determine $m$ such that $langle m rangle = langle 28 rangle cap langle 35 rangle$
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I need to find a value for $m$, thought of finding the greatest common divisor between the two numbers, but $langle rangle$ represents an ideal, don't know if that's the way to solve this problem.
I should also mention that I already know that the intersection of two ideals is also an ideal.
Help would be appreciated.
ring-theory algebraic-number-theory
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up vote
1
down vote
favorite
I need to find a value for $m$, thought of finding the greatest common divisor between the two numbers, but $langle rangle$ represents an ideal, don't know if that's the way to solve this problem.
I should also mention that I already know that the intersection of two ideals is also an ideal.
Help would be appreciated.
ring-theory algebraic-number-theory
1
The proper TeX for ideal brackets islangle generator rangle
. Which is why a lot of people on this site prefer instead to use(generator)
, or even a Fraktur letter, like $mathfrakG$ or $mathfrakM$.
â Mr. Brooks
Sep 10 at 20:27
add a comment |Â
up vote
1
down vote
favorite
up vote
1
down vote
favorite
I need to find a value for $m$, thought of finding the greatest common divisor between the two numbers, but $langle rangle$ represents an ideal, don't know if that's the way to solve this problem.
I should also mention that I already know that the intersection of two ideals is also an ideal.
Help would be appreciated.
ring-theory algebraic-number-theory
I need to find a value for $m$, thought of finding the greatest common divisor between the two numbers, but $langle rangle$ represents an ideal, don't know if that's the way to solve this problem.
I should also mention that I already know that the intersection of two ideals is also an ideal.
Help would be appreciated.
ring-theory algebraic-number-theory
ring-theory algebraic-number-theory
edited Sep 10 at 20:45
Mr. Brooks
13811237
13811237
asked Sep 10 at 3:19
DavidTomahawk
455216
455216
1
The proper TeX for ideal brackets islangle generator rangle
. Which is why a lot of people on this site prefer instead to use(generator)
, or even a Fraktur letter, like $mathfrakG$ or $mathfrakM$.
â Mr. Brooks
Sep 10 at 20:27
add a comment |Â
1
The proper TeX for ideal brackets islangle generator rangle
. Which is why a lot of people on this site prefer instead to use(generator)
, or even a Fraktur letter, like $mathfrakG$ or $mathfrakM$.
â Mr. Brooks
Sep 10 at 20:27
1
1
The proper TeX for ideal brackets is
langle generator rangle
. Which is why a lot of people on this site prefer instead to use (generator)
, or even a Fraktur letter, like $mathfrakG$ or $mathfrakM$.â Mr. Brooks
Sep 10 at 20:27
The proper TeX for ideal brackets is
langle generator rangle
. Which is why a lot of people on this site prefer instead to use (generator)
, or even a Fraktur letter, like $mathfrakG$ or $mathfrakM$.â Mr. Brooks
Sep 10 at 20:27
add a comment |Â
2 Answers
2
active
oldest
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up vote
3
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You want $m in langle 28 rangle cap langle 35 rangle$. So $m=28k$ and $m=35l$ for some $k,l in mathbbZ$. Thus $28k=35l implies 4k=5l$. But $gcd(4,5)=1$, therefore $4 | l$ and $5 | k$. This implies $$m=140j qquad text for some j in mathbbZ.$$
But $m$ is a generator so least positive such value is $m=140$.
How come "$4 | l$ and $5 | k$" implies that value of m?
â DavidTomahawk
Sep 10 at 3:44
1
@DavidTomahawk $4 | l implies l=4j$, thus $m=35l=35(4j)=140j$.
â Anurag A
Sep 10 at 3:52
add a comment |Â
up vote
0
down vote
You want to find the least common multiple of $28$ and $35$
That is $140$ so you ideal is$$ <140> = <28> cap <35> $$
add a comment |Â
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
3
down vote
accepted
You want $m in langle 28 rangle cap langle 35 rangle$. So $m=28k$ and $m=35l$ for some $k,l in mathbbZ$. Thus $28k=35l implies 4k=5l$. But $gcd(4,5)=1$, therefore $4 | l$ and $5 | k$. This implies $$m=140j qquad text for some j in mathbbZ.$$
But $m$ is a generator so least positive such value is $m=140$.
How come "$4 | l$ and $5 | k$" implies that value of m?
â DavidTomahawk
Sep 10 at 3:44
1
@DavidTomahawk $4 | l implies l=4j$, thus $m=35l=35(4j)=140j$.
â Anurag A
Sep 10 at 3:52
add a comment |Â
up vote
3
down vote
accepted
You want $m in langle 28 rangle cap langle 35 rangle$. So $m=28k$ and $m=35l$ for some $k,l in mathbbZ$. Thus $28k=35l implies 4k=5l$. But $gcd(4,5)=1$, therefore $4 | l$ and $5 | k$. This implies $$m=140j qquad text for some j in mathbbZ.$$
But $m$ is a generator so least positive such value is $m=140$.
How come "$4 | l$ and $5 | k$" implies that value of m?
â DavidTomahawk
Sep 10 at 3:44
1
@DavidTomahawk $4 | l implies l=4j$, thus $m=35l=35(4j)=140j$.
â Anurag A
Sep 10 at 3:52
add a comment |Â
up vote
3
down vote
accepted
up vote
3
down vote
accepted
You want $m in langle 28 rangle cap langle 35 rangle$. So $m=28k$ and $m=35l$ for some $k,l in mathbbZ$. Thus $28k=35l implies 4k=5l$. But $gcd(4,5)=1$, therefore $4 | l$ and $5 | k$. This implies $$m=140j qquad text for some j in mathbbZ.$$
But $m$ is a generator so least positive such value is $m=140$.
You want $m in langle 28 rangle cap langle 35 rangle$. So $m=28k$ and $m=35l$ for some $k,l in mathbbZ$. Thus $28k=35l implies 4k=5l$. But $gcd(4,5)=1$, therefore $4 | l$ and $5 | k$. This implies $$m=140j qquad text for some j in mathbbZ.$$
But $m$ is a generator so least positive such value is $m=140$.
answered Sep 10 at 3:42
Anurag A
22.9k12244
22.9k12244
How come "$4 | l$ and $5 | k$" implies that value of m?
â DavidTomahawk
Sep 10 at 3:44
1
@DavidTomahawk $4 | l implies l=4j$, thus $m=35l=35(4j)=140j$.
â Anurag A
Sep 10 at 3:52
add a comment |Â
How come "$4 | l$ and $5 | k$" implies that value of m?
â DavidTomahawk
Sep 10 at 3:44
1
@DavidTomahawk $4 | l implies l=4j$, thus $m=35l=35(4j)=140j$.
â Anurag A
Sep 10 at 3:52
How come "$4 | l$ and $5 | k$" implies that value of m?
â DavidTomahawk
Sep 10 at 3:44
How come "$4 | l$ and $5 | k$" implies that value of m?
â DavidTomahawk
Sep 10 at 3:44
1
1
@DavidTomahawk $4 | l implies l=4j$, thus $m=35l=35(4j)=140j$.
â Anurag A
Sep 10 at 3:52
@DavidTomahawk $4 | l implies l=4j$, thus $m=35l=35(4j)=140j$.
â Anurag A
Sep 10 at 3:52
add a comment |Â
up vote
0
down vote
You want to find the least common multiple of $28$ and $35$
That is $140$ so you ideal is$$ <140> = <28> cap <35> $$
add a comment |Â
up vote
0
down vote
You want to find the least common multiple of $28$ and $35$
That is $140$ so you ideal is$$ <140> = <28> cap <35> $$
add a comment |Â
up vote
0
down vote
up vote
0
down vote
You want to find the least common multiple of $28$ and $35$
That is $140$ so you ideal is$$ <140> = <28> cap <35> $$
You want to find the least common multiple of $28$ and $35$
That is $140$ so you ideal is$$ <140> = <28> cap <35> $$
answered Sep 10 at 3:33
Mohammad Riazi-Kermani
32.2k41853
32.2k41853
add a comment |Â
add a comment |Â
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1
The proper TeX for ideal brackets is
langle generator rangle
. Which is why a lot of people on this site prefer instead to use(generator)
, or even a Fraktur letter, like $mathfrakG$ or $mathfrakM$.â Mr. Brooks
Sep 10 at 20:27