A question on existence of a Sobolev Hilbert space, where convergence implies uniform convergence

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Is there a Sobolev Hilbert space $H^k(Omega)$($Omega$ open subset of $mathbbR^m$, with a smooth boundary), for some $k in mathbbN$, such that, any sequence in the space $C^0(barOmega)cap H^k(Omega)$, that converges in the norm $|.|_H^k$, also has to converge in the norm $|.|_C^0(barOmega)$
real-analysis functional-analysis sobolev-spaces
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Is there a Sobolev Hilbert space $H^k(Omega)$($Omega$ open subset of $mathbbR^m$, with a smooth boundary), for some $k in mathbbN$, such that, any sequence in the space $C^0(barOmega)cap H^k(Omega)$, that converges in the norm $|.|_H^k$, also has to converge in the norm $|.|_C^0(barOmega)$
real-analysis functional-analysis sobolev-spaces
3
Try to look up Sobolev's embedding theorem.
â gerw
Aug 15 at 6:50
add a comment |Â
up vote
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down vote
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up vote
0
down vote
favorite
Is there a Sobolev Hilbert space $H^k(Omega)$($Omega$ open subset of $mathbbR^m$, with a smooth boundary), for some $k in mathbbN$, such that, any sequence in the space $C^0(barOmega)cap H^k(Omega)$, that converges in the norm $|.|_H^k$, also has to converge in the norm $|.|_C^0(barOmega)$
real-analysis functional-analysis sobolev-spaces
Is there a Sobolev Hilbert space $H^k(Omega)$($Omega$ open subset of $mathbbR^m$, with a smooth boundary), for some $k in mathbbN$, such that, any sequence in the space $C^0(barOmega)cap H^k(Omega)$, that converges in the norm $|.|_H^k$, also has to converge in the norm $|.|_C^0(barOmega)$
real-analysis functional-analysis sobolev-spaces
asked Aug 15 at 5:59
Rajesh Dachiraju
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3
Try to look up Sobolev's embedding theorem.
â gerw
Aug 15 at 6:50
add a comment |Â
3
Try to look up Sobolev's embedding theorem.
â gerw
Aug 15 at 6:50
3
3
Try to look up Sobolev's embedding theorem.
â gerw
Aug 15 at 6:50
Try to look up Sobolev's embedding theorem.
â gerw
Aug 15 at 6:50
add a comment |Â
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3
Try to look up Sobolev's embedding theorem.
â gerw
Aug 15 at 6:50