A question on existence of a Sobolev Hilbert space, where convergence implies uniform convergence

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Is there a Sobolev Hilbert space $H^k(Omega)$($Omega$ open subset of $mathbbR^m$, with a smooth boundary), for some $k in mathbbN$, such that, any sequence in the space $C^0(barOmega)cap H^k(Omega)$, that converges in the norm $|.|_H^k$, also has to converge in the norm $|.|_C^0(barOmega)$







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    Try to look up Sobolev's embedding theorem.
    – gerw
    Aug 15 at 6:50














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Is there a Sobolev Hilbert space $H^k(Omega)$($Omega$ open subset of $mathbbR^m$, with a smooth boundary), for some $k in mathbbN$, such that, any sequence in the space $C^0(barOmega)cap H^k(Omega)$, that converges in the norm $|.|_H^k$, also has to converge in the norm $|.|_C^0(barOmega)$







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  • 3




    Try to look up Sobolev's embedding theorem.
    – gerw
    Aug 15 at 6:50












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up vote
0
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Is there a Sobolev Hilbert space $H^k(Omega)$($Omega$ open subset of $mathbbR^m$, with a smooth boundary), for some $k in mathbbN$, such that, any sequence in the space $C^0(barOmega)cap H^k(Omega)$, that converges in the norm $|.|_H^k$, also has to converge in the norm $|.|_C^0(barOmega)$







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Is there a Sobolev Hilbert space $H^k(Omega)$($Omega$ open subset of $mathbbR^m$, with a smooth boundary), for some $k in mathbbN$, such that, any sequence in the space $C^0(barOmega)cap H^k(Omega)$, that converges in the norm $|.|_H^k$, also has to converge in the norm $|.|_C^0(barOmega)$









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asked Aug 15 at 5:59









Rajesh Dachiraju

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  • 3




    Try to look up Sobolev's embedding theorem.
    – gerw
    Aug 15 at 6:50












  • 3




    Try to look up Sobolev's embedding theorem.
    – gerw
    Aug 15 at 6:50







3




3




Try to look up Sobolev's embedding theorem.
– gerw
Aug 15 at 6:50




Try to look up Sobolev's embedding theorem.
– gerw
Aug 15 at 6:50















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