What is the probability that a random family of 4 gets wiped out by Thanos? (i.e 50 % of population being dead) [closed]
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I am confused about this. Do we need to consider in the factor of household distribution in the world?
The context is the movie Avengers: Infinity War. The important part of the question is a movie spoiler:
At the end of the movie, Thanos gets all six infinity stones, snaps his fingers, and half of the universe dies.
probability
closed as off-topic by Lee Mosher, amWhy, Xander Henderson, drhab, user 170039 Aug 7 at 15:33
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." â amWhy, Xander Henderson, drhab
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I am confused about this. Do we need to consider in the factor of household distribution in the world?
The context is the movie Avengers: Infinity War. The important part of the question is a movie spoiler:
At the end of the movie, Thanos gets all six infinity stones, snaps his fingers, and half of the universe dies.
probability
closed as off-topic by Lee Mosher, amWhy, Xander Henderson, drhab, user 170039 Aug 7 at 15:33
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." â amWhy, Xander Henderson, drhab
2
What are you talking about?
â lulu
Aug 7 at 15:22
I am asking if 50% of the world population is dying then what is the probability of family of 4 dying.
â Sagar Karira
Aug 7 at 15:23
@lulu The ending of Avengers: Infinity Wars.
â John
Aug 7 at 15:24
1
That's fine for those who have seen the movie. But this is a mathematics site, not a movie fan site, hence this question is entirely unclear.
â Lee Mosher
Aug 7 at 15:25
1
It was perfectly clear to me! :)
â John
Aug 7 at 15:25
 |Â
show 3 more comments
up vote
-1
down vote
favorite
up vote
-1
down vote
favorite
I am confused about this. Do we need to consider in the factor of household distribution in the world?
The context is the movie Avengers: Infinity War. The important part of the question is a movie spoiler:
At the end of the movie, Thanos gets all six infinity stones, snaps his fingers, and half of the universe dies.
probability
I am confused about this. Do we need to consider in the factor of household distribution in the world?
The context is the movie Avengers: Infinity War. The important part of the question is a movie spoiler:
At the end of the movie, Thanos gets all six infinity stones, snaps his fingers, and half of the universe dies.
probability
edited Aug 7 at 15:37
John
22k32347
22k32347
asked Aug 7 at 15:21
Sagar Karira
1075
1075
closed as off-topic by Lee Mosher, amWhy, Xander Henderson, drhab, user 170039 Aug 7 at 15:33
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." â amWhy, Xander Henderson, drhab
closed as off-topic by Lee Mosher, amWhy, Xander Henderson, drhab, user 170039 Aug 7 at 15:33
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." â amWhy, Xander Henderson, drhab
2
What are you talking about?
â lulu
Aug 7 at 15:22
I am asking if 50% of the world population is dying then what is the probability of family of 4 dying.
â Sagar Karira
Aug 7 at 15:23
@lulu The ending of Avengers: Infinity Wars.
â John
Aug 7 at 15:24
1
That's fine for those who have seen the movie. But this is a mathematics site, not a movie fan site, hence this question is entirely unclear.
â Lee Mosher
Aug 7 at 15:25
1
It was perfectly clear to me! :)
â John
Aug 7 at 15:25
 |Â
show 3 more comments
2
What are you talking about?
â lulu
Aug 7 at 15:22
I am asking if 50% of the world population is dying then what is the probability of family of 4 dying.
â Sagar Karira
Aug 7 at 15:23
@lulu The ending of Avengers: Infinity Wars.
â John
Aug 7 at 15:24
1
That's fine for those who have seen the movie. But this is a mathematics site, not a movie fan site, hence this question is entirely unclear.
â Lee Mosher
Aug 7 at 15:25
1
It was perfectly clear to me! :)
â John
Aug 7 at 15:25
2
2
What are you talking about?
â lulu
Aug 7 at 15:22
What are you talking about?
â lulu
Aug 7 at 15:22
I am asking if 50% of the world population is dying then what is the probability of family of 4 dying.
â Sagar Karira
Aug 7 at 15:23
I am asking if 50% of the world population is dying then what is the probability of family of 4 dying.
â Sagar Karira
Aug 7 at 15:23
@lulu The ending of Avengers: Infinity Wars.
â John
Aug 7 at 15:24
@lulu The ending of Avengers: Infinity Wars.
â John
Aug 7 at 15:24
1
1
That's fine for those who have seen the movie. But this is a mathematics site, not a movie fan site, hence this question is entirely unclear.
â Lee Mosher
Aug 7 at 15:25
That's fine for those who have seen the movie. But this is a mathematics site, not a movie fan site, hence this question is entirely unclear.
â Lee Mosher
Aug 7 at 15:25
1
1
It was perfectly clear to me! :)
â John
Aug 7 at 15:25
It was perfectly clear to me! :)
â John
Aug 7 at 15:25
 |Â
show 3 more comments
2 Answers
2
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3
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accepted
Consider each person getting turned to dust as an independent event, which happens with probability $1/2$. Then the probability of an entire family of four getting it is $(1/2)^4 = 1/16.$
And to answer your question about the household disbribution, if half of the family has to get it, then you already have your answer.
add a comment |Â
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3
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50% of all people will be wiped out. The probability that all 4 get wiped out is $left(dfrac12right)^4 = dfrac116$.
The full breakdown is as follows:
$$beginarrayc textNum survivors in fam & textProbability \
hline 0 & binom40frac116 = frac116 \
1 & binom41frac116 = frac14 \
2 & binom42frac116 = frac38 \
3 & binom43frac116 = frac14 \
4 & binom44frac116 = frac116 \
hline textTotal & 1 endarray$$
I was talking about the number of families on earth that has household size of 4 members. There are 12% of families out of 126 million families in USA that have 4 family members. So I thought the answer should be 12% of 1/16 since. That was my confusion.
â Sagar Karira
Aug 7 at 16:37
It depends on how you word the question. If you worded it as the probability that a random family had four members and all four were wiped out, then you are correct, and it would be 12% of 1/16. If you are only looking at families with four members, then there is a 100% chance that there are only four members in the family. This is known as a conditional probability.
â InterstellarProbe
Aug 7 at 19:05
add a comment |Â
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
3
down vote
accepted
Consider each person getting turned to dust as an independent event, which happens with probability $1/2$. Then the probability of an entire family of four getting it is $(1/2)^4 = 1/16.$
And to answer your question about the household disbribution, if half of the family has to get it, then you already have your answer.
add a comment |Â
up vote
3
down vote
accepted
Consider each person getting turned to dust as an independent event, which happens with probability $1/2$. Then the probability of an entire family of four getting it is $(1/2)^4 = 1/16.$
And to answer your question about the household disbribution, if half of the family has to get it, then you already have your answer.
add a comment |Â
up vote
3
down vote
accepted
up vote
3
down vote
accepted
Consider each person getting turned to dust as an independent event, which happens with probability $1/2$. Then the probability of an entire family of four getting it is $(1/2)^4 = 1/16.$
And to answer your question about the household disbribution, if half of the family has to get it, then you already have your answer.
Consider each person getting turned to dust as an independent event, which happens with probability $1/2$. Then the probability of an entire family of four getting it is $(1/2)^4 = 1/16.$
And to answer your question about the household disbribution, if half of the family has to get it, then you already have your answer.
edited Aug 7 at 15:35
answered Aug 7 at 15:23
John
22k32347
22k32347
add a comment |Â
add a comment |Â
up vote
3
down vote
50% of all people will be wiped out. The probability that all 4 get wiped out is $left(dfrac12right)^4 = dfrac116$.
The full breakdown is as follows:
$$beginarrayc textNum survivors in fam & textProbability \
hline 0 & binom40frac116 = frac116 \
1 & binom41frac116 = frac14 \
2 & binom42frac116 = frac38 \
3 & binom43frac116 = frac14 \
4 & binom44frac116 = frac116 \
hline textTotal & 1 endarray$$
I was talking about the number of families on earth that has household size of 4 members. There are 12% of families out of 126 million families in USA that have 4 family members. So I thought the answer should be 12% of 1/16 since. That was my confusion.
â Sagar Karira
Aug 7 at 16:37
It depends on how you word the question. If you worded it as the probability that a random family had four members and all four were wiped out, then you are correct, and it would be 12% of 1/16. If you are only looking at families with four members, then there is a 100% chance that there are only four members in the family. This is known as a conditional probability.
â InterstellarProbe
Aug 7 at 19:05
add a comment |Â
up vote
3
down vote
50% of all people will be wiped out. The probability that all 4 get wiped out is $left(dfrac12right)^4 = dfrac116$.
The full breakdown is as follows:
$$beginarrayc textNum survivors in fam & textProbability \
hline 0 & binom40frac116 = frac116 \
1 & binom41frac116 = frac14 \
2 & binom42frac116 = frac38 \
3 & binom43frac116 = frac14 \
4 & binom44frac116 = frac116 \
hline textTotal & 1 endarray$$
I was talking about the number of families on earth that has household size of 4 members. There are 12% of families out of 126 million families in USA that have 4 family members. So I thought the answer should be 12% of 1/16 since. That was my confusion.
â Sagar Karira
Aug 7 at 16:37
It depends on how you word the question. If you worded it as the probability that a random family had four members and all four were wiped out, then you are correct, and it would be 12% of 1/16. If you are only looking at families with four members, then there is a 100% chance that there are only four members in the family. This is known as a conditional probability.
â InterstellarProbe
Aug 7 at 19:05
add a comment |Â
up vote
3
down vote
up vote
3
down vote
50% of all people will be wiped out. The probability that all 4 get wiped out is $left(dfrac12right)^4 = dfrac116$.
The full breakdown is as follows:
$$beginarrayc textNum survivors in fam & textProbability \
hline 0 & binom40frac116 = frac116 \
1 & binom41frac116 = frac14 \
2 & binom42frac116 = frac38 \
3 & binom43frac116 = frac14 \
4 & binom44frac116 = frac116 \
hline textTotal & 1 endarray$$
50% of all people will be wiped out. The probability that all 4 get wiped out is $left(dfrac12right)^4 = dfrac116$.
The full breakdown is as follows:
$$beginarrayc textNum survivors in fam & textProbability \
hline 0 & binom40frac116 = frac116 \
1 & binom41frac116 = frac14 \
2 & binom42frac116 = frac38 \
3 & binom43frac116 = frac14 \
4 & binom44frac116 = frac116 \
hline textTotal & 1 endarray$$
edited Aug 7 at 16:05
answered Aug 7 at 15:23
InterstellarProbe
2,262518
2,262518
I was talking about the number of families on earth that has household size of 4 members. There are 12% of families out of 126 million families in USA that have 4 family members. So I thought the answer should be 12% of 1/16 since. That was my confusion.
â Sagar Karira
Aug 7 at 16:37
It depends on how you word the question. If you worded it as the probability that a random family had four members and all four were wiped out, then you are correct, and it would be 12% of 1/16. If you are only looking at families with four members, then there is a 100% chance that there are only four members in the family. This is known as a conditional probability.
â InterstellarProbe
Aug 7 at 19:05
add a comment |Â
I was talking about the number of families on earth that has household size of 4 members. There are 12% of families out of 126 million families in USA that have 4 family members. So I thought the answer should be 12% of 1/16 since. That was my confusion.
â Sagar Karira
Aug 7 at 16:37
It depends on how you word the question. If you worded it as the probability that a random family had four members and all four were wiped out, then you are correct, and it would be 12% of 1/16. If you are only looking at families with four members, then there is a 100% chance that there are only four members in the family. This is known as a conditional probability.
â InterstellarProbe
Aug 7 at 19:05
I was talking about the number of families on earth that has household size of 4 members. There are 12% of families out of 126 million families in USA that have 4 family members. So I thought the answer should be 12% of 1/16 since. That was my confusion.
â Sagar Karira
Aug 7 at 16:37
I was talking about the number of families on earth that has household size of 4 members. There are 12% of families out of 126 million families in USA that have 4 family members. So I thought the answer should be 12% of 1/16 since. That was my confusion.
â Sagar Karira
Aug 7 at 16:37
It depends on how you word the question. If you worded it as the probability that a random family had four members and all four were wiped out, then you are correct, and it would be 12% of 1/16. If you are only looking at families with four members, then there is a 100% chance that there are only four members in the family. This is known as a conditional probability.
â InterstellarProbe
Aug 7 at 19:05
It depends on how you word the question. If you worded it as the probability that a random family had four members and all four were wiped out, then you are correct, and it would be 12% of 1/16. If you are only looking at families with four members, then there is a 100% chance that there are only four members in the family. This is known as a conditional probability.
â InterstellarProbe
Aug 7 at 19:05
add a comment |Â
2
What are you talking about?
â lulu
Aug 7 at 15:22
I am asking if 50% of the world population is dying then what is the probability of family of 4 dying.
â Sagar Karira
Aug 7 at 15:23
@lulu The ending of Avengers: Infinity Wars.
â John
Aug 7 at 15:24
1
That's fine for those who have seen the movie. But this is a mathematics site, not a movie fan site, hence this question is entirely unclear.
â Lee Mosher
Aug 7 at 15:25
1
It was perfectly clear to me! :)
â John
Aug 7 at 15:25