determine $m$ such that $langle m rangle = langle 28 rangle cap langle 35 rangle$

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I need to find a value for $m$, thought of finding the greatest common divisor between the two numbers, but $langle rangle$ represents an ideal, don't know if that's the way to solve this problem.



I should also mention that I already know that the intersection of two ideals is also an ideal.



Help would be appreciated.










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    The proper TeX for ideal brackets is langle generator rangle. Which is why a lot of people on this site prefer instead to use (generator), or even a Fraktur letter, like $mathfrakG$ or $mathfrakM$.
    – Mr. Brooks
    Sep 10 at 20:27














up vote
1
down vote

favorite












I need to find a value for $m$, thought of finding the greatest common divisor between the two numbers, but $langle rangle$ represents an ideal, don't know if that's the way to solve this problem.



I should also mention that I already know that the intersection of two ideals is also an ideal.



Help would be appreciated.










share|cite|improve this question



















  • 1




    The proper TeX for ideal brackets is langle generator rangle. Which is why a lot of people on this site prefer instead to use (generator), or even a Fraktur letter, like $mathfrakG$ or $mathfrakM$.
    – Mr. Brooks
    Sep 10 at 20:27












up vote
1
down vote

favorite









up vote
1
down vote

favorite











I need to find a value for $m$, thought of finding the greatest common divisor between the two numbers, but $langle rangle$ represents an ideal, don't know if that's the way to solve this problem.



I should also mention that I already know that the intersection of two ideals is also an ideal.



Help would be appreciated.










share|cite|improve this question















I need to find a value for $m$, thought of finding the greatest common divisor between the two numbers, but $langle rangle$ represents an ideal, don't know if that's the way to solve this problem.



I should also mention that I already know that the intersection of two ideals is also an ideal.



Help would be appreciated.







ring-theory algebraic-number-theory






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edited Sep 10 at 20:45









Mr. Brooks

13811237




13811237










asked Sep 10 at 3:19









DavidTomahawk

455216




455216







  • 1




    The proper TeX for ideal brackets is langle generator rangle. Which is why a lot of people on this site prefer instead to use (generator), or even a Fraktur letter, like $mathfrakG$ or $mathfrakM$.
    – Mr. Brooks
    Sep 10 at 20:27












  • 1




    The proper TeX for ideal brackets is langle generator rangle. Which is why a lot of people on this site prefer instead to use (generator), or even a Fraktur letter, like $mathfrakG$ or $mathfrakM$.
    – Mr. Brooks
    Sep 10 at 20:27







1




1




The proper TeX for ideal brackets is langle generator rangle. Which is why a lot of people on this site prefer instead to use (generator), or even a Fraktur letter, like $mathfrakG$ or $mathfrakM$.
– Mr. Brooks
Sep 10 at 20:27




The proper TeX for ideal brackets is langle generator rangle. Which is why a lot of people on this site prefer instead to use (generator), or even a Fraktur letter, like $mathfrakG$ or $mathfrakM$.
– Mr. Brooks
Sep 10 at 20:27










2 Answers
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You want $m in langle 28 rangle cap langle 35 rangle$. So $m=28k$ and $m=35l$ for some $k,l in mathbbZ$. Thus $28k=35l implies 4k=5l$. But $gcd(4,5)=1$, therefore $4 | l$ and $5 | k$. This implies $$m=140j qquad text for some j in mathbbZ.$$
But $m$ is a generator so least positive such value is $m=140$.






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  • How come "$4 | l$ and $5 | k$" implies that value of m?
    – DavidTomahawk
    Sep 10 at 3:44






  • 1




    @DavidTomahawk $4 | l implies l=4j$, thus $m=35l=35(4j)=140j$.
    – Anurag A
    Sep 10 at 3:52


















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0
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You want to find the least common multiple of $28$ and $35$



That is $140$ so you ideal is$$ <140> = <28> cap <35> $$






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    2 Answers
    2






    active

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    2 Answers
    2






    active

    oldest

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    active

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    up vote
    3
    down vote



    accepted










    You want $m in langle 28 rangle cap langle 35 rangle$. So $m=28k$ and $m=35l$ for some $k,l in mathbbZ$. Thus $28k=35l implies 4k=5l$. But $gcd(4,5)=1$, therefore $4 | l$ and $5 | k$. This implies $$m=140j qquad text for some j in mathbbZ.$$
    But $m$ is a generator so least positive such value is $m=140$.






    share|cite|improve this answer




















    • How come "$4 | l$ and $5 | k$" implies that value of m?
      – DavidTomahawk
      Sep 10 at 3:44






    • 1




      @DavidTomahawk $4 | l implies l=4j$, thus $m=35l=35(4j)=140j$.
      – Anurag A
      Sep 10 at 3:52















    up vote
    3
    down vote



    accepted










    You want $m in langle 28 rangle cap langle 35 rangle$. So $m=28k$ and $m=35l$ for some $k,l in mathbbZ$. Thus $28k=35l implies 4k=5l$. But $gcd(4,5)=1$, therefore $4 | l$ and $5 | k$. This implies $$m=140j qquad text for some j in mathbbZ.$$
    But $m$ is a generator so least positive such value is $m=140$.






    share|cite|improve this answer




















    • How come "$4 | l$ and $5 | k$" implies that value of m?
      – DavidTomahawk
      Sep 10 at 3:44






    • 1




      @DavidTomahawk $4 | l implies l=4j$, thus $m=35l=35(4j)=140j$.
      – Anurag A
      Sep 10 at 3:52













    up vote
    3
    down vote



    accepted







    up vote
    3
    down vote



    accepted






    You want $m in langle 28 rangle cap langle 35 rangle$. So $m=28k$ and $m=35l$ for some $k,l in mathbbZ$. Thus $28k=35l implies 4k=5l$. But $gcd(4,5)=1$, therefore $4 | l$ and $5 | k$. This implies $$m=140j qquad text for some j in mathbbZ.$$
    But $m$ is a generator so least positive such value is $m=140$.






    share|cite|improve this answer












    You want $m in langle 28 rangle cap langle 35 rangle$. So $m=28k$ and $m=35l$ for some $k,l in mathbbZ$. Thus $28k=35l implies 4k=5l$. But $gcd(4,5)=1$, therefore $4 | l$ and $5 | k$. This implies $$m=140j qquad text for some j in mathbbZ.$$
    But $m$ is a generator so least positive such value is $m=140$.







    share|cite|improve this answer












    share|cite|improve this answer



    share|cite|improve this answer










    answered Sep 10 at 3:42









    Anurag A

    22.9k12244




    22.9k12244











    • How come "$4 | l$ and $5 | k$" implies that value of m?
      – DavidTomahawk
      Sep 10 at 3:44






    • 1




      @DavidTomahawk $4 | l implies l=4j$, thus $m=35l=35(4j)=140j$.
      – Anurag A
      Sep 10 at 3:52

















    • How come "$4 | l$ and $5 | k$" implies that value of m?
      – DavidTomahawk
      Sep 10 at 3:44






    • 1




      @DavidTomahawk $4 | l implies l=4j$, thus $m=35l=35(4j)=140j$.
      – Anurag A
      Sep 10 at 3:52
















    How come "$4 | l$ and $5 | k$" implies that value of m?
    – DavidTomahawk
    Sep 10 at 3:44




    How come "$4 | l$ and $5 | k$" implies that value of m?
    – DavidTomahawk
    Sep 10 at 3:44




    1




    1




    @DavidTomahawk $4 | l implies l=4j$, thus $m=35l=35(4j)=140j$.
    – Anurag A
    Sep 10 at 3:52





    @DavidTomahawk $4 | l implies l=4j$, thus $m=35l=35(4j)=140j$.
    – Anurag A
    Sep 10 at 3:52











    up vote
    0
    down vote













    You want to find the least common multiple of $28$ and $35$



    That is $140$ so you ideal is$$ <140> = <28> cap <35> $$






    share|cite|improve this answer
























      up vote
      0
      down vote













      You want to find the least common multiple of $28$ and $35$



      That is $140$ so you ideal is$$ <140> = <28> cap <35> $$






      share|cite|improve this answer






















        up vote
        0
        down vote










        up vote
        0
        down vote









        You want to find the least common multiple of $28$ and $35$



        That is $140$ so you ideal is$$ <140> = <28> cap <35> $$






        share|cite|improve this answer












        You want to find the least common multiple of $28$ and $35$



        That is $140$ so you ideal is$$ <140> = <28> cap <35> $$







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered Sep 10 at 3:33









        Mohammad Riazi-Kermani

        32.2k41853




        32.2k41853



























             

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