= int^2_0 162pi t^2 (t^2+1) dt $



$ S= 162pi [fract^55 +fract^33] $



$ S= frac7344pi5$



I'm not sure where I went wrong , any help pointing that out is greatly appreciated.







share|cite|improve this question



















  • Hence you are claiming you went wrong somewhere I guess you know the right solution. Could you please add the right one somewhere? I think it is easier to seach for a mistake by knowing what the outcome should look like.
    – mrtaurho
    Aug 7 at 21:06










  • Furthermore I have to say that I cannot spot any mistake beside the typo with the third line where it should be $(9+9t^2)$.
    – mrtaurho
    Aug 7 at 21:12










  • Do you understand "How this curve is"? Your calculation is correct when x increase monotonically.
    – Takahiro Waki
    Aug 7 at 21:28










  • wolfram alpha show this curve need a few integrals. wolframalpha.com/input/?i=x%3D9t-3t%5E3,y%3D9t%5E2,+0%3Ct%3C2
    – Takahiro Waki
    Aug 7 at 21:35













up vote
0
down vote

favorite









up vote
0
down vote

favorite











I have the equations $x=9t-3t^3 $ and $ y=9t^2$ , $0le tle 2$ rotated about the x-axis



what I did to try and solve this was:



$ S= int^2_0 2pi(9t^2) sqrt(9-9t^2)^2+(18t)^2dt $



$S= int^2_0 18pi t^2 sqrt81t^4 +162t^2+81dt $



$ S=int^2_0 18pi t^2 (9-9t^2)dt $



$S= int^2_0 162pi t^2 (t^2+1) dt $



$ S= 162pi [fract^55 +fract^33] $



$ S= frac7344pi5$



I'm not sure where I went wrong , any help pointing that out is greatly appreciated.







share|cite|improve this question











I have the equations $x=9t-3t^3 $ and $ y=9t^2$ , $0le tle 2$ rotated about the x-axis



what I did to try and solve this was:



$ S= int^2_0 2pi(9t^2) sqrt(9-9t^2)^2+(18t)^2dt $



$S= int^2_0 18pi t^2 sqrt81t^4 +162t^2+81dt $



$ S=int^2_0 18pi t^2 (9-9t^2)dt $



$S= int^2_0 162pi t^2 (t^2+1) dt $



$ S= 162pi [fract^55 +fract^33] $



$ S= frac7344pi5$



I'm not sure where I went wrong , any help pointing that out is greatly appreciated.









share|cite|improve this question










share|cite|improve this question




share|cite|improve this question









asked Aug 7 at 20:58









C_bri

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  • Hence you are claiming you went wrong somewhere I guess you know the right solution. Could you please add the right one somewhere? I think it is easier to seach for a mistake by knowing what the outcome should look like.
    – mrtaurho
    Aug 7 at 21:06










  • Furthermore I have to say that I cannot spot any mistake beside the typo with the third line where it should be $(9+9t^2)$.
    – mrtaurho
    Aug 7 at 21:12










  • Do you understand "How this curve is"? Your calculation is correct when x increase monotonically.
    – Takahiro Waki
    Aug 7 at 21:28










  • wolfram alpha show this curve need a few integrals. wolframalpha.com/input/?i=x%3D9t-3t%5E3,y%3D9t%5E2,+0%3Ct%3C2
    – Takahiro Waki
    Aug 7 at 21:35

















  • Hence you are claiming you went wrong somewhere I guess you know the right solution. Could you please add the right one somewhere? I think it is easier to seach for a mistake by knowing what the outcome should look like.
    – mrtaurho
    Aug 7 at 21:06










  • Furthermore I have to say that I cannot spot any mistake beside the typo with the third line where it should be $(9+9t^2)$.
    – mrtaurho
    Aug 7 at 21:12










  • Do you understand "How this curve is"? Your calculation is correct when x increase monotonically.
    – Takahiro Waki
    Aug 7 at 21:28










  • wolfram alpha show this curve need a few integrals. wolframalpha.com/input/?i=x%3D9t-3t%5E3,y%3D9t%5E2,+0%3Ct%3C2
    – Takahiro Waki
    Aug 7 at 21:35
















Hence you are claiming you went wrong somewhere I guess you know the right solution. Could you please add the right one somewhere? I think it is easier to seach for a mistake by knowing what the outcome should look like.
– mrtaurho
Aug 7 at 21:06




Hence you are claiming you went wrong somewhere I guess you know the right solution. Could you please add the right one somewhere? I think it is easier to seach for a mistake by knowing what the outcome should look like.
– mrtaurho
Aug 7 at 21:06












Furthermore I have to say that I cannot spot any mistake beside the typo with the third line where it should be $(9+9t^2)$.
– mrtaurho
Aug 7 at 21:12




Furthermore I have to say that I cannot spot any mistake beside the typo with the third line where it should be $(9+9t^2)$.
– mrtaurho
Aug 7 at 21:12












Do you understand "How this curve is"? Your calculation is correct when x increase monotonically.
– Takahiro Waki
Aug 7 at 21:28




Do you understand "How this curve is"? Your calculation is correct when x increase monotonically.
– Takahiro Waki
Aug 7 at 21:28












wolfram alpha show this curve need a few integrals. wolframalpha.com/input/?i=x%3D9t-3t%5E3,y%3D9t%5E2,+0%3Ct%3C2
– Takahiro Waki
Aug 7 at 21:35





wolfram alpha show this curve need a few integrals. wolframalpha.com/input/?i=x%3D9t-3t%5E3,y%3D9t%5E2,+0%3Ct%3C2
– Takahiro Waki
Aug 7 at 21:35
















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